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		<title>A to Z of IR Spectroscopy</title>
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					<description><![CDATA[Click here to see other posts about FT-IR Only 10 $per sample for interpreting of your FT-IR spectrum Payment Upon Completion Send your spectra... Infrared (IR) spectroscopy is based on molecular vibrations caused by the oscillation of molecular dipoles. Bonds have characteristic vibrations depending on the atoms in the bond, the number of bonds and [&#8230;]]]></description>
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<p>Infrared (IR) spectroscopy is based on molecular vibrations caused by the oscillation of molecular dipoles. Bonds have characteristic vibrations depending on the atoms in the bond, the number of bonds and the orientation of those bonds with respect to the rest of the molecule. Thus, different molecules have specific spectra that can be collected for use in distinguishing products or identifying an unknown substance (to an extent.)</p>



<figure class="wp-block-image size-large"><a href="http://www.analyzetest.com/index.php/contact-us/"><img decoding="async" src="http://s7.picofile.com/file/8392387542/ftir_in.gif" alt=""/></a></figure>



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<p>Collecting spectra through this method goes about one of three general ways. Nujol mulls and pressed pellets are typically used for collecting spectra of solids, while thin-film cells are used for solution-phase IR spectroscopy. Spectra of gases can also be obtained but will not be discussed in this guide.</p>



<h3 class="wp-block-heading" id="infrared-optical-materials-and-handling">Infrared Optical Materials and Handling</h3>



<p>While it is all well and wonderful that substances can be characterized in this fashion one still has to be able to hold the substances inside of the instrument and properly prepare the samples. In an infrared spectrometer (Figure&nbsp;4.2.14.2.1)</p>



<p>the sample to be analyzed is held in front of an infrared laser beam, in order to do this, the sample must be contained in something, consequently this means that the very container the sample is in will absorb some of the infrared beam.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/5a6dcbf29a0296eddf32aaceb6c8f19946dd8c37/graphics1.jpg" alt=""/><figcaption class="wp-element-caption">Figure<em></em>4.2.14.2.1<em>&nbsp;An example of a modern benchtop FT-IR spectrometer (Varian Corp.)</em></figcaption></figure>



<p>This is made somewhat complicated by the fact that all materials have some sort of vibration associated with them. Thus, if the sample holder has an optical window made of something that absorbs near where your sample does, the sample might not be distinguishable from the optical window of the sample holder. The range that is not blocked by a strong absorbance is known as a&nbsp;<em>window</em>&nbsp;(not to be confused with the optical materials of the cell.)</p>



<p>Windows are an important factor to consider when choosing the method to perform an analysis, as seen in Table&nbsp;4.2.14.2.1&nbsp;there are a number of different materials each with their own characteristic absorption spectra and chemical properties. Keep these factors in mind when performing analyses and precious sample will be saved. For most organic compounds NaCl works well though it is susceptible to attack from moisture. For metal coordination complexes KBr, or CsI typically work well due to their large windows. If money is not a problem then diamond or sapphire can be used for plates.</p>



<figure class="wp-block-table"><table><thead><tr><th scope="col"><strong>Material</strong></th><th scope="col"><strong>Transparent Ranges (cm&nbsp;<sup>-1</sup>)</strong></th><th scope="col"><strong>Solubility</strong></th><th scope="col"><strong>Notes</strong></th></tr></thead><tbody><tr><td>NaCl</td><td>40,000 &#8211; 625</td><td>H<sub>2O</sub></td><td>Easy to polish, hygroscopic</td></tr><tr><td>Silica glass</td><td>55,000-3,000</td><td>HF</td><td>Attacked by HF</td></tr><tr><td>Quartz</td><td>40,000-2,500</td><td>HF</td><td>Attacked by HF</td></tr><tr><td>Sapphire</td><td>20,000-1,780</td><td>&#8211;</td><td>Strong</td></tr><tr><td>Diamond</td><td>40,000-2,500 and 1,800-200</td><td>&#8211;</td><td>Very strong, expensive, hard, useless for pellets</td></tr><tr><td>CaF<sub>2</sub></td><td>70,000-1,110</td><td>Acids</td><td>Attacked by acids, avoid ammonium salts</td></tr><tr><td>BaF<sub>2</sub></td><td>65,000-700</td><td>&#8211;</td><td>Avoid ammonium salts</td></tr><tr><td>ZnSe</td><td>10,000 &#8211; 550</td><td>Acids</td><td>Brittle, attacked by acids</td></tr><tr><td>AgCl</td><td>25,000-400</td><td>&#8211;</td><td>Soft, sensitive to light.</td></tr><tr><td>KCl</td><td>40,000-500</td><td>H<sub>2</sub>O, Et<sub>2</sub>O, acetone</td><td>Hygroscopic, soft, easily polished, commonly used in making pellets.</td></tr><tr><td>KBr</td><td>40,000-400</td><td>H<sub>2</sub>O, EtOH</td><td>Hygroscopic, soft, easily polished, commonly used in making pellets.</td></tr><tr><td>CsBr</td><td>10,000-250</td><td>H<sub>2</sub>O, EtOH, acetone</td><td>Hygroscopic soft</td></tr><tr><td>CsI</td><td>10,000-200</td><td>H<sub>2</sub>O, EtOH, MeOH, acetone</td><td>Hygroscopic, soft.</td></tr><tr><td>Teflon</td><td>5,000-1,200; 1,200-900</td><td>&#8211;</td><td>Inert, disposable</td></tr><tr><td>Polyethylene</td><td>4,000-3,000; 2,800-1,460; 1,380 &#8211; 730; 720- 30</td><td>&#8211;</td><td>Inert, disposable</td></tr></tbody></table></figure>



<p>Proper handling of these plates will ensure they have a long, useful life. Here follows a few simple pointers on how to handle plates:</p>



<ul class="wp-block-list">
<li>Avoid contact with solvents that the plates are soluble in.</li>



<li>Keep the plates in a dessicator, the less water the better, even if the plates are insoluble to water.</li>



<li>Handle with gloves, clean gloves.</li>



<li>Avoid wiping the plates to prevent scratching.</li>
</ul>



<p>That said, these simple guidelines will likely reduce most damage that can occur to a plate by simply holding it other faults such as dropping the plate from a sufficient height can result in more serious damage.</p>



<h3 class="wp-block-heading" id="preparation-of-nujol-mulls">Preparation of Nujol Mulls</h3>



<p>A common method of preparing solid samples for IR analysis is mulling. The principle here is by grinding the particles to below the wavelength of incident radiation that will be passing through there should be limited scattering. To suspend those tiny particles, an oil, often referred to as Nujol is used. IR-transparent salt plates are used to hold the sample in front of the beam in order to acquire data. To prepare a sample for IR analysis using a salt plate, first decide what segment of the frequency band should be studied, refer to Table&nbsp;4.2.14.2.1&nbsp;for the materials best suited for the sample. Figure&nbsp;4.2.24.2.2&nbsp;shows the materials needed for preparing a mull.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/b53ab1989b75c6c491341c265041d69e4792f549/IMG_9026.jpg" alt="Necessary materials for preparing a KBr plate with a Nujol mull"/><figcaption class="wp-element-caption">Figure&nbsp;4.2.24.2.2&nbsp;In this photograph, the sample, ferrocene, two clean and polished KBr plates, an agate mortar and pestle, a mounting card and a spatula are displayed as the base minimum requirements for preparing a sample though a Nujol mull. Of course, a small bottle of mineral oil is also necessary.</figcaption></figure>



<p>Preparing the mull is performed by taking a small portion of sample and adding approximately 10% of the sample volume worth of the oil and grinding this in an agate mortar and pestle as demonstrated in Figure&nbsp;4.2.34.2.3&nbsp;. The resulting mull should be transparent with no visible particles.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/2a8dd6add50cd267a0c28ef8b9a207a7964eda34/IMG_9040.jpg" alt="Mulling ferrocene into mineral oil with a mortar and pestle."/><figcaption class="wp-element-caption">Figure&nbsp;4.2.34.2.3&nbsp;Mulling ferrocene into mineral oil with a mortar and pestle.</figcaption></figure>



<p>Another method involves dissolving the solid in a solvent and allowing it to dry in the agate pestle. If using this method ensure that all of the solvent has evaporated since the solvent bands will appear in the spectrum. Some gentle heating may assist this process. This method creates very fine particles that are of a relatively consistent size. After addition of the oil further mixing (or grinding) may be necessary.</p>



<p>Plates should be stored in a desiccator to prevent erosion by atmospheric moisture and should appear roughly transparent. Some materials such as silicon will not, however. Gently rinse the plates with hexanes to wash any residual material off of the plates. Removing the plates from the desiccator and cleaning them should follow the preparation of the mull in order to maintain the integrity of the salt plates. Of course, if the plate is not soluble in water then it is still a good idea just to prevent the threat of mechanical trauma or a stray jet of acetone from a wash bottle.</p>



<p>Once the mull has been prepared, add a drop to one IR plate (Figure&nbsp;4.2.44.2.4&nbsp;), place the second plate on top of the drop and give it a quarter turn in order to evenly coat the plate surface as seen in Figure&nbsp;4.2.54.2.5&nbsp;. Place it into the spectrometer and acquire the desired data.</p>



<p>Always handle with gloves and preferably away from any sinks, faucets, or other sources of running or spraying water.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/2b4ccf6ed82273357df1a837777b9494d5b89e14/IMG_9046.jpg" alt="The prepared mull from an agate mortar and pestle being applied to a polished KBr plate."/><figcaption class="wp-element-caption">Figure&nbsp;4.2.44.2.4&nbsp;The prepared mull from an agate mortar and pestle being applied to a polished KBr plate.</figcaption></figure>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/f8b8b94f2566f4257bc9dde8127da5d9950a25bb/IMG_9050.jpg" alt="Sandwiched KBr plates with a Nujol mull of ferrocene."/><figcaption class="wp-element-caption">Figure&nbsp;4.2.54.2.5&nbsp;Sandwiched KBr plates with a Nujol mull of ferrocene.</figcaption></figure>



<p>Spectra acquired by this method will have strong C-H absorption bands throughout several ranges 3,000 – 2,800 cm<sup>-1</sup>&nbsp;and 1,500 – 1,300 cm<sup>-1</sup>&nbsp;and may obscure signal.</p>



<p>Cleaning the plate is performed as previously mentioned with hexanes or chloroform can easily be performed by rinsing and leaving them to dry in the hood. Place the salt plates back into the desiccator as soon as reasonably possible to prevent damage. It is highly advisable to polish the plates after use, no scratches, fogging, or pits should be visible on the face of the plate. Chips, so long as they don’t cross the center of the plate are survivable but not desired. The samples of damaged salt plates in Figure&nbsp;4.2.64.2.6&nbsp;show common problems associated with use or potentially mishandling. Clouding, and to an extent, scratches can be polished out with an iron rouge. Areas where the crystal lattice is disturbed below the surface are impossible to fix and chips cannot be reattached.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/29490b3b2e95f4020d8a3a464162918f4bb5ac52/graphics2.jpg" alt=""/></figure>



<p><strong>FIgure&nbsp;4.2.64.2.6&nbsp;</strong>A series of plates indicating various forms of physical damage with a comparison to a good plate (Copyright: Colorado University-Boulder).</p>



<h3 class="wp-block-heading" id="preparation-of-pellets">Preparation of Pellets</h3>



<p>In an alternate method, this technique is along the same lines of the nujol mull except instead of the suspending medium being mineral oil, the suspending medium is a salt. The solid is ground into a fine powder with an agate mortar and pestle with an amount of the suspending salt. Preparing pellets with diamond for the suspending agent is somewhat illadvised considering the great hardness of the substance. Generally speaking, an amount of KBr or CsI is used for this method since they are both soft salts. Two approaches can be used to prepare pellets, one is somewhat more expensive but both usually yield decent results.</p>



<p>The first method is the use of a press. The salt is placed into a cylindrical holder and pressed together with a ram such as the one seen in (Figure&nbsp;4.2.74.2.7&nbsp;). Afterwards, the pellet, in the holder, is placed into the instrument and spectra acquired.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/9607f35c44410ed61fba7313f99209e0635a9cd4/graphics3.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.74.2.7&nbsp;A large benchtop hydraulic press (Specac Inc.)</figcaption></figure>



<p>An alternate, and cheaper method requires the use of a large hex nut with a 0.5 inch inner diameter, two bolts, and two wrenches such as the kit seen in Figure&nbsp;4.2.84.2.8&nbsp;. Step-by-step instructions for loading and using the press follows:</p>



<ol class="wp-block-list">
<li>Screw one of the bolts into the nut about half way.</li>



<li>Place the salt pellet mixture into the other opening of the nut and level by tapping the assembly on a countertop.</li>



<li>Screw in the second bolt and place the assembly on its side with the bolts parallel to the countertop. Place one of the wrenches on the bolt on the right side with the handle aiming towards yourself.</li>



<li>Take the second wrench and place it on the other bolt so that it attaches with an angle from the table of about 45 degrees.</li>



<li>The second bolt is tightened with a body weight and left to rest for several minutes. Afterwards, the bolts are removed, and the sample placed into the instrument.</li>
</ol>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/957698439a64cecc928993b7dc5ebcb3f4906c0c/graphics4.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.84.2.8&nbsp;A simple pellet press with cell holder. (Cole-Parmer)</figcaption></figure>



<p>Some pellet presses also have a vacuum barb such as the one seen in (Figure&nbsp;4.2.84.2.8&nbsp;. If your pellet press has one of these, consider using it as it will help remove air from the salt pellet as it is pressed. This ensures a more uniform pellet and removes absorbances in the collected spectrum due to air trapped in the pellet.</p>



<h3 class="wp-block-heading" id="preparation-of-solution-cells">Preparation of Solution Cells</h3>



<p>Solution cells (Figure&nbsp;4.2.94.2.9&nbsp;) are a handy way of acquiring infrared spectra of compounds in solution and is particularly handy for monitoring reactions.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/5f8c967f48a0a92958438200ce06ebadbe81d1af/graphics5.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.94.2.9&nbsp;A sealed solution cell with two injection ports and a schematic of its construction (Perkin-Elmer Inc.)</figcaption></figure>



<p>A thin-film cell consists of two salt plates with a very thin space in between them (Figure&nbsp;4.2.104.2.10&nbsp;). Two channels allow liquid to be injected and then subsequently removed. The windows on these cells can be made from a variety of IR optical materials. One particularly useful one for water-based solutions is CaF<sub>2</sub>&nbsp;as it is not soluble in water.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/0dd9a57a03a3ecc8e3be7a9a9896627e8626c3a7/graphics6.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.104.2.10&nbsp;A sealed solution cell with two injection ports and a schematic of its construction (Perkin-Elmer Inc.).</figcaption></figure>



<p>Cleaning these cells can be performed by removing the solution, flushing with fresh solvent and gently removing the solvent by syringe. Do not blow air or nitrogen through the ports as this can cause mechanical deformation in the salt window if the pressure is high enough.</p>



<figure class="wp-block-image size-large"><a href="http://www.analyzetest.com/index.php/contact-us/"><img decoding="async" src="http://s7.picofile.com/file/8392387542/ftir_in.gif" alt=""/></a></figure>



<h3 class="wp-block-heading" id="deuterated-solvent-effects">Deuterated Solvent Effects</h3>



<p>One of the other aspects to solution-phase IR is that the solvent utilized in the cell has a characteristic absorption spectra. In some cases this can be alleviated by replacing the solvent with its deuterated sibling. The benefit here is that C-H bonds are now C-D bonds and have lower vibrational frequencies. Compiled in Figure&nbsp;4.2.114.2.11&nbsp;is a set of common solvents.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/cd4fc8059756c41e5aea05033d2fe484a02259b4/graphics7.png" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.114.2.11&nbsp;IR transparencies of various solvents and their heavy counterparts. Adapted from N. L. McNiven and R. Court,&nbsp;<em>Appl. Spectrosc.</em>, 1970,&nbsp;<strong>24</strong>, 296.</figcaption></figure>



<p>This effect has numerous benefits and is often applied to determining what vibrations correspond to what bond in a given molecular sample. This is often accomplished by using isotopically labeled “heavy” reagents such as ones that contain&nbsp;<sup>2</sup>H,&nbsp;<sup>15</sup>N,&nbsp;<sup>18</sup>O, or&nbsp;<sup>13</sup>C.</p>



<h3 class="wp-block-heading" id="basic-troubleshooting">Basic Troubleshooting</h3>



<p>There are numerous problems that can arise from improperly prepared samples, this section will go through some of the common problems and how to correct them. For this demonstration, spectra of ferrocene will be used. The molecular structure and a photograph of the brightly colored organometallic compound are shown in Figure&nbsp;4.2.124.2.12&nbsp;and Figure&nbsp;4.2.134.2.13&nbsp;.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/80fb0cd674a89b63ffb3338ade41f4d4a149c404/ferrocene.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.124.2.12&nbsp;Structure of ferrocene (Fe(C<sub>5</sub>H<sub>5</sub>)<sub>2</sub>).</figcaption></figure>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/30807c9ed92130334b91b585d3eacc3cbbcfbefb/powder.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.134.2.13&nbsp;Image of ferrocene powder (Fe(C<sub>5</sub>H<sub>5</sub>)<sub>2</sub>).</figcaption></figure>



<p>Figure&nbsp;4.2.144.2.14&nbsp;illustrates what a good sample of ferrocene looks like prepared in a KBr pellet. The peaks are well defined and sharp. No peak is flattened at 0% transmittance and Christiansen scattering is not evident in the baseline.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/8a7376f96c24ff6b7bca4a6b7cf6a71c817db32a/ferrocene-good-kbr.png" alt="A good spectrum of Ferrocene in a KBr Pellet"/><figcaption class="wp-element-caption">Figure&nbsp;4.2.144.2.14&nbsp;A good spectrum of ferrocene in a KBr Pellet. Adapted from NIST Chemistry WebBook.</figcaption></figure>



<p>Figure&nbsp;4.2.154.2.15&nbsp;illustrates a sample with some peaks with intensities that are saturated and lose resolution making peak-picking difficult. In order to correct for this problem, scrape some of the sample off of the salt plate with a rubber spatula and reseat the opposite plate. By applying a thinner layer of sample one can improve the resolution of strongly absorbing vibrations.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/7b16dbd7d09ad4ee1553d8ac0d6dbf07785759b4/ferrocene-overconcentrated-kbr.png" alt="An overly concentrated sample of ferrocene in a KBr pellet"/><figcaption class="wp-element-caption">Figure&nbsp;4.2.154.2.15&nbsp;An overly concentrated sample of ferrocene in a KBr pellet. Adapted from NIST Chemistry WebBook.</figcaption></figure>



<p>Figure&nbsp;4.2.164.2.16&nbsp;illustrates a sample in which too much mineral oil was added to the mull so that the C-H bonds are far more intense than the actual sample. This can be remedied by removing the sample from the plate, grinding more sample and adding a smaller amount of the mull to the plate. Another possible way of doing this is if the sample is insoluble in hexanes, add a little to the mull and wick away the hexane-oil mixture to leave a dry solid sample. Apply a small portion of oil and replate.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/a307f1fc2debe6033caf67695d7efed8c3468ffc/ferrocene-occulted-nujol.png" alt="An occulted spectrum of Ferrocene in a Nujol mull."/><figcaption class="wp-element-caption">Figure&nbsp;4.2.164.2.16&nbsp;A spectrum illustrating the problems of using Nujol, areas highlighted in orange are absorbances related to the addition of Nujol to a sample. Notice how in the 1500 wavenumber region the addition of the Nujol has partially occulted the absorbance by the ferrocene. Adapted from NIST Chemistry WebBook.</figcaption></figure>



<p>Figure&nbsp;4.2.174.2.17&nbsp;illustrates the result of particles being too large and scattering light. To remedy this, remove the mull and grind further or else use the solvent deposition technique described earlier.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/fdbaf1206debc635278f59f28b6a663c81b6ba29/ferrocene-christiansen-nujol.png" alt="A sample exhibiting the Christiansen effect on Ferrocene in a Nujol mull."/><figcaption class="wp-element-caption">Figure&nbsp;4.2.174.2.17&nbsp;A sample exhibiting the Christiansen effect on ferrocene in a Nujol mull. Orange boxes indicate Nujol occult ranges. Adapted from NIST Chemistry WebBook.</figcaption></figure>



<h2 class="wp-block-heading" id="characteristic-ir-vibrational-modes-for-hydrocarbon-compounds">Characteristic IR Vibrational Modes for Hydrocarbon Compounds</h2>



<figure class="wp-block-table"><table><tbody><tr><td><strong>Functional group</strong></td><td><strong>Mode</strong></td><td><strong>Wavenumber range (cm<sup>-1</sup>)</strong></td></tr><tr><td>CH<sub>3</sub></td><td>Asymmetric stretch</td><td>2962±10</td></tr><tr><td>CH<sub>3</sub></td><td>Symmetric stretch</td><td>2872±10</td></tr><tr><td>CH<sub>3</sub></td><td>Asymmetric bend</td><td>1460±10</td></tr><tr><td>CH<sub>3</sub></td><td>Symmetric bend (umbrella mode)</td><td>1375±10</td></tr><tr><td>CH<sub>2</sub></td><td>Asymmetric stretch</td><td>2926±10</td></tr><tr><td>CH<sub>2</sub></td><td>Symmetric stretch</td><td>2855±10</td></tr><tr><td>CH<sub>2</sub></td><td>Scissors</td><td>1455±10</td></tr><tr><td>CH<sub>2</sub></td><td>Rock</td><td>720±10</td></tr><tr><td>CH</td><td>Stretch</td><td>~2900 (weak)</td></tr><tr><td>CH</td><td>Bend</td><td>~1350 (weak)</td></tr></tbody></table></figure>



<figure class="wp-block-table"><table><tbody><tr><td><strong>Substitution</strong></td><td><strong>C-H stretch (cm<sup>-1</sup>)</strong></td><td><strong>C=C stretch (cm<sup>-1</sup>)</strong></td><td><strong>Out of plane bend (cm<sup>-1</sup>)</strong></td></tr><tr><td>Vinyl</td><td>3090-3075</td><td>1660-1630</td><td>900±5, 910±5</td></tr><tr><td>Vinylidine</td><td>3090-3075</td><td>1660-1630</td><td>890±5</td></tr><tr><td>Cis</td><td>3050-3000</td><td>1660-1630</td><td>690±10</td></tr><tr><td>Trans</td><td>3050-3000</td><td>1680-1665</td><td>965±5</td></tr><tr><td>Tri-substituted</td><td>3050-3000</td><td>1680-1665</td><td>815±25</td></tr><tr><td>Tetra-substituted</td><td>&#8211;</td><td>1680-1665</td><td>&#8211;</td></tr></tbody></table></figure>



<p><strong>Table4.2.34.2.3</strong>&nbsp;The stretching bands for alkenes.</p>



<figure class="wp-block-table"><table><tbody><tr><td><strong>Substitution</strong></td><td><strong>C-H stretch (cm<sup>-1</sup>)</strong></td><td><strong>C=C stretch (cm<sup>-1</sup>)</strong></td><td><strong>C-H wag (cm<sup>-1</sup>)</strong></td></tr><tr><td>Mono-substituted</td><td>3350-3250</td><td>2140-2100</td><td>700-600</td></tr><tr><td>Di-substituted</td><td>&#8211;</td><td>2260-2190</td><td>&#8211;</td></tr></tbody></table></figure>



<figure class="wp-block-table"><table><tbody><tr><td><strong>Substitution</strong></td><td><strong>Out of plane C-H bending</strong></td><td><strong>Ring bend (cm<sup>-1</sup>)</strong></td></tr><tr><td>Mono</td><td>770-710</td><td>690±10</td></tr><tr><td>Ortho</td><td>810-750</td><td>&#8211;</td></tr><tr><td>Meta</td><td>770-735</td><td>690±10</td></tr><tr><td>Para</td><td>860-790</td><td>&#8211;</td></tr></tbody></table></figure>



<figure class="wp-block-table"><table><tbody><tr><td><strong>Vibration</strong></td><td><strong>Wavenumber (cm<sup>-1</sup>)</strong></td></tr><tr><td>CH<sub>3</sub>&nbsp;symmetric stretch</td><td>2925±5</td></tr><tr><td>CH<sub>3</sub>&nbsp;bend overtone</td><td>2865±5</td></tr></tbody></table></figure>



<h2 class="wp-block-heading" id="fourier-transform-infrared-spectroscopy-of-metal-ligand-complexes">Fourier Transform Infrared Spectroscopy of Metal Ligand Complexes</h2>



<p>The infrared (IR) range of the electromagnetic spectrum is usually divided into three regions:</p>



<ul class="wp-block-list">
<li>The far-infrared is always used for rotational spectroscopy, with wavenumber range 400 – 10 cm<sup>−1</sup>&nbsp;and lower energy.</li>



<li>The mid-infrared is suitable for a detection of the fundamental vibrations and associated rotational-vibrational structure with the frequency range approximately 4000 – 400 cm<sup>−1</sup>.</li>



<li>The near-Infrared with higher energy and wave number range 14000 – 4000 cm<sup>−1</sup>, can excite overtone or higher harmonic vibrations.</li>
</ul>



<p>For classical light material interaction theory, if a molecule can interact with an electromagnetic field and absorb a photon of certain frequency, the transient dipole of molecular functional group must oscillate at that frequency. Correspondingly, this transition dipole moment must be a non-zero value, however, some special vibration can be IR inactive for the stretching motion of a homonuclear diatomic molecule and vibrations do not affect the molecule’s dipole moment (e.g., N<sub>2</sub>).</p>



<h3 class="wp-block-heading" id="mechanistic-description-of-the-vibrations-of-polyatomic-molecules">Mechanistic Description of the Vibrations of Polyatomic Molecules</h3>



<p>A molecule can vibrate in many ways, and each way is called a &#8220;vibrational mode&#8221;. If a molecule has N atoms, linear molecules have 3N-5 degrees of vibrational modes whereas nonlinear molecules have 3N-6 degrees of vibrational modes. Take H<sub>2</sub>O for example; a single molecule of H<sub>2</sub>O has O-H bending mode (Figure&nbsp;4.2.184.2.18&nbsp;a), antisymmetric stretching mode (Figure&nbsp;4.2.184.2.18&nbsp;b), and symmetric stretching mode (Figure&nbsp;4.2.184.2.18&nbsp;c).</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/674bc02ee6bff3b731f87a23b02252f6343771ff/graphics1.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.184.2.18&nbsp;Three types of hydroxy vibration modes. (a) bending mode; (b) antisymmetric stretching mode; (c) symmetric stretching mode.</figcaption></figure>



<p>If a diatomic molecule has a harmonic vibration with the energy,&nbsp;<a href="https://chem.libretexts.org/Bookshelves/Analytical_Chemistry/Book%3A_Physical_Methods_in_Chemistry_and_Nano_Science_(Barron)/04%3A_Chemical_Speciation/4.02%3A_IR_Spectroscopy#mjx-eqn-1" target="_blank" rel="noopener">4.2.1</a>4.2.1&nbsp;, where n+<sup>1</sup>/<sub>2</sub>&nbsp;with n = 0, 1, 2 &#8230;). The motion of the atoms can be determined by the force equation,&nbsp;<a href="https://chem.libretexts.org/Bookshelves/Analytical_Chemistry/Book%3A_Physical_Methods_in_Chemistry_and_Nano_Science_(Barron)/04%3A_Chemical_Speciation/4.02%3A_IR_Spectroscopy#mjx-eqn-2" target="_blank" rel="noopener">4.2.2</a>4.2.2&nbsp;, where k is the force constant). The vibration frequency can be described by&nbsp;<a href="https://chem.libretexts.org/Bookshelves/Analytical_Chemistry/Book%3A_Physical_Methods_in_Chemistry_and_Nano_Science_(Barron)/04%3A_Chemical_Speciation/4.02%3A_IR_Spectroscopy#mjx-eqn-3" target="_blank" rel="noopener">4.2.3</a>4.2.3&nbsp;. In which&nbsp;<em>m</em>&nbsp;is actually the reduced mass (m<sub>red</sub>&nbsp;or μ), which is determined from the mass m<sub>1</sub>&nbsp;and m<sub>2</sub>&nbsp;of the two atoms,&nbsp;<a href="https://chem.libretexts.org/Bookshelves/Analytical_Chemistry/Book%3A_Physical_Methods_in_Chemistry_and_Nano_Science_(Barron)/04%3A_Chemical_Speciation/4.02%3A_IR_Spectroscopy#mjx-eqn-4" target="_blank" rel="noopener">4.2.4</a>4.2.4&nbsp;.En&nbsp;=&nbsp;−hv(4.2.1)(4.2.1)En&nbsp;=&nbsp;−hvF&nbsp;=&nbsp;−kx(4.2.2)(4.2.2)F&nbsp;=&nbsp;−kxω&nbsp;=&nbsp;(k/m)1/2(4.2.3)(4.2.3)ω&nbsp;=&nbsp;(k/m)1/2mred&nbsp;=&nbsp;μ&nbsp;=&nbsp;m1m2m1&nbsp;+&nbsp;m2(4.2.4)(4.2.4)mred&nbsp;=&nbsp;μ&nbsp;=&nbsp;m1m2m1&nbsp;+&nbsp;m2</p>



<h3 class="wp-block-heading" id="principle-of-absorption-bands">Principle of Absorption Bands</h3>



<p>In IR spectrum, absorption information is generally presented in the form of both wavenumber and absorption intensity or percent transmittance. The spectrum is generally showing wavenumber (cm<sup>-1</sup>) as the x-axis and absorption intensity or percent transmittance as the y-axis.</p>



<p>Transmittance, &#8220;T&#8221;, is the ratio of radiant power transmitted by the sample (I) to the radiant power incident on the sample (I<sub>0</sub>). Absorbance (A) is the logarithm to the base 10 of the reciprocal of the transmittance (T). The absorption intensity of molecule vibration can be determined by the Lambert-Beer Law, \label{5} . In this equation, the transmittance spectra ranges from 0 to 100%, and it can provide clear contrast between intensities of strong and weak bands. Absorbance ranges from infinity to zero. The absorption of molecules can be determined by several components. In the absorption equation,&nbsp;<em>ε</em>&nbsp;is called molar extinction coefficient, which is related to the molecule behavior itself, mainly the transition dipole moment,&nbsp;<em>c</em>&nbsp;is the concentration of the sample, and&nbsp;<em>l</em>&nbsp;is the sample length. Line width can be determined by the interaction with surroundings.A&nbsp;=&nbsp;log(1/T)&nbsp;=&nbsp;−log(I/I0)&nbsp;=&nbsp;εcl(4.2.5)(4.2.5)A&nbsp;=&nbsp;log(1/T)&nbsp;=&nbsp;−log(I/I0)&nbsp;=&nbsp;εcl</p>



<h3 class="wp-block-heading" id="the-infrared-spectrometer">The Infrared Spectrometer</h3>



<p>As shown in Figure&nbsp;4.2.194.2.19&nbsp;, there are mainly four parts for fourier transform infrared spectrometer (FTIR):</p>



<ul class="wp-block-list">
<li><strong>Light source.</strong>&nbsp;Infrared energy is emitted from a glowing black-body source as continuous radiations.</li>



<li><strong>Interferometer.</strong>&nbsp;It contains the interferometer, the beam splitter, the fixed mirror and the moving mirror. The beam splittertakes the incoming infrared beam and divides it into two optical beams. One beam reflects off the fixed mirror. The other beam reflects off of the moving mirror which moves a very short distance. After the divided beams are reflected from the two mirrors, they meet each other again at the beam splitter. Therefore, an interference pattern is generated by the changes in the relative position of the moving mirror to the fixed mirror. The resulting beam then passes through the sample and is eventually focused on the detector.</li>



<li><strong>Sample compartment.</strong>&nbsp;It is the place where the beam is transmitted through the sample. In the sample compartment, specific frequencies of energy are absorbed.</li>



<li><strong>Detector.&nbsp;</strong>The beam finally passes to the detector for final measurement. The two most popular detectors for a FTIR spectrometer are deuterated triglycine sulfate (pyroelectric detector) and mercury cadmium telluride (photon or quantum detector). The measured signal is sent to the computer where the Fourier transformation takes place.</li>
</ul>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/ef4ded13cf37e6c45749c66a5534663f2ce8e430/graphics2.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.194.2.19&nbsp;The main components of a fourier transform infrared (FTIR) spectrometer.</figcaption></figure>



<h3 class="wp-block-heading" id="a-typical-application-the-detection-of-metal-ligand-complexes">A Typical Application: the detection of metal ligand complexes</h3>



<h4 class="wp-block-heading" id="some-general-absorption-peaks-for-common-types-of-functional-groups">Some General Absorption peaks for common types of functional groups</h4>



<p>It is well known that all molecules chemicals have distinct absorption regions in the IR spectrum. Table&nbsp;4.2.74.2.7&nbsp;shows the absorption frequencies of common types of functional groups. For systematic evaluation, the IR spectrum is commonly divided into some sub-regions.</p>



<ul class="wp-block-list">
<li>In the region of 4000 &#8211; 2000 cm<sup>–1</sup>, the appearance of absorption bands usually comes from stretching vibrations between hydrogen and other atoms. The O-H and N-H stretching frequencies range from 3700 &#8211; 3000 cm<sup>–1</sup>. If hydrogen bond forms between O-H and other group, it generally caused peak line shape broadening and shifting to lower frequencies. The C-H stretching bands occur in the region of 3300 &#8211; 2800 cm<sup>–1</sup>. The acetylenic C-H exhibits strong absorption at around 3300 cm<sup>–1</sup>. Alkene and aromatic C-H stretch vibrations absorb at 3200-3000 cm<sup>–1</sup>. Generally, asymmetric vibrational stretch frequency of alkene C-H is around 3150 cm<sup>-1</sup>, and symmetric vibrational stretch frequency is between 3100 cm<sup>-1</sup>&nbsp;and 3000 cm<sup>-1</sup>. The saturated aliphatic C-H stretching bands range from 3000 &#8211; 2850 cm<sup>–1</sup>, with absorption intensities that are proportional to the number of C-H bonds. Aldehydes often show two sharp C-H stretching absorption bands at 2900 &#8211; 2700 cm<sup>–1</sup>. However, in water solution, C-H vibrational stretch is much lower than in non-polar solution. It means that the strong polarity solution can greatly reduce the transition dipole moment of C-H vibration.</li>



<li>Furthermore, the stretching vibrations frequencies between hydrogen and other heteroatoms are between 2600 &#8211; 2000cm<sup>-1</sup>, for example, S-H at 2600 &#8211; 2550 cm<sup>–1</sup>, P-H at 2440 &#8211; 2275 cm<sup>–1</sup>, Si-H at 2250 &#8211; 2100 cm<sup>–1</sup>.</li>



<li>The absorption bands at the 2300 &#8211; 1850 cm<sup>–1</sup>&nbsp;region usually present only from triple bonds, such as C≡C at 2260 &#8211; 2100 cm<sup>–1</sup>, C≡N at 2260 &#8211; 2000 cm<sup>–1</sup>, diazonium salts –N≡N at approximately 2260 cm<sup>–1</sup>, allenes C=C=C at 2000 &#8211; 1900 cm<sup>–1</sup>. The peaks of these groups are all have strong absorption intensities. The 1950 &#8211; 1450 cm<sup>–1</sup>&nbsp;region stands for double-bonded functional groups vibrational stretching.</li>



<li>Most carbonyl C=O stretching bands range from 1870 &#8211; 1550 cm<sup>–1</sup>, and the peak intensities are from mean to strong. Conjugation, ring size, hydrogen bonding, and steric and electronic effects can lead to significant shifts in absorption frequencies. Furthermore, if carbonyl links with electron-withdrawing group, such as acid chlorides and acid anhydrides, it would give rise to IR bands at 1850 &#8211; 1750 cm<sup>–1</sup>. Ketones usually display stretching bands at 1715 cm<sup>-1</sup>.</li>



<li>None conjugated aliphatic C=C and C=N have absorption bands at 1690 &#8211; 1620 cm<sup>–1</sup>. Besides, around 1430 and 1370cm<sup>-1</sup>, there are two identical peaks presenting C-H bending.</li>



<li>The region from 1300 &#8211; 910 cm<sup>–1</sup>&nbsp;always includes the contributions from skeleton C-O and C-C vibrational stretches, giving additional molecular structural information correlated with higher frequency areas. For example, ethyl acetate not only shows its carbonyl stretch at 1750 &#8211; 1735 cm<sup>–1</sup>, but also exhibits its identical absorption peaks at 1300 &#8211; 1000 cm<sup>–1</sup>&nbsp;from the skeleton vibration of C-O and C-C stretches.</li>
</ul>



<figure class="wp-block-table"><table><tbody><tr><td><strong>Group</strong></td><td><strong>Frequency (cm<sup>-1</sup>)</strong></td><td><strong>Strength Appearance</strong></td></tr><tr><td>C-H stretch</td><td>2850-3400</td><td>Strong in nonpolar solvent<br>Weak in polar solvent</td></tr><tr><td>O-H stretch, N-H stretch</td><td>3200-3700</td><td>Broad in solvent</td></tr><tr><td>C≡N stretch,<br>R-N=C=S stretch</td><td>2050-2300</td><td>Medium or strong</td></tr><tr><td>C≡O stretch (bound with metal)</td><td>around 2000</td><td>Medium or strong</td></tr><tr><td>C≡C stretch</td><td>2100-2260</td><td>Weak</td></tr><tr><td>C=O stretch</td><td>ca 1715 (ketone),<br>ca 1650 (amides)</td><td>Strong</td></tr><tr><td>C=C stretch</td><td>1450-1700</td><td>Weak to strong</td></tr><tr><td>C-H bend</td><td>1260 &#8211; 1470</td><td>Strong</td></tr><tr><td>C-O stretch</td><td>1040-1300</td><td>Medium or strong</td></tr></tbody></table></figure>



<h4 class="wp-block-heading" id="general-introduction-of-metal-ligand-complex">General Introduction of Metal Ligand Complex</h4>



<p>The metal electrons fill into the molecular orbital of ligands (CN, CO, etc.) to form complex compound. As shown in Figure&nbsp;4.2.204.2.20&nbsp;, a simple molecular orbital diagram for CO can be used to explain the binding mechanism.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/a82d8b855a5a8184644d2ab5f67f9f0b45a2fe89/graphics3.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.204.2.20&nbsp;Molecular orbital diagram for carbon monoxide (CO).</figcaption></figure>



<p>The CO and metal can bind with three ways:</p>



<ul class="wp-block-list">
<li>Donation of a pair of electrons from the C-O σ* orbital into an empty metal orbital (Figure&nbsp;4.2.214.2.21&nbsp;a).</li>



<li>Donation from a metal d orbital into the C-O π* orbital to form a M-to-CO π-back bond (Figure&nbsp;4.2.214.2.21&nbsp;b).</li>



<li>Under some conditions a pair of carbon π electron can donate into an empty metal d-orbital.</li>
</ul>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/454b93821fe212446840f7acd6f94a7dcadb06f0/graphics4.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.214.2.21&nbsp;Main binding interaction types between metal and CO. (a) CO-to-metal σ bond; (b) M-to-CO π-back bond.</figcaption></figure>



<h4 class="wp-block-heading" id="some-factors-to-include-the-band-shifts-and-strength">Some Factors to Include the Band Shifts and Strength</h4>



<p>Herein, we mainly consider two properties: ligand stretch frequency and their absorption intensity. Take the ligand CO for example again. The frequency shift of the carbonyl peaks in the IR mainly depends on the bonding mode of the CO (terminal or bridging) and electron density on the metal. The intensity and peak numbers of the carbonyl bands depends on some factors: CO ligands numbers, geometry of the metal ligand complex and fermi resonance.</p>



<h4 class="wp-block-heading" id="effect-on-electron-density-on-metal">Effect on Electron Density on Metal</h4>



<p>As shown in Table&nbsp;4.2.84.2.8&nbsp;, a greater charge on the metal center result in the CO stretches vibration frequency decreasing. For example, [Ag(CO)]+show higher frequency of CO than free CO, which indicates a strengthening o</p>



<p>f the CO bond. σ donation removes electron density from the nonbonding HOMO of CO. From Figure, it is clear that the HOMO has a small amount of anti-bonding property, so removal of an electron actually increases (slightly) the CO bond strength. Therefore, the effect of charge and electronegativity depends on the amount of metal to CO π-back bonding and the CO IR stretching frequency.</p>



<figure class="wp-block-table"><table><tbody><tr><td><strong>d<sup>x</sup></strong></td><td><strong>Complex</strong></td><td><strong>CO stretch frequency (cm<sup>-1</sup>)</strong></td></tr><tr><td></td><td>free CO</td><td>2143</td></tr><tr><td>d<sup>10</sup></td><td>[Ag(CO)]<sup>+</sup></td><td>2204</td></tr><tr><td>d<sup>10</sup></td><td>Ni(CO)<sub>4</sub></td><td>2060</td></tr><tr><td>d<sup>10</sup></td><td>[Co(CO)<sub>4</sub>]<sup>&#8211;</sup></td><td>1890</td></tr><tr><td>d<sup>6</sup></td><td>[Mn(CO)<sub>6</sub>]<sup>+</sup></td><td>2090</td></tr><tr><td>d<sup>6</sup></td><td>Cr(CO)<sub>6</sub></td><td>2000</td></tr><tr><td>d<sup>6</sup></td><td>[V(CO)<sub>6</sub>]<sup>&#8211;</sup></td><td>1860</td></tr></tbody></table></figure>



<p>If the electron density on a metal center is increasing, more π-back bonding to the CO ligand(s) will also increase, as shown in Table&nbsp;4.2.94.2.9&nbsp;. It means more electron density would enter into the empty carbonyl π* orbital and weaken the C-O bond. Therefore, it makes the M-CO bond strength increasing and more double-bond-like (M=C=O).</p>



<h4 class="wp-block-heading" id="ligation-donation-effect">Ligation Donation Effect</h4>



<p>Some cases, as shown in Table&nbsp;4.2.94.2.9&nbsp;, different ligands would bind with same metal at the same metal-ligand complex. For example, if different electron density groups bind with Mo(CO)<sub>3</sub>&nbsp;as the same form, as shown in Figure&nbsp;4.2.224.2.22&nbsp;, the CO vibrational frequencies would depend on the ligand donation effect. Compared with the PPh<sub>3</sub>&nbsp;group, CO stretching frequency which the complex binds the PF<sub>3&nbsp;</sub>group (2090, 2055 cm<sup>-1</sup>) is higher. It indicates that the absolute amount of electron density on that metal may have certain effect on the ability of the ligands on a metal to donate electron density to the metal center. Hence, it may be explained by the Ligand donation effect. Ligands that are&nbsp;<em>trans</em>&nbsp;to a carbonyl can have a large effect on the ability of the CO ligand to effectively π-backbond to the metal. For example, two&nbsp;<em>trans</em>&nbsp;π-backbonding ligands will partially compete for the same d-orbital electron density, weakening each other’s net M-L π-backbonding. If the&nbsp;<em>trans</em>ligand is a π-donating ligand, the free metal to CO π-backbonding can increase the M-CO bond strength (more M=C=O character). It is well known that pyridine and amines are not those strong π-donors. However, they are even worse π-backbonding ligands. So the CO is actually easy for π-back donation without any competition. Therefore, it naturally reduces the CO IR stretching frequencies in metal carbonyl complexes for the ligand donation effect.</p>



<figure class="wp-block-table"><table><tbody><tr><td><strong>Metal Ligand Complex</strong></td><td><strong>CO Stretch Frequency (cm<sup>-1</sup>)</strong></td></tr><tr><td>Mo(CO)<sub>3</sub>(PF<sub>3</sub>)<sub>3</sub></td><td>2090, 2055</td></tr><tr><td>Mo(CO)<sub>3</sub>[P(OMe)<sub>3</sub>]<sub>3</sub></td><td>1977, 1888</td></tr><tr><td>Mo(CO)<sub>3</sub>(PPh<sub>3</sub>)<sub>3</sub></td><td>1934, 1835</td></tr><tr><td>Mo(CO)<sub>3</sub>(NCCH<sub>3</sub>)<sub>3</sub></td><td>1915, 1783</td></tr><tr><td>Mo(CO)<sub>3</sub>(pyridine)<sub>3</sub></td><td>1888, 1746</td></tr></tbody></table></figure>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/d461ca364abe1eda6e3448709927c597b257dfc7/graphics5.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.224.2.22&nbsp;Schematic representation of competitive back-donation from a transition metal to multiple π-acceptor ligands</figcaption></figure>



<h4 class="wp-block-heading" id="geometry-effects">Geometry Effects</h4>



<p>Some cases, metal-ligand complex can form not only terminal but also bridging geometry. As shown in Figure&nbsp;4.2.234.2.23&nbsp;, in the compound Fe<sub>2</sub>(CO)<sub>7</sub>(dipy), CO can act as a bridging ligand. Evidence for a bridging mode of coordination can be easily obtained through IR spectroscopy. All the metal atoms bridged by a carbonyl can donate electron density into the π* orbital of the CO and weaken the CO bond, lowering vibration frequency of CO. In this example, the CO frequency in terminal is around 2080 cm<sup>-1</sup>, and in bridge, it shifts to around 1850 cm<sup>-1</sup>.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/0890ffd371d21eaa4a1471d4cac6d66efa5d4e49/graphics6.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.234.2.23&nbsp;The structure of Fe<sub>2</sub>(CO)<sub>7</sub>(dipy)</figcaption></figure>



<h2 class="wp-block-heading" id="pump-probe-detection-of-molecular-functional-group-vibrational-lifetime">Pump-probe Detection of Molecular Functional Group Vibrational Lifetime</h2>



<p>The dynamics of molecular functional group plays an important role during a chemical process, chemical bond forming and breaking, energy transfer and other dynamics happens within picoseconds domain. It is very difficult to study such fast processes directly, for decades scientists can only learn from theoretical calculations, lacking experimental methods.</p>



<p>However, with the development of ultrashort pulsed laser enable experimental study of molecular functional group dynamics. With ultrafast laser technologies, people develop a series of measuring methods, among which, pump-probe technique is widely used to study the molecular functional group dynamics. Here we concentrate on how to use pump-probe experiment to measure functional group vibrational lifetime. The principle, experimental setup and data analysis will be introduced.</p>



<figure class="wp-block-image size-large"><a href="http://www.analyzetest.com/index.php/contact-us/"><img decoding="async" src="http://s7.picofile.com/file/8392387542/ftir_in.gif" alt=""/></a></figure>



<h3 class="wp-block-heading" id="principles-of-the-pump-probe-technique">Principles of the Pump-probe Technique</h3>



<p>For every function group within a molecule, such as the C≡N triple bond in phenyl selenocyanate (C<sub>6</sub>H<sub>5</sub>SeCN) or the C-D single bond in deuterated chloroform (DCCl<sub>3</sub>), they have an individual infrared vibrational mode and associated energy levels. For a typical 3-level system (Figure&nbsp;4.2.244.2.24&nbsp;, both the 0 to 1 and the 1 to 2 transition are near the probe pulse frequency (they don&#8217;t necessarily need to have exactly the same frequency).</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/fde1b446ed7f483f7327169f0d363742e04a59c8/1.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.244.2.24&nbsp;Schematic representation of a typical three level system</figcaption></figure>



<p>In a pump-probe experiment, we use the geometry as is shown in Figure&nbsp;4.2.254.2.25&nbsp;. Two synchronized laser beams, one of which is called pump beam (E<sub>pu</sub>) while the other probe beam (E<sub>pr</sub>). There is a delay in time between each pulse. The laser pulses hit the sample, the intensity of ultrafast laser (fs or ps) is strong enough to generated 3<sup>rd</sup>&nbsp;order polarization and produce 3<sup>rd</sup>&nbsp;order optical response signal which is use to give dynamics information of molecular function groups. For the total response signals we have \label{6} , where µ<sub>10</sub>&nbsp;µ<sub>21</sub>&nbsp;are transition dipole moment and E<sub>0</sub>, E<sub>1</sub>, and E<sub>2</sub>&nbsp;are the energies of the three levels, and t<sub>3</sub>&nbsp;is the time delay between pump and probe beam. The delay t<sub>3</sub>&nbsp;is varied and the response signal intensity is measured. The functional group vibration life time is determined from the data.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/0b72d0a2ead8555d05df21108c2a9460db325787/2j.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.254.2.25</figcaption></figure>



<p>S&nbsp;=&nbsp;4μ410e−i(E1−E0)t3/h−Γt3(4.2.6)(4.2.6)S&nbsp;=&nbsp;4μ104e−i(E1−E0)t3/h−Γt3</p>



<h3 class="wp-block-heading" id="typical-experimental-set-up">Typical Experimental Set-up</h3>



<p>The optical layout of a typical pump-probe setup is schematically displayed in Figure&nbsp;4.2.264.2.26&nbsp;. In the setup, the output of the oscillator (500 mW at 77 MHz repetition rate, 40 nm bandwidth centered at 800 nm) is split into two beams (1:4 power ratio). Of this, 20% of the power is to seed a femtosecond (fs) amplifier whose output is 40 fs pulses centered at 800 nm with power of ~3.4 W at 1 KHz repetition rate. The rest (80%) of the seed goes through a bandpass filter centered at 797.5nm with a width of 0.40 nm to seed a picosecond (ps) amplifier. The power of the stretched seed before entering the ps amplifier cavity is only ~3 mW. The output of the ps amplifier is 1ps pulses centered at 800 nm with a bandwidth ~0.6 nm. The power of the ps amplifier output is ~3 W. The fs amplifier is then to pump an optical parametric amplifier (OPA) which produces ~100 fs IR pulses with bandwidth of ~200 cm<sup>-1</sup>&nbsp;that is tunable from 900 to 4000 cm<sup>-1</sup>. The power of the fs IR pulses is 7~40 mW, depending on the frequencies. The ps amplifier is to pump a ps OPA which produces ~900 fs IR pulses with bandwidth of ~21 cm<sup>-1</sup>, tunable from 900 &#8211; 4000 cm<sup>-1</sup>. The power of the fs IR pulses is 10 ~ 40 mW, depending on frequencies.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/fa50ec3a5885940fc8bd3fda26eeeee9dd686ce5/Picture%206.png" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.264.2.26&nbsp;Schematic representation of the optical layout for a pump-probe experiment.</figcaption></figure>



<p>In a typical pump-probe setup, the ps IR beam is collimated and used as the pump beam. Approximately 1% of the fs IR OPA output is used as the probe beam whose intensity is further modified by a polarizer placed before the sample. Another polarizer is placed after the sample and before the spectrograph to select different polarizations of the signal. The signal is then sent into a spectrograph to resolve frequency, and detected with a mercury cadmium telluride (MCT) dual array detector. Use of a pump pulse (femtosecond, wide band) and a probe pulse (picoseconds, narrow band), scanning the delay time and reading the data from the spectrometer, will give the lifetime of the functional group. The wide band pump and spectrometer described here is for collecting multiple group of pump-probe combination.</p>



<h4 class="wp-block-heading" id="data-analysis">Data Analysis</h4>



<p>For a typical pump-probe curve shown in Figure&nbsp;4.2.274.2.27&nbsp;life time&nbsp;<em>t</em>&nbsp;is defined as the corresponding time value to the half intensity as time zero.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/bbbc5c3e0387f56ab1924ce50a7e6a9c83145778/Picture%207.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.274.2.27&nbsp;A tympical pump-probe curve.</figcaption></figure>



<p><strong>Table&nbsp;4.2.104.2.10</strong>&nbsp;shows the pump-probe data of the C≡N triple bond in a series of aromatic cyano compounds:&nbsp;<em>n</em>-propyl cyanide (C<sub>3</sub>H<sub>7</sub>CN), ethyl thiocyanate (C<sub>2</sub>H<sub>5</sub>SCN), and ethyl selenocyanate (C<sub>2</sub>H<sub>5</sub>SeCN) for which the ν<sub>C≡N</sub>&nbsp;for each compound (measured in CCl<sub>4</sub>&nbsp;solution) is 2252 cm<sup>-1</sup>), 2156 cm<sup>-1</sup>, and ~2155 cm<sup>-1</sup>, respectively.</p>



<figure class="wp-block-table"><table><tbody><tr><td><strong>Delay (ps)</strong></td><td><strong>C<sub>3</sub>H<sub>7</sub>CN</strong></td><td><strong>C<sub>2</sub>H<sub>5</sub>SCN</strong></td><td><strong>C<sub>2</sub>H<sub>5</sub>SeCN</strong></td></tr><tr><td>0</td><td>-0.00695</td><td>-0.10918</td><td>-0.06901</td></tr><tr><td>0.1</td><td>-0.0074</td><td>-0.10797</td><td>-0.07093</td></tr><tr><td>0.2</td><td>-0.00761</td><td>-0.1071</td><td>-0.07247</td></tr><tr><td>0.3</td><td>-0.00768</td><td>-0.10545</td><td>-0.07346</td></tr><tr><td>0.4</td><td>-0.0076</td><td>-0.10487</td><td>-0.07429</td></tr><tr><td>0.5</td><td>-0.00778</td><td>-0.10287</td><td>-0.07282</td></tr><tr><td>0.6</td><td>-0.00782</td><td>-0.10286</td><td>-0.07235</td></tr><tr><td>0.7</td><td>-0.00803</td><td>-0.10222</td><td>-0.07089</td></tr><tr><td>0.8</td><td>-0.00764</td><td>-0.10182</td><td>-0.07073</td></tr><tr><td>0.9</td><td>-0.00776</td><td>-0.10143</td><td>-0.06861</td></tr><tr><td>1</td><td>-0.00781</td><td>-0.10099</td><td>-0.06867</td></tr><tr><td>1.1</td><td>-0.00745</td><td>-0.10013</td><td>-0.06796</td></tr><tr><td>1.2</td><td>-0.00702</td><td>-0.10066</td><td>-0.06773</td></tr><tr><td>1.3</td><td>-0.00703</td><td>-0.0989</td><td>-0.0676</td></tr><tr><td>1.4</td><td>-0.00676</td><td>-0.0995</td><td>-0.06638</td></tr><tr><td>1.5</td><td>-0.00681</td><td>-0.09757</td><td>-0.06691</td></tr><tr><td>1.6</td><td>-0.00639</td><td>-0.09758</td><td>-0.06696</td></tr><tr><td>1.7</td><td>-0.00644</td><td>-0.09717</td><td>-0.06583</td></tr><tr><td>1.8</td><td>-0.00619</td><td>-0.09741</td><td>-0.06598</td></tr><tr><td>1.9</td><td>-0.00613</td><td>-0.09723</td><td>-0.06507</td></tr><tr><td>2</td><td>-0.0066</td><td>-0.0962</td><td>-0.06477</td></tr><tr><td>2.5</td><td>-0.00574</td><td>-0.09546</td><td>-0.0639</td></tr><tr><td>3</td><td>-0.0052</td><td>-0.09453</td><td>-0.06382</td></tr><tr><td>3.5</td><td>-0.0482</td><td>-0.09353</td><td>-0.06389</td></tr><tr><td>4</td><td>-0.0042</td><td>-0.09294</td><td>-0.06287</td></tr><tr><td>4.5</td><td>-0.00387</td><td>-0.09224</td><td>-0.06197</td></tr><tr><td>5</td><td>-0.00351</td><td>-0.09009</td><td>-0.06189</td></tr><tr><td>5.5</td><td>-0.00362</td><td>-0.09084</td><td>-0.06188</td></tr><tr><td>6</td><td>-0.00352</td><td>-0.08938</td><td>-0.06021</td></tr><tr><td>6.5</td><td>-0.00269</td><td>-0.08843</td><td>-0.06028</td></tr><tr><td>7</td><td>-0.00225</td><td>-0.08788</td><td>-0.05961</td></tr><tr><td>7.5</td><td>-0.00231</td><td>-0.08694</td><td>-0.06065</td></tr><tr><td>8</td><td>-0.00206</td><td>-0.08598</td><td>-0.05963</td></tr><tr><td>8.5</td><td>-0.00233</td><td>-0.08552</td><td>-0.05993</td></tr><tr><td>9</td><td>-0.00177</td><td>-0.08503</td><td>-0.05902</td></tr><tr><td>9.5</td><td>-0.00186</td><td>-0.08508</td><td>-0.05878</td></tr><tr><td>10</td><td>-0.00167</td><td>-0.0842</td><td>-0.0591</td></tr><tr><td>11</td><td>-0.00143</td><td>-0.08295</td><td>-0.05734</td></tr></tbody></table></figure>



<p>A plot of intensity versus time for the data from TABLE is shown Figure&nbsp;4.2.284.2.28&nbsp;. From these curves the C≡N stretch lifetimes can be determined for C<sub>3</sub>H<sub>7</sub>CN, C<sub>2</sub>H<sub>5</sub>SCN, and C<sub>2</sub>H<sub>5</sub>SeCN as ~5.5 ps, ~84 ps, and ~282 ps, respectively.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/08216c7f2766567d2a7e1727b8a4951c7bc3d80d/Picture%208.png" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.284.2.28&nbsp;The C≡N stretch lifetimes for benzyl cyanide, phenyl thiocyanate, and phenyl selenocyanate.</figcaption></figure>



<p>From what is shown above, the pump-probe method is used in detecting C≡N vibrational lifetimes in different chemicals. One measurement only takes several second to get all the data and the lifetime, showing that pump-probe method is a powerful way to measure functional group vibrational lifetime.</p>



<h2 class="wp-block-heading" id="attenuated-total-reflectace-fourier-transform-infrared-spectroscopy">Attenuated Total Reflectace- Fourier Transform Infrared Spectroscopy</h2>



<p>Attenuated total reflectance-Fourier transform infrared spectroscopy (ATR-FTIR) is a physical method of compositional analysis that builds upon traditional transmission FTIR spectroscopy to minimize sample preparation and optimize reproducibility. Condensed phase samples of relatively low refractive index are placed in close contact with a crystal of high refractive index and the infrared (IR) absorption spectrum of the sample can be collected. Based on total internal reflection, the absorption spectra of ATR resemble those of transmission FTIR. To learn more about transmission IR spectroscopy (FTIR) please refer to the section further up this page titled Fourier Transform Infrared Spectroscopy of Metal Ligand Complexes.</p>



<p>First publicly proposed in 1959 by Jacques Fahrenfort from the Royal Dutch Shell laboratories in Amsterdam, ATR IR spectroscopy was described as a technique to effectively measure weakly absorbing condensed phase materials. In Fahrenfort&#8217;s first article describing the technique, published in 1961, he used a hemicylindrical ATR crystal (see Experimental Conditions) to produce single-reflection ATR (Figure&nbsp;4.2.294.2.29&nbsp;). ATR IR spectroscopy was slow to become accepted as a method of characterization due to concerns about its quantitative effectiveness and reproducibility. The main concern being the sample and ATR crystal contact necessary to achieve decent spectral contrast. In the late 1980’s FTIR spectrometers began improving due to an increased dynamic range, signal to noise ratio, and faster computers. As a result ATR-FTIR also started gaining traction as an efficient spectroscopic technique. These days ATR accessories are often manufactured to work in conjunction with most FTIR spectrometers, as can be seen in Figure&nbsp;4.2.304.2.30&nbsp;.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/42fd68854a1d340342f1fbef8e426a718f70b55a/fahrenfort.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.294.2.29&nbsp;The first ATR Infrared Spectrometer designed by Jacques Fahrenfort featuring a hemicylindrical ATR crystal. Reproduced from J. Fahrenfort,&nbsp;<em>Spectrochim. Acta</em>, 1961,&nbsp;<strong>17</strong>, 698. Copyright: Elsevier (1961).</figcaption></figure>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/bf23314ce78657323b17bc6128aa6712d16cdcb3/Picture%205.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.304.2.30&nbsp;An ATR attachment on an FTIR spectrometer.</figcaption></figure>



<h3 class="wp-block-heading" id="total-internal-reflection">Total Internal Reflection</h3>



<p>For additional information on light waves and their properties please refer to the module on Vertical Scanning Interferometry (VSI) in chapter 10.1.</p>



<p>When considering light propagating across an interface between two materials with different indices of refraction, the angle of refraction can be given by Snell’s law,&nbsp;<a href="https://chem.libretexts.org/Bookshelves/Analytical_Chemistry/Book%3A_Physical_Methods_in_Chemistry_and_Nano_Science_(Barron)/04%3A_Chemical_Speciation/4.02%3A_IR_Spectroscopy#mjx-eqn-7" target="_blank" rel="noopener">4.2.7</a>4.2.7&nbsp;, where none of the incident light will be transmitted.φc&nbsp;=&nbsp;φmax(4.2.7)(4.2.7)φc&nbsp;=&nbsp;φmax</p>



<p>The reflectance of the interface is total and whenever light is incident from a higher refractive index medium onto a lower refractive index medium, the reflection is deemed internal (as opposed to external in the opposite scenario). Total internal reflectance experiences no losses, or no transmitted light (Figure&nbsp;4.2.314.2.31</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/93c1faf90f8c3435c1414ef2f3fdb839f36c30d2/tir1.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.314.2.31&nbsp;At the interface between two materials with different indices of refraction, (a) when the angle of incident light, θ<sub>1</sub>, is below the critical angle, θ<sub>c</sub>, both reflection and transmission occur, and (b) when the angle of incident light exceeds the critical angle, total internal reflection (TIR) occurs, spawning an evanescent wave at the interface. Adapted from M. Schnippering, S. R. T. Neil, S. R. Mackenzie, and P. R. Unwin,&nbsp;<em>Chem. Soc. Rev.</em>, 2011,&nbsp;<strong>40</strong>, 207. Copyright: Royal Society of Chemistry (2011).</figcaption></figure>



<p>Supercritical internal reflection refers to angles of incidence above the critical angle of incidence allowing total internal reflectance. It is in this angular regime where only incident and reflected waves will be present. The transmitted wave is confined to the interface where its amplitude is at a maximum and will damp exponentially into the lower refractive index medium as a function of distance. This wave is referred to as the evanescent wave and it extends only a very short distance beyond the interface.</p>



<p>To apply total internal reflection to the experimental setup in ATR, consider&nbsp;<em>n</em><sub>2&nbsp;</sub>to be the internal reflectance element or ATR crystal (the blue trapezoid in Figure&nbsp;4.2.324.2.32&nbsp;)</p>



<p>where&nbsp;<em>n</em><sub>2&nbsp;</sub>is the material with the higher index of refraction. This should be a material that is fully transparent to the incident infrared radiation to give a real value for the refractive index. The ATR crystal must also have a high index of refraction to allow total internal reflection with many samples that have an index of refraction&nbsp;<em>n</em><sub>1</sub>, where&nbsp;<em>n</em><sub>1</sub>&lt;<em>n</em><sub>2</sub>.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/ed11b9954cd5b5ccde8594e66dc91c3a91ad4965/Total%20internal%20reflection.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.324.2.32&nbsp;The ATR crystal shown in blue, within which the incident IR light shown in red is totally reflecting. Above the crystal the evanescent wave is emitted and penetrates the sample.</figcaption></figure>



<p>We can consider the sample to be absorbing in the infrared. Electromagnetic energy will pass through the crystal/sample interface and propagate into the sample via the evanescent wave. This energy loss must be compensated with the incident IR light. Thus, total reflectance is no longer occurring and the reflection inside the crystal is attenuated. If a sample does not absorb, the reflectance at the interface shows no attenuation. Therefore if the IR light at a particular frequency does not reach the detector, the sample must have absorbed it.</p>



<p>The penetration depth of the evanescent wave within the sample is on the order of 1µm. The expression of the penetration depth is given in&nbsp;<a href="https://chem.libretexts.org/Bookshelves/Analytical_Chemistry/Book%3A_Physical_Methods_in_Chemistry_and_Nano_Science_(Barron)/04%3A_Chemical_Speciation/4.02%3A_IR_Spectroscopy#mjx-eqn-8" target="_blank" rel="noopener">4.2.8</a>4.2.8&nbsp;and is dependent upon the wavelength and angle of incident light as well as the refractive indices of the ATR crystal and sample. The effective path length is the product of the depth of penetration of the evanescent wave and the number of points that the IR light reflects at the interface between the crystal and sample. This path length is equivalent to the path length of a sample in a traditional transmission FTIR setup.dp=λ2πn1(sinω−(n1n2)2)1/2(4.2.8)(4.2.8)dp=λ2πn1(sinω−(n1n2)2)1/2</p>



<h3 class="wp-block-heading" id="experimental-conditions">Experimental Conditions</h3>



<h4 class="wp-block-heading" id="refractive-indices-of-atr-crystal-and-sample">Refractive Indices of ATR Crystal and Sample</h4>



<p>Typically an ATR attachment can be used with a traditional FTIR where the beam of incident IR light enters a horizontally positioned crystal with a high refractive index in the range of 1.5 to 4, as can be seen in Table&nbsp;4.2.114.2.11&nbsp;will consist of organic compounds, inorganic compounds, and polymers which have refractive indices below 2 and can readily be found on a database.</p>



<figure class="wp-block-table"><table><tbody><tr><td><strong>Material</strong></td><td><strong>Refractive Index (RI)</strong></td><td><strong>Spectral Range (cm<sup>-1</sup>)</strong></td></tr><tr><td>Zinc Selenide (ZnSe)</td><td>2.4</td><td>20,000 &#8211; 650</td></tr><tr><td>Germanium (Ge)</td><td>4</td><td>5,500 &#8211; 870</td></tr><tr><td>Sapphire (Al<sub>2</sub>O<sub>3</sub>)</td><td>1.74</td><td>50,000 &#8211; 2,000</td></tr><tr><td>Diamond (C)</td><td>2.4</td><td>45,000 &#8211; 2,500,<br>1650 &#8211; 200</td></tr></tbody></table></figure>



<h4 class="wp-block-heading" id="single-and-multiple-reflection-crystals">Single and Multiple Reflection Crystals</h4>



<p>Multiple reflection ATR was initially more popular than single reflection ATR because of the weak absorbances associated with single reflection ATR. More reflections increased the evanescent wave interaction with the sample, which was believed to increase the signal to noise ratio of the spectrum. When IR spectrometers developed better spectral contrast, single reflection ATR became more popular. The number of reflections and spectral contrast increases with the length of the crystal and decreases with the angle of incidence as well as thickness. Within multiple reflection crystals some of the light is transmitted and some is reflected as the light exits the crystal, resulting in some of the light going back through the crystal for a round trip. Therefore, light exiting the ATR crystal contains components that experienced different number of reflections at the crystal-sample interface.</p>



<h4 class="wp-block-heading" id="angle-of-incidence">Angle of Incidence</h4>



<p>It was more common in earlier instruments to allow selection of the incident angle, sometimes offering selection between 30°, 45°, and 60°. In all cases for total internal reflection to hold, the angle of incidence must exceed the critical angle and ideally complement the angle of the crystal edge so that the light enters at a normal angle of incidence. These days 45° is the standard angle on most ATR-FTIR setups.</p>



<h4 class="wp-block-heading" id="atr-crystal-shape">ATR Crystal Shape</h4>



<p>For the most part ATR crystals will have a trapezoidal shape as shown in Figure&nbsp;4.2.314.2.31. This shape facilitates sample preparation and handling on the crystal surface by enabling the optical setup to be placed below the crystal. However, different crystal shapes (Figure&nbsp;4.2.334.2.33&nbsp;) may be used for particular purposes, whether it is to achieve multiple reflections or reduce the spot size. For example, a hemispherical crystal may be used in a microsampling experiment in which the beam diameter can be reduced at no expense to the light intensity. This allows appropriate measurement of a small sample without compromising the quality of the resulting spectral features.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/97b4887085367da3313b23275388d6a2c5dcfcf9/crystalshapes.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.334.2.33&nbsp;An assortment of ATR crystal shapes: a)triangular, b)hemispherical, c)parallelogram, d) trapezoidal, e) pentagonal, f)cylindrical. Adapted from F. M. Mirabella,&nbsp;<em>Internal reflection spectroscopy: Theory and applications</em>, 15, Marcel Dekker, Inc., New York (1993).</figcaption></figure>



<p>Crystal-sample contact</p>



<p>Because the path length of the evanescent wave is confined to the interface between the ATR crystal and sample, the sample should make firm contact with the ATR crystal (Figure&nbsp;4.2.344.2.34&nbsp;). The sample sits atop the crystal and intimate contact can be ensured by applying pressure above the sample. However, one must be mindful of the ATR crystal hardness. Too much pressure may distort the crystal and affect the reproducibility of the resulting spectrum.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/024e7676621ed2367cfbcde0a9384e2489f156b2/Picture%2012.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.344.2.34&nbsp;A close-up image of an ATR accessory attached to a Nexus 670 FTIR.</figcaption></figure>



<p>The wavelength effect expressed in \label{7} shows an increase in penetration depth at increased wavelength. In terms of wavenumbers the relationship becomes inverse. At 4000 cm<sup>-1</sup>&nbsp;penetration of the sample is 10x less than penetration at 400 cm<sup>-1</sup>&nbsp;meaning the intensity of the peaks may appear higher at lower wavenumbers in the absorbance spectrum compared to the spectral features in a transmission FTIR spectrum (if an automated correction to the ATR setup is not already in place).</p>



<h3 class="wp-block-heading" id="selecting-an-atr-crystal">Selecting an ATR Crystal</h3>



<p>ATR functions effectively on the condition that the refractive index of the crystal is of a higher refractive index than the sample. Several crystals are available for use and it is important to select an appropriate option for any given experiment (Table&nbsp;4.2.114.2.11&nbsp;).</p>



<p>When selecting a material, it is important to consider reactivity, temperature, toxicity, solubility, and hardness.</p>



<p>The first ATR crystals in use were KRS-5, a mixture of thallium bromide and iodide, and silver halides. These materials are not listed in the table because they are not in use any longer. While cost-effective, they are not practical due to their light sensitivity, softness, and relatively low refractive indices. In addition KRS-5 is terribly toxic and dissolves on contact with many solvents, including water.</p>



<p>At present diamond is a favorable option for its hardness, inertness and wide spectral range, but may not be a financially viable option for some experiments. ZnSe and germanium are the most common crystal materials. ZnSe is reasonably priced, has significant mechanical strength and a long endurance. However, the surface will become etched with exposure to chemicals on either extreme of the pH scale. With a strong acid ZnSe will react to form toxic hydrogen selenide gas. ZnSe is also prone to oxidation and care must be taken to avoid the formation of an IR absorbing layer of SeO<sub>2</sub>. Germanium has a higher refractive index, which reduces the depth of penetration to 1 µm and may be preferable to ZnSe in applications involving intense sample absorptions or for use with samples that produce strong background absorptions. Sapphire is physically robust with a wide spectral range, but has a relatively low refractive index in terms of ATR crystals, meaning it may not be able to test as many samples as another crystal might.</p>



<h3 class="wp-block-heading" id="sample-versatility">Sample Versatility</h3>



<h4 class="wp-block-heading" id="solids">Solids</h4>



<p>The versatility of ATR is reflected in the various forms and phases that a sample can assume. Solid samples need not be compressed into a pellet, dispersed into a mull or dissolve in a solution. A ground solid sample is simply pressed to the surface of the ATR crystal. For hard samples that may present a challenge to grind into a fine solid, the total area in contact with the crystal may be compromised unless small ATR crystals with exceptional durability are used (e.g., 2 mm diamond). Loss of contact with the crystal would result in decreased signal intensity because the evanescent wave may not penetrate the sample effectively. The inherently short path length of ATR due to the short penetration depth (0.5-5 µm) enables surface-modified solid samples to be readily characterized with ATR.</p>



<p>Powdered samples are often tedious to prepare for analysis with transmission spectroscopy because they typically require being made into a KBr pellet to and ensuring the powdered sample is ground up sufficiently to reduce scattering. However, powdered samples require no sample preparation when taking the ATR spectra. This is advantageous in terms of time and effort, but also means the sample can easily be recovered after analysis.</p>



<h4 class="wp-block-heading" id="liquids">Liquids</h4>



<p>The advantage of using ATR to analyze liquid samples becomes apparent when short effective path lengths are required. The spectral reproducibility of liquid samples is certain as long as the entire length of the crystal is in contact with the liquid sample, ensuring the evanescent wave is interacting with the sample at the points of reflection, and the thickness of the liquid sample exceeds the penetration depth. A small path length may be necessary for aqueous solutions in order to reduce the absorbance of water.</p>



<h3 class="wp-block-heading" id="sample-preparation">Sample Preparation</h3>



<p>ATR-FTIR has been used in fields spanning forensic analysis to pharmaceutical applications and even art preservation. Due to its ease of use and accessibility ATR can be used to determine the purity of a compound. With only a minimal amount of sample this researcher is able to collect a quick analysis of her sample and determine whether it has been adequately purified or requires further processing. As can be seen in Figure&nbsp;4.2.354.2.35&nbsp;, the sample size is minute and requires no preparation. The sample is placed in close contact with the ATR crystal by turning a knob that will apply pressure to the sample (Figure&nbsp;4.2.364.2.36&nbsp;).</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/9e652f9d5b54566aaeb759bcff014023bf8ffe17/Picture%207.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.354.2.35&nbsp;Photograph of a small sample size is being placed on the ATR crystal.</figcaption></figure>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/3b7ba2de71fd2196cc24f88658c8dd655d61c2d4/Picture%2013.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.364.2.36&nbsp;Turning the knob applies pressure to the sample, ensuring good contact with the ATR crystal.</figcaption></figure>



<p>ATR has an added advantage in that it inherently encloses the optical path of the IR beam. In a transmission FTIR, atmospheric compounds are constantly exposed to the IR beam and can present significant interference with the sample measurement. Of course the transmission FTIR can be purged in a dry environment, but sample measurement may become cumbersome. In an ATR measurement, however, light from the spectrometer is constantly in contact with the sample and exposure to the environment is reduced to a minimum.</p>



<h3 class="wp-block-heading" id="application-to-inorganic-chemistry">Application to Inorganic Chemistry</h3>



<p>One exciting application of ATR is in the study of classical works of art. In the study of fragments of a piece of artwork, where samples are scarce and one-of-a-kind, ATR is a suitable method of characterization because it requires only a small sample size. Determining the compounds present in art enables proper preservation and historical insight into the pieces.</p>



<p>In a study examining several paint samples from a various origins, a micro-ATR was employed for analysis. This study used a silicon crystal with a refractive index of 2.4 and a reduced beam size. Going beyond a simple surface analysis, this study explored the localization of various organic and inorganic compounds in the samples by performing a stratigraphic analysis. The researchers did so by embedding the samples in both KBr and a polyester resins. Two embedding techniques were compared to observe cross-sections of the samples. The mapping of the samples took approximately 1-3 hours which may seem quite laborious to some, but considering the precious nature of the sample, the wait time was acceptable to the researchers.</p>



<p>The optical microscope picture ( Figure&nbsp;4.2.374.2.37&nbsp;) shows a sample of a blue painted area from the robe of a 14<sup>th</sup>&nbsp;century Italian polychrome statue of a Madonna. The spectra shown in Figure&nbsp;4.2.384.2.38&nbsp;were acquired from the different layers pictured in the box marked in Figure&nbsp;4.2.374.2.37&nbsp;. All spectra were collected from the cross-sectioned sample and the false-color map on each spectrum indicates the location of each of these compounds within the embedded sample. The spectra correspond to the inorganic compounds listed in Table&nbsp;4.2.124.2.12&nbsp;, which also highlights characteristic vibrational bands.</p>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/9d6b680ba1c6ff40ee4f4e9b06d03f0d16400698/Picture%209.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.374.2.37&nbsp;A paint sample from which four inorganic compounds were identified by ATR spectroscopy. The numbers indicate different layers in the sample, composed of different inorganic compounds. The boxed area shows the region within which ATR mapping occurred. Reproduced from R. Mazzeo, E. Joseph, S. Prati, and A. Millemaggi. Anal. Chim. Acta, 2007, 599, 107. Copyright: Elsevier (2007).</figcaption></figure>



<figure class="wp-block-image"><img decoding="async" src="https://cnx.org/resources/23842bdd284c0597229a35edb912b15f3bc8be6b/Picture%208.jpg" alt=""/><figcaption class="wp-element-caption">Figure&nbsp;4.2.374.2.37&nbsp;. The images are labeled with the layer that corresponds to its location in the paint sample. Reproduced from R. Mazzeo, E. Joseph, S. Prati, and A. Millemaggi.&nbsp;<em>Anal. Chim. Acta</em>, 2007,&nbsp;<strong>599</strong>, 107. Copyright: Elsevier (2007)</figcaption></figure>



<figure class="wp-block-table"><table><tbody><tr><td><strong>Compound</strong></td><td><strong>Selected Spectral Bands</strong></td><td><strong>Assignment</strong></td></tr><tr><td>Cu<sub>3</sub>(CO<sub>3</sub>)<sub>2</sub>(OH)<sub>2</sub>&nbsp;(Azurite)</td><td>1493</td><td>CO<sub>3</sub><sup>2-&nbsp;</sup>asymmetric stretch</td></tr><tr><td>Silicate based blue-pigments</td><td>1035</td><td>Si-O stretching</td></tr><tr><td>2PbCO<sub>3</sub>&nbsp;⋅⋅&nbsp;Pb(OH)<sub>2</sub>&nbsp;(White lead)</td><td>1399</td><td>CO<sub>3</sub><sup>2-&nbsp;</sup>asymmetric stretch</td></tr><tr><td>A natural ferruginous aluminum silicate red pigment (Bole)</td><td>3697</td><td>OH stretching</td></tr><tr><td>CaSO<sub>4</sub>&nbsp;⋅⋅&nbsp;(Gypsum)</td><td>1109</td><td>SO<sub>4</sub><sup>2-</sup>&nbsp;asymmetric stretch</td></tr></tbody></table></figure>



<p>The deep blue layer 3 corresponds to azurite and the light blue paint layer 2 to a mixture of silicate based blue pigments and white lead. Although beyond the ATR crystal’s spatial resolution limit of 20 µm, the absorption of bole was detected by the characteristic triple absorption bands of 3697, 3651, and 3619 cm<sup>-1</sup>&nbsp;as seen in spectrum d of Figure&nbsp;4.2.374.2.37&nbsp;. The white layer 0 was identified as gypsum.</p>



<p>To identify the binding material, the KBr embedded sample proved to be more effective than the polyester resin. This was due in part to the overwhelming IR absorbance of gypsum in the same spectral range (1700-1600 cm<sup>-1</sup>) as a characteristic stretch of the binding as well as some contaminant absorption due to the polyester embedding resin.</p>



<p>To spatially locate specific pigments and binding media, ATR mapping was performed on the area highlighted with a box in Figure&nbsp;4.2.374.2.37&nbsp;. The false color images alongside each spectrum in Figure&nbsp;4.2.384.2.38&nbsp;indicate the relative presence of the compound corresponding to each spectrum in the boxed area. ATR mapping was achieved by taking 108 spectra across the 220&#215;160 µm area and selecting for each identified compound by its characteristic vibrational band.</p>



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					<description><![CDATA[Click here to see more posts about UV-Vis spectroscopy Only 10$ for interpretation of your UV-Vis spectrum Payment Upon Completion Send your UV-Vis spectra... In Figure 10.9 we examined Nessler’s original method for matching the color of a sample to the color of a standard. Matching the colors was a labor intensive process for the [&#8230;]]]></description>
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<p>In Figure 10.9 we examined Nessler’s original method for matching the color of a sample to the color of a standard. Matching the colors was a labor intensive process for the analyst. Not surprisingly, spectroscopic methods of analysis were slow to develop. The 1930s and 1940s saw the introduction of photoelectric transducers for ultraviolet and visible radiation, and thermocouples for infrared radiation. As a result, modern instrumentation for absorption spectroscopy became routinely available in the 1940s—progress has been rapid ever since.</p>



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<h2 class="wp-block-heading" id="10-3-1-instrumentation">10.3.1 Instrumentation</h2>



<p>Frequently an analyst must select—from among several instruments of different design—the one instrument best suited for a particular analysis. In this section we examine several different instruments for molecular absorption spectroscopy, emphasizing their advantages and limitations. Methods of sample introduction are also covered in this section.</p>



<h3 class="wp-block-heading" id="instrument-designs-for-molecular-uv-vis-absorption">Instrument Designs for Molecular UV/Vis Absorption</h3>



<p><em><strong>Filter Photometer.</strong></em>&nbsp;The simplest instrument for molecular UV/Vis absorption is a&nbsp;<strong>filter photometer</strong>&nbsp;(Figure 10.25), which uses an absorption or interference filter to isolate a band of radiation. The filter is placed between the source and the sample to prevent the sample from decomposing when exposed to higher energy radiation. A filter photometer has a single optical path between the source and detector, and is called a&nbsp;<strong>single-beam</strong>&nbsp;instrument. The instrument is calibrated to 0% T while using a shutter to block the source radiation from the detector. After opening the shutter, the instrument is calibrated to 100% T using an appropriate blank. The blank is then replaced with the sample and its transmittance measured. Because the source’s incident power and the sensitivity of the detector vary with wavelength, the photometer must be recalibrated whenever the filter is changed. Photometers have the advantage of being relatively inexpensive, rugged, and easy to maintain. Another advantage of a photometer is its portability, making it easy to take into the field. Disadvantages of a photometer include the inability to record an absorption spectrum and the source’s relatively large effective bandwidth, which limits the calibration curve’s linearity.</p>



<p>Note</p>



<p>The percent transmittance varies between 0% and 100%. As we learned in Figure 10.21, we use a blank to determine&nbsp;<em>P</em><sub>0</sub>, which corresponds to 100% T. Even in the absence of light the detector records a signal. Closing the shutter allows us to assign 0% T to this signal. Together, setting 0% T and 100% T calibrates the instrument. The amount of light passing through a sample produces a signal that is greater than or equal to that for 0% T and smaller than or equal to that for 100%T.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12706/Figure10.25.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12706/Figure10.25.jpg?revision=1&amp;size=bestfit&amp;width=474&amp;height=362" alt="Figure10.25.jpg"/></a></figure>



<p><strong>Figure 10.25</strong>&nbsp;Schematic diagram of a filter photometer. The analyst either inserts a removable filter or the filters are placed in a carousel, an example of which is shown in the photographic inset. The analyst selects a filter by rotating it into place.</p>



<p><em><strong>Single-Beam Spectrophotometer.&nbsp;</strong></em>An instrument that uses a monochromator for wavelength selection is called a&nbsp;<strong>spectrophotometer</strong>. The simplest spectrophotometer is a single-beam instrument equipped with a fixed-wavelength monochromator (Figure 10.26). Single-beam spectrophotometers are calibrated and used in the same manner as a photometer. One example of a single-beam spectrophotometer is Thermo Scientific’s Spectronic 20D+, which is shown in the photographic insert to Figure 10.26. The Spectronic 20D+ has a range of 340–625 nm (950 nm when using a red-sensitive detector), and a fixed effective bandwidth of 20 nm. Battery-operated, hand-held single-beam spectrophotometers are available, which are easy to transport into the field. Other single-beam spectrophotometers also are available with effective bandwidths of 2–8 nm. Fixed wavelength single-beam spectrophotometers are not practical for recording spectra because manually adjusting the wavelength and recalibrating the spectrophotometer is awkward and time-consuming. The accuracy of a single-beam spectrophotometer is limited by the stability of its source and detector over time.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12707/Figure10.26.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12707/Figure10.26.jpg?revision=1&amp;size=bestfit&amp;width=475&amp;height=349" alt="Figure10.26.jpg"/></a></figure>



<p><strong>Figure 10.26</strong>&nbsp;Schematic diagram of a fixed-wavelength single-beam spectrophotometer. The photographic inset shows a typical instrument. The shutter remains closed until the sample or blank is placed in the sample compartment. The analyst manually selects the wavelength by adjusting the wavelength dial. Inset photo modified from:&nbsp;<a href="http://commons.wikimedia.org/wiki/File:Spektrofotometr.JPG" rel="noreferrer noopener" target="_blank">Adi</a>&nbsp;(www.commons.wikipedia.org).</p>



<p><em><strong>Double-Beam Spectrophotometer.</strong></em>&nbsp;The limitations of fixed-wavelength, single-beam spectrophotometers are minimized by using a&nbsp;<strong>double-beam</strong>spectrophotometer (Figure 10.27). A chopper controls the radiation’s path, alternating it between the sample, the blank, and a shutter. The signal processor uses the chopper’s known speed of rotation to resolve the signal reaching the detector into the transmission of the blank,&nbsp;<em>P</em><sub>0</sub>, and the sample,&nbsp;<em>P</em><sub>T</sub>. By including an opaque surface as a shutter, it is possible to continuously adjust 0% T. The effective bandwidth of a double-beam spectrophotometer is controlled by adjusting the monochromator’s entrance and exit slits. Effective bandwidths of 0.2–3.0 nm are common. A scanning monochromator allows for the automated recording of spectra. Double-beam instruments are more versatile than single-beam instruments, being useful for both quantitative and qualitative analyses, but also are more expensive.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12708/Figure10.27.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12708/Figure10.27.jpg?revision=1&amp;size=bestfit&amp;width=700&amp;height=437" alt="Figure10.27.jpg"/></a></figure>



<p><strong>Figure 10.27</strong>&nbsp;Schematic diagram of a scanning, double-beam spectrophotometer. A chopper directs the source’s radiation, using a transparent window to pass radiation to the sample and a mirror to reflect radiation to the blank. The chopper’s opaque surface serves as a shutter, which allows for a constant adjustment of the spectrophotometer’s 0% T. The photographic insert shows a typical instrument. The unit in the middle of the photo is a temperature control unit that allows the sample to be heated or cooled.</p>



<p><em><strong>Diode Array Spectrometer.</strong></em>&nbsp;An instrument with a single detector can monitor only one wavelength at a time. If we replace a single photomultiplier with many photodiodes, we can use the resulting array of detectors to record an entire spectrum simultaneously in as little as 0.1 s. In a diode array spectrometer the source radiation passes through the sample and is dispersed by a grating (Figure 10.28). The photodiode array is situated at the grating’s focal plane, with each diode recording the radiant power over a narrow range of wavelengths. Because we replace a full monochromator with just a grating, a diode array spectrometer is small and compact.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12709/Figure10.28.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12709/Figure10.28.jpg?revision=1&amp;size=bestfit&amp;width=565&amp;height=431" alt="Figure10.28.jpg"/></a></figure>



<p><strong>Figure 10.28</strong>&nbsp;Schematic diagram of a diode array spectrophotometer. The photographic insert shows a typical instrument. Note that the 50-mL beaker provides a sense of scale.</p>



<p>One advantage of a diode array spectrometer is the speed of data acquisition, which allows to collect several spectra for a single sample. Individual spectra are added and averaged to obtain the final spectrum. This&nbsp;<strong>signal averaging</strong>&nbsp;improves a spectrum’s signal-to-noise ratio. If we add together&nbsp;<em>n</em>&nbsp;spectra, the sum of the signal at any point,&nbsp;<em>x</em>, increases as&nbsp;<em>nS<sub>x</sub></em>, where&nbsp;<em>S<sub>x</sub>&nbsp;</em>is the signal. The noise at any point,&nbsp;<em>N<sub>x</sub></em>, is a random event, which increases as&nbsp;√<em>nN<sub>x</sub></em>&nbsp;when we add together&nbsp;<em>n</em>spectra. The&nbsp;<strong>signal-to-noise ratio</strong>&nbsp;(S/N) after&nbsp;<em>n</em>&nbsp;scans isSN=nSxn−−√Nx=n−−√SxnNx(4.8.1)(4.8.1)SN=nSxnNx=nSxnNx</p>



<p>where&nbsp;<em>S<sub>x</sub></em>/<em>N<sub>x</sub></em>&nbsp;is the signal-to-noise ratio for a single scan. The impact of signal averaging is shown in Figure 10.29. The first spectrum shows the signal for a single scan, which consists of a single, noisy peak. Signal averaging using 4 scans and 16 scans decreases the noise and improves the signal-to-noise ratio. One disadvantage of a photodiode array is that the effective bandwidth per diode is roughly an order of magnitude larger than that for a high quality monochromator.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12710/Figure10.29.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12710/Figure10.29.jpg?revision=1&amp;size=bestfit&amp;width=275&amp;height=734" alt="Figure10.29.jpg"/></a></figure>



<p><strong>Figure 10.29</strong>&nbsp;Effect of signal averaging on a spectrum’s signal-to-noise ratio. From top to bottom: spectrum for a single scan; average spectrum after four scans; and average spectrum after adding 16 scans.</p>



<p><em><strong>Sample Cells.&nbsp;</strong></em>The sample compartment provides a light-tight environment that limits the addition of stray radiation. Samples are normally in the liquid or solution state, and are placed in cells constructed with UV/Vis transparent materials, such as quartz, glass, and plastic (Figure 10.30). A quartz or fused-silica cell is required when working at a wavelength &lt;300 nm where other materials show a significant absorption. The most common pathlength is 1 cm (10 mm), although cells with shorter (as little as 0.1 cm) and longer pathlengths (up to 10 cm) are available. Longer pathlength cells are useful when analyzing a very dilute solution, or for gas samples. The highest quality cells allow the radiation to strike a flat surface at a 90<sup>o</sup>&nbsp;angle, minimizing the loss of radiation to reflection. A test tube is often used as a sample cell with simple, single-beam instruments, although differences in the cell’s pathlength and optical properties add an additional source of error to the analysis.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12781/Figure_10.30.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12781/Figure_10.30.jpg?revision=1&amp;size=bestfit&amp;width=675&amp;height=262" alt="Figure 10.30.jpg"/></a></figure>



<p><strong>Figure 10.30</strong>&nbsp;Examples of sample cells for UV/Vis spectroscopy. From left to right (with path lengths in parentheses): rectangular plastic cuvette (10.0 mm), rectangular quartz cuvette (5.000 mm), rectangular quartz cuvette (1.000 mm), cylindrical quartz cuvette (10.00 mm), cylindrical quartz cuvette (100.0 mm). Cells often are available as a matched pair, which is important when using a double-beam instrument.</p>



<p>If we need to monitor an analyte’s concentration over time, it may not be possible to physically remove samples for analysis. This is often the case, for example, when monitoring industrial production lines or waste lines, when monitoring a patient’s blood, or when monitoring environmental systems. With a&nbsp;<strong>fiber-optic probe</strong>&nbsp;we can analyze samples in situ. An example of a remote sensing fiber-optic probe is shown in Figure 10.31. The probe consists of two bundles of fiber-optic cable. One bundle transmits radiation from the source to the probe’s tip, which is designed to allow the sample to flow through the sample cell. Radiation from the source passes through the solution and is reflected back by a mirror. The second bundle of fiber-optic cable transmits the nonabsorbed radiation to the wavelength selector. Another design replaces the flow cell shown in Figure 10.31 with a membrane containing a reagent that reacts with the analyte. When the analyte diffuses across the membrane it reacts with the reagent, producing a product that absorbs UV or visible radiation. The nonabsorbed radiation from the source is reflected or scattered back to the detector. Fiber optic probes that show chemical selectivity are called optrodes.<sup>6</sup></p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12711/Figure10.31.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12711/Figure10.31.jpg?revision=1&amp;size=bestfit&amp;width=500&amp;height=324" alt="Figure10.31.jpg"/></a></figure>



<p><strong>Figure 10.31</strong>&nbsp;Example of a fiber-optic probe. The inset photographs provide a close-up look at the probe’s flow cell and the reflecting mirror.</p>



<h3 class="wp-block-heading" id="instrument-designs-for-infrared-absorption">Instrument Designs for Infrared Absorption</h3>



<p><em><strong>Filter Photometer.</strong></em>&nbsp;The simplest instrument for IR absorption spectroscopy is a filter photometer similar to that shown in Figure 10.25 for UV/Vis absorption. These instruments have the advantage of portability, and typically are used as dedicated analyzers for gases such as HCN and CO.</p>



<p><em><strong>Double-beam spectrophotometer.</strong></em>&nbsp;Infrared instruments using a monochromator for wavelength selection use double-beam optics similar to that shown in Figure 10.27. Double-beam optics are preferred over single-beam optics because the sources and detectors for infrared radiation are less stable than those for UV/Vis radiation. In addition, it is easier to correct for the absorption of infrared radiation by atmospheric CO<sub>2</sub>&nbsp;and H<sub>2</sub>O vapor when using double-beam optics. Resolutions of 1–3 cm<sup>–1</sup>&nbsp;are typical for most instruments.</p>



<p><em><strong>Fourier transform spectrometer.</strong></em>&nbsp;In a Fourier transform infrared spectrometer, or FT–IR, the monochromator is replaced with an interferometer (Figure 10.13). Because an FT-IR includes only a single optical path, it is necessary to collect a separate spectrum to compensate for the absorbance of atmospheric CO<sub>2</sub>&nbsp;and H<sub>2</sub>O vapor. This is done by collecting a background spectrum without the sample and storing the result in the instrument’s computer memory. The background spectrum is removed from the sample’s spectrum by ratioing the two signals. In comparison to other instrument designs, an FT–IR provides for rapid data acquisition, allowing an enhancement in signal-to-noise ratio through signal-averaging.</p>



<p><em><strong>Sample Cells.</strong></em>&nbsp;Infrared spectroscopy is routinely used to analyze gas, liquid, and solid samples. Sample cells are made from materials, such as NaCl and KBr, that are transparent to infrared radiation. Gases are analyzed using a cell with a pathlength of approximately 10 cm. Longer pathlengths are obtained by using mirrors to pass the beam of radiation through the sample several times.</p>



<p>A liquid samples may be analyzed using a variety of different sample cells (Figure 10.32). For non-volatile liquids a suitable sample can be prepared by placing a drop of the liquid between two NaCl plates, forming a thin film that typically is less than 0.01 mm thick. Volatile liquids must be placed in a sealed cell to prevent their evaporation.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12712/Figure10.32.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12712/Figure10.32.jpg?revision=1&amp;size=bestfit&amp;width=700&amp;height=403" alt="Figure10.32.jpg"/></a></figure>



<p><strong>Figure 10.32</strong>&nbsp;Three examples of IR sample cells: (a) NaCl salts plates; (b) fixed pathlength (0.5 mm) sample cell with NaCl windows; (c) disposable card with a polyethylene window that is IR transparent with the exception of strong absorption bands at 2918 cm<sup>–1</sup>&nbsp;and 2849 cm<sup>–1</sup>.</p>



<p>The analysis of solution samples is limited by the solvent’s IR absorbing properties, with CCl<sub>4</sub>, CS<sub>2</sub>, and CHCl<sub>3</sub>&nbsp;being the most common solvents. Solutions are placed in cells containing two NaCl windows separated by a Teflon spacer. By changing the Teflon spacer, pathlengths from 0.015–1.0 mm can be obtained.</p>



<p>Transparent solid samples can be analyzed directly by placing them in the IR beam. Most solid samples, however, are opaque, and must be dispersed in a more transparent medium before recording the IR spectrum. If a suitable solvent is available, then the solid can be analyzed by preparing a solution and analyzing as described above. When a suitable solvent is not available, solid samples may be analyzed by preparing a mull of the finely powdered sample with a suitable oil. Alternatively, the powdered sample can be mixed with KBr and pressed into an optically transparent pellet.</p>



<p>The analysis of an aqueous sample is complicated by the solubility of the NaCl cell window in water. One approach to obtaining infrared spectra on aqueous solutions is to use&nbsp;<strong>attenuated total reflectance</strong>&nbsp;instead of transmission. Figure 10.33 shows a diagram of a typical attenuated total reflectance (ATR) FT–IR instrument. The ATR cell consists of a high refractive index material, such as ZnSe or diamond, sandwiched between a low refractive index substrate and a lower refractive index sample. Radiation from the source enters the ATR crystal where it undergoes a series of total internal reflections before exiting the crystal. During each reflection the radiation penetrates into the sample to a depth of a few microns. The result is a selective attenuation of the radiation at those wavelengths where the sample absorbs. ATR spectra are similar, but not identical, to those obtained by measuring the transmission of radiation.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12713/Figure10.33.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12713/Figure10.33.jpg?revision=1&amp;size=bestfit&amp;width=700&amp;height=327" alt="Figure10.33.jpg"/></a></figure>



<p><strong>Figure 10.33</strong>&nbsp;FT-IR spectrometer equipped with a diamond ATR sample cell. The inserts show a close-up photo of the sample platform, a sketch of the ATR’s sample slot, and a schematic showing how the source’s radiation interacts with the sample. The pressure tower is used to ensure the contact of solid samples with the ATR crystal.</p>



<p>Solid samples also can be analyzed using an ATR sample cell. After placing the solid in the sample slot, a compression tip ensures that it is in contact with the ATR crystal. Examples of solids that have been analyzed by ATR include polymers, fibers, fabrics, powders, and biological tissue samples. Another reflectance method is diffuse reflectance, in which radiation is reflected from a rough surface, such as a powder. Powdered samples are mixed with a non-absorbing material, such as powdered KBr, and the reflected light is collected and analyzed. As with ATR, the resulting spectrum is similar to that obtained by conventional transmission methods.</p>



<p>Note</p>



<p>Further details about these, and other methods for preparing solids for infrared analysis can be found in this chapter’s&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/Additional_Resources#Chapter_10" target="_blank" rel="noopener">additional resources</a>.</p>



<h2 class="wp-block-heading" id="10-3-2-quantitative-applications">10.3.2 Quantitative Applications</h2>



<p>The determination of an analyte’s concentration based on its absorption of ultraviolet or visible radiation is one of the most frequently encountered quantitative analytical methods. One reason for its popularity is that many organic and inorganic compounds have strong absorption bands in the UV/Vis region of the electromagnetic spectrum. In addition, if an analyte does not absorb UV/Vis radiation—or if its absorbance is too weak—we often can react it with another species that is strongly absorbing. For example, a dilute solution of Fe<sup>2</sup><sup>+</sup>&nbsp;does not absorb visible light. Reacting Fe<sup>2</sup><sup>+</sup>&nbsp;with&nbsp;<em>o</em>-phenanthroline, however, forms an orange–red complex of Fe(phen)<sub>3</sub><sup>2+</sup>&nbsp;that has a strong, broad absorbance band near 500 nm. An additional advantage to UV/Vis absorption is that in most cases it is relatively easy to adjust experimental and instrumental conditions so that Beer’s law is obeyed.</p>



<p>Note</p>



<p>Figure 10.18 shows the visible spectrum for Fe(phen)<sub>3</sub><sup>2+</sup>.</p>



<p>A quantitative analysis based on the absorption of infrared radiation, although important, is less frequently encountered than those for UV/Vis absorption. One reason is the greater tendency for instrumental deviations from Beer’s law when using infrared radiation. Because an infrared absorption band is relatively narrow, any deviation due to the lack of monochromatic radiation is more pronounced. In addition, infrared sources are less intense than UV/Vis sources, making stray radiation more of a problem. Differences in pathlength for samples and standards when using thin liquid films or KBr pellets are a problem, although an internal standard can be used to correct for any difference in pathlength. Finally, establishing a 100% T (<em>A</em>&nbsp;= 0) baseline is often difficult because the optical properties of NaCl sample cells may change significantly with wavelength due to contamination and degradation. We can minimize this problem by measuring absorbance relative to a baseline established for the absorption band. Figure 10.34 shows how this is accomplished.</p>



<p>Note</p>



<p>Another approach is to use a cell with a fixed pathlength, such as that shown in Figure 10.32b.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12714/Figure10.34.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12714/Figure10.34.jpg?revision=1&amp;size=bestfit&amp;width=450&amp;height=385" alt="Figure10.34.jpg"/></a></figure>



<p><strong>Figure 10.34</strong>&nbsp;Method for determining absorbance from an IR spectrum.</p>



<h3 class="wp-block-heading" id="environmental-applications">Environmental Applications</h3>



<p>The analysis of waters and wastewaters often relies on the absorption of ultraviolet and visible radiation. Many of these methods are outlined in Table 10.6. Several of these methods are described here in more detail.</p>



<figure class="wp-block-table"><table><thead><tr><th scope="col">Analyte</th><th scope="col">Method</th><th scope="col">λ&nbsp;(nm)</th></tr></thead><tbody><tr><td><em>T</em><em>r</em><em>ace Metals</em></td></tr><tr><td>aluminum</td><td>react with Eriochrome cyanide R dye at pH6; forms red to pink complex</td><td>535</td></tr><tr><td>arsenic</td><td>reduce to AsH<sub>3</sub>&nbsp;using Zn and react with silver diethyldithiocarbamate; forms red complex</td><td>535</td></tr><tr><td>cadmium</td><td>extract into CHCl<sub>3</sub>&nbsp;containing dithizone from a sample made basic with NaOH; forms pink to red complex</td><td>518</td></tr><tr><td>chromium</td><td>oxidize to Cr(VI) and react with diphenylcarbazide; forms red-violet product</td><td>540</td></tr><tr><td>copper</td><td>react with neocuprine in neutral to slightly acid solution and extract into CHCl<sub>3</sub>/CH<sub>3</sub>OH; forms yellow complex</td><td>457</td></tr><tr><td>iron</td><td>reduce to Fe<sup>2</sup><sup>+</sup>&nbsp;and react with&nbsp;<em>o</em>-phenanthroline; forms orange-red complex</td><td>510</td></tr><tr><td>lead</td><td>extract into CHCl<sub>3</sub>&nbsp;containing dithizone from sample made basic with NH<sub>3</sub>/NH<sub>4</sub><sup>+</sup>&nbsp;buffer; forms cherry red complex</td><td>510</td></tr><tr><td>manganese</td><td>oxidize to MnO<sub>4</sub><sup>–</sup>&nbsp;with persulfate; forms purple solution</td><td>525</td></tr><tr><td>mercury</td><td>extract into CHCl<sub>3</sub>&nbsp;containing dithizone from acidic sample; forms orange complex</td><td>492</td></tr><tr><td>zinc</td><td>react with zincon at pH 9; forms blue complex</td><td>620</td></tr><tr><td><em>I</em><em>norganic Nonmetals</em></td></tr><tr><td>ammonia</td><td>reaction with hypochlorite and phenol using a manganous salt catalyst; forms blue indophenol as product</td><td>630</td></tr><tr><td>cyanide</td><td>react with chloroamine-T to form CNCl and then with a pyridine-barbituric acid; forms a red-blue dye</td><td>578</td></tr><tr><td>fluoride</td><td>react with red Zr-SPADNS lake; formation of ZrF<sub>6</sub><sup>2–</sup>&nbsp;decreases color of the red lake</td><td>570</td></tr><tr><td>chlorine (residual)</td><td>react with leuco crystal violet; forms blue product</td><td>592</td></tr><tr><td>nitrate</td><td>react with Cd to form NO<sub>2</sub><sup>–</sup>&nbsp;and then react with sulfanilamide and&nbsp;<em>N</em>-(1-napthyl)-ethylenediamine; forms red azo dye</td><td>543</td></tr><tr><td>phosphate</td><td>react with ammonium molybdate and then reduce with SnCl<sub>2</sub>; forms molybdenum blue</td><td>690</td></tr><tr><td><em>O</em><em>rganics</em></td></tr><tr><td>phenol</td><td>react with 4-aminoantipyrine and K<sub>3</sub>Fe(CN)<sub>6</sub>; forms yellow antipyrine dye</td><td>460</td></tr><tr><td>anionic surfactant</td><td>react with cationic methylene blue dye and extract into CHCl<sub>3</sub>; forms blue ion pair</td><td>652</td></tr></tbody></table></figure>



<p><img decoding="async" alt="dithizone.png" width="68px" height="184px" src="https://chem.libretexts.org/@api/deki/files/12102/dithizone.png?revision=1&amp;size=bestfit&amp;width=68&amp;height=184">Although the quantitative analysis of metals in waters and wastewaters is accomplished primarily by atomic absorption or atomic emission spectroscopy, many metals also can be analyzed following the formation of a colored metal–ligand complex. One advantage to these spectroscopic methods is that they are easily adapted to the analysis of samples in the field using a filter photometer. One ligand that is used in the analysis of several metals is diphenylthiocarbazone, also known as dithizone. Dithizone is not soluble in water, but when a solution of dithizone in CHCl<sub>3</sub>&nbsp;is shaken with an aqueous solution containing an appropriate metal ion, a colored metal–dithizonate complex forms that is soluble in CHCl<sub>3</sub>. The selectivity of dithizone is controlled by adjusting the sample’s pH. For example, Cd<sup>2</sup><sup>+</sup>&nbsp;is extracted from solutions that are made strongly basic with NaOH, Pb<sup>2</sup><sup>+</sup>&nbsp;from solutions that are made basic with an NH<sub>3</sub>/NH<sub>4</sub><sup>+</sup>&nbsp;buffer, and Hg<sup>2</sup><sup>+</sup>&nbsp;from solutions that are slightly acidic.</p>



<p>Note</p>



<p>Atomic absorption is the subject of&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.4%3A_Atomic_Absorption_Spectroscopy" target="_blank" rel="noopener">Section 10.4</a>&nbsp;and atomic emission is the subject of&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.7%3A_Atomic_Emission_Spectroscopy" target="_blank" rel="noopener">Section 10.7</a>.</p>



<p>The structure of dithizone is shown to the right. See Chapter 7 for a discussion of extracting metal ions using dithizone.</p>



<p>When chlorine is added to water the portion available for disinfection is called the chlorine residual. There are two forms of chlorine residual. The free chlorine residual includes Cl<sub>2</sub>, HOCl, and OCl<sup>–</sup>. The combined chlorine residual, which forms from the reaction of NH<sub>3</sub>&nbsp;with HOCl, consists of monochloramine, NH<sub>2</sub>Cl, dichloramine, NHCl<sub>2</sub>, and trichloramine, NCl<sub>3</sub>. Because the free chlorine residual is more efficient at disinfection, there is an interest in methods that can distinguish between the different forms of the total chlorine residual. One such method is the leuco crystal violet method. The free residual chlorine is determined by adding leuco crystal violet to the sample, which instantaneously oxidizes to give a blue colored compound that is monitored at 592 nm. Completing the analysis in less than five minutes prevents a possible interference from the combined chlorine residual. The total chlorine residual (free + combined) is determined by reacting a separate sample with iodide, which reacts with both chlorine residuals to form HOI. When the reaction is complete, leuco crystal violet is added and oxidized by HOI, giving the same blue colored product. The combined chlorine residual is determined by difference.</p>



<p>Note</p>



<p>In Chapter 9 we explored how the total chlorine residual can be determined by a redox titration; see&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/09_Titrimetric_Methods/9.4%3A_Redox_Titrations#Representative_Method_9.3" target="_blank" rel="noopener">Representative Method 9.3</a>&nbsp;for further details. The method described here allows us to divide the total chlorine residual into its component parts.</p>



<p>The concentration of fluoride in drinking water may be determined indirectly by its ability to form a complex with zirconium. In the presence of the dye SPADNS, solutions of zirconium form a red colored compound, called a lake, that absorbs at 570 nm. When fluoride is added, the formation of the stable ZrF<sub>6</sub><sup>2–</sup>&nbsp;complex causes a portion of the lake to dissociate, decreasing the absorbance. A plot of absorbance versus the concentration of fluoride, therefore, has a negative slope.</p>



<p>Note</p>



<p>SPADNS, which is shown below, is an abbreviation for the sodium salt of 2-(4-sulfophenylazo)-1,8-dihydroxy-3,6-napthalenedisulfonic acid, which is a mouthful to say.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12103/SPADNS2.png?revision=1" alt="SPADNS2.png"/></figure>



<p><img decoding="async" alt="4-aminoantipyrene.png" src="https://chem.libretexts.org/@api/deki/files/12104/4-aminoantipyrene.png?revision=1">Spectroscopic methods also are used to determine organic constituents in water. For example, the combined concentrations of phenol, and ortho- and meta- substituted phenols are determined by using steam distillation to separate the phenols from nonvolatile impurities. The distillate reacts with 4-aminoantipyrine at pH 7.9 ± 0.1 in the presence of K<sub>3</sub>Fe(CN)<sub>6</sub>, forming a yellow colored antipyrine dye. After extracting the dye into CHCl<sub>3</sub>, its absorbance is monitored at 460 nm. A calibration curve is prepared using only the unsubstituted phenol, C<sub>6</sub>H<sub>5</sub>OH. Because the molar absorptivity of substituted phenols are generally less than that for phenol, the reported concentration represents the minimum concentration of phenolic compounds.</p>



<p>Molecular absorption also can be used for the analysis of environmentally significant airborne pollutants. In many cases the analysis is carried out by collecting the sample in water, converting the analyte to an aqueous form that can be analyzed by methods such as those described in Table 10.6. For example, the concentration of NO<sub>2</sub>&nbsp;can be determined by oxidizing NO<sub>2</sub>&nbsp;to NO<sub>3</sub><sup>–</sup>. The&nbsp;<img decoding="async" alt="red azo dye.png" src="https://chem.libretexts.org/@api/deki/files/12105/red_azo_dye.png?revision=1">concentration of NO<sub>3</sub><sup>–</sup>&nbsp;is then determined by first reducing it to NO<sub>2</sub><sup>–</sup>&nbsp;with Cd, and then reacting NO<sub>2</sub><sup>–</sup>&nbsp;with sulfanilamide and&nbsp;<em>N</em>-(1-naphthyl)-ethylenediamine to form a red azo dye. Another important application is the analysis for SO<sub>2</sub>, which is determined by collecting the sample in an aqueous solution of HgCl<sub>4</sub><sup>2–</sup>&nbsp;where it reacts to form Hg(SO<sub>3</sub>)<sub>2</sub><sup>2–</sup>. Addition of&nbsp;<em>p</em>-rosaniline and formaldehyde produces a purple complex that is monitored at 569 nm. Infrared absorption is useful for the analysis of organic vapors, including HCN, SO<sub>2</sub>, nitrobenzene, methyl mercaptan, and vinyl chloride. Frequently, these analyses are accomplished using portable, dedicated infrared photometers.</p>



<figure class="wp-block-image size-large"><a href="http://www.analyzetest.com/index.php/contact-us/"><img decoding="async" src="http://s7.picofile.com/file/8392387600/uv_vis_in.gif" alt=""/></a></figure>



<h3 class="wp-block-heading" id="clinical-applications">Clinical Applications</h3>



<p>The analysis of clinical samples is often complicated by the complexity of the sample matrix, which may contribute a significant background absorption at the desired wavelength. The determination of serum barbiturates provides one example of how this problem is overcome. The barbiturates are first extracted from a sample of serum with CHCl<sub>3</sub>&nbsp;and then extracted from the CHCl<sub>3</sub>&nbsp;into 0.45 M NaOH (pH ≈ 13). The absorbance of the aqueous extract is measured at 260 nm, and includes contributions from the barbiturates as well as other components extracted from the serum sample. The pH of the sample is then lowered to approximately 10 by adding NH<sub>4</sub>Cl and the absorbance remeasured. Because the barbiturates do not absorb at this pH, we can use the absorbance at pH 10,&nbsp;<em>A</em><sub>pH</sub><sub>&nbsp;10</sub>, to correct the absorbance at pH 13,&nbsp;<em>A</em><sub>pH</sub><sub>&nbsp;13</sub>Abarb=ApH 13−Vsamp+VNH4ClVsamp×ApH 10(4.8.2)(4.8.2)Abarb=ApH 13−Vsamp+VNH4ClVsamp×ApH 10</p>



<p>where&nbsp;<em>A</em><sub>barb</sub>&nbsp;is the absorbance due to the serum barbiturates, and&nbsp;<em>V</em><sub>samp</sub>&nbsp;and&nbsp;<em>V</em><sub>NH4Cl</sub>&nbsp;are the volumes of sample and NH<sub>4</sub>Cl, respectively. Table 10.7 provides a summary of several other methods for analyzing clinical samples.</p>



<figure class="wp-block-table"><table><thead><tr><th scope="col">Analyte</th><th scope="col">Method</th><th scope="col">λ&nbsp;(nm)</th></tr></thead><tbody><tr><td>total serum protein</td><td>react with NaOH and Cu<sup>2</sup><sup>+</sup>; forms blue-violet complex</td><td>540</td></tr><tr><td>serum cholesterol</td><td>react with Fe<sup>3</sup><sup>+</sup>&nbsp;in presence of isopropanol, acetic acid, and H<sub>2</sub>SO<sub>4</sub>; forms blue-violet complex</td><td>540</td></tr><tr><td>uric acid</td><td>react with phosphotungstic acid; forms tungsten blue</td><td>710</td></tr><tr><td>serum barbiturates</td><td>extract into CHCl<sub>3</sub>&nbsp;to isolate from interferents and then extract into 0.45 M NaOH</td><td>260</td></tr><tr><td>glucose</td><td>react with&nbsp;<em>o</em>-toludine at 100<sup>o</sup>C; forms blue-green complex</td><td>630</td></tr><tr><td>protein-bound iodine</td><td>decompose protein to release iodide, which catalyzes redox reaction between Ce<sup>3</sup><sup>+</sup>&nbsp;and As<sup>3</sup><sup>+</sup>; forms yellow colored Ce<sup>4</sup><sup>+</sup></td><td>420</td></tr></tbody></table></figure>



<h3 class="wp-block-heading" id="industrial-analysis">Industrial Analysis</h3>



<p>UV/Vis molecular absorption is used for the analysis of a diverse array of industrial samples including pharmaceuticals, food, paint, glass, and metals. In many cases the methods are similar to those described in Table 10.6 and Table 10.7. For example, the amount of iron in food can be determined by bringing the iron into solution and analyzing using the&nbsp;<em>o</em>-phenanthroline method listed in Table 10.6.</p>



<p>Many pharmaceutical compounds contain chromophores that make them suitable for analysis by UV/Vis absorption. Products that have been analyzed in this fashion include antibiotics, hormones, vitamins, and analgesics. One example of the use of UV absorption is in determining the purity of aspirin tablets, for which the active ingredient is acetylsalicylic acid. Salicylic acid, which is produced by the hydrolysis of acetylsalicylic acid, is an undesirable impurity in aspirin tablets, and should not be present at more than 0.01% w/w. Samples can be screened for unacceptable levels of salicylic acid by monitoring the absorbance at a wavelength of 312 nm. Acetylsalicylic acid absorbs at 280 nm, but absorbs poorly at 312 nm. Conditions for preparing the sample are chosen such that an absorbance of greater than 0.02 signifies an unacceptable level of salicylic acid.</p>



<h3 class="wp-block-heading" id="forensic-applications">Forensic Applications</h3>



<p>UV/Vis molecular absorption is routinely used for the analysis of narcotics and for drug testing. One interesting forensic application is the determination of blood alcohol using the Breathalyzer test. In this test a 52.5-mL breath sample is bubbled through an acidified solution of K<sub>2</sub>Cr<sub>2</sub>O<sub>7</sub>, which oxidizes ethanol to acetic acid. The concentration of ethanol in the breath sample is determined by the decrease in absorbance at 440 nm where the dichromate ion absorbs. A blood alcohol content of 0.10%, which is above the legal limit, corresponds to 0.025 mg of ethanol in the breath sample.</p>



<h3 class="wp-block-heading" id="developing-a-quantitative-method-for-a-single-component">Developing a Quantitative Method for a Single Component</h3>



<p>In developing a quantitative analytical method, the conditions under which Beer’s law is obeyed must be established. First, the most appropriate wavelength for the analysis is determined from an absorption spectrum. In most cases the best wavelength corresponds to an absorption maximum because it provides greater sensitivity and is less susceptible to instrumental limitations. Second, if an instrument with adjustable slits is being used, then an appropriate slit width needs to be chosen. The absorption spectrum also aids in selecting a slit width. Usually we set the slits to be as wide as possible because this increases the throughput of source radiation, while also being narrow enough to avoid instrumental limitations to Beer’s law. Finally, a calibration curve is constructed to determine the range of concentrations for which Beer’s law is valid. Additional considerations that are important in any quantitative method are the effect of potential interferents and establishing an appropriate blank.</p>



<p>Note</p>



<p>The best way to appreciate the theoretical and practical details discussed in this section is to carefully examine a typical analytical method. Although each method is unique, the following description of the determination of iron in water and wastewater provides an instructive example of a typical procedure. The description here is based on Method 3500- Fe B as published in&nbsp;<em>Standard Methods for the Examination of Water and Wastewater</em>, 20th Ed., American Public Health Association: Washington, D. C., 1998.</p>



<p>Representative Method 10.1</p>



<p><strong>Determination of Iron in Water and Wastewater</strong></p>



<p><em><strong>Description of Method</strong></em></p>



<p>Iron in the +2 oxidation state reacts with&nbsp;<em>o</em>-phenanthroline to form the orange-red Fe(phen)<sub>3</sub><sup>2+</sup>&nbsp;complex. The intensity of the complex’s color is independent of solution acidity between a pH of 3 and 9. Because the complex forms more rapidly at lower pH levels, the reaction is usually carried out within a pH range of 3.0–3.5. Any iron present in the +3 oxidation state is reduced with hydroxylamine before adding&nbsp;<em>o</em>-phenanthroline. The most important interferents are strong oxidizing agents, polyphosphates, and metal ions such as Cu<sup>2</sup><sup>+</sup>, Zn<sup>2</sup><sup>+</sup>, Ni<sup>2</sup><sup>+</sup>, and Cd<sup>2</sup><sup>+</sup>. An interference from oxidizing agents is minimized by adding an excess of hydroxylamine, and an interference from polyphosphate is minimized by boiling the sample in the presence of acid. The absorbance of samples and standards are measured at a wavelength of 510 nm using a 1-cm cell (longer pathlength cells also may be used). Beer’s law is obeyed for concentrations of within the range of 0.2–4.0 mg Fe/L.</p>



<p>(Figure 10.18 shows the visible spectrum for Fe(phen)<sub>3</sub><sup>2+</sup>.)</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12106/o-phenanthroline1.png?revision=1" alt="o-phenanthroline1.png"/></figure>



<p><em><strong>Procedure</strong></em></p>



<p>For samples containing less than 2 mg Fe/L, directly transfer a 50-mL portion to a 125-mL Erlenmeyer flask. Samples containing more than 2 mg Fe/L must be diluted before acquiring the 50-mL portion. Add 2 mL of concentrated HCl and 1 mL of hydroxylamine to the sample. Heat the solution to boiling and continue boiling until the solution’s volume is reduced to between 15 and 20 mL. After cooling to room temperature, transfer the solution to a 50-mL volumetric flask, add 10 mL of an ammonium acetate buffer, 2 mL of a 1000 ppm solution of&nbsp;<em>o</em>-phenanthroline, and dilute to volume. Allow 10–15 minutes for color development before measuring the absorbance, using distilled water to set 100% T. Calibration standards, including a blank, are prepared by the same procedure using a stock solution containing a known concentration of Fe<sup>2</sup><sup>+</sup>.</p>



<p><em><strong>Questions</strong></em></p>



<p>1. Explain why strong oxidizing agents are interferents, and why an excess of hydroxylamine prevents the interference.</p>



<p>A strong oxidizing agent oxidizes some Fe<sup>2</sup><sup>+</sup>&nbsp;to Fe<sup>3</sup><sup>+</sup>. Because Fe(phen)<sub>3</sub><sup>3+</sup>&nbsp;does not absorb as strongly as Fe(phen)<sub>3</sub><sup>2+</sup>, the absorbance decreases, producing a negative determinate error. The excess hydroxylamine reacts with the oxidizing agents, removing them from the solution.</p>



<p>2. The color of the complex is stable between pH levels of 3 and 9. What are some possible complications at more acidic or more basic pH’s?</p>



<p>Because&nbsp;<em>o</em>-phenanthroline is a weak base, its conditional formation constant for Fe(phen)<sub>3</sub><sup>2+</sup>&nbsp;is less favorable at more acidic pH levels, where&nbsp;<em>o</em>-phenanthroline is protonated. The result is a decrease in absorbance and a less sensitive analytical method.</p>



<p>(In&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/09_Titrimetric_Methods/9.3%3A_Complexation_Titrations" target="_blank" rel="noopener">Chapter 9</a>&nbsp;we saw the same effect of pH on the complexation reactions between EDTA and metal ions.)</p>



<p>When the pH is greater than 9, competition between OH<sup>–</sup>&nbsp;and&nbsp;<em>o</em>-phenanthroline for Fe<sup>2</sup><sup>+</sup>&nbsp;also decreased the absorbance. In addition, if the pH is sufficiently basic there is a risk that the iron will precipitate as Fe(OH)<sub>2</sub>.</p>



<p>3. Cadmium is an interferent because it forms a precipitate with&nbsp;<em>o</em>-phenanthroline. What effect would the formation of precipitate have on the determination of iron?</p>



<p>Because&nbsp;<em>o</em>-phenanthroline is present in large excess (2000 μg of&nbsp;<em>o</em>-phenanthroline for 100 μg of Fe<sup>2</sup><sup>+</sup>), it is not likely that the interference is due to an insufficient amount of&nbsp;<em>o</em>-phenanthroline being available to react with the Fe<sup>2</sup><sup>+</sup>. The presence of a precipitate in the sample cell results in the scattering of radiation, which causes an apparent increase in absorbance. Because the measured absorbance increases, the reported concentration is too high.</p>



<p>(Although scattering is a problem here, it can serve as the basis of a useful analytical method. See&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.8%3A_Spectroscopy_Based_on_Scattering" target="_blank" rel="noopener">Section 10.8</a>&nbsp;for further details.)</p>



<p>4. Even high quality ammonium acetate contains a significant amount of iron. Why is this source of iron not a problem?</p>



<p>Because all samples and standards are prepared using the same volume of ammonium acetate buffer, the contribution of this source of iron is accounted for by the calibration curve’s reagent blank.</p>



<h3 class="wp-block-heading" id="quantitative-analysis-for-a-single-analyte">Quantitative Analysis for a Single Analyte</h3>



<p>To determine the concentration of a an analyte we measure its absorbance and apply Beer’s law using any of the standardization methods described in Chapter 5. The most common methods are a normal calibration curve using external standards and the method of standard additions. A single point standardization is also possible, although we must first verify that Beer’s law holds for the concentration of analyte in the samples and the standard.</p>



<p>Example 10.5</p>



<p>The determination of Fe in an industrial waste stream was carried out by the&nbsp;<em>o</em>‑phenanthroline described in&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.3%3A_UV%2F%2FVis_and_IR_Spectroscopy#Representative_Method_10.1" target="_blank" rel="noopener">Representative Method 10.1</a>. Using the data in the following table, determine the mg Fe/L in the waste stream.</p>



<figure class="wp-block-table"><table><tbody><tr><td>mg Fe/L</td><td>absorbance</td></tr><tr><td>0.00</td><td>0.000</td></tr><tr><td>1.00</td><td>0.183</td></tr><tr><td>2.00</td><td>0.364</td></tr><tr><td>3.00</td><td>0.546</td></tr><tr><td>4.00</td><td>0.727</td></tr><tr><td>sample</td><td>0.269</td></tr></tbody></table></figure>



<p><strong><em>Solution</em></strong></p>



<p>Linear regression of absorbance versus the concentration of Fe in the standards gives a calibration curve with the following equation.A=0.0006+0.1817×(mgFe/L)(4.8.3)(4.8.3)A=0.0006+0.1817×(mgFe/L)</p>



<p>Substituting the sample’s absorbance into the calibration expression gives the concentration of Fe in the waste stream as 1.48 mg Fe/L.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12107/absorbance_vs_Fe.png?revision=1" alt="absorbance vs Fe.png"/></figure>



<p>Practice Exercise 10.5</p>



<p>The concentration of Cu<sup>2</sup><sup>+</sup>&nbsp;in a sample can be determined by reacting it with the ligand cuprizone and measuring its absorbance at 606 nm in a 1.00-cm cell. When a 5.00-mL sample is treated with cuprizone and diluted to 10.00 mL, the resulting solution has an absorbance of 0.118. A second 5.00-mL sample is mixed with 1.00 mL of a 20.00 mg/L standard of Cu<sup>2</sup><sup>+</sup>, treated with cuprizone and diluted to 10.00 mL, giving an absorbance of 0.162. Report the mg Cu<sup>2</sup><sup>+</sup>/L in the sample.</p>



<p>Click&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.E%3A_Spectroscopic_Methods_(Exercises)#Practice_Exercise_10.5" target="_blank" rel="noopener">here</a>&nbsp;to review your answer to this exercise.</p>



<h3 class="wp-block-heading" id="quantitative-analysis-of-mixtures">Quantitative Analysis of Mixtures</h3>



<p>Suppose we need to determine the concentration of two analytes, X and Y, in a sample. If each analyte has a wavelength where the other analyte does not absorb, then we can proceed using the approach in Example 10.5. Unfortunately, UV/Vis absorption bands are so broad that it frequently is not possible to find suitable wavelengths. Because Beer’s law is additive the mixture’s absorbance,&nbsp;<em>A</em><sub>mix</sub>, is(Amix)λ1=(εX)λ1bCX+(εY)λ1bCY(10.11)(10.11)(Amix)λ1=(εX)λ1bCX+(εY)λ1bCY</p>



<p>where&nbsp;λ1 is the wavelength at which we measure the absorbance. Because equation 10.11 includes terms for the concentration of both X and Y, the absorbance at one wavelength does not provide enough information to determine either&nbsp;<em>C</em><sub>X</sub>&nbsp;or&nbsp;<em>C</em><sub>Y</sub>. If we measure the absorbance at a second wavelength(Amix)λ2=(εX)λ2bCX+(εY)λ2bCY(10.12)(10.12)(Amix)λ2=(εX)λ2bCX+(εY)λ2bCY</p>



<p>then&nbsp;<em>C</em><sub>X</sub>&nbsp;and&nbsp;<em>C</em><sub>Y</sub>&nbsp;can be determined by solving simultaneously equation10.11 and equation 10.12. Of course, we also must determine the value for ε<sub>X</sub>&nbsp;and ε<sub>Y</sub>&nbsp;at each wavelength. For a mixture of&nbsp;<em>n</em>&nbsp;components, we must measure the absorbance at&nbsp;<em>n</em>&nbsp;different wavelengths.</p>



<p>Example 10.6</p>



<p>The concentrations of Fe<sup>3</sup><sup>+</sup>&nbsp;and Cu<sup>2</sup><sup>+</sup>&nbsp;in a mixture can be determined following their reaction with hexacyanoruthenate (II), Ru(CN)<sub>6</sub><sup>4–</sup>, which forms a purple-blue complex with Fe<sup>3</sup><sup>+</sup>&nbsp;(λ<sub>max</sub>&nbsp;= 550 nm) and a pale-green complex with Cu<sup>2</sup><sup>+</sup>&nbsp;(λ<sub>max</sub>&nbsp;= 396 nm).<sup>7</sup>&nbsp;The molar absorptivities (M<sup>–1</sup>&nbsp;cm<sup>–1</sup>) for the metal complexes at the two wavelengths are summarized in the following table.</p>



<figure class="wp-block-table"><table><tbody><tr><td></td><td>ε<sub>550</sub></td><td>ε<sub>396</sub></td></tr><tr><td>Fe<sup>3</sup><sup>+</sup></td><td>9970</td><td>84</td></tr><tr><td>Cu<sup>2</sup><sup>+</sup></td><td>34</td><td>856</td></tr></tbody></table></figure>



<p>When a sample containing Fe<sup>3</sup><sup>+</sup>&nbsp;and Cu<sup>2</sup><sup>+</sup>&nbsp;is analyzed in a cell with a pathlength of 1.00 cm, the absorbance at 550 nm is 0.183 and the absorbance at 396 nm is 0.109. What are the molar concentrations of Fe<sup>3</sup><sup>+</sup>&nbsp;and Cu<sup>2</sup><sup>+</sup>&nbsp;in the sample?</p>



<p><strong><em>Solution</em></strong></p>



<p>Substituting known values into equations 10.11 and 10.12 givesA550=0.183=9970CFe+34CCu(4.8.4)(4.8.4)A550=0.183=9970CFe+34CCuA396=0.109=84CFe+856CCu(4.8.5)(4.8.5)A396=0.109=84CFe+856CCu</p>



<p>To determine&nbsp;<em>C</em><sub>Fe</sub>&nbsp;and&nbsp;<em>C</em><sub>Cu</sub>&nbsp;we solve the first equation for&nbsp;<em>C</em><sub>Cu</sub>CCu=0.183–9970CFe34(4.8.6)(4.8.6)CCu=0.183–9970CFe34</p>



<p>and substitute the result into the second equation.0.109=84CFe+856×0.183−9970CFe34=4.607–(2.51×105)CFe(4.8.7)(4.8.7)0.109=84CFe+856×0.183−9970CFe34=4.607–(2.51×105)CFe</p>



<p>Solving for&nbsp;<em>C</em><sub>Fe</sub>&nbsp;gives the concentration of Fe<sup>3+</sup>&nbsp;as 1.79 × 10<sup>–5</sup>&nbsp;M. Substituting this concentration back into the equation for the mixture’s absorbance at 396 nm gives the concentration of Cu<sup>2</sup><sup>+</sup>&nbsp;as 1.26 × 10<sup>–4</sup>&nbsp;M.</p>



<p>(Another approach is to multiply the first equation by 856/34 giving4.607=251009CFe+856CCu(4.8.8)(4.8.8)4.607=251009CFe+856CCu</p>



<p>Subtracting the second equation from this equation4.607=251009CFe+856CCu−0.109=84CFe+856CCu–––––––––––––––––––––––––––––––4.498=250925CFe(4.8.9)(4.8.10)(4.8.11)(4.8.9)−4.607=251009CFe+856CCu(4.8.10)−0.109=84CFe+856CCu6CCu_(4.8.11)−4.498=250925CFe</p>



<p>we find that&nbsp;<em>C</em><sub>Fe</sub>&nbsp;is 1.79×10<sup>–5</sup>. Having determined&nbsp;<em>C</em><sub>Fe</sub>&nbsp;we can substitute back into one of the other equations to solve for&nbsp;<em>C</em><sub>Cu</sub>, which is 1.26×10<sup>–5</sup>.)</p>



<p>Practice Exercise 10.6</p>



<p>The absorbance spectra for Cr<sup>3</sup><sup>+</sup>&nbsp;and Co<sup>2</sup><sup>+</sup>&nbsp;overlap significantly. To determine the concentration of these analytes in a mixture, its absorbance was measured at 400 nm and at 505 nm, yielding values of 0.336 and 0.187, respectively. The individual molar absorptivities (M<sup>–1</sup>&nbsp;cm<sup>–1</sup>) are</p>



<figure class="wp-block-table"><table><tbody><tr><td></td><td>ε<sub>400</sub></td><td>ε<sub>505</sub></td></tr><tr><td>Cr<sup>3</sup><sup>+</sup></td><td>15.2</td><td>0.533</td></tr><tr><td>Co<sup>2</sup><sup>+</sup></td><td>5.60</td><td>5.07</td></tr></tbody></table></figure>



<p>Click&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.E%3A_Spectroscopic_Methods_(Exercises)#Practice_Exercise_10.6" target="_blank" rel="noopener">here</a>&nbsp;to review your answer to this exercise.</p>



<p>To obtain results with good accuracy and precision the two wavelengths should be selected so that ε<sub>X</sub>&nbsp;&gt; ε<sub>Y</sub>&nbsp;at one wavelength and ε<sub>X</sub>&nbsp;&lt; ε<sub>Y</sub>&nbsp;at the other wavelength. It is easy to appreciate why this is true. Because the absorbance at each wavelength is dominated by one analyte, any uncertainty in the concentration of the other analyte has less of an impact. Figure 10.35 shows that the choice of wavelengths for Practice Exercise 10.6 are reasonable. When the choice of wavelengths is not obvious, one method for locating the optimum wavelengths is to plot ε<sub>X</sub>/ε<sub>Y</sub>&nbsp;as function of wavelength, and determine the wavelengths where ε<sub>X</sub>/ε<sub>Y</sub>&nbsp;reaches maximum and minimum values.<sup>8</sup></p>



<p>Note</p>



<p>For example, in Example 10.6 the molar absorptivity for Fe<sup>3</sup><sup>+</sup>&nbsp;at 550 nm is 119× that for Cu<sup>2</sup><sup>+</sup>, and the molar absorptivity for Cu<sup>2+</sup>&nbsp;at 396 nm is 10.2× that for Fe<sup>3</sup><sup>+</sup>.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12715/Figure10.35.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12715/Figure10.35.jpg?revision=1&amp;size=bestfit&amp;width=450&amp;height=394" alt="Figure10.35.jpg"/></a></figure>



<p><strong>Figure 10.35</strong>&nbsp;Visible absorption spectra for 0.0250 M Cr<sup>3</sup><sup>+</sup>, 0.0750 M Co<sup>2</sup><sup>+</sup>, and for a mixture of Cr<sup>3</sup><sup>+</sup>&nbsp;and Co<sup>2</sup><sup>+</sup>. The two wavelengths used for analyzing the mixture of Cr<sup>3+</sup>&nbsp;and Co<sup>2</sup><sup>+</sup>&nbsp;are shown by the dashed lines. The data for the two standard solutions are from reference 7.</p>



<p>When the analyte’s spectra overlap severely, such that ε<sub>X</sub>&nbsp;≈ ε<sub>Y</sub>&nbsp;at all wavelength, other computational methods may provide better accuracy and precision. In a multiwavelength linear regression analysis, for example, a mixture’s absorbance is compared to that for a set of standard solutions at several wavelengths.<sup>9</sup>&nbsp;If&nbsp;<em>A</em><sub>SX</sub>and&nbsp;<em>A</em><sub>SY</sub>&nbsp;are the absorbance values for standard solutions of components X and Y at any wavelength, thenASX=εXbCSX(10.13)(10.13)ASX=εXbCSXASY=εYbCSY(10.14)(10.14)ASY=εYbCSY</p>



<p>where&nbsp;<em>C</em><sub>SX</sub>&nbsp;and&nbsp;<em>C</em><sub>SY</sub>&nbsp;are the known concentrations of X and Y in the standard solutions. Solving equation 10.13 and equation 10.14 for ε<sub>X</sub>&nbsp;and ε<sub>Y</sub>, substituting into equation 10.11, and rearranging, givesAmixASX=CXCSX+CYCSY×ASYASX(4.8.12)(4.8.12)AmixASX=CXCSX+CYCSY×ASYASX</p>



<p>To determine&nbsp;<em>C</em><sub>X</sub>&nbsp;and&nbsp;<em>C</em><sub>Y</sub>&nbsp;the mixture’s absorbance and the absorbances of the standard solutions are measured at several wavelengths. Graphing&nbsp;<em>A</em><sub>mix</sub>/<em>A</em><sub>SX</sub>&nbsp;versus&nbsp;<em>A</em><sub>SY</sub>/<em>A</em><sub>SX</sub>&nbsp;gives a straight line with a slope of&nbsp;<em>C</em><sub>Y</sub>/<em>C</em><sub>SY</sub>&nbsp;and a&nbsp;<em>y</em>-intercept of&nbsp;<em>C</em><sub>X</sub>/<em>C</em><sub>SX</sub>. This approach is particularly helpful when it is not possible to find wavelengths where ε<sub>X</sub>&nbsp;&gt; ε<sub>Y</sub>&nbsp;and ε<sub>X</sub>&nbsp;&lt; ε<sub>Y</sub>.</p>



<p>Note</p>



<p>The approach outlined here for a multiwavelength linear regression uses a single standard solution for each analyte. A more rigorous approach uses multiple standards for each analyte. The math behind the analysis of this data—what we call a multiple linear regression—is beyond the level of this text. For more details about multiple linear regression see Brereton, R. G.&nbsp;<em>Chemometrics: Data Analysis for the Laboratory and Chemical Plant</em>, Wiley: Chichester, England, 2003.</p>



<p>Example 10.7</p>



<p>Figure 10.35 shows visible absorbance spectra for a standard solution of 0.0250 M Cr<sup>3</sup><sup>+</sup>, a standard solution of 0.0750 M Co<sup>2+</sup>, and a mixture containing unknown concentrations of each ion. The data for these spectra are shown here.<sup>10</sup></p>



<figure class="wp-block-table"><table><tbody><tr><td>λ&nbsp;(nm)</td><td><em>A</em><sub>Cr</sub></td><td><em>A</em><sub>Co</sub></td><td><em>A</em><sub>mix</sub></td><td>λ&nbsp;(nm)</td><td><em>A</em><sub>Cr</sub></td><td><em>A</em><sub>Co</sub></td><td><em>A</em><sub>mix</sub></td></tr><tr><td>375</td><td>0.26</td><td>0.01</td><td>0.53</td><td>520</td><td>0.19</td><td>0.38</td><td>0.63</td></tr><tr><td>400</td><td>0.43</td><td>0.03</td><td>0.88</td><td>530</td><td>0.24</td><td>0.33</td><td>0.70</td></tr><tr><td>425</td><td>0.39</td><td>0.07</td><td>0.83</td><td>540</td><td>0.28</td><td>0.26</td><td>0.73</td></tr><tr><td>440</td><td>0.29</td><td>0.13</td><td>0.67</td><td>550</td><td>0.32</td><td>0.18</td><td>0.76</td></tr><tr><td>455</td><td>0.20</td><td>0.21</td><td>0.54</td><td>570</td><td>0.38</td><td>0.08</td><td>0.81</td></tr><tr><td>470</td><td>0.14</td><td>0.28</td><td>0.47</td><td>575</td><td>0.39</td><td>0.06</td><td>0.82</td></tr><tr><td>480</td><td>0.12</td><td>0.30</td><td>0.44</td><td>580</td><td>0.38</td><td>0.05</td><td>0.79</td></tr><tr><td>490</td><td>0.11</td><td>0.34</td><td>0.45</td><td>600</td><td>0.34</td><td>0.03</td><td>0.70</td></tr><tr><td>500</td><td>0.13</td><td>0.38</td><td>0.51</td><td>625</td><td>0.24</td><td>0.02</td><td>0.49</td></tr></tbody></table></figure>



<p>Use a multiwavelength regression analysis to determine the composition of the unknown.</p>



<p><em><strong>Solution</strong></em></p>



<p>First we need to calculate values for&nbsp;<em>A</em><sub>mix</sub>/<em>A</em><sub>SX</sub>&nbsp;and for&nbsp;<em>A</em><sub>SY</sub>/<em>A</em><sub>SX</sub>. Let’s define X as Co<sup>2</sup><sup>+</sup>&nbsp;and Y as Cr<sup>3</sup><sup>+</sup>. For example, at a wavelength of 375 nm&nbsp;<em>A</em><sub>mix</sub>/<em>A</em><sub>SX</sub>&nbsp;is 0.53/0.01, or 53 and&nbsp;<em>A</em><sub>SY</sub>/<em>A</em><sub>SX</sub>&nbsp;is 0.26/0.01, or 26. Completing the calculation for all wavelengths and graphing&nbsp;<em>A</em><sub>mix</sub>/<em>A</em><sub>SX</sub>&nbsp;versus&nbsp;<em>A</em><sub>SY</sub>/<em>A</em><sub>SX</sub>gives the result shown in Figure 10.36. Fitting a straight-line to the data gives a regression model ofAmixASX=0.636+2.01×ASYASX(4.8.13)(4.8.13)AmixASX=0.636+2.01×ASYASX</p>



<p>Using the&nbsp;<em>y</em>-intercept, the concentration of Co<sup>2</sup><sup>+</sup>&nbsp;isCXCSX=CCo0.0750M=0.636(4.8.14)(4.8.14)CXCSX=CCo0.0750M=0.636</p>



<p>or&nbsp;<em>C</em><sub>Co</sub>&nbsp;= 0.048 M, and using the slope the concentration of Cr<sup>3+</sup>&nbsp;isCYCSY=CCr0.0250M=2.01(4.8.15)(4.8.15)CYCSY=CCr0.0250M=2.01</p>



<p>or&nbsp;<em>C</em><sub>Cr</sub>&nbsp;= 0.050 M.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12716/Figure10.36.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12716/Figure10.36.jpg?revision=1&amp;size=bestfit&amp;width=330&amp;height=286" alt="Figure10.36.jpg"/></a></figure>



<p><strong>Figure 10.36</strong>&nbsp;Multiwavelength linear regression analysis for the data in Example 10.7.</p>



<p>Practice Exercise 10.7</p>



<p>A mixture of MnO<sub>4</sub><sup>–</sup>&nbsp;and Cr<sub>2</sub>O<sub>7</sub><sup>2–</sup>, and standards of 0.10 mM KMnO<sub>4</sub>&nbsp;and of 0.10 mM K<sub>2</sub>Cr<sub>2</sub>O<sub>7</sub>&nbsp;gives the results shown in the following table. Determine the composition of the mixture. The data for this problem is from Blanco, M. C.; Iturriaga, H.; Maspoch, S.; Tarin, P.&nbsp;<em>J. Chem. Educ.&nbsp;</em><strong>1989</strong>,&nbsp;<em>66</em>, 178–180.</p>



<figure class="wp-block-table"><table><tbody><tr><td>λ&nbsp;(nm)</td><td><em>A</em><sub>Mn</sub></td><td><em>A</em><sub>Cr</sub></td><td><em>A</em><sub>mix</sub></td></tr><tr><td>266</td><td>0.042</td><td>0.410</td><td>0.766</td></tr><tr><td>288</td><td>0.082</td><td>0.283</td><td>0.571</td></tr><tr><td>320</td><td>0.168</td><td>0.158</td><td>0.422</td></tr><tr><td>350</td><td>0.125</td><td>0.318</td><td>0.672</td></tr><tr><td>360</td><td>0.056</td><td>0.181</td><td>0.366</td></tr></tbody></table></figure>



<p>(There are many additional ways to analyze mixtures spectrophotometrically, including generalized standard additions, H-point standard additions, principal component regression to name a few. Consult the chapter’s&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/Additional_Resources#Chapter_10" target="_blank" rel="noopener">additional resources</a>&nbsp;for further information.)</p>



<p>Click&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.E%3A_Spectroscopic_Methods_(Exercises)#Practice_Exercise_10.7" target="_blank" rel="noopener">here</a>&nbsp;to review your answer to this exercise.</p>



<h2 class="wp-block-heading" id="10-3-3-qualitative-applications">10.3.3 Qualitative Applications</h2>



<p>As discussed earlier in&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.2%3A_Spectroscopy_Based_on_Absorption#10.2.1_Absorbance_Spectra" target="_blank" rel="noopener">Section 10.2.1</a>, ultraviolet, visible, and infrared absorption bands result from the absorption of electromagnetic radiation by specific valence electrons or bonds. The energy at which the absorption occurs, and its intensity is determined by the chemical environment of the absorbing moiety. For example, benzene has several ultraviolet absorption bands due to π → π* transitions. The position and intensity of two of these bands, 203.5 nm (ε = 7400 M<sup>–1</sup>&nbsp;cm<sup>–1</sup>) and 254 nm (ε = 204 M<sup>–1</sup>&nbsp;cm<sup>–1</sup>), are sensitive to substitution. For benzoic acid, in which a carboxylic acid group replaces one of the aromatic hydrogens, the two bands shift to 230 nm (ε = 11 600 M<sup>–1</sup>&nbsp;cm<sup>–1</sup>) and 273 nm (ε = 970 M<sup>–1</sup>&nbsp;cm<sup>–1</sup>). A variety of rules have been developed to aid in correlating UV/Vis absorption bands to chemical structure. Similar correlations have been developed for infrared absorption bands. For example a carbonyl’s C=O stretch is sensitive to adjacent functional groups, occurring at 1650 cm<sup>–1</sup>&nbsp;for acids, 1700 cm<sup>–1</sup>&nbsp;for ketones, and 1800 cm<sup>–1</sup>&nbsp;for acid chlorides. The interpretation of UV/Vis and IR spectra receives adequate coverage elsewhere in the chemistry curriculum, notably in organic chemistry, and is not considered further in this text.</p>



<p>With the availability of computerized data acquisition and storage it is possible to build digital libraries of standard reference spectra. The identity of an a unknown compound can often be determined by comparing its spectrum against a library of reference spectra, a process is known as&nbsp;<strong>spectral searching</strong>. Comparisons are made using an algorithm that calculates the cumulative difference between the sample’s spectrum and a reference spectrum. For example, one simple algorithm uses the following equationD=∑i=1n|(Asample)i−(Areference)i|(4.8.16)(4.8.16)D=∑i=1n|(Asample)i−(Areference)i|</p>



<p>where&nbsp;<em>D</em>&nbsp;is the cumulative difference,&nbsp;<em>A</em><sub>sample</sub>&nbsp;is the sample’s absorbance at wavelength or wavenumber&nbsp;<em>i</em>,&nbsp;<em>A</em><sub>reference</sub>&nbsp;is the absorbance of the reference compound at the same wavelength or wavenumber, and&nbsp;<em>n</em>&nbsp;is the number of digitized points in the spectra. The cumulative difference is calculated for each reference spectrum. The reference compound with the smallest value of&nbsp;<em>D</em>&nbsp;provides the closest match to the unknown compound. The accuracy of spectral searching is limited by the number and type of compounds included in the library, and by the effect of the sample’s matrix on the spectrum.</p>



<p>Another advantage of computerized data acquisition is the ability to subtract one spectrum from another. When coupled with spectral searching it may be possible, by repeatedly searching and subtracting reference spectra, to determine the identity of several components in a sample without the need of a prior separation step. An example is shown in Figure 10.37 in which the composition of a two-component mixture is determined by successive searching and subtraction. Figure 10.37a shows the spectrum of the mixture. A search of the spectral library selects cocaine&nbsp;<sup>.</sup>&nbsp;HCl (Figure 10.37b) as a likely component of the mixture. Subtracting the reference spectrum for cocaine&nbsp;<sup>.&nbsp;</sup>HCl from the mixture’s spectrum leaves a result (Figure 10.37c) that closely matches mannitol’s reference spectrum (Figure 10.37d). Subtracting the reference spectrum for leaves only a small residual signal (Figure 10.37e).</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12717/Figure10.37.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12717/Figure10.37.jpg?revision=1&amp;size=bestfit&amp;width=600&amp;height=838" alt="Figure10.37.jpg"/></a></figure>



<p><strong>Figure 10.37</strong>&nbsp;Identifying the components of a mixture by spectral searching and subtracting. (a) IR spectrum of the mixture; (b) Reference IR spectrum of cocaine<sup>.</sup>&nbsp;HCl; (c) Result of subtracting the spectrum of cocaine&nbsp;<sup>.</sup>&nbsp;HCl from the mixture’s spectrum; (d) Reference IR spectrum of mannitol; and (e) The residual spectrum after removing mannitol’s contribution to the mixture’s spectrum.</p>



<p>Note</p>



<p>IR spectra traditionally are displayed using percent transmittance, %T, along the<em>&nbsp;y</em>-axis (for example, see Figure 10.16). Because absorbance—not percent transmittance—is a linear function of concentration, spectral searching and spectral subtraction, is easier to do when displaying absorbance on the&nbsp;<em>y</em>-axis.</p>



<h2 class="wp-block-heading" id="10-3-4-characterization-applications">10.3.4 Characterization Applications</h2>



<p>Molecular absorption, particularly in the UV/Vis range, has been used for a variety of different characterization studies, including determining the stoichiometry of metal–ligand complexes and determining equilibrium constants. Both of these examples are examined in this section.</p>



<h3 class="wp-block-heading" id="stoichiometry-of-a-metal-ligand-complex">Stoichiometry of a Metal-Ligand Complex</h3>



<p>We can determine the stoichiometry of a metal–ligand complexation reactionM+yL⇋MLy(4.8.17)(4.8.17)M+yL⇋MLy</p>



<p>using one of three methods: the method of continuous variations, the mole-ratio method, and the slope-ratio method. Of these approaches, the&nbsp;<strong>method of continuous variations</strong>, also called Job’s method, is the most popular. In this method a series of solutions is prepared such that the total moles of metal and ligand,&nbsp;<em>n</em><sub>total</sub>, in each solution is the same. If (<em>n</em><sub>M</sub>)<sub><em>i</em></sub>&nbsp;and (<em>n</em><sub>L</sub>)<sub><em>i</em></sub>&nbsp;are, respectively, the moles of metal and ligand in solution&nbsp;<em>i</em>, thenntotal=(nM)i+(nL)i(4.8.18)(4.8.18)ntotal=(nM)i+(nL)i</p>



<p>The relative amount of ligand and metal in each solution is expressed as the mole fraction of ligand, (<em>X</em><sub>L</sub>)<sub><em>i</em></sub>, and the mole fraction of metal, (<em>X</em><sub>M</sub>)<sub><em>i</em></sub>,(XL)i=(nL)intotal(4.8.19)(4.8.19)(XL)i=(nL)intotal(XM)i=1−(nL)intotal=(nM)intotal(4.8.20)(4.8.20)(XM)i=1−(nL)intotal=(nM)intotal</p>



<p>The concentration of the metal–ligand complex in any solution is determined by the limiting reagent, with the greatest concentration occurring when the metal and the ligand are mixed stoichiometrically. If we monitor the complexation reaction at a wavelength where only the metal–ligand complex absorbs, a graph of absorbance versus the mole fraction of ligand will have two linear branches—one when the ligand is the limiting reagent and a second when the metal is the limiting reagent. The intersection of these two branches represents a stoichiometric mixing of the metal and the ligand. We can use the mole fraction of ligand at the intersection to determine the value of&nbsp;<em>y</em>&nbsp;for the metal–ligand complex ML<sub><em>y</em></sub>.y=nLnM=XLXM=XL1−XL(4.8.21)(4.8.21)y=nLnM=XLXM=XL1−XL</p>



<p>Note</p>



<p>You also can plot the data as absorbance versus the mole fraction of metal. In this case, y is equal to (1–<em>X</em><sub>M</sub>)/<em>X</em><sub>M</sub>.</p>



<figure class="wp-block-image size-large"><img decoding="async" src="http://s7.picofile.com/file/8392387600/uv_vis_in.gif" alt=""/></figure>



<p>Example 10.8</p>



<p>To determine the formula for the complex between Fe<sup>2+</sup>&nbsp;and&nbsp;<em>o</em>-phenanthroline, a series of solutions is prepared in which the total concentration of metal and ligand is held constant at 3.15 × 10<sup>–4</sup>&nbsp;M. The absorbance of each solution is measured at a wavelength of 510 nm. Using the following data, determine the formula for the complex.</p>



<figure class="wp-block-table"><table><tbody><tr><td><em>X</em><sub>L</sub></td><td>absorbance</td><td><em>X</em><sub>L</sub></td><td>absorbance</td></tr><tr><td>0.000</td><td>0.000</td><td>0.600</td><td>0.693</td></tr><tr><td>0.100</td><td>0.116</td><td>0.700</td><td>0.809</td></tr><tr><td>0.200</td><td>0.231</td><td>0.800</td><td>0.693</td></tr><tr><td>0.300</td><td>0.347</td><td>0.900</td><td>0.347</td></tr><tr><td>0.400</td><td>0.462</td><td>1.000</td><td>0.000</td></tr><tr><td>0.500</td><td>0.578</td><td></td><td></td></tr></tbody></table></figure>



<p>(To prepare the solutions for this example I first prepared a solution of 3.15 × 10<sup>-4</sup>&nbsp;M Fe<sup>2</sup><sup>+</sup>&nbsp;and a solution of 3.15 × 10<sup>-4</sup>&nbsp;M&nbsp;<em>o</em>-phenanthroline. Because the two stock solutions are of equal concentration, diluting a portion of one solution with the other solution gives a mixture in which the combined concentration of&nbsp;<em>o</em>-phenanthroline and Fe<sup>2</sup><sup>+</sup>&nbsp;is 3.15 × 10<sup>-4</sup>&nbsp;M. If each solution has the same volume, then each solution contains the same total moles of metal and ligand.)</p>



<p><strong><em>Solution</em></strong></p>



<p>A plot of absorbance versus the mole fraction of ligand is shown in Figure 10.38. To find the maximum absorbance, we extrapolate the two linear portions of the plot. The two lines intersect at a mole fraction of ligand of 0.75. Solving for&nbsp;<em>y</em>&nbsp;givesy=XL1–XL=0.751–0.75=3(4.8.22)(4.8.22)y=XL1–XL=0.751–0.75=3</p>



<p>The formula for the metal–ligand complex is Fe(<em>o</em>-phenanthroline)<sub>3</sub><sup>2+</sup>.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12718/Figure10.38.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12718/Figure10.38.jpg?revision=1&amp;size=bestfit&amp;width=600&amp;height=565" alt="Figure10.38.jpg"/></a></figure>



<p><strong>Figure 10.38&nbsp;</strong>Continuous variations plot for Example 10.8. The photo shows the solutions used in gathering the data. Each solution is displayed directly below its corresponding point on the continuous variations plot.</p>



<p>Practice Exercise 10.8</p>



<p>Use the continuous variations data in the following table to determine the formula for the complex between Fe<sup>2</sup><sup>+</sup>&nbsp;and SCN<sup>–</sup>. The data for this problem is adapted from Meloun, M.; Havel, J.; Högfeldt, E.&nbsp;<em>Computation of Solution Equilibria</em>, Ellis Horwood: Chichester, England, 1988, p. 236.</p>



<figure class="wp-block-table"><table><tbody><tr><td><em>X</em><sub>L</sub></td><td>absorbance</td><td><em>X</em><sub>L</sub></td><td>absorbance</td><td><em>X</em><sub>L</sub></td><td>absorbance</td><td><em>X</em><sub>L</sub></td><td>absorbance</td></tr><tr><td>0.0200</td><td>0.068</td><td>0.2951</td><td>0.670</td><td>0.5811</td><td>0.790</td><td>0.8923</td><td>0.325</td></tr><tr><td>0.0870</td><td>0.262</td><td>0.3887</td><td>0.767</td><td>0.6860</td><td>0.701</td><td>0.9787</td><td>0.071</td></tr><tr><td>0.1792</td><td>0.471</td><td>0.4964</td><td>0.807</td><td>0.7885</td><td>0.540</td><td></td><td></td></tr></tbody></table></figure>



<p>Click&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.E%3A_Spectroscopic_Methods_(Exercises)#Practice_Exercise_10.8" target="_blank" rel="noopener">here</a>&nbsp;to review your answer to this exercise.</p>



<p>Several precautions are necessary when using the method of continuous variations. First, the metal and the ligand must form only one metal–ligand complex. To determine if this condition is true, plots of absorbance versus&nbsp;<em>X</em><sub>L</sub>&nbsp;are constructed at several different wavelengths and for several different values of&nbsp;<em>n</em><sub>total</sub>. If the maximum absorbance does not occur at the same value of&nbsp;<em>X</em><sub>L</sub>&nbsp;for each set of conditions, then more than one metal–ligand complex must be present. A second precaution is that the metal–ligand complex’s absorbance must obey Beer’s law. Third, if the metal–ligand complex’s formation constant is relatively small, a plot of absorbance versus&nbsp;<em>X</em><sub>L</sub>&nbsp;may show significant curvature. In this case it is often difficult to determine the stoichiometry by extrapolation. Finally, because the stability of a metal–ligand complex may be influenced by solution conditions, the composition of the solutions must be carefully controlled. When the ligand is a weak base, for example, the solutions must be buffered to the same pH.</p>



<p>In the&nbsp;<strong>mole-ratio method</strong>&nbsp;the amount of one reactant, usually the moles of metal, is held constant, while the amount of the other reactant is varied. The absorbance is monitored at a wavelength where the metal–ligand complex absorbs. A plot of absorbance as a function of the ligand-to-metal mole ratio,&nbsp;<em>n</em><sub>L</sub>/<em>n</em><sub>M</sub>, has two linear branches, which intersect at a mole–ratio corresponding to the complex’s formula. Figure 10.39a shows a mole-ratio plot for the formation of a 1:1 complex in which the absorbance is monitored at a wavelength where only the complex absorbs. Figure 10.39b shows a mole-ratio plot for a 1:2 complex in which all three species—the metal, the ligand, and the complex—absorb at the selected wavelength. Unlike the method of continuous variations, the mole-ratio method can be used for complexation reactions that occur in a stepwise fashion if there is a difference in the molar absorptivities of the metal–ligand complexes, and if the formation constants are sufficiently different. A typical mole-ratio plot for the step-wise formation of ML and ML<sub>2</sub>&nbsp;is shown in Figure 10.39c.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12719/Figure10.39.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12719/Figure10.39.jpg?revision=1&amp;size=bestfit&amp;width=700&amp;height=202" alt="Figure10.39.jpg"/></a></figure>



<p><strong>Figure 10.39</strong>&nbsp;Mole-ratio plots for: (a) a 1:1 metal–ligand complex in which only the complex absorbs; (b) a 1:2 metal–ligand complex in which the metal, the ligand, and the complex absorb; and (c) the stepwise formation of a 1:1 and a 1:2 metal–ligand complex.</p>



<p>In both the method of continuous variations and the mole-ratio method we determine the complex’s stoichiometry by extrapolating absorbance data from conditions in which there is a linear relationship between absorbance and the relative amounts of metal and ligand. If a metal–ligand complex is very weak, a plot of absorbance versus<em>&nbsp;X</em><sub>L</sub>&nbsp;or&nbsp;<em>n</em><sub>L</sub>/<em>n</em><sub>M</sub>&nbsp;may be so curved that it is impossible to determine the stoichiometry by extrapolation. In this case the slope-ratio may be used.</p>



<p>In the&nbsp;<strong>slope-ratio method</strong>&nbsp;two sets of solutions are prepared. The first set of solutions contains a constant amount of metal and a variable amount of ligand, chosen such that the total concentration of metal,&nbsp;<em>C</em><sub>M</sub>, is much larger than the total concentration of ligand,&nbsp;<em>C</em><sub>L</sub>. Under these conditions we may assume that essentially all the ligand reacts in forming the metal–ligand complex. The concentration of the complex, which has the general form M<sub><em>x</em></sub>L<sub><em>y</em></sub>, is[MxLy]=CLy(4.8.23)(4.8.23)[MxLy]=CLy</p>



<p>If we monitor the absorbance at a wavelength where only M<sub><em>x</em></sub>L<sub><em>y</em></sub>&nbsp;absorbs, thenA=εb[MxLy]=εbCLy(4.8.24)(4.8.24)A=εb[MxLy]=εbCLy</p>



<p>and a plot of absorbance versus&nbsp;<em>C</em><sub>L</sub>&nbsp;is linear with a slope,&nbsp;<em>s</em><sub>L</sub>, ofsL=εby(4.8.25)(4.8.25)sL=εby</p>



<p>A second set of solutions is prepared with a fixed concentration of ligand that is much greater than a variable concentration of metal; thus[MxLy]=CMx(4.8.26)(4.8.26)[MxLy]=CMxA=εb[MxLy]=εbCMx(4.8.27)(4.8.27)A=εb[MxLy]=εbCMxsM=εbx(4.8.28)(4.8.28)sM=εbx</p>



<p>A ratio of the slopes provides the relative values of&nbsp;<em>x</em>&nbsp;and&nbsp;<em>y</em>.sMsL=εb/xεb/y=yx(4.8.29)(4.8.29)sMsL=εb/xεb/y=yx</p>



<p>An important assumption in the slope-ratio method is that the complexation reaction continues to completion in the presence of a sufficiently large excess of metal or ligand. The slope-ratio method also is limited to systems in which only a single complex is formed and for which Beer’s law is obeyed.</p>



<h3 class="wp-block-heading" id="determination-of-equilibrium-constants">Determination of Equilibrium Constants</h3>



<p>Another important application of molecular absorption spectroscopy is the determination of equilibrium constants. Let’s consider, as a simple example, an acid–base reaction of the general formHIn(aq)+H2O(l)⇋H3O+(aq)+In−(aq)(4.8.30)(4.8.30)HIn(aq)+H2O(l)⇋H3O+(aq)+In−(aq)</p>



<p>where HIn and In<sup>–</sup>&nbsp;are the conjugate weak acid and weak base forms of an acid–base indicator. The equilibrium constant for this reaction isKa=[H3O+][In−][HIn](4.8.31)(4.8.31)Ka=[H3O+][In−][HIn]</p>



<p>To determine the equilibrium constant’s value, we prepare a solution in which the reaction is in a state of equilibrium and determine the equilibrium concentration of H<sub>3</sub>O<sup>+</sup>, HIn, and In<sup>–</sup>. The concentration of H<sub>3</sub>O<sup>+</sup>&nbsp;is easy to determine by simply measuring the solution’s pH. To determine the concentration of HIn and In<sup>–</sup>&nbsp;we can measure the solution’s absorbance.</p>



<p>If both HIn and In<sup>–</sup>&nbsp;absorb at the selected wavelength, then, from equation 10.6, we know thatA=εHInb[HIn]+εInb[In−](10.15)(10.15)A=εHInb[HIn]+εInb[In−]</p>



<p>where ε<sub>HIn</sub>&nbsp;and ε<sub>In</sub>&nbsp;are the molar absorptivities for HIn and In<sup>–</sup>. The total concentration of indicator,&nbsp;<em>C</em>, is given by a mass balance equationC=[HIn]+[In−](10.16)(10.16)C=[HIn]+[In−]</p>



<p>Solving equation 10.16 for [HIn] and substituting into equation 10.15 givesA=εHInb(C−[In−])+εInb[In−](4.8.32)(4.8.32)A=εHInb(C−[In−])+εInb[In−]</p>



<p>which we simplify toA=εHInbC−εHInb[In−]+εInb[In−](4.8.33)(4.8.33)A=εHInbC−εHInb[In−]+εInb[In−]A=AHIn+b[In−](εIn−εHIn)(10.17)(10.17)A=AHIn+b[In−](εIn−εHIn)</p>



<p>where&nbsp;<em>A</em><sub>HIn</sub>, which is equal to ε<sub>HIn</sub><em>bC</em>, is the absorbance when the pH is acidic enough that essentially all the indicator is present as HIn. Solving equation 10.17 for the concentration of In<sup>–</sup>&nbsp;gives[In−]=A−AHInb(εIn−εHIn)(10.18)(10.18)[In−]=A−AHInb(εIn−εHIn)</p>



<p>Proceeding in the same fashion, we can derive a similar equation for the concentration of HIn[HIn]=AIn−Ab(εIn−εHIn)(10.19)(10.19)[HIn]=AIn−Ab(εIn−εHIn)</p>



<p>where&nbsp;<em>A</em><sub>In</sub>, which is equal to ε<sub>In</sub><em>bC</em>, is the absorbance when the pH is basic enough that only In<sup>–</sup>&nbsp;contributes to the absorbance. Substituting equation 10.18 and equation 10.19 into the equilibrium constant expression for HIn givesKa=[H3O+]A−AHInAIn−A(10.20)(10.20)Ka=[H3O+]A−AHInAIn−A</p>



<p>We can use equation 10.20 to determine the value of&nbsp;<em>K</em><sub>a</sub>&nbsp;in one of two ways. The simplest approach is to prepare three solutions, each of which contains the same amount,&nbsp;<em>C</em>, of indicator. The pH of one solution is made sufficiently acidic such that [HIn] &gt;&gt; [In<sup>−</sup>]. The absorbance of this solution gives&nbsp;<em>A</em><sub>HIn</sub>. The value of&nbsp;<em>A</em><sub>In</sub>&nbsp;is determined by adjusting the pH of the second solution such that [In<sup>−</sup>] &gt;&gt; [HIn]. Finally, the pH of the third solution is adjusted to an intermediate value, and the pH and absorbance,&nbsp;<em>A</em>, recorded. The value of&nbsp;<em>K</em><sub>a</sub>&nbsp;is calculated using equation 10.20.</p>



<p>Example 10.9</p>



<p>The acidity constant for an acid–base indicator is determined by preparing three solutions, each of which has a total indicator concentration of 5.00 × 10<sup>–5</sup>&nbsp;M. The first solution is made strongly acidic with HCl and has an absorbance of 0.250. The second solution was made strongly basic and has an absorbance of 1.40. The pH of the third solution is 2.91 and has an absorbance of 0.662. What is the value of&nbsp;<em>K</em><sub>a</sub>&nbsp;for the indicator?</p>



<p><strong><em>Solution</em></strong></p>



<p>The value of&nbsp;<em>K</em><sub>a</sub>&nbsp;is determined by making appropriate substitutions into 10.20; thusKa=(1.23×10−3)×0.662−0.2501.40−0.662=6.87×10−4(4.8.34)(4.8.34)Ka=(1.23×10−3)×0.662−0.2501.40−0.662=6.87×10−4</p>



<p>Practice Exercise 10.9</p>



<p>To determine the&nbsp;<em>K</em><sub>a</sub>&nbsp;of a merocyanine dye, the absorbance of a solution of 3.5×10<sup>–4</sup>&nbsp;M dye was measured at a pH of 2.00, a pH of 6.00, and a pH of 12.00, yielding absorbances of 0.000, 0.225, and 0.680, respectively. What is the value of&nbsp;<em>K</em><sub>a</sub>&nbsp;for this dye? The data for this problem is adapted from Lu, H.; Rutan, S. C.&nbsp;<em>Anal. Chem.</em>,&nbsp;<strong>1996</strong>,&nbsp;<em>68</em>, 1381–1386.</p>



<p>Click&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.E%3A_Spectroscopic_Methods_(Exercises)#Practice_Exercise_10.9" target="_blank" rel="noopener">here</a>&nbsp;to review your answer to this exercise.</p>



<p>A second approach for determining&nbsp;<em>K</em><sub>a</sub>&nbsp;is to prepare a series of solutions, each containing the same amount of indicator. Two solutions are used to determine values for&nbsp;<em>A</em><sub>HIn</sub>&nbsp;and&nbsp;<em>A</em><sub>In</sub>. Taking the log of both sides of equation 10.20 and rearranging leave us with the following equation.logA−AHInAIn−A=pH−pKa(10.21)(10.21)log⁡A−AHInAIn−A=pH−pKa</p>



<p>A plot of log[(<em>A</em>&nbsp;–&nbsp;<em>A</em><sub>HIn</sub>)/(<em>A</em><sub>In</sub>&nbsp;–&nbsp;<em>A</em>)] versus pH is a straight-line with a slope of +1 and a&nbsp;<em>y</em>-intercept of –p<em>K</em><sub>a</sub>.</p>



<p>Practice Exercise 10.10</p>



<p>To determine the&nbsp;<em>K</em><sub>a</sub>&nbsp;of the indicator bromothymol blue, the absorbance of a series of solutions containing the same concentration of the indicator was measured at pH levels of 3.35, 3.65, 3.94, 4.30, and 4.64, yielding absorbances of 0.170, 0.287, 0.411, 0.562, and 0.670, respectively. Acidifying the first solution to a pH of 2 changes its absorbance to 0.006, and adjusting the pH of the last solution to 12 changes its absorbance to 0.818. What is the value of&nbsp;<em>K</em><sub>a</sub>&nbsp;for this day? The data for this problem is from Patterson, G. S.<em>&nbsp;J. Chem. Educ.</em>,&nbsp;<strong>1999</strong>,&nbsp;<em>76</em>, 395–398.</p>



<p>Click&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.E%3A_Spectroscopic_Methods_(Exercises)#Practice_Exercise_10.10" target="_blank" rel="noopener">here</a>&nbsp;to review your answer to this exercise.</p>



<p>In developing these approaches for determining&nbsp;<em>K</em><sub>a</sub>&nbsp;we considered a relatively simple system in which the absorbance of HIn and In<sup>–</sup>&nbsp;are easy to measure and for which it is easy to determine the concentration of H<sub>3</sub>O<sup>+</sup>. In addition to acid–base reactions, we can adapt these approaches to any reaction of the general formX(aq)+Y(aq)⇋Z(aq)(4.8.35)(4.8.35)X(aq)+Y(aq)⇋Z(aq)</p>



<p>including metal–ligand complexation reactions and redox reactions, provided that we can determine spectrophotometrically the concentration of the product, Z, and one of the reactants, and that the concentration of the other reactant can be measured by another method. With appropriate modifications, more complicated systems, in which one or more of these parameters can not be measured, also can be treated.<sup>11</sup></p>



<h2 class="wp-block-heading" id="10-3-5-evaluation-of-uv-vis-and-ir-spectroscopy">10.3.5 Evaluation of UV/Vis and IR Spectroscopy</h2>



<h3 class="wp-block-heading" id="scale-of-operation">Scale of Operation</h3>



<p>Molecular UV/Vis absorption is routinely used for the analysis of trace analytes in macro and meso samples. Major and minor analytes can be determined by diluting the sample before analysis, while concentrating a sample may allow for the analysis of ultratrace analytes. The scale of operations for infrared absorption is generally poorer than that for UV/Vis absorption.</p>



<p>Note</p>



<p>See&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/03_The_Vocabulary_of_Analytical_Chemistry/3.4%3A_Selecting_an_Analytical_Method#3D.6_Scale_of_Operation" target="_blank" rel="noopener">Figure 3.5</a>&nbsp;to review the meaning of macro and meso for describing samples, and the meaning of major, minor, and ultratrace for describing analytes.</p>



<h3 class="wp-block-heading" id="accuracy">Accuracy</h3>



<p>Under normal conditions a relative error of 1–5% is easy to obtained with UV/Vis absorption. Accuracy is usually limited by the quality of the blank. Examples of the type of problems that may be encountered include the presence of particulates in a sample that scatter radiation and interferents that react with analytical reagents. In the latter case the interferent may react to form an absorbing species, giving rise to a positive determinate error. Interferents also may prevent the analyte from reacting, leading to a negative determinate error. With care, it may be possible to improve the accuracy of an analysis by as much as an order of magnitude.</p>



<h3 class="wp-block-heading" id="precision">Precision</h3>



<p>In absorption spectroscopy, precision is limited by indeterminate errors—primarily instrumental noise—introduced when measuring absorbance. Precision is generally worse for low absorbances where&nbsp;<em>P</em><sub>0&nbsp;</sub>≈&nbsp;<em>P</em><sub>T</sub>, and for high absorbances when&nbsp;<em>P</em><sub>T</sub>&nbsp;approaches 0. We might expect, therefore, that precision will vary with transmittance.</p>



<p>We can derive an expression between precision and transmittance by applying the propagation of uncertainty as described in Chapter 4. To do so we rewrite Beer’s law asC=−1εblogT(10.22)(10.22)C=−1εblog⁡T</p>



<p>Table 4.10 in Chapter 4 helps us in completing the propagation of uncertainty for equation 10.22, giving the absolute uncertainty in the concentration,&nbsp;<em>s</em><sub>C</sub>, assC=−0.4343εb×sTT(10.23)(10.23)sC=−0.4343εb×sTT</p>



<p>where&nbsp;<em>s</em><sub>T</sub>&nbsp;is the absolute uncertainty in the transmittance. Dividing equation 10.23 by equation 10.22 gives the relative uncertainty in concentration,&nbsp;<em>s</em><sub>C</sub>/<em>C</em>, assCC=0.4343sTTlogT(4.8.36)(4.8.36)sCC=0.4343sTTlog⁡T</p>



<p>If we know the absolute uncertainty in transmittance, we can determine the relative uncertainty in concentration for any transmittance.</p>



<p>Determining the relative uncertainty in concentration is complicated because&nbsp;<em>s</em><sub>T</sub>&nbsp;may be a function of the transmittance. As shown in Table 10.8, three categories of indeterminate instrumental error have been observed.<sup>12</sup>&nbsp;A constant&nbsp;<em>s</em><sub>T</sub>&nbsp;is observed for the uncertainty associated with reading %T on a meter’s analog or digital scale. Typical values are ±0.2–0.3% (a&nbsp;<em>k</em><sub>1</sub>&nbsp;of ±0.002–0.003) for an analog scale, and ±0.001% a (<em>k</em><sub>1</sub>&nbsp;of ±0.000 01) for a digital scale. A constant&nbsp;<em>s</em><sub>T</sub>&nbsp;also is observed for the thermal transducers used in infrared spectrophotometers. The effect of a constant&nbsp;<em>s</em><sub>T</sub>&nbsp;on the relative uncertainty in concentration is shown by curve A in Figure 10.40. Note that the relative uncertainty is very large for both high and low absorbances, reaching a minimum when the absorbance is 0.4343. This source of indeterminate error is important for infrared spectrophotometers and for inexpensive UV/Vis spectrophotometers. To obtain a relative uncertainty in concentration of ±1–2%, the absorbance must be kept within the range 0.1–1.</p>



<figure class="wp-block-table"><table><thead><tr><th scope="col">Category</th><th scope="col">Sources of Indeterminate Error</th><th scope="col">Relative Uncertainty in Concentration</th></tr></thead><tbody><tr><td>sT=k1sT=k1</td><td>%T readout resolution noise in thermal detectors</td><td>sCC=0.4343k1TlogTsCC=0.4343k1Tlog⁡T</td></tr><tr><td>sT=k2T2+T−−−−−−√sT=k2T2+T</td><td>noise in photon detectors</td><td>sCC=0.4343k2logT1+1T−−−−−√sCC=0.4343k2log⁡T1+1T</td></tr><tr><td>sT=k3TsT=k3T</td><td>positioning of sample cell fluctuations in source intensity</td><td>sCC=0.4343k3logTsCC=0.4343k3log⁡T</td></tr></tbody></table></figure>



<p>Values of&nbsp;<em>s</em><sub>T</sub>&nbsp;are a complex function of transmittance when indeterminate errors are dominated by the noise associated with photon detectors. Curve B in Figure 10.40 shows that the relative uncertainty in concentration is very large for low absorbances, but is less at higher absorbances. Although the relative uncertainty reaches a minimum when the absorbance is 0.963, there is little change in the relative uncertainty for absorbances within the range 0.5–2. This source of indeterminate error generally limits the precision of high quality UV/Vis spectrophotometers for mid-to-high absorbances.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12720/Figure10.40.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12720/Figure10.40.jpg?revision=1&amp;size=bestfit&amp;width=450&amp;height=392" alt="Figure10.40.jpg"/></a></figure>



<p><strong>Figure 10.40</strong>&nbsp;Percent relative uncertainty in concentration as a function of absorbance for the categories of indeterminate errors in Table 10.8. A:&nbsp;<em>k</em><sub>1</sub>&nbsp;= ±0.0030; B:&nbsp;<em>k</em><sub>2</sub>&nbsp;= ±0.0030; C:<em>k</em><sub>3</sub>&nbsp;= ±0.0130. The dashed lines correspond to the minimum uncertainty for curve A (absorbance of 0.4343) and for curve B (absorbance of 0.963).</p>



<p>Finally, the value of&nbsp;<em>s</em><sub>T</sub>&nbsp;is directly proportional to transmittance for indeterminate errors resulting from fluctuations in the source’s intensity and from uncertainty in positioning the sample within the spectrometer. The latter is particularly important because the optical properties of any sample cell are not uniform. As a result, repositioning the sample cell may lead to a change in the intensity of transmitted radiation. As shown by curve C in Figure 10.40, the effect is only important at low absorbances. This source of indeterminate errors is usually the limiting factor for high quality UV/Vis spectrophotometers when the absorbance is relatively small.</p>



<p>When the relative uncertainty in concentration is limited by the %T readout resolution, the precision of the analysis can be improved by redefining 100% T and 0% T. Normally 100% T is established using a blank and 0% T is established while preventing the source’s radiation from reaching the detector. If the absorbance is too high, precision can be improved by resetting 100% T using a standard solution of the analyte whose concentration is less than that of the sample (Figure 10.41a). For a sample whose absorbance is too low, precision can be improved by redefining 0% T using a standard solution of the analyte whose concentration is greater than that of the analyte (Figure 10.41b). In this case a calibration curve is required because a linear relationship between absorbance and concentration no longer exists. Precision can be further increased by combining these two methods (Figure 10.41c). Again, a calibration curve is necessary since the relationship between absorbance and concentration is no longer linear.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12721/Figure10.41.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12721/Figure10.41.jpg?revision=1&amp;size=bestfit&amp;width=300&amp;height=330" alt="Figure10.41.jpg"/></a></figure>



<p><strong>Figure 10.41</strong>&nbsp;Methods for improving the precision of absorption methods: (a) high-absorbance method; (b) low-absorbance method; (c) maximum precision method.</p>



<h3 class="wp-block-heading" id="sensitivity">Sensitivity</h3>



<p>The sensitivity of a molecular absorption method, which is the slope of a Beer’s law calibration curve, is the product of the analyte’s absorptivity and the pathlength of the sample cell (ε<em>b</em>). You can improve a method’s sensitivity by selecting a wavelength where absorbance is at a maximum or by increasing the pathlength.</p>



<p>Note</p>



<p>See Figure 10.24 for an example of how the choice of wavelength affects a calibration curve’s sensitivity.</p>



<h3 class="wp-block-heading" id="selectivity">Selectivity</h3>



<p>Selectivity is rarely a problem in molecular absorption spectrophotometry. In many cases it is possible to find a wavelength where only the analyte absorbs. When two or more species do contribute to the measured absorbance, a multicomponent analysis is still possible, as shown in Example 10.6 and Example 10.7.</p>



<h3 class="wp-block-heading" id="time-cost-and-equipment">Time, Cost, and Equipment</h3>



<p>The analysis of a sample by molecular absorption spectroscopy is relatively rapid, although additional time may be required if we need to chemically convert a nonabsorbing analyte into an absorbing form. The cost of UV/Vis instrumentation ranges from several hundred dollars for a simple filter photometer, to more than $50,000 for a computer controlled high resolution, double-beam instrument equipped with variable slits, and operating over an extended range of wavelengths. Fourier transform infrared spectrometers can be obtained for as little as $15,000–$20,000, although more expensive models are available.</p>



<h2 class="wp-block-heading" id="contributors">Contributors</h2>



<p><a rel="noreferrer noopener" href="http://dpuadweb.depauw.edu/harvey_web/Index.html" target="_blank">David Harvey</a>&nbsp;<a rel="noreferrer noopener" href="http://www.depauw.edu/" target="_blank">(DePauw University)</a></p>



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<p>While interaction with infrared light causes molecules to undergo vibrational transitions, the shorter wavelength, higher energy radiation in the UV (200-400 nm) and visible (400-700 nm) range of the electromagnetic spectrum causes many organic molecules to undergo&nbsp;<strong>electronic transitions</strong>. What this means is that when the energy from UV or visible light is absorbed by a molecule, one of its electrons jumps from a lower energy to a higher energy molecular orbital.</p>



<figure class="wp-block-image size-large"><a href="http://www.analyzetest.com/index.php/contact-us/"><img decoding="async" src="http://s7.picofile.com/file/8392387600/uv_vis_in.gif" alt=""/></a></figure>



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<h2 class="wp-block-heading" id="electronic-transitions">Electronic transitions</h2>



<p>Let’s take as our first example the simple case of molecular hydrogen, H<sub>2</sub>. As you may recall from section 2.1A, the molecular orbital picture for the hydrogen molecule consists of one bonding&nbsp;σ&nbsp;MO, and a higher energy antibonding&nbsp;σ* MO. When the molecule is in the ground state, both electrons are paired in the lower-energy bonding orbital – this is the Highest Occupied Molecular Orbital (HOMO). The antibonding&nbsp;σ* orbital, in turn, is the Lowest Unoccupied Molecular Orbital (LUMO).</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140660/image023.png?revision=1" alt="image024.png"/></figure>



<p>If the molecule is exposed to light of a wavelength with energy equal to&nbsp;<strong>Δ</strong>E, the HOMO-LUMO energy gap, this wavelength will be absorbed and the energy used to bump one of the electrons from the HOMO to the LUMO – in other words, from the&nbsp;σ&nbsp;to the&nbsp;σ* orbital. This is referred to as a&nbsp;<strong>σ&nbsp;</strong><strong>&#8211;&nbsp;</strong><strong>σ</strong><strong>* transition</strong>.&nbsp;<strong>Δ</strong>E for this electronic transition is 258 kcal/mol, corresponding to light with a wavelength of 111 nm.</p>



<p>When a double-bonded molecule such as ethene (common name ethylene) absorbs light, it undergoes a&nbsp;<strong>π</strong><strong>&nbsp;&#8211;&nbsp;</strong><strong>π</strong><strong>* transition.&nbsp;</strong>Because&nbsp;π-&nbsp;π* energy gaps are narrower than&nbsp;σ&nbsp;<strong>&#8211;</strong>&nbsp;σ<strong>*&nbsp;</strong>gaps, ethene absorbs light at 165 nm &#8211; a longer wavelength than molecular hydrogen.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140652/image025.png?revision=1" alt="image026.png"/></figure>



<p>The electronic transitions of both molecular hydrogen and ethene are too energetic to be accurately recorded by standard UV spectrophotometers, which generally have a range of 220 – 700 nm. Where UV-vis spectroscopy becomes useful to most organic and biological chemists is in the study of molecules with conjugated&nbsp;ππsystems. In these groups, the energy gap for&nbsp;π&nbsp;-π* transitions is smaller than for isolated double bonds, and thus the wavelength absorbed is longer. Molecules or parts of molecules that absorb light strongly in the UV-vis region are called&nbsp;<strong>chromophores</strong>.</p>



<p>Let’s revisit the MO picture for 1,3-butadiene, the simplest conjugated system. Recall that we can draw a diagram showing the four pi MO’s that result from combining the four 2p<sub>z</sub>&nbsp;atomic orbitals. The lower two orbitals are bonding, while the upper two are antibonding.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140644/image027.png?revision=1" alt="image028.png"/></figure>



<p>Comparing this MO picture to that of ethene, our isolated pi-bond example, we see that the HOMO-LUMO energy gap is indeed smaller for the conjugated system. 1,3-butadiene absorbs UV light with a wavelength of 217 nm.</p>



<p>As conjugated pi systems become larger, the energy gap for a&nbsp;π&nbsp;&#8211;&nbsp;π* transition becomes increasingly narrow, and the wavelength of light absorbed correspondingly becomes longer. The absorbance due to the&nbsp;π&nbsp;&#8211;&nbsp;π* transition in 1,3,5-hexatriene, for example, occurs at 258 nm, corresponding to a&nbsp;<strong>Δ</strong>E of 111 kcal/mol.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140637/image029.png?revision=1" alt="image030.png"/></figure>



<p>In molecules with extended pi systems, the HOMO-LUMO energy gap becomes so small that absorption occurs in the visible rather then the UV region of the electromagnetic spectrum. Beta-carotene, with its system of 11 conjugated double bonds, absorbs light with wavelengths in the blue region of the visible spectrum while allowing other visible wavelengths – mainly those in the red-yellow region &#8211; to be transmitted. This is why carrots are orange.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140631/image031.png?revision=1" alt="image032.png"/></figure>



<p>The conjugated pi system in 4-methyl-3-penten-2-one gives rise to a strong UV absorbance at 236 nm due to a&nbsp;π&nbsp;&#8211;&nbsp;π* transition. However, this molecule also absorbs at 314 nm. This second absorbance is due to the transition of a non-bonding (lone pair) electron on the oxygen up to a&nbsp;π* antibonding MO:</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140625/image033.png?revision=1" alt="image034.png"/></figure>



<p>This is referred to as an&nbsp;<strong>n</strong><strong>&nbsp;&#8211;&nbsp;π</strong><strong>* transition</strong>. The nonbonding (n) MO’s are higher in energy than the highest bonding p orbitals, so the energy gap for an&nbsp;n→π∗n→π∗transition is smaller that that of a&nbsp;π&nbsp;&#8211;&nbsp;π* transition – and thus the n &#8211;&nbsp;π* peak is at a longer wavelength. In general, n &#8211;&nbsp;π* transitions are weaker (less light absorbed) than those due to&nbsp;π &#8211;&nbsp;π* transitions.</p>



<p><strong><u>Exercise 4.9</u></strong></p>



<p>What is the energy of the photons (in kJ/mol) of light with wavelength of 470 nm, the&nbsp;l<sub>max</sub>&nbsp;of&nbsp;b-carotene?</p>



<p><strong><u>Exercise 4.10</u></strong></p>



<p>Which of the following molecules would you expect absorb at a longer wavelength in the UV region of the electromagnetic spectrum? Explain your answer.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140619/image035.png?revision=1&amp;size=bestfit&amp;width=306&amp;height=155" alt="image036.png"/></figure>



<p><a target="_blank" href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)/Solution_Manual/Chapter_04_Solutions" rel="noreferrer noopener">Solutions</a></p>



<p><strong>Protecting yourself from sunburn</strong></p>



<p>Human skin can be damaged by exposure to ultraviolet light from the sun. We naturally produce a pigment, called melanin, which protects the skin by absorbing much of the ultraviolet radiation. Melanin is a complex polymer, two of the most common monomers units of which are shown below.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140772/sunscreen.png?revision=1&amp;size=bestfit&amp;width=461&amp;height=391" alt=""/></figure>



<p>Overexposure to the sun is still dangerous, because there is a limit to how much radiation our melanin can absorb. Most commercial sunscreens claim to offer additional protection from both UV-A and UV-B radiation: UV-A refers to wavelengths between 315-400 nm, UV-B to shorter, more harmful wavelengths between 280-315 nm. PABA (<em>para</em>-aminobenzoic acid) was used in sunscreens in the past, but its relatively high polarity meant that it was not very soluble in oily lotions, and it tended to rinse away when swimming. Many sunscreens today contain, among other active ingredients, a more hydrophobic derivative of PABA called Padimate O.</p>



<figure class="wp-block-image size-large"><a href="http://www.analyzetest.com/index.php/contact-us/"><img decoding="async" src="http://s7.picofile.com/file/8392387600/uv_vis_in.gif" alt=""/></a></figure>



<h2 class="wp-block-heading" id="looking-at-uv-vis-spectra">Looking at UV-vis spectra</h2>



<p>We have been talking in general terms about how molecules absorb UV and visible light – now let&#8217;s look at some actual examples of data from a UV-vis absorbance spectrophotometer. The basic setup is the same as for IR spectroscopy: radiation with a range of wavelengths is directed through a sample of interest, and a detector records which wavelengths were absorbed and to what extent the absorption occurred.</p>



<p><img decoding="async" alt="" width="670px" height="376px" src="https://chem.libretexts.org/@api/deki/files/140776/Schematic_of_UV-_visible_spectrophotometer.png?revision=1&amp;size=bestfit&amp;width=670&amp;height=376"><strong>Schematic for a UV-Vis spectrophotometer</strong></p>



<p>(Image from&nbsp;<a target="_blank" href="https://upload.wikimedia.org/wikipedia/commons/9/95/Schematic_of_UV-_visible_spectrophotometer.png" rel="noreferrer noopener">Wikipedia Commons</a>)</p>



<p>Below is the absorbance spectrum of an important biological molecule called nicotinamide adenine dinucleotide, abbreviated NAD<sup>+</sup>. This compound absorbs light in the UV range due to the presence of conjugated pi-bonding systems.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140612/image037.png?revision=1" alt="image038.png"/></figure>



<p>You’ll notice that this UV spectrum is much simpler than the IR spectra we saw earlier: this one has only one peak, although many molecules have more than one. Notice also that the convention in UV-vis spectroscopy is to show the baseline at the bottom of the graph with the peaks pointing up. Wavelength values on the x-axis are generally measured in nanometers (nm) rather than in cm<sup>-1</sup>&nbsp;as is the convention in IR spectroscopy.</p>



<p>Peaks in UV spectra tend to be quite broad, often spanning well over 20 nm at half-maximal height. Typically, there are two things that we look for and record from a UV-Vis spectrum. The first is&nbsp;λmaxλmax, which is the wavelength at maximal light absorbance. As you can see, NAD<sup>+</sup>&nbsp;has&nbsp;λmax=260nmλmax=260nm. We also want to record how much light is absorbed at&nbsp;λmaxλmax. Here we use a unitless number called&nbsp;<strong>absorbance</strong>, abbreviated &#8216;A&#8217;. This contains the same information as the &#8216;percent transmittance&#8217; number used in IR spectroscopy, just expressed in slightly different terms. To calculate absorbance at a given wavelength, the computer in the spectrophotometer simply takes the intensity of light at that wavelength&nbsp;<em>before</em>&nbsp;it passes through the sample (I<sub>0</sub>), divides this value by the intensity of the same wavelength&nbsp;<em>after</em>&nbsp;it passes through the sample (I), then takes the log<sub>10</sub>&nbsp;of that number:A=logI0I(4.3.1)(4.3.1)A=log⁡I0I</p>



<p>You can see that the absorbance value at 260 nm (A<sub>260</sub>) is about 1.0 in this spectrum.</p>



<p><strong>Exercise 4.11</strong></p>



<p>Express A = 1.0 in terms of percent transmittance (%T, the unit usually used in IR spectroscopy (and sometimes in UV-vis as well).</p>



<p><a target="_blank" href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)/Solution_Manual/Chapter_04_Solutions" rel="noreferrer noopener">Solutions</a></p>



<p>Here is the absorbance spectrum of the common food coloring Red #3:</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140602/image039.png?revision=1" alt="image040.png"/></figure>



<p>Here, we see that the extended system of conjugated pi bonds causes the molecule to absorb light in the visible range. Because the&nbsp;<strong>λ</strong><sub>max&nbsp;</sub>of 524 nm falls within the green region of the spectrum, the compound appears red to our eyes. Now, take a look at the spectrum of another food coloring, Blue #1:</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140595/image041.png?revision=1" alt="image042.png"/></figure>



<p>Here, maximum absorbance is at 630 nm, in the orange range of the visible spectrum, and the compound appears blue.</p>



<h2 class="wp-block-heading" id="applications-of-uv-spectroscopy-in-organic-and-biological-chemistry">Applications of UV spectroscopy in organic and biological chemistry</h2>



<p>UV-vis spectroscopy has many different applications in organic and biological chemistry. One of the most basic of these applications is the use of the&nbsp;<a href="https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)/Spectroscopy/Electronic_Spectroscopy/Electronic_Spectroscopy_Basics/The_Beer-Lambert_Law" target="_blank" rel="noopener"><strong>Beer &#8211; Lambert Law</strong></a>&nbsp;to determine the concentration of a chromophore. You most likely have performed a Beer – Lambert experiment in a previous chemistry lab. The law is simply an application of the observation that, within certain ranges, the absorbance of a chromophore at a given wavelength varies in a linear fashion with its concentration: the higher the concentration of the molecule, the greater its absorbance.</p>



<p>If we divide the observed value of A at&nbsp;λ<sub>max</sub>&nbsp;by the concentration of the sample (<em>c</em>, in mol/L), we obtain the&nbsp;<strong>molar absorptivity</strong>, or&nbsp;<strong>extinction coefficient</strong>&nbsp;(<strong>ε</strong>), which is a characteristic value for a given compound.ϵ=Ac(4.3.2)(4.3.2)ϵ=Ac</p>



<p>The absorbance will also depend, of course, on the&nbsp;<strong>path length</strong>&nbsp;&#8211; in other words, the distance that the beam of light travels though the sample. In most cases, sample holders are designed so that the path length is equal to 1 cm, so the units for molar absorptivity are L<sub>*</sub>&nbsp;mol<sup>-1</sup><sub>*</sub>cm<sup>-1</sup>. If we look up the value of e for our compound at&nbsp;λ<sub>max</sub>, and we measure absorbance at this wavelength, we can easily calculate the concentration of our sample. As an example, for NAD<sup>+</sup>&nbsp;the literature value of&nbsp;ε&nbsp;at 260 nm is 18,000 L<sub>*</sub>&nbsp;mol<sup>-1</sup><sub>*</sub>cm<sup>-1</sup>. In our NAD<sup>+</sup>&nbsp;spectrum we observed A<sub>260</sub>&nbsp;= 1.0, so using equation 4.4 and solving for concentration we find that our sample is 5.6 x 10<sup>-5</sup>&nbsp;M.</p>



<p>The bases of DNA and RNA are good chromophores:</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140587/image043.png?revision=1" alt="image044.png"/></figure>



<p>Biochemists and molecular biologists often determine the concentration of a DNA sample by assuming an average value of&nbsp;ε&nbsp;= 0.020 ng<sup>-1</sup>×mL for double-stranded DNA at its&nbsp;λ<sub>max</sub>&nbsp;of 260 nm (notice that concentration in this application is expressed in mass/volume rather than molarity: ng/mL is often a convenient unit for DNA concentration when doing molecular biology).<strong><u>Exercise 4.12</u></strong>50&nbsp;microliters of an aqueous sample of double stranded DNA is dissolved in 950 microliters of water. This diluted solution has a maximal absorbance of 0.326 at 260 nm. What is the concentration of the original (more concentrated) DNA sample, expressed in&nbsp;micrograms&nbsp;per microliter?<a target="_blank" href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)/Solution_Manual/Chapter_04_Solutions" rel="noreferrer noopener">Solutions</a></p>



<p>Because the extinction coefficient of double stranded DNA is slightly lower than that of single stranded DNA, we can use UV spectroscopy to monitor a process known as DNA melting. If a short stretch of double stranded DNA is gradually heated up, it will begin to ‘melt’, or break apart, as the temperature increases (recall that two strands of DNA are held together by a specific pattern of hydrogen bonds formed by ‘base-pairing’).</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140579/image045.png?revision=1" alt="image046.png"/></figure>



<p>As melting proceeds, the absorbance value for the sample increases, eventually reaching a high plateau as all of the double-stranded DNA breaks apart, or ‘melts’. The mid-point of this process, called the ‘melting temperature’, provides a good indication of how tightly the two strands of DNA are able to bind to each other.</p>



<p>Later we will see how the Beer &#8211; Lambert Law and UV spectroscopy provides us with a convenient way to follow the progress of many different enzymatic redox (oxidation-reduction) reactions. In biochemistry, oxidation of an organic molecule often occurs concurrently with reduction of nicotinamide adenine dinucleotide (NAD<sup>+</sup>, the compound whose spectrum we saw earlier in this section) to NADH:</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140570/image047.png?revision=1" alt="image048.png"/></figure>



<p>Both NAD<sup>+</sup>&nbsp;and NADH absorb at 260 nm. However NADH, unlike NAD<sup>+</sup>, has a second absorbance band with&nbsp;λ<sub>max</sub>&nbsp;= 340 nm and&nbsp;ε&nbsp;= 6290 L<sub>*</sub>mol<sup>-1</sup><sub>*</sub>cm<sup>-1</sup>. The figure below shows the spectra of both compounds superimposed, with the NADH spectrum offset slightly on the y-axis:</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140562/image049.png?revision=1" alt="image050.png"/></figure>



<p>By monitoring the absorbance of a reaction mixture at 340 nm, we can &#8216;watch&#8217; NADH being formed as the reaction proceeds, and calculate the rate of the reaction.</p>



<p>UV spectroscopy is also very useful in the study of proteins. Proteins absorb light in the UV range due to the presence of the aromatic amino acids tryptophan, phenylalanine, and tyrosine, all of which are chromophores.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140551/image051.png?revision=1" alt="image052.png"/></figure>



<p>Biochemists frequently use UV spectroscopy to study conformational changes in proteins &#8211; how they change shape in response to different conditions. When a protein undergoes a conformational shift (partial unfolding, for example), the resulting change in the environment around an aromatic amino acid chromophore can cause its UV spectrum to be altered.</p>



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		<title>Fundamentals of Fourier Transform Infrared spectroscopy</title>
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					<description><![CDATA[Click here to see other posts about FT-IR Only 10 $ for interpretation of your FT-IR spectrum Payment Upon Completion Send your spectra... Infrared (IR) spectroscopy is a chemical analytical technique, which measures the infrared intensity versus wavelength (wavenumber) of light. Based upon the wavenumber, infrared light can be categorized as far infrared (4 ~ [&#8230;]]]></description>
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<p>Infrared (IR) spectroscopy is a chemical analytical technique, which measures the infrared intensity versus wavelength (wavenumber) of light. Based upon the wavenumber, infrared light can be categorized as far infrared (4 ~ 400cm‐1), mid infrared (400 ~ 4,000cm‐1) and near infrared (4,000 ~ 14,000cm‐1).</p>



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<p><br>Infrared spectroscopy detects the vibration characteristics of chemical functional groups in a sample. When an infrared light interacts with the matter, chemical bonds will stretch, contract and bend. As a result, a chemical functional group tends to adsorb infrared radiation in a<br>specific wavenumber range regardless of the structure of the rest of the molecule. For example, the C=O stretch of a carbonyl group appears at around 1700cm‐1 in a variety of molecules.<br>Hence, the correlation of the band wavenumber position with the chemical structure is used to identify a functional group in a sample. The wavenember positions where functional groups adsorb are consistent, despite the effect of temperature, pressure, sampling, or change in the<br>molecule structure in other parts of the molecules. Thus the presence of specific functional groups can be monitored by these types of infrared bands, which are called group wavenumbers.<br>The early‐stage IR instrument is of the dispersive type, which uses a prism or a grating monochromator. The dispersive instrument is characteristic of a slow scanning. A Fourier Transform Infrared (FTIR) spectrometer obtains infrared spectra by first collecting an interferogram of a sample signal with an interferometer, which measures all of infrared frequencies simultaneously. An FTIR spectrometer acquires and digitizes the interferogram, performs the FT function, and outputs the spectrum.</p>



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<p>An interferometer utilizes a beamsplitter to split the incoming infrared beam into two optical beams. One beam reflects off of a flat mirror which is fixed in place. Another beam reflects off of a flat mirror which travels a very short distance (typically a few millimeters) away from the beamsplitter. The two beams reflect off of their respective mirrors and are recombined when they meet together at the beamsplitter. The re‐combined signal results from the “interfering” with each other. Consequently, the resulting signal is called interferogram, which has every infrared frequency “encoded” into it. When the interferogram signal is transmitted through or<br>reflected off of the sample surface, the specific frequencies of energy are adsorbed by the sample due to the excited vibration of function groups in molecules. The infrared signal after interaction with the sample is uniquely characteristic of the sample. The beam finally arrives at the detector and is measure by the detector. The detected interferogram can not be directly<br>interpreted. It has to be “decoded” with a well‐known mathematical technique in term of Fourier Transformation. The computer can perform the Fourier transformation calculation and present an infrared spectrum, which plots adsorbance (or transmittance) versus wavenumber.<br>When an interferogram is Fourier transformed, a single beam spectrum is generated. A single beam spectrum is a plot of raw detector response versus wavenumber. A single beam spectrum obtained without a sample is called a background spectrum, which is induced by the instrument and the environments. Characteristic bands around 3500 cm‐1 and 1630 cm‐1 are ascribed to atmospheric water vapor, and the bands at 2350 cm‐1 and 667 cm‐1 are attributed to carbon dioxide. A background spectrum must always be run when analyzing samples by FTIR. When an interferogram is measured with a sample and Fourier transformed, a sample single beam spectrum is obtained. It looks similar to the background spectrum except that the sample peaks are superimposed upon the instrumental and atmospheric contributions to the spectrum. To eliminate these contributions, the sample single beam spectrum must be normalized against the background spectrum. Consequently, a transmittance spectrum is obtained as follows.<br>%T = I/Io<br>Where %T is transmittance; I is the intensity measured with a sample in the beam (from the sample single beam spectrum); Io is the intensity measured from the back ground spectrum. The absorbance spectrum can be calculated from the transmittance spectrum using the following equation.<br>A = ‐log10 T<br>Where A is the absorbance.<br>The final transmittance/absorbance spectrum should be devoid of all instrumental and environmental contributions, and only present the features of the sample. If the concentrations of gases such as water vapor and carbon dioxide in the instrument are the same when the background and sample spectra are obtained, their contributions to the spectrum will ratio out exactly and their bands will not occur. If the concentrations of these gases are different when the background and sample spectra are obtained, their bands will appear in the sample spectrum.<br>Reference:<br>Brian C. Smith, Fundamentals of Fourier Transform Infrared spectroscopy, CRC press, Boca Raton, 1996.</p>



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		<title>How to analyze UV-Vis spectra?</title>
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					<description><![CDATA[Click here to see more posts about UV-Vis Only 10$ for interpretation of your VSM curve Payment Upon Completion Send your VSM curves... An obvious difference between certain compounds is their color. Thus, quinone is yellow; chlorophyll is green; the 2,4-dinitrophenylhydrazone derivatives of aldehydes and ketones range in color from bright yellow to deep red, [&#8230;]]]></description>
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<p>An obvious difference between certain compounds is their color. Thus, quinone is yellow; chlorophyll is green; the 2,4-dinitrophenylhydrazone derivatives of aldehydes and ketones range in color from bright yellow to deep red, depending on double bond conjugation; and aspirin is colorless. In this respect the human eye is functioning as a spectrometer analyzing the light reflected from the surface of a solid or passing through a liquid.</p>



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<p> Although we see sunlight (or white light) as uniform or homogeneous in color, it is actually composed of a broad range of radiation wavelengths in the ultraviolet (UV), visible and infrared (IR) portions of the spectrum. As shown on the right, the component colors of the visible portion can be separated by passing sunlight through a prism, which acts to bend the light in differing degrees according to wavelength. Electromagnetic radiation such as visible light is commonly treated as a wave phenomenon, characterized by a wavelength or frequency.&nbsp;<strong>Wavelength</strong>&nbsp;is defined on the left below, as the distance between adjacent peaks (or troughs), and may be designated in meters, centimeters or nanometers (10<sup>-9</sup>&nbsp;meters).&nbsp;<strong>Frequency</strong>&nbsp;is the number of wave cycles that travel past a fixed point per unit of time, and is usually given in cycles per second, or hertz (Hz). Visible wavelengths cover a range from approximately 400 to 800 nm. The longest visible wavelength is red and the shortest is violet. Other common colors of the spectrum, in order of decreasing wavelength, may be remembered by the mnemonic:&nbsp;<strong>ROY G BIV</strong>. The wavelengths of what we perceive as particular colors in the visible portion of the spectrum are displayed and listed below. In horizontal diagrams, such as the one on the bottom left, wavelength will increase on moving from left to right.&nbsp;<br></p>



<figure class="wp-block-table"><table><tbody><tr><td></td><td><strong>Violet:</strong>&nbsp;&nbsp; 400 &#8211; 420 nm&nbsp;<br><strong>Indigo:</strong>&nbsp;&nbsp; 420 &#8211; 440 nm&nbsp;<br><strong>Blue:</strong>&nbsp;&nbsp; 440 &#8211; 490 nm&nbsp;<br><strong>Green:</strong>&nbsp;&nbsp; 490 &#8211; 570 nm&nbsp;<br><strong>Yellow:</strong>&nbsp;&nbsp; 570 &#8211; 585 nm&nbsp;<br><strong>Orange:</strong>&nbsp;&nbsp; 585 &#8211; 620 nm&nbsp;<br><strong>Red:</strong>&nbsp;&nbsp; 620 &#8211; 780 nm</td></tr><tr><td></td></tr></tbody></table></figure>



<figure class="wp-block-image"><img decoding="async" src="https://www2.chemistry.msu.edu/faculty/reusch/VirtTxtJml/Spectrpy/Images/colwheel.gif" alt=""/></figure>



<p>When white light passes through or is reflected by a colored substance, a characteristic portion of the mixed wavelengths is absorbed. The remaining light will then assume the complementary color to the wavelength(s) absorbed. This relationship is demonstrated by the color wheel shown on the right. Here, complementary colors are diametrically opposite each other. Thus, absorption of 420-430 nm light renders a substance yellow, and absorption of 500-520 nm light makes it red. Green is unique in that it can be created by absoption close to 400 nm as well as absorption near 800 nm.<br>Early humans valued colored pigments, and used them for decorative purposes. Many of these were inorganic minerals, but several important organic dyes were also known. These included the crimson pigment, kermesic acid, the blue dye, indigo, and the yellow saffron pigment, crocetin. A rare dibromo-indigo derivative, punicin, was used to color the robes of the royal and wealthy. The deep orange hydrocarbon carotene is widely distributed in plants, but is not sufficiently stable to be used as permanent pigment, other than for food coloring. A common feature of all these colored compounds, displayed below, is a system of&nbsp;<strong>extensively conjugated pi-electrons</strong>.</p>



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<figure class="wp-block-image"><img decoding="async" src="https://www2.chemistry.msu.edu/faculty/reusch/VirtTxtJml/Spectrpy/Images/natpigm.gif" alt=""/></figure>



<h3 class="wp-block-heading" id="2-the-electromagnetic-spectrum">2. The Electromagnetic Spectrum</h3>



<p>The visible spectrum constitutes but a small part of the total radiation spectrum. Most of the radiation that surrounds us cannot be seen, but can be detected by dedicated sensing instruments. This&nbsp;<strong>electromagnetic spectrum</strong>&nbsp;ranges from very short wavelengths (including gamma and x-rays) to very long wavelengths (including microwaves and broadcast radio waves). The following chart displays many of the important regions of this spectrum, and demonstrates the inverse relationship between wavelength and frequency (shown in the top equation below the chart).</p>



<figure class="wp-block-image"><img decoding="async" src="https://www2.chemistry.msu.edu/faculty/reusch/VirtTxtJml/Spectrpy/Images/emspec.gif" alt=""/></figure>



<p>The energy associated with a given segment of the spectrum is proportional to its frequency. The bottom equation describes this relationship, which provides the energy carried by a photon of a given wavelength of radiation.</p>



<figure class="wp-block-image"><img decoding="async" src="https://www2.chemistry.msu.edu/faculty/reusch/VirtTxtJml/Spectrpy/Images/equation.gif" alt=""/></figure>



<p>To obtain specific frequency, wavelength and energy values use&nbsp;<a href="javascript:chngtxt(x1)">this calculator</a>.</p>



<h3 class="wp-block-heading" id="3-uv-visible-absorption-spectra">3. UV-Visible Absorption Spectra</h3>



<p>To understand why some compounds are colored and others are not, and to determine the relationship of conjugation to color, we must make accurate measurements of light absorption at different wavelengths in and near the visible part of the spectrum. Commercial optical spectrometers enable such experiments to be conducted with ease, and usually survey both the near ultraviolet and visible portions of the spectrum.</p>



<p>The visible region of the spectrum comprises photon energies of 36 to 72 kcal/mole, and the near ultraviolet region, out to 200 nm, extends this energy range to 143 kcal/mole. Ultraviolet radiation having wavelengths less than 200 nm is difficult to handle, and is seldom used as a routine tool for structural analysis. Ultraviolet  The visible region of the spectrum comprises photon energies of 36 to 72 kcal/mole, and the near ultraviolet region, out to 200 nm, extends this energy range to 143 kcal/mole. Ultraviolet radiation having wavelengths less than 200 nm is difficult to handle, and is seldom used as a routine tool for structural analysis.</p>



<figure class="wp-block-image"><img decoding="async" src="https://www2.chemistry.msu.edu/faculty/reusch/VirtTxtJml/Spectrpy/Images/electrns.gif" alt=""/></figure>



<p>The energies noted above are sufficient to promote or excite a molecular electron to a higher energy orbital. Consequently, absorption spectroscopy carried out in this region is sometimes called &#8220;electronic spectroscopy&#8221;. A diagram showing the various kinds of electronic excitation that may occur in organic molecules is shown on the left. Of the six transitions outlined, only the two lowest energy ones (left-most, colored blue) are achieved by the energies available in the 200 to 800 nm spectrum. As a rule, energetically favored electron promotion will be from the&nbsp;<strong>highest occupied molecular orbital (HOMO)</strong>&nbsp;to the&nbsp;<strong>lowest unoccupied molecular orbital (LUMO)</strong>, and the resulting species is called an&nbsp;<strong>excited state</strong>. For a review of molecular orbitals&nbsp;<a href="https://www2.chemistry.msu.edu/faculty/reusch/VirtTxtJml/intro3.htm#strc8a" target="_blank" rel="noopener">click here</a>.<br>When sample molecules are exposed to light having an energy that matches a possible electronic transition within the molecule, some of the light energy will be absorbed as the electron is promoted to a higher energy orbital. An optical spectrometer records the wavelengths at which absorption occurs, together with the degree of absorption at each wavelength. The resulting spectrum is presented as a graph of absorbance (A) versus wavelength, as in the isoprene spectrum shown below. Since isoprene is colorless, it does not absorb in the visible part of the spectrum and this region is not displayed on the graph.&nbsp;<strong>Absorbance</strong>&nbsp;usually ranges from 0 (no absorption) to 2 (99% absorption), and is precisely defined in context with spectrometer operation.</p>



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<p>Because the absorbance of a sample will be proportional to the number of absorbing molecules in the spectrometer light beam (e.g. their molar concentration in the sample tube), it is necessary to correct the absorbance value for this and other operational factors if the spectra of different compounds are to be compared in a meaningful way. The corrected absorption value is called &#8220;molar absorptivity&#8221;, and is particularly useful when comparing the spectra of different compounds and determining the relative strength of light absorbing functions (chromophores).&nbsp;<strong>Molar absorptivity</strong>&nbsp;(ε) is defined as:</p>



<figure class="wp-block-table"><table><tbody><tr><th>Molar Absorptivity, ε =&nbsp;<em>A</em>&nbsp;/ c l</th><td></td><td>(where&nbsp;<em>A</em>= absorbance,&nbsp;<strong>c</strong>&nbsp;= sample concentration in moles/liter &amp;&nbsp;<strong>l</strong>&nbsp;= length of light path through the sample in cm.)</td></tr></tbody></table></figure>



<p>If the isoprene spectrum on the right was obtained from a dilute hexane solution (c = 4 * 10<sup>-5</sup>&nbsp;moles per liter) in a 1 cm sample cuvette, a simple calculation using the above formula indicates a molar absorptivity of 20,000 at the maximum absorption wavelength. Indeed the entire vertical absorbance scale may be changed to a molar absorptivity scale once this information about the sample is in hand. Clicking on the spectrum will display this change in units.</p>



<figure class="wp-block-table"><table><tbody><tr><td>ChromophoreExampleExcitationλ<sub>max</sub>, nmεSolventC=CEtheneπ &nbsp;<strong><sup>__</sup>&gt;</strong>&nbsp;&nbsp; π*17115,000hexaneC≡C1-Hexyneπ &nbsp;<strong><sup>__</sup>&gt;</strong>&nbsp;&nbsp; π*18010,000hexaneC=OEthanaln &nbsp;<strong><sup>__</sup>&gt;</strong>&nbsp;&nbsp;π*<br>π &nbsp;<strong><sup>__</sup>&gt;</strong>&nbsp;&nbsp;π*290<br>18015<br>10,000hexane<br>hexaneN=ONitromethanen &nbsp;<strong><sup>__</sup>&gt;</strong>&nbsp;&nbsp;π*<br>π &nbsp;<strong><sup>__</sup>&gt;</strong>&nbsp;&nbsp;π*275<br>20017<br>5,000ethanol<br>ethanolC-X &nbsp; X=Br<br>&nbsp; &nbsp; &nbsp; X=IMethyl bromide<br>Methyl Iodiden &nbsp;<strong><sup>__</sup>&gt;</strong>&nbsp;&nbsp;σ*<br>n &nbsp;<strong><sup>__</sup>&gt;</strong>&nbsp;&nbsp;σ*205<br>255200<br>360hexane<br>hexane</td><td></td><td><a href="javascript:chg1();"></a></td></tr></tbody></table></figure>



<p>From the chart above it should be clear that the only molecular moieties likely to absorb light in the 200 to 800 nm region are pi-electron functions and hetero atoms having non-bonding valence-shell electron pairs. Such light absorbing groups are referred to as&nbsp;<strong>chromophores</strong>. A list of some simple chromophores and their light absorption characteristics is provided on the left above. The oxygen non-bonding electrons in alcohols and ethers do not give rise to absorption above 160 nm. Consequently, pure alcohol and ether solvents may be used for spectroscopic studies.<br>The presence of chromophores in a molecule is best documented by UV-Visible spectroscopy, but the failure of most instruments to provide absorption data for wavelengths below 200 nm makes the detection of isolated chromophores problematic. Fortunately, conjugation generally moves the absorption maxima to longer wavelengths, as in the case of isoprene, so conjugation becomes the major structural feature identified by this technique.<br>Molar absorptivities may be very large for strongly absorbing chromophores (&gt;10,000) and very small if absorption is weak (10 to 100). The magnitude ofε reflects both the size of the chromophore and the probability that light of a given wavelength will be absorbed when it strikes the chromophore.</p>



<h3 class="wp-block-heading" id="4-the-importance-of-conjugation">4. The Importance of Conjugation</h3>



<p>A comparison of the absorption spectrum of 1-pentene, λ<sub>max</sub>&nbsp;= 178 nm, with that of isoprene (above) clearly demonstrates the importance of chromophore conjugation. Further evidence of this effect is shown below. The spectrum on the left illustrates that conjugation of double and triple bonds also shifts the absorption maximum to longer wavelengths. From the polyene spectra displayed in the center diagram, it is clear that each additional double bond in the conjugated pi-electron system shifts the absorption maximum about 30 nm in the same direction. Also, the molar absorptivity (ε) roughly doubles with each new conjugated double bond. Spectroscopists use the terms defined in the table on the right when describing shifts in absorption. Thus, extending conjugation generally results in bathochromic and hyperchromic shifts in absorption.<br>The appearance of several absorption peaks or shoulders for a given chromophore is common for highly conjugated systems, and is often solvent dependent. This fine structure reflects not only the different conformations such systems may assume, but also electronic transitions between the different vibrational energy levels possible for each electronic state. Vibrational fine structure of this kind is most pronounced in vapor phase spectra, and is increasingly broadened and obscured in solution as the solvent is changed from hexane to methanol.</p>



<figure class="wp-block-table"><table><tbody><tr><td></td><td></td><td>&nbsp;</td><th>Terminology for Absorption ShiftsNature of ShiftDescriptive TermTo Longer WavelengthBathochromicTo Shorter WavelengthHypsochromicTo Greater AbsorbanceHyperchromicTo Lower AbsorbanceHypochromic</th></tr></tbody></table></figure>



<p>To understand why conjugation should cause bathochromic shifts in the absorption maxima of chromophores, we need to look at the relative energy levels of the pi-orbitals. When two double bonds are conjugated, the four p-atomic orbitals combine to generate four pi-molecular orbitals (two are bonding and two are antibonding). This was&nbsp;<a href="https://www2.chemistry.msu.edu/faculty/reusch/VirtTxtJml/addene2.htm#dien1c" target="_blank" rel="noopener">described earlier</a>&nbsp;in the section concerning diene chemistry. In a similar manner, the three double bonds of a conjugated triene create six pi-molecular orbitals, half bonding and half antibonding. The energetically most favorable π &nbsp;<strong><sup>__</sup>&gt;</strong>&nbsp;π* excitation occurs from the highest energy bonding pi-orbital (<strong>HOMO</strong>) to the lowest energy antibonding pi-orbital (<strong>LUMO</strong>).&nbsp;<br>The following diagram illustrates this excitation for an isolated double bond (only two pi-orbitals) and, on&nbsp;clicking the diagram, for a conjugated diene and triene. In each case the HOMO is colored blue and the LUMO is colored magenta. Increased conjugation brings the HOMO and LUMO orbitals closer together. The energy (ΔE) required to effect the electron promotion is therefore less, and the wavelength that provides this energy is increased correspondingly (<a href="https://www2.chemistry.msu.edu/faculty/reusch/VirtTxtJml/Spectrpy/UV-Vis/spectrum.htm#uv2" target="_blank" rel="noopener">remember</a>&nbsp;&nbsp;&nbsp;<strong>λ = h&nbsp;•&nbsp;c/ΔE</strong>&nbsp;).</p>



<figure class="wp-block-table"><table><tbody><tr><td><a href="javascript:chg2();"></a></td></tr><tr><th>Examples of π&nbsp;<strong><sup>__</sup>&gt;</strong>&nbsp;π* Excitation<br>Click on the Diagram to Advance</th></tr></tbody></table></figure>



<p>Many other kinds of conjugated pi-electron systems act as chromophores and absorb light in the 200 to 800 nm region. These include unsaturated aldehydes and ketones and aromatic ring compounds. A few examples are displayed below. The spectrum of the unsaturated ketone (on the left) illustrates the advantage of a logarithmic display of molar absorptivity. The π&nbsp;<strong><sup>__</sup>&gt;</strong>&nbsp;π* absorption located at 242 nm is very strong, with an ε = 18,000. The weak n&nbsp;<strong><sup>__</sup>&gt;</strong>&nbsp;π* absorption near 300 nm has an ε = 100.</p>



<p>Benzene exhibits very strong light absorption near 180 nm (ε &gt; 65,000) , weaker absorption at 200 nm (ε = 8,000) and a group of much weaker bands at 254 nm (ε = 240). Only the last group of absorptions are completely displayed because of the 200 nm cut-off characteristic of most spectrophotometers. The added conjugation in naphthalene, anthracene and tetracene causes bathochromic shifts of these absorption bands, as displayed in the chart on the left below. All the absorptions do not shift by the same amount, so for anthracene (green shaded box) and tetracene (blue shaded box) the weak absorption is obscured by stronger bands that have experienced a greater red shift. As might be expected from their spectra, naphthalene and anthracene are colorless, but tetracene is orange.</p>



<p>The spectrum of the bicyclic diene (above right) shows some vibrational fine structure, but in general is similar in appearance to that of isoprene,&nbsp;<a href="https://www2.chemistry.msu.edu/faculty/reusch/VirtTxtJml/Spectrpy/UV-Vis/spectrum.htm#uv3b" target="_blank" rel="noopener">shown above</a>. Closer inspection discloses that the absorption maximum of the more highly substituted diene has moved to a longer wavelength by about 15 nm. This &#8220;substituent effect&#8221; is general for dienes and trienes, and is even more pronounced for enone chromophores.</p>



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