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		<title>Free software for NMR interpretation</title>
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					<description><![CDATA[Click here to see more posts about NMR Only 15$ for interpretation of your NMR spectrum Payment Upon Completion Send your results... NMRshiftdb NMRshiftdb2 is a NMR database (web database) for organic structures and their nuclear magnetic resonance (nmr) spectra. It allows for spectrum prediction (13C,&#160;1H and other nuclei) as well as for searching spectra, [&#8230;]]]></description>
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<p class="has-text-align-center"><strong><a href="http://www.analyzetest.com/index.php/category/analyzing/nmr/">Click here to see more posts about NMR</a></strong></p>



<pre class="wp-block-verse has-text-align-center"><span style="color:#ffffff" class="tadv-color">Only 15$ for interpretation of your NMR spectrum
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<ol class="wp-block-list"><li>NMRshiftdb</li></ol>



<p>NMRshiftdb2 is a NMR database (web database) for organic structures and their nuclear magnetic resonance (nmr) spectra. It allows for spectrum prediction (<sup>13</sup>C,&nbsp;<sup>1</sup>H and other nuclei) as well as for searching spectra, structures and other properties. The nmrshiftdb2 software is open source, the data is published under an open content license. The core of nmrshitdb2 are fully assigned spectra with raw data and peak lists (we have pure peak lists as well). Those datasets are peer reviewed by a&nbsp;board of reviewers. The project is supported by a&nbsp;scientific advisory board.</p>



<span id="more-596"></span>



<p>nmrshiftdb2 is part of the&nbsp;NFDI4Chem initiative&nbsp;and will provide a component for a curated repository there. Please consult the&nbsp;documentation&nbsp;for more detailed information.</p>



<p class="has-text-align-center"><strong>See: https://nmrshiftdb.nmr.uni-koeln.de/portal</strong></p>



<p>2. ACD/NMR</p>



<p>ACD/NMR Workbook Suite is a comprehensive NMR software application with an intuitive interface. It features a full suite of advanced processing, analysis, and databasing functionalities for 1D and 2D NMR data from all major vendor formats. NMR Workbook Suite is built upon cutting-edge algorithms for the most reliable NMR data interpretation. It is designed to streamline routine NMR workflows, simplify structure characterization, and much more. </p>



<h5 class="wp-block-heading" id="powerful-nmr-interpretation-software-highlights">Powerful NMR Interpretation Software | Highlights</h5>



<ul class="wp-block-list"><li>Import and process 1D and 2D NMR data from all major instrument vendor formats in a single collaborative platform</li><li>Process NMR data manually or automate routine processing workflows—Fourier transformation, calibration, peak picking, integration, multiplet analysis, etc.</li><li>Synchronize peak picking and assignments across datasets within a project</li><li>Confidently verify structures with 3 different verification levels</li><li>Perform targeted analysis of known mixture components and optimize untargeted mixture analysis workflow</li><li>Perform Conformational Analysis using NOESY/ROESY spectra</li><li>Create comprehensive multiplet reports and publication-ready data</li><li>Store, manage, and share live NMR spectra</li></ul>



<p>Synchronize peak picking and assignments across NMR datasets using NMR<em>Sync</em>—our game-changing technology. Plus, the associated peaks from NMR<em>Sync</em>, NMR prediction, and connectivity-based algorithms are automatically used to only identify the assignments that match all data. This quick and accurate peak picking and assignment workflow helps you to maximize your productivity in the following ways:</p>



<ul class="wp-block-list"><li>Use any peak in any spectrum to initiate NMRSync</li><li>Integrate a peak in any spectrum and all related peaks in the 1D and 2D NMR spectra of that dataset will be identified and linked in real time</li><li>Automatically resolve overlapping&nbsp;<sup>1</sup>H and&nbsp;<sup>13</sup>C peaks from 2D NMR data</li><li>Receive immediate color-coded feedback on the best assignment for instant decision-making purposes</li></ul>



<p>NMR Workbook Suite includes three levels of structure verification that evaluate alternative structures to varying degrees for added flexibility in your NMR analysis. This ensures the best structure that matches the experimental NMR data is confirmed with much less time and effort than manual interpretation.</p>



<ul class="wp-block-list"><li>Determine how well your proposed structure matches the datasets in your NMR project with single structure verification</li><li>Generate a specified number of alternative structures, based on the user-defined proposed structure, and evaluate whether they are a better match to the NMR dataset using Combined and Concurrent Verification</li><li>Generate and view every alternative structural and&nbsp;<em>cis/trans</em>&nbsp;isomer that matches the experimental data in real-time using Unbiased Verification for an absolute level of confidence. This workflow eliminates the user bias and ensures the assigned structure is indeed the best structure that fits the experimental data.</li></ul>



<p class="has-text-align-center"><strong>See: https://www.acdlabs.com/products/spectrus/workbooks/nmr/</strong></p>



<p>3. <strong>See: http://www.cheminfo.org/Spectra/NMR/Predictions/1H_Prediction/index.html</strong></p>



<p>4. <strong>See: https://www.nmrprocflow.org/</strong></p>



<p>5. <strong>See: https://chem.washington.edu/facilities/data-processing</strong></p>



<p>6. <strong>See: https://www.cgl.ucsf.edu/home/sparky/</strong></p>



<p><strong>7. See: http://www.nmrdb.org/about/</strong></p>
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		<title>How to analyze Nuclear Magnetic Resonance (NMR) spectra</title>
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					<description><![CDATA[Click here to see more posts about NMR Only 15$ for interpretation of your NMR spectrum Payment Upon Completion Send your results... Nuclear Magnetic Resonance (NMR) interpretation plays a pivotal role in molecular identifications. As interpreting NMR spectra, the structure of an unknown compound, as well as known structures, can be assigned by several factors [&#8230;]]]></description>
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<p class="has-text-align-center"><strong><a href="http://www.analyzetest.com/index.php/category/analyzing/nmr/">Click here to see more posts about NMR</a></strong></p>



<pre class="wp-block-verse has-text-align-center"><span style="color:#ffffff" class="tadv-color">Only 15$ for interpretation of your NMR spectrum
</span><strong><mark>Payment Upon Completion
</mark></strong><a href="http://www.analyzetest.com/index.php/contact-us/">Send your results...</a></pre>



<p>Nuclear Magnetic Resonance (NMR) interpretation plays a pivotal role in molecular identifications. As interpreting NMR spectra, the structure of an unknown compound, as well as known structures, can be assigned by several factors such as chemical shift, spin multiplicity, coupling constants, and integration. This Module focuses on the most important&nbsp;<sup>1</sup>H and&nbsp;<sup>13</sup>C NMR spectra to find out structure even though there are various kinds of NMR spectra such as&nbsp;<sup>14</sup>N,&nbsp;<sup>19</sup>F, and&nbsp;<sup>31</sup>P. NMR spectrum shows that x- axis is chemical shift in ppm. It also contains integral areas, splitting pattern, and coupling constant.</p>



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<span id="more-582"></span>



<p>Strategy for Solving Structure</p>



<p>Here is the general strategy for solving structure with NMR:</p>



<ol class="wp-block-list"><li>Molecular formula is determined by chemical analysis such as elementary analysis</li><li><strong>Double-bond equivalent</strong>&nbsp;(also known as&nbsp;<a href="https://chem.libretexts.org/Bookshelves/Organic_Chemistry/Supplemental_Modules_(Organic_Chemistry)/Alkenes/Properties_of_Alkenes/Degree_of_Unsaturation" target="_blank" rel="noopener">Degree of Unsaturation</a>) is calculated by a simple equation to estimate the number of the multiple bonds and rings. It assumes that oxygen (O) and sulfur (S) are ignored and halogen (Cl, Br) and nitrogen is replaced by CH. The resulting empirical formula is C<sub>a</sub>H<sub>b</sub></li></ol>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9380/Equation_1_(1).jpg?revision=1" alt="Equation 1 (1).jpg"/></figure>



<ol class="wp-block-list" start="3"><li>Structure fragmentation is determined by chemical shift, spin multiplicity, integral (peak area), and coupling constants (1J1J,&nbsp;2J2J)</li><li>Molecular skeleton is built up using 2-dimensional NMR spectroscopy.</li><li>Relative configuration is predicted by coupling constant (<sup>3</sup>J).</li></ol>



<h2 class="wp-block-heading" id="1h-nmr"><sup>1</sup>H NMR</h2>



<h3 class="wp-block-heading" id="chemical-shift">Chemical Shift</h3>



<p><a href="https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)/Spectroscopy/Magnetic_Resonance_Spectroscopies/Nuclear_Magnetic_Resonance/NMR_-_Theory" target="_blank" rel="noopener">Chemical shift</a>&nbsp;is associated with the Larmor frequency of a nuclear spin to its chemical environment. Tetramethylsilane (TMS,&nbsp;(CH3)4Si(CH3)4Si) is generally used as an internal standard to determine chemical shift of compounds: δ<sub>TMS</sub>=0 ppm. In other words, frequencies for chemicals are measured for a&nbsp;<sup>1</sup>H or&nbsp;<sup>13</sup>C nucleus of a sample from the&nbsp;<sup>1</sup>H or&nbsp;<sup>13</sup>C resonance of TMS. It is important to understand trend of chemical shift in terms of NMR interpretation. The proton NMR chemical shift is affect by nearness to electronegative atoms (O, N, halogen.) and unsaturated groups (C=C,C=O, aromatic). Electronegative groups move to the down field (left; increase in ppm). Unsaturated groups shift to downfield (left) when affecting nucleus is in the plane of the unsaturation, but reverse shift takes place in the regions above and below this plane.&nbsp;<sup>1</sup>H chemical shift play a role in identifying many functional groups. Figure&nbsp;11. indicates important example to figure out the functional groups.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9384/Fig1.bmp?revision=1&amp;size=bestfit&amp;width=732&amp;height=323" alt="Fig1.bmp"/><figcaption>Figure&nbsp;11: 1H chemical shift ranges for organic compound</figcaption></figure>



<h3 class="wp-block-heading" id="chemical-equivalence">Chemical equivalence</h3>



<p>Protons with Chemical equivalence has the same chemical shift due to symmetry within molecule (CH3COCH3CH3COCH3) or fast rotation around single bond (-CH<sub>3</sub>; methyl groups).</p>



<h2 class="wp-block-heading" id="spin-spin-splitting">Spin-Spin Splitting</h2>



<p><a href="https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)/Spectroscopy/Magnetic_Resonance_Spectroscopies/Nuclear_Magnetic_Resonance/NMR_-_Theory" target="_blank" rel="noopener">Spin-Spin splitting</a>&nbsp;means that an absorbing peak is split by more than one “neighbor” proton. Splitting signals are separated to J Hz, where is called the coupling constant. The spitting is a very essential part to obtain exact information about the number of the neighboring protons. The maximum of distance for splitting is three bonds. Chemical equivalent protons do not result in spin-spin splitting. When a proton splits, the proton’s chemical shift is determined in the center of the splitting lines.</p>



<h4 class="wp-block-heading" id="spin-multiplicity-splitting-pattern">Spin Multiplicity (Splitting pattern)</h4>



<p>Spin Multiplicity plays a role in determining the number of neighboring protons. Here is a multiplicity rules: In case of&nbsp;AmBnAmBn&nbsp;system, the multiplicity rule is that Nuclei of&nbsp;BB&nbsp;element produce a splitting the&nbsp;AA&nbsp;signal into&nbsp;nB+1nB+1&nbsp;lines. The general formula which applies to all nuclei is&nbsp;2nI+12nI+1, where&nbsp;II&nbsp;is the spin quantum number of the coupled element. The relative intensities of the each lines are given by the coefficients of the Pascal’s triangle (Figure&nbsp;22).</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/24873/pascalstriangle8.png?revision=1&amp;size=bestfit&amp;width=550&amp;height=334" alt="Fig2.bmp"/><figcaption>Figure&nbsp;22: Pascal&#8217;s triangle</figcaption></figure>



<h4 class="wp-block-heading" id="first-order-splitting-pattern">First-order splitting pattern</h4>



<p>The chemical shift difference in Hertz between coupled protons in Hertz is much larger than the&nbsp;JJ&nbsp;coupling constant:ΔνJ≥8(1)(1)ΔνJ≥8</p>



<p>Where&nbsp;ΔνΔν&nbsp;is the difference of chemical shift. In other word, the proton is only coupled to other protons that are far away in chemical shift. The spectrum is called&nbsp;<em>first-order spectrum</em>. The splitting pattern depends on the magnetic field. The second-order splitting at the lower field can be resolved into first-order splitting pattern at the high field. The first-order splitting pattern is allowed to multiplicity rule (N+1) and Pascal’s triangle to determine splitting pattern and intensity distribution.</p>



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<p>Example&nbsp;11</p>



<p>The note is that structure system is A<sub>3</sub>M<sub>2</sub>X<sub>2</sub>. H<sub>a</sub>&nbsp;and H<sub>x</sub>&nbsp;has the triplet pattern by Hm because of N+1 rule. The signal of Hm is split into six peaks by H<sub>x</sub>&nbsp;and H<sub>a</sub>(Figure3) The First order pattern easily is predicted due to separation with equal splitting pattern.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9390/Fig3.bmp?revision=1&amp;size=bestfit&amp;width=561&amp;height=149" alt="Fig3.bmp"/><figcaption>Figure&nbsp;33: An example of splitting pattern</figcaption></figure>



<h4 class="wp-block-heading" id="high-order-splitting-pattern">High-order splitting pattern</h4>



<p>High-order splitting pattern takes place when chemical shift difference in Hertz is much less or the same that order of magnitude as the j coupling.ΔvJ≤10(2)(2)ΔvJ≤10</p>



<p>The second order pattern is observed as leaning of a classical pattern: the inner peaks are taller and the outer peaks are shorter in case of AB system (Figure&nbsp;44). This is called the&nbsp;<strong>roof effect</strong>.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9391/Fig4.bmp?revision=1&amp;size=bestfit&amp;width=646&amp;height=131" alt="Fig4.bmp"/><figcaption>Figure&nbsp;44: a) first-order pattern and b) second-order pattern of AB system</figcaption></figure>



<p>Here is other system as an example: A<sub>2</sub>B<sub>2</sub>&nbsp;(Figure&nbsp;55). The two triplet incline toward each other. Outer lines of the triplet are less than 1 in relative area and the inner lines are more than 1. The center lines have relative area 2.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9392/Fig5.bmp?revision=1&amp;size=bestfit&amp;width=720&amp;height=189" alt="Fig5.bmp"/><figcaption>Figure&nbsp;55: a) first-order pattern and b) second-order pattern of A<sub>2</sub>B<sub>2</sub>&nbsp;system</figcaption></figure>



<h4 class="wp-block-heading" id="coupling-constant-j-value">Coupling constant (J Value)</h4>



<p>Coupling constant is the strength of the spin-spin splitting interaction and the distance between the split lines. The value of distance is equal or different depending on the coupled nuclei. The coupling constants reflect the bonding environments of the coupled nuclei. Coupling constant is classified by the number of bonds:</p>



<h5 class="wp-block-heading" id="geminal-proton-proton-coupling-2jhh">Geminal proton-proton coupling (<sup>2</sup>J<sub>HH</sub>)</h5>



<p>Germinal coupling generates through two bonds (Figure&nbsp;66). Two proton having geminal coupling are not chemically equivalent. This coupling ranges from -20 to 40 Hz.&nbsp;<sup>2</sup>J<sub>HH</sub>depends on hybridization of carbon atom and the bond angle and the substituent such as electronegative atoms. When S-character is increased, Geminal coupling constant is increased:&nbsp;<sup>2</sup>J<sub>sp1</sub>&gt;<sup>2</sup>J<sub>sp2</sub>&gt;<sup>2</sup>J<sub>sp3</sub>&nbsp;The bond angle(HCH) gives rise to change&nbsp;<sup>2</sup>J<sub>HH</sub>&nbsp;value and depend on the strain of the ring in the cyclic systems. Geminal coupling constant determines ring size. When bond angle is decreased, ring size is decreased so that geminal coupling constant is more positive. If a atom is replace to an electronegative atom, Geminal coupling constant move to positive value.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9393/Fig6.bmp?revision=1&amp;size=bestfit&amp;width=408&amp;height=92" alt="Fig6.bmp"/><figcaption>Figure&nbsp;66: Geminal coupling</figcaption></figure>



<h5 class="wp-block-heading" id="vicinal-proton-proton-coupling-3jhh">Vicinal proton-proton coupling (<sup>3</sup>J<sub>HH</sub>)</h5>



<p>Vicinal coupling occurs though three bonds (Figure&nbsp;77.). The Vicinal coupling is the most useful information of dihedral angle, leading to stereochemistry and conformation of molecules. Vicinal coupling constant always has the positive value and is affected by the dihedral angle (?;HCCH), the valence angle (?; HCC), the bond length of carbon-carbon, and the effects of electronegative atoms. Vicinal coupling constant depending on the dihedral angle (Figure&nbsp;88) is given by the Karplus equation.3J=7.0−0.5cosϕ+4.5cos2ϕ(3)(3)3J=7.0−0.5cos⁡ϕ+4.5cos2⁡ϕ</p>



<p>When ? is the 90<sup>o</sup>, vicinal coupling constant is zero. In addition, vicinal coupling constant ranges from 8 to 10 Hz at the and ?=180<sup>o</sup>, where ?=0<sup>o</sup>&nbsp;and ?=180<sup>o</sup>&nbsp;means that the coupled protons have cis and trans configuration, respectively.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9394/Fig7.bmp?revision=1&amp;size=bestfit&amp;width=534&amp;height=111" alt="Fig7.bmp"/><figcaption>Figure&nbsp;77: Vicinal coupling</figcaption></figure>



<p>The valence angle(?;Figure&nbsp;88) also causes change of&nbsp;<sup>3</sup>J<sub>HH</sub>&nbsp;value. Valence angle is related with ring size. Typically, when the valence angle decreases, the coupling constant reduces. The distance between the carbons atoms gives influences to vicinal coupling constant</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9395/Fig8.bmp?revision=1&amp;size=bestfit&amp;width=299&amp;height=86" alt="Fig8.bmp"/><figcaption>Figure&nbsp;88: a) Dihedral angle and b) valence angle</figcaption></figure>



<p>The coupling constant increases with the decrease of bond length. Electronegative atoms affect vicinal coupling constants so that electronegative atoms decrease the vicinal coupling constants.</p>



<h4 class="wp-block-heading" id="integral">Integral</h4>



<p>Integral is referred to integrated peak area of 1H signals. The intensity is directly proportionally to the number of hydrogen.</p>



<h2 class="wp-block-heading" id="13c-nmr"><sup>13</sup>C NMR</h2>



<h4 class="wp-block-heading" id="chemical-shift">Chemical Shift</h4>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9378/1.jpg?revision=1" alt="1.jpg"/><figcaption>Figure&nbsp;99&nbsp;shows typical&nbsp;<sup>13</sup>C chemical shift regions of the major chemical class.</figcaption></figure>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9396/Fig9.bmp?revision=1&amp;size=bestfit&amp;width=719&amp;height=415" alt="Fig9.bmp"/><figcaption>Figure&nbsp;99:&nbsp;<sup>13</sup>C Chemical shift range for organic compound</figcaption></figure>



<h4 class="wp-block-heading" id="spin-spin-splitting">Spin-Spin splitting</h4>



<p>Comparing the&nbsp;<sup>1</sup>H NMR, there is a big difference thing in the&nbsp;<sup>13</sup>C NMR. The&nbsp;<sup>13</sup>C-&nbsp;<sup>13</sup>&nbsp;C spin-spin splitting rarely exit between adjacent carbons because&nbsp;<sup>13</sup>C is naturally lower abundant (1.1%)</p>



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<ul class="wp-block-list"><li><strong><sup>13</sup>C-<sup>1</sup>H Spin coupling</strong>:&nbsp;<sup>13</sup>C-<sup>1</sup>H Spin coupling provides useful information about the number of protons attached a carbon atom. In case of one bond coupling (<sup>1</sup>J<sub>CH</sub>), -CH, -CH<sub>2</sub>, and CH<sub>3</sub>&nbsp;have respectively doublet, triplet, quartets for the&nbsp;<sup>13</sup>C resonances in the spectrum. However,&nbsp;<sup>13</sup>C-<sup>1</sup>H Spin coupling has an disadvantage for&nbsp;<sup>13</sup>C spectrum interpretation.&nbsp;<sup>13</sup>C-<sup>1</sup>H Spin coupling is hard to analyze and reveal structure due to a forest of overlapping peaks that result from 100% abundance of&nbsp;<sup>1</sup>H.</li><li><strong>Decoupling</strong>: Decoupling is the process of removing&nbsp;<sup>13</sup>C-<sup>1</sup>H coupling interaction to simplify a spectrum and identify which pair of nuclei is involved in the J coupling. The decoupling&nbsp;<sup>13</sup>C spectra shows only one peak(singlet) for each unique carbon in the molecule(Figure&nbsp;1010.). Decoupling is performed by irradiating at the frequency of one proton with continuous low-power RF.</li></ul>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9385/Fig10.bmp?revision=1&amp;size=bestfit&amp;width=456&amp;height=143" alt="Fig10.bmp"/><figcaption>Figure&nbsp;1010. Decoupling in the&nbsp;<sup>13</sup>C&nbsp;NMR</figcaption></figure>



<ul class="wp-block-list"><li><strong>Distortionless enhancement by polarization transfer (DEPT):</strong>&nbsp;DEPT is used for distinguishing between a CH<sub>3</sub>&nbsp;group, a CH<sub>2</sub>&nbsp;group, and a CH group. The proton pulse is set at 45<sup>o</sup>, 90<sup>o</sup>, or 135<sup>o</sup>&nbsp;in the three separate experiments. The different pulses depend on the number of protons attached to a carbon atom. Figure&nbsp;1111. is an example about DEPT spectrum.</li></ul>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9386/Fig11.bmp?revision=1&amp;size=bestfit&amp;width=517&amp;height=430" alt="Fig11.bmp"/><figcaption>Figure&nbsp;1111. DEPT spectrum of n-isobutlybutrate</figcaption></figure>



<h3 class="wp-block-heading" id="2-dimensional-nmr-spectroscopy-cosy">2-dimensional NMR spectroscopy (COSY)</h3>



<p>COSY stands for COrrelation SpectroscopY. COSY spectrum is more useful information about what is being correlated.</p>



<h4 class="wp-block-heading" id="1h-1h-cosy-correlation-spectroscopy"><sup>1</sup>H-<sup>1</sup>H COSY (COrrelation SpectroscopY)</h4>



<p><sup>1</sup>H-<sup>1</sup>H COSY is used for clearly indicate correlation with coupled protons. A point of entry into a COSY spectrum is one of the keys to predict information from it successfully. Relation of Coupling protons is determined by cross peaks(correlation peaks) and in the COSY spectrum. In other words, Diagonal peaks by lines ar e coupled to each other. Figure&nbsp;1212&nbsp;indicates that there are correlation peaks between proton H<sub>1</sub>&nbsp;and H<sub>2</sub>&nbsp;as well as between H<sub>2</sub>&nbsp;and H<sub>4</sub>. This means the H<sub>2</sub>&nbsp;coupled to H<sub>1</sub>&nbsp;and H<sub>4</sub>.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9387/Fig12.bmp?revision=1&amp;size=bestfit&amp;width=455&amp;height=406" alt="Fig12.bmp"/><figcaption>Figure&nbsp;1212.&nbsp;<sup>1</sup>H-<sup>1</sup>H COSY spectrum</figcaption></figure>



<h4 class="wp-block-heading" id="1h-13c-cosy-hetcor"><sup>1</sup>H-<sup>13</sup>C COSY (HETCOR)</h4>



<p><sup>1</sup>H-<sup>13</sup>C COSY is the heteronuclear correlation spectroscopy. The HETCOR spectrum is correlated&nbsp;<sup>13</sup>C nuclei with directly attached protons.&nbsp;<sup>1</sup>H-<sup>13</sup>C coupling is one bond. The cross peaks mean correlation between a proton and a carbon (Figure&nbsp;1313). If a line does not have cross peak, this means that this carbon atoms has no attached proton (e.g. a quaternary carbon atom)</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9388/Fig13.bmp?revision=1&amp;size=bestfit&amp;width=512&amp;height=439" alt="Fig13.bmp"/><figcaption>Figure&nbsp;1313.&nbsp;<sup>1</sup>H-<sup>13</sup>C COSY spectrum</figcaption></figure>



<h2 class="wp-block-heading" id="references">References</h2>



<ol class="wp-block-list"><li>Balc*, M., Basic p1 sH- and p13 sC-NMR spectroscopy. 1st ed.; Elsevier: Amsterdam ; Boston, 2005; p xii, 427.</li><li>Breitmaier, E., Structure elucidation by NMR in organic chemistry : a practical guide. 3rd rev. ed.; Wiley: Chichester, West Sussex, England, 2002; p xii, 258.</li><li>Jacobsen, N. E., NMR spectroscopy explained : simplified theory, applications and examples for organic chemistry and structural biology. Wiley-Interscience: Hoboken, N.J., 2007; p xv, 668.</li><li>Silverstein, R. M.; Webster, F. X., Spectrometric identification of organic compounds. 6th ed.; Wiley: New York, 1998; p xiv, 482.</li></ol>



<h2 class="wp-block-heading" id="outside-links">Outside Links</h2>



<ul class="wp-block-list"><li>NMRShiftDB: a Free web database for NMR data : nmrshiftdb.chemie.uni-mainz.de/nmrshiftdb</li><li>NMR database from ACD/LAbs : www.acdlabs.com/products/spec_lab/exp_spectra/spec_libraries/aldrich.html</li><li>NMR database from John Crerar Library :&nbsp;<a href="http://crerar.typepad.com/crerar_lib...h_ir_nmr_.html" rel="noreferrer noopener" target="_blank">http://crerar.typepad.com/crerar_lib&#8230;h_ir_nmr_.html</a></li></ul>



<h2 class="wp-block-heading" id="problems">Problems</h2>



<p>Draw the 1H NMR spectrum for 2-Hydroxypropane in CDCl3. Assume sufficient resolution to provide a first-order spectrum and ignore vicinal proton-proton coupling(3JHH)</p>



<h2 class="wp-block-heading" id="solution">Solution</h2>



<p>1) the structure of 2-hydoroxyporpane is drawn</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9397/Pro1_1.bmp?revision=1" alt="Pro1_1.bmp"/></figure>



<p>Figure out which protons are chemically equivalent, i.e., two methyl (-CH<sub>3</sub>) groups are chemical equivalent.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9398/Pro1_2.bmp?revision=1" alt="Pro1_2.bmp"/><figcaption>Figure1): chemical shift of methyl groups (H<sub>a</sub>) : 1-2 ppm (?H<sub>a</sub>=1.1 ppm); chemical shift of -CH- groups (H<sub>b</sub>) moves to downfield due to effect on aldehyde groups:2-3ppm ( ?H<sub>b</sub>=2.4 ppm); chemical shift of aldehyde groups (H<sub>c</sub>):9-10 ppm (?H<sub>c</sub>=9.6 ppm)</figcaption></figure>



<p>4) Splitting pattern is determined by (N+1) rule: Ha is split into two peaks by H<sub>b</sub>(#of proton=1). H<sub>b</sub>&nbsp;has the septet pattern by H<sub>a</sub>&nbsp;(#of proton=6). H<sub>c</sub>&nbsp;has one peak.(Note that H<sub>c</sub>&nbsp;has doublet pattern by H<sub>b</sub>&nbsp;due to vicinal proton-proton coupling.)</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/9379/Answer1.bmp?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/9379/Answer1.bmp?revision=1&amp;size=bestfit&amp;width=720&amp;height=308" alt="Answer1.bmp"/></a></figure>



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					<description><![CDATA[Click here to see more posts about NMR Only 15$ for interpretation of your NMR spectrum Payment Upon Completion Send your results... This handout relates the basic theory of NMR described on&#160;the theory web handout&#160;with spectra of real molecules and how to deduce structure from the spectra. Before reading this handout, you need to be [&#8230;]]]></description>
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<p>This handout relates the basic theory of NMR described on&nbsp;the theory web handout&nbsp;with spectra of real molecules and how to deduce structure from the spectra. Before reading this handout, you need to be thoroughly familiar with all of theory concepts that were described.</p>



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<p><strong>1.0&nbsp;</strong>The NMR spectrum.</p>



<p><strong>1.1</strong>&nbsp;Because different amounts of electron density are around different non-eqivalent nuclei, the different non-equivalent nuclei in a molecule are experiencing slightly different net magnetic fields in an NMR experiment<a href="http://iverson.cm.utexas.edu/courses/310N/Handouts/NMRhandout.html" target="_blank" rel="noopener">&nbsp;(Review Section&nbsp;<strong>5.2A</strong>&nbsp;of the theory handout)</a>. Recall also that the difference in energy between the two allowed spin states (+1/2 and -1/2 spin states) of a spin 1/2 nucleus (like in 1H and 13C nuclei) depends on the exact magnetic field felt by the nucleus&nbsp;<a href="http://iverson.cm.utexas.edu/courses/310N/Handouts/NMRhandout.html" target="_blank" rel="noopener">(Review Section&nbsp;<strong>2.3C</strong>in the theory handout)</a>. Recall further that in the NMR experiment, when and only when nuclei are irradiated with electromagnetic radiation of energy that<em>&nbsp;exactly</em>corresponds to the energy difference between the +1/2 and -1/2 spin states, the nuclei absorb the energy and the NMR spectrometer measures this absorbance&nbsp;<a href="http://iverson.cm.utexas.edu/courses/310N/Handouts/NMRhandout.html" target="_blank" rel="noopener">(Review section&nbsp;<strong>3.1</strong>&nbsp;of the theory handout)</a>. The absorbance of energy to convert a nucleus from a +1/2 to a -1/2 spin state is referred to as &#8220;resonance&#8221; of that nucleus.<strong>1.1A</strong>&nbsp;The key conclusion is that nuclei with different electron densities have +1/2 and -1/2 spin states that differ in energy by differing amounts, so these nuclei will absorb electromagnetic radiation of different frequencies in the NMR experiment.</p>



<p><strong>1.1B&nbsp;</strong>Nuclei surrounded by greater amounts of electron density will be more shielded from the external magnetic field, so they will absorb electromagnetic radiation of lower energy, that is, lower frequency&nbsp;(energy is proportional to frequency).&nbsp;You may want to review&nbsp;<a href="http://iverson.cm.utexas.edu/courses/310N/Handouts/NMRhandout.html" target="_blank" rel="noopener">Section&nbsp;<strong>5.2A</strong>&nbsp;of the theory handout again</a>.</p>



<p><strong>1.1C</strong>&nbsp;The converse is also true, namely that nuclei surrounded by lesser amounts of electron density will be less shielded (referred to as being &#8220;deshielded&#8221;) from the external magnetic field, so they will absorb electromagnetic radiation of higher energy, that is, higher frequency(energy is proportional to frequency).</p>



<p><strong>1.1D&nbsp;</strong>The three most important factors influencing the electron density around a hydrogen nucleus are: (i) adjacent electronegative atoms remove electron density; (ii) hybridization of the attached carbon atom, increasing shielding is observed in the order sp2, sp, sp3; (iii) adjacent pi bonds are deshielding, which relates to (ii).<strong>1.2</strong>&nbsp;An NMR spectrum is a plot of absorbance versus frequency.</p>



<p><strong>1.2A</strong>&nbsp;To make different spectra directly comparable, a standard is used for all NMR spectra. For 1H NMR spectra, the standard is called tetramethylsilane (TMS)&nbsp;and a small amount of TMS is usually added to any 1H NMR sample.</p>



<p><strong>1.2B</strong>&nbsp;Magnets of different strengths lead to absorbance of electromagnetic radiation at different frequencies for the same nucleus, meaning that if simple frequency were plotted in an NMR spectra, you could not compare spectra taken of the same sample on machines with different magnet strengths. To solve this problem,&nbsp;the frequency of absorption plotted on NMR spectra are corrected for the magnet strength. In addition, frequency is correlated to the reference compound TMS.&nbsp;The frequency at which TMS absorbs is defined as 0 frequency by convention. In the NMR spectrum, absorbance frequencies of electromagnetic radiation are plotted as chemical shift (d) listed in units called&nbsp;<strong>p</strong>arts&nbsp;<strong>p</strong>er&nbsp;<strong>m</strong>illion (ppm) that is defined by the following equation:</p>



<figure class="wp-block-image"><img decoding="async" src="http://iverson.cm.utexas.edu/courses/310N/GIFssp04/miscgifs/NMRhandout4.gif" alt=""/></figure>



<figure class="wp-block-image"><img decoding="async" src="http://iverson.cm.utexas.edu/courses/310N/GIFssp04/miscgifs/NMRhandout5.gif" alt=""/></figure>



<p><strong>1.3 The bottom line to this entire section is that the hydrogen atoms of different functional groups (methyl groups, -CH2- groups, aldehyde -C(O)H, alkene C-H, etc.) have characteristic chemical shifts, i.e. absorbance frequencies. These characteristic chemical shifts are collected in tables such as Fgure 13.8 and Appendix 4 of your book. From the chemical shift information, you thus know what functional groups are present in a molecule.</strong></p>



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<p><strong>1.4 Chemically equivalent hydrogen atoms will have the same chemical shift and therefore give rise to the same signal.</strong>&nbsp;This is why we defined equivalent atoms in<a href="http://iverson.cm.utexas.edu/courses/310N/Handouts/NMRhandout.html" target="_blank" rel="noopener">&nbsp;Section<strong>6.1</strong>&nbsp;of the theory handout.</a>&nbsp;Non-equivalent groups of hydrogens will have different chemical shifts.&nbsp;<strong>Thus, you will have as many different signals in an NMR spectrum as there are chemically non-equivalent groups of hydrogen atoms.</strong></p>



<p><strong>2.0</strong>&nbsp;The nuclear spin of hydrogen atoms creates a magnetic field that influences the chemical shift of nearby hydrogen atoms&nbsp;<a href="http://iverson.cm.utexas.edu/courses/310N/Handouts/NMRhandout.html" target="_blank" rel="noopener">(Review Sections 5.1 and 5.2)</a>.</p>



<blockquote class="wp-block-quote is-layout-flow wp-block-quote-is-layout-flow"><p><strong>2.1&nbsp;</strong>Nuclear spin magnetic fields will influence hydrogen atoms that are three or fewer bonds away from each other in the same molecule.&nbsp;Hydrogen atoms that are four or greater bonds away usually do not influence each other.</p><p><strong>2.2&nbsp;</strong>A hydrogen atom with a nuclecus in a spin state of +1/2 produces a slightly different magnetic field than a one in a –1/2 spin state.</p><p><strong>2.3&nbsp;</strong>Even in a strong magnetic field, across a population of molecules, there is only a very slight excess of nuclei in the +1/2 spin state.</p><p><strong>2.4&nbsp;</strong>Putting all of these ideas together means the following: Consider a hydrogen X adjacent (three bonds away) to another hydrogen Y in a molecule. In around half of the molecules in the NMR sample, hydrogen X feels the magnetic field from a Y with nuclear spin of +1/2. The other half feel from Y a nuclear spin of –1/2. Thus, when you look at the spectrum, there are actually two different, but closely spaced peaks as the signal for hydrogen X. This phenomenon is called “spin-spin” splitting, and the distance between the two signals for X is called the “coupling constant”, often denoted as “J”. Similarly, the signal for Y actually has two peaks because of spin-spin splitting by X.</p><p><strong>2.5&nbsp;</strong>Consider a –CH2- group adjacent to a hydrogen X.&nbsp;Both of the hydrogen atoms in the –CH2- are chemically equivalent and could be either in the +1/2 or –1/2 nuclear spin state. Thus, there are three situations possible:<strong>&nbsp;i)</strong>&nbsp;+1/2,+1/2;<strong>&nbsp;ii)</strong>&nbsp;+1/2,-1/2, which is the same as –1/2, +1/2 and<strong>&nbsp;iii)</strong>&nbsp;–1/2,-1/2. Thus, there are actually three different magnetic fields that are felt by X in molecules of the sample, in a 1:2:1 ratio.&nbsp;Thus, the signal for hydrogen X is split into three peaks in a 1:2:1 ratio.</p><p><strong>2.6</strong>&nbsp;The same holds for a –CH3&nbsp;group, that will split an adjacent hydrogen signal into four peaks, with a 1:3:3:1 ratio. You should verify this for yourself by making all the possible combinations of nuclear spins for the three equivalent hydrogen atoms of a methyl group.</p><p><strong>2.7&nbsp;</strong>In the general case, N equivalent hydrogen atoms will split an adjacent signal into (N+1) peaks, with relative ratios that are predicted by Pascal’s triangle (Figure 13.16 in the book).</p></blockquote>



<figure class="wp-block-image"><img decoding="async" src="http://iverson.cm.utexas.edu/courses/310N/GIFssp04/miscgifs/splitting.gif" alt=""/></figure>



<p><strong>3.0</strong>&nbsp;Following the same logic, the splitting should&nbsp;<strong>multiply</strong>&nbsp;if a single hydrogen atom is adjacent to hydrogen atoms on either side.&nbsp;Think about combining all the possible nuclear spin states for these nearby sets of hydrogen atoms. Thus, if you have a hydrogen atom X between one –CH2- and one –CH3&nbsp;group, it should be split into an amazing (2+1) x (3 + 1) = 12 signals because there are that many different combinations of +1/2 and -1/2 spins possible.</p>



<blockquote class="wp-block-quote is-layout-flow wp-block-quote-is-layout-flow"><p><strong>3.1&nbsp;</strong>Thus, if the coupling constants (J) from the –CH2- and –CH3&nbsp;groups are significantly different from each other, then 12 peaks will be observed as the signal for hydrogen X.</p><p><strong>3.2&nbsp;</strong>However, in practice, coupling constants (J) are pretty close to the same value for almost all sets of hydrogen atoms in organic molecules, simplifying the splitting pattern, since now many of the twelve peaks will overlap with each other. What this means is that for almost all the spectra you will see, if a hydrogen X is surrounded by N hydrogen atoms, the signal for X will be split into only (N+1) peaks, no matter how those N hydrogen atoms are grouped in terms of sets of equivalent atoms.&nbsp;Thus, what is actually seen for the example above is that the signal for X would&nbsp;<strong><em>appear</em></strong>&nbsp;in the spectrum to be split into 2 + 3 + 1 = 6 peaks, not 12, peaks.&nbsp;<strong>This is the so-called “N+1” rule.</strong></p><p><strong>3.3&nbsp;</strong>The diagram below shows these two different situations. When nuclei from hydrogen atoms Z and Y split the signal for hydrogen X with very different coupling constants (notice how the coupling constant J for the red Z hydrogen nuclei is larger than J for the blue Y hydrogen nuclei), all twelve peaks are spread out and identifiable. Below that is shown the situation in which the coupling constants are the same for nuclei of both Z and Y, so only 6 peaks are actually observed in the signal for hydrogen X due to extensive overlap. This latter case, with six peaks, is what you will almost always see in reality since coupling constants tend to be similar in organic molecules.</p></blockquote>



<figure class="wp-block-image"><img decoding="async" src="http://iverson.cm.utexas.edu/courses/310N/GIFssp04/miscgifs/splitting1.gif" alt=""/></figure>



<blockquote class="wp-block-quote is-layout-flow wp-block-quote-is-layout-flow"><p><strong>3.3&nbsp;</strong>The above explanation of splitting can confuse students for a while. The important point is that in the example given,&nbsp;you see 6 different peaks in the spectrum (N+1 rule) even though there are really 12 peaks produced, it is just that several of them are on top of each other because the coupling constants are the same. For alkyl groups in organic molecules, the coupling constants are generally the same so you will almost always see the fewer peaks, corresponding to the simple N+1 rule, rather than the greater number of peaks derived from the multiplication rule.</p><p><strong>3.4&nbsp;</strong>The bottom line here is that by seeing how a given signal is split, you can figure out how many hydrogen atoms are adjacent on the molecule, namely the number of peaks in the signal minus 1.&nbsp;<strong>From this information you can piece together what a molecule looks like</strong>&nbsp;if you know how many atoms of each type are present (i.e. the molecular formula such as C4H10N2O). You get the molecular formula information from something called a mass spectrum, described later in the text. Molecular formulas will be provided to you in homework or test questions.</p></blockquote>



<p><strong>4.0&nbsp;</strong>For a given signal, integrating the signal (include all splitting peaks for a given signal) gives you a relative value that is proportional to the number of equivalent hydrogen atoms that gave rise to the signal. Thus, by looking at the integration values, you can deduce how many of each type of equivalent hydrogen atoms are in the molecule. For example, a -CH3&nbsp;group would have a signal that integrates to a relative value of 3 (no matter how the signal is split), and a -CH2- group would have a relative integration of 2, etc. Note that sometimes integrations are simply given as absolute numbers, and you must find the common factor to deduce how many hydrogen atoms are represented by each integration value.</p>



<p><strong>5.0 Putting it all together: How to deduce a structure from an NMR spectrum. First, you must be given the molecular formula, so you know how many of each type of atom are present. Second, count the number of different signals and their relative integrations to see how many different sets of equivalent hydrogen atoms are in a molecule, and how many of each set are present. Compare the chemical shifts of each signal to tables to identify what functional groups are present. Finally, use the signal splittings to determine which hydrogen atoms must be no more than 3 bonds away from each other.</strong></p>



<p><strong>6.0&nbsp;</strong>For alkenes, the pi bond prevents bond rotation so the different hydrogen atoms on an&nbsp;<em>unsymmetrical</em>&nbsp;alkene are not equivalent, so they all have different signals, and splitting follows the multiplicative rule (the coupling constants are usually significantly different for geminal vs. cis. vs. trans relationships).</p>



<p><strong>7.0</strong>&nbsp;For hydrogens in a -CH2- group adjacent to a chiral center, the two different H atoms are no longer equivalent, because even with bond rotation, the two hydrogens are never in the same environment with respect to the groups on the adjacent chiral center. Thus, each H of -CH2- group adjacent to a chiral center usually has its own signal in the NMR spectrum.</p>



<p><strong>8.0</strong>&nbsp;There is a great deal more to NMR than this, I am only trying to give you the basics here.</p>



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		<title>Analysis and interpretation of Raman spectroscopy</title>
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					<description><![CDATA[Click here to see other posts about Raman spectroscopy Only 10 $ for interpretation of your Raman spectrum Payment Upon Completion Contact us... Raman Spectroscopy is a non-destructive chemical analysis technique which provides detailed information about chemical structure, phase and polymorphy, crystallinity and molecular interactions. It is based upon the interaction of light with the [&#8230;]]]></description>
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<p>Raman Spectroscopy is a non-destructive chemical analysis technique which provides detailed information about chemical structure, phase and polymorphy, crystallinity and molecular interactions. It is based upon the interaction of light with the chemical bonds within a material.</p>



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<p>Raman is a light scattering technique, whereby a molecule scatters incident light from a high intensity laser light source. Most of the scattered light is at the same wavelength (or color) as the laser source and does not provide useful information – this is called Rayleigh Scatter. However a small amount of light (typically 0.0000001%) is scattered at different wavelengths (or colors), which depend on the chemical structure of the analyte – this is called Raman Scatter.</p>



<p>A Raman spectrum features a number of peaks, showing the intensity and wavelength position of the Raman scattered light. Each peak corresponds to a specific molecular bond vibration, including individual bonds such as C-C, C=C, N-O, C-H etc., and groups of bonds such as benzene ring breathing mode, polymer chain vibrations, lattice modes, etc.<img decoding="async" width="1200" alt="A typical Raman spectrum, in this case, of aspirin (4-acetylsalicylic acid). " src="https://static.horiba.com/fileadmin/Horiba/_processed_/5/f/csm_fig_2_A_typical_Raman_spectrum_d02f339e0b.png"></p>



<p>Fig. 2: A typical Raman spectrum, in this case, of aspirin (4-acetylsalicylic acid). The inset image shows the detail which is present in the spectrum</p>



<h2 class="wp-block-heading" id="information-provided-by-raman-spectroscopy">Information provided by Raman spectroscopy</h2>



<p><img decoding="async" width="1200" alt="Raman spectra of ethanol and methanol" src="https://static.horiba.com/fileadmin/Horiba/_processed_/d/1/csm_fig_3_Raman_spectra_of_ethanol_and_methanol_dabf593771.png"></p>



<p>Fig. 3: Raman spectra of ethanol and methanol, showing the significant spectral differences which allow the two liquids to be distinguished.</p>



<p>Raman spectroscopy probes the chemical structure of a material and provides information about:</p>



<ul class="wp-block-list"><li>Chemical structure and identity</li><li>Phase and polymorphism</li><li>Intrinsic stress/strain</li><li>Contamination and impurity</li></ul>



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<p>Typically a Raman spectrum is a distinct chemical fingerprint for a particular molecule or material, and can be used to very quickly identify the material, or distinguish it from others. Raman spectral libraries are often used for identification of a material based on its Raman spectrum – libraries containing thousands of spectra are rapidly searched to find a match with the spectrum of the analyte.<img decoding="async" width="1200" alt="Mineral distribution" src="https://static.horiba.com/fileadmin/Horiba/_processed_/5/a/csm_fig_4_Mineral_distribution_c91efaf884.png"></p>



<p>Fig. 4: Mineral distribution</p>



<p>In combination with mapping (or imaging) Raman systems, it is possible to generate images based on the sample’s Raman spectrum. These images show distribution of individual chemical components, polymorphs and phases, and variation in crystallinity.</p>



<h2 class="wp-block-heading" id="raman-spectroscopy-is-both-qualitative-and-quantitative">Raman spectroscopy is both qualitative and quantitative.</h2>



<p>The general spectrum profile (peak position and relative peak intensity) provides a unique chemical fingerprint which can be used to identify a material, and distinguish it from others. Often the actual spectrum is quite complex, so comprehensive Raman spectral libraries can be searched to find a match, and thus provide a chemical identification.</p>



<p>The intensity of a spectrum is directly proportional to concentration. Typically, a calibration procedure will be used to determine the relationship between peak intensity and concentration, and then routine measurements can be made to analyze for concentration. With mixtures, relative peak intensities provide information about the relative concentration of the components, while absolute peak intensities can be used for absolute concentration information.</p>



<h2 class="wp-block-heading" id="raman-is-used-for-microscopic-analysis">Raman is used for microscopic analysis</h2>



<p><img decoding="async" width="1200" alt="A modern Raman microscope system" src="https://static.horiba.com/fileadmin/Horiba/_processed_/1/6/csm_fig_5_modern_Raman_microscope_495097cdca.png"></p>



<p>Fig. 5: A modern Raman microscope system</p>



<p>Raman spectroscopy can be used for microscopic analysis, with a spatial resolution in the order of 0.5-1 µm. Such analysis is possible using a Raman microscope.</p>



<p>A Raman microscope couples a Raman spectrometer to a standard optical microscope, allowing high magnification visualization of a sample and Raman analysis with a microscopic laser spot. Raman micro-analysis is easy: simply place the sample under the microscope, focus, and make a measurement.</p>



<p>A true confocal Raman microscope can be used for the analysis of micron size particles or volumes. It can even be used for the analysis of different layers in a multilayered sample (e.g., polymer coatings), and of contaminants and features beneath the surface of a transparent sample (e.g., impurities within glass, and fluid/gas inclusions in minerals).</p>



<p>Motorized mapping stages allow Raman spectral images to be generated, which contain many thousands of Raman spectra acquired from different positions on the sample. False color images can be created based on the Raman spectrum – these show the distribution of individual chemical components, and variation in other effects such as phase, polymorphism, stress/strain, and crystallinity.</p>



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<h2 class="wp-block-heading" id="type-of-samples-analyzed-with-raman">Type of samples analyzed with Raman</h2>



<p>Raman can be used to analyze many different samples. In general it is suitable for analysis of:</p>



<ul class="wp-block-list"><li>Solids, powders, liquids, gels, slurries and gases</li><li>Inorganic, organic and biological materials</li><li>Pure chemicals, mixtures and solutions</li><li>Metallic oxides and corrosion</li></ul>



<p>In general it is not suitable for analysis of:</p>



<ul class="wp-block-list"><li>Metals and their alloys</li></ul>



<p>Typical examples of where Raman is used today include:</p>



<ul class="wp-block-list"><li>Art and archaeology – characterization of pigments, ceramics and gemstones</li><li>Carbon materials – structure and purity of nano-tubes, defect/disorder characterization</li><li>Chemistry – structure, purity, and reaction monitoring</li><li>Geology – mineral identification and distribution, fluid inclusions and phase transitions</li><li>Life sciences – single cells and tissue, drug interactions, disease diagnosis</li><li>Pharmaceutics – content uniformity and component distribution</li><li>Semiconductors – purity, alloy composition, intrinsic stress/strain microscope.</li></ul>



<h2 class="wp-block-heading" id="analysis-of-solids-liquids-and-gases">Analysis of solids, liquids and gases</h2>



<p>Raman spectra can be acquired from nearly all samples which contain true molecular bonding. This means that solids, powders, slurries, liquids, gels and gases can be analyzed using Raman spectroscopy.</p>



<p>Although gases can be analyzed using Raman spectroscopy, the concentration of molecules in a gas is typically very low, so the measurement is often more challenging. Usually specialized equipment such as higher powered lasers and long path length sample cells are necessary. In some cases where gas pressures are high (such as gas inclusions in minerals) standard Raman instrumentation can easily be used.</p>



<h2 class="wp-block-heading" id="analysis-from-a-mixture-of-materials">Analysis from a mixture of materials</h2>



<p>The Raman spectrum from a material will contain Raman information about all of the molecules which are within the analysis volume of the system. Thus, if there is a mixture of molecules, the Raman spectrum will contain peaks representing all of the different molecules. If the components are known, the relative peak intensities can be used to generate quantitative information about the mixture’s composition. In case of complex matrixes, chemometrics methods might also be employed to build quantitative methods.</p>



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