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		<title>Interpreting &#038; Analyzing of FTIR Results for Beginners</title>
		<link>https://www.analyzetest.com/2022/02/05/interpreting-analyzing-of-ftir-results-for-beginners/</link>
		
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		<pubDate>Sat, 05 Feb 2022 16:18:36 +0000</pubDate>
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					<description><![CDATA[Click here to see other posts about FT-IR Only 10 $ per sample for interpreting of your FT-IR spectrum Payment Upon Completion Send your spectra... Fourier transform infrared spectroscopy (FTIR) is an experimental test to identify organic/inorganic materials. But for understanding and interpretation of FTIR results, the principles of the analysis should be studied. Principles [&#8230;]]]></description>
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<p class="has-text-align-center"><a href="http://www.analyzetest.com/index.php/category/analyzing/ft-ir/"><em><strong>Click here to see other posts about FT-IR</strong></em></a></p>



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<p>Fourier transform infrared spectroscopy (FTIR) is an experimental test to identify organic/inorganic materials. But for understanding and interpretation of FTIR results, the principles of the analysis should be studied.</p>



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<h2 class="wp-block-heading">Principles of FTIR</h2>


<div class="wp-block-image">
<figure class="alignleft"><a href="https://www.innovatechlabs.com/materials-analysis-ftir/" target="_blank" rel="noopener"><img decoding="async" src="https://www.innovatechlabs.com/wp-content/uploads/2018/07/Innovatech-FTIR-Contact.png" alt="Contact Us for FTIR Analysis" class="wp-image-1883"/></a></figure></div>


<p>To better interpretation of FTIR results, it’s useful to know about&nbsp;the principles of the test.</p>



<p>Generally, by introducing infrared radiation (IR) to a material, FTIR&#8217;s detectors detect a sample’s absorbance of infrared light at various wavenumbers to determine the material’s chemical structure. FTIR spectrometer converts the experimental data from the broadband source to the absorbance level at each wavenumber.</p>



<p>This method can be employed for solids, liquids, and gaseous samples. Some times, the weight of samples required for a viable analysis is very low and most analyses can be conducted with little sampling process.</p>



<h2 class="wp-block-heading" id="how-to-read-ftir-results-graphs">How to interpret FTIR spectra</h2>



<h3 class="wp-block-heading" id="the-x-axis-the-infrared-spectrum">The X-Axis</h3>



<p>The horizontal axis shows the IR spectrum, which represents the intensity of the IR spectra. The absorbance peaks, can be attributed to the various vibrations of the sample’s bonds exposed to the IR energy of the electromagnetic spectrum. Usually, the wavenumber on the IR spectrum is drew between 4000 to 400 cm-1.</p>



<figure class="wp-block-image"><img decoding="async" src="https://www.innovatechlabs.com/wp-content/uploads/2018/07/FTIR-Data-Analysis-X-Axis.png" alt="FTIR Graph Pointing Out X-Axis" class="wp-image-1884"/></figure>



<h3 class="wp-block-heading" id="the-y-axis-absorbance-or-frequency">The Y-Axis</h3>



<p>The vertical axis shows the amount of IR absorbance/transmittance by the under-studied material.</p>



<figure class="wp-block-image"><img decoding="async" src="https://www.innovatechlabs.com/wp-content/uploads/2018/07/FTIR-Data-Analysis-Y-Axis.png" alt="FTIR Graph Pointing Out Y-Axis" class="wp-image-1885"/></figure>



<h3 class="wp-block-heading" id="the-absorbance-bands">The Absorbance Bands</h3>



<p>Generally, absorbance bands can be derived into two groups: Group frequencies and fingerprint frequencies.</p>



<p>Group frequencies are assigned to small groups of bonds such as C-H, O-H, and C=O. These types of bonds are usually observable at 1500-400 cm-1 in the IR spectrum and they are typically unique to a specific bond or functional group in a structure.</p>



<p>For fingerprint frequencies, these are assigned to the chemical structure as a whole. These types of absorbances are usually observable at 400-1500cm-1 in the IR spectrum. Therefore, this region  is less reliable for identification, however the absence of a peak is often more indicative than the presence of a peak in this region.</p>



<figure class="wp-block-image"><img decoding="async" src="https://www.innovatechlabs.com/wp-content/uploads/2018/07/Interpretation-of-FTIR-Spectra-v3.png" alt="Absorbance Bands on a FTIR Graph" class="wp-image-1886"/></figure>



<h2 class="wp-block-heading" id="how-to-interpret-ftir-spectra">How to analyze FT-IR Spectra</h2>



<p>Generally, interpretation of FT-IR spectra starts at the high frequencies end to identify the presence functional groups. The fingerprint regions are then investigated to identify the chemical bonds. </p>



<figure class="wp-block-image"><img decoding="async" src="https://www.innovatechlabs.com/wp-content/uploads/2018/07/Interpretation-of-FTIR-Spectra.png" alt="Interpreting a FTIR Spectra Graph" class="wp-image-1887"/></figure>



<h2 class="wp-block-heading" id="still-curious-about-ftir-analysis">Still Curious About FTIR Analysis?</h2>



<p><a href="http://www.analyzetest.com/index.php/2020/02/14/electrochemical-impedance-spectroscopy-eis/" data-type="post" data-id="27">FTIR&nbsp;</a>is a useful technique for manufacturers and researchers of various industries. If you have more questions about the analysis or are wondering if it may be a fit for your testing needs,<a href="http://www.analyzetest.com/index.php/contact-us/">&nbsp;contact us for a quote</a>. </p>



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		<title>Raman Spectroscopic Study of Graphene</title>
		<link>https://www.analyzetest.com/2021/04/18/raman-spectroscopic-study-of-as-deposited-and-exfoliated-defected-graphene-grown-on-001-si-substrates-by-cvd/</link>
		
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		<pubDate>Sun, 18 Apr 2021 15:06:03 +0000</pubDate>
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					<description><![CDATA[Click here to see other posts about Raman Only 10 $ per sample for interpreting of your Raman spectrum Payment Upon Completion Contact us... We present here results on a Raman spectroscopic study of the deposited defected graphene on Si substrates by chemical vapor deposition (thermal decomposition of acetone). The graphene films are not deposited [&#8230;]]]></description>
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<p>We present here results on a Raman spectroscopic study of the deposited defected graphene on Si substrates by chemical vapor deposition (thermal decomposition of acetone). The graphene films are not deposited on the (001) Si substrate directly but on two types of interlayers of mixed phases unintentionally deposited on the substrates: а diamond-like carbon (designated here as DLC) and amorphous carbon (designated here as&nbsp;<em>α</em>C) are dominated ones. </p>



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<span id="more-1033"></span>



<p>The performed thorough Raman spectroscopic study of as-deposited as well as exfoliated specimens by two different techniques using different excitation wavelengths (488, 514, and 613 nm) as well as polarized Raman spectroscopy establishes that the composition of the designated DLC layers varies with depth: the initial layers on the Si substrate consist of DLC, nanodiamond species, and C<sub>70</sub>fullerenes while the upper ones are dominated by DLC with an occasional presence of C<sub>70</sub>&nbsp;fullerenes. The&nbsp;<em>α</em>C interlayer is dominated by turbostratic graphite and contains a larger quantity of C<sub>70</sub>&nbsp;than the DLC-designated interlayers. The results of polarized and unpolarized Raman spectroscopic studies of as-grown and exfoliated graphene films tend to assume that single- to three-layered defected graphene is deposited on the interlayers. It can be concluded that the observed slight upshift of the 2D band as well as the broadening of 2D band should be related to the strain and doping.</p>



<h4 class="wp-block-heading" id="introduction">1. Introduction</h4>



<p>Graphene is a one-atom-thick layered material that consists of completely sp<sup>2</sup>-bonded carbon atoms tightly packed into a honeycomb lattice. It has a lot of unique properties promising a huge number of possible applications (see, e.g., [<a>1</a>]). A lot of different ways of synthesizing graphene were experimentally tested during the last decade; however, only thermally and plasma-assisted chemical vapor deposition (CVD/PECVD) on metal substrates (copper, nickel, etc.) [<a>2</a>,&nbsp;<a>3</a>] as well as epitaxial growth on SiC substrates and so on [<a>4</a>,&nbsp;<a>5</a>] were developed for industrial application. The latter method is based on C (or Si) termination of the (0001)<sub>C</sub>&nbsp;(or (0001)<sub>Si</sub>) SiC surface and requires high temperature and expensive SiC substrates. The CVD method is based on the plasma-enhanced thermal decomposition of a carbon-containing precursor on a catalytic metal surface. This method provides high reliability and relatively high quality of graphene films, and now, there are a lot of suppliers of reactors for PECVD of graphene. The most preferred precursor is methane (CH<sub>4</sub>) as the chemical bond in CH<sub>4</sub>&nbsp;is relatively strong and prevents fast decomposition of the reagent at temperatures below 1000°C (see, e.g., [<a>6</a>]). However, production for microelectronic applications requires transfer of the graphene layers on an insulating surface and, consequently, a large number of additional defects affecting the properties of graphene can be introduced. Therefore, the problem with the deposition of graphene on silicon (or surfaces compatible with silicon technology such as SiO<sub>2</sub>) still remains unsolved. We demonstrated the possible application of acetone as a precursor in a thermally assisted CVD and showed that few-layered defected graphene/folded graphene can be deposited on commercially available metal foils—Ni, (Cu<sub>0.5</sub>Ni<sub>0.5</sub>),&nbsp;<em>μ</em>-metal, and stainless steel SS 304 in a recently published work [<a>7</a>]. Further, we established (see [<a>8</a>]) by Raman spectroscopy, scanning electron microscopy (SEM), X-ray diffraction (XRD), and grazing incidence X-ray diffraction (GIXRD) as well as by X-ray photoelectron spectroscopy (XPS) the presence of single- to few-layered defected graphene on two different types of interlayers deposited on (100) Si surface: (i) a diamond-like carbon (DLC) layer with some SiC contents (in the range below 5w%) and some residual quantities of SiO<sub>2</sub>, and (ii) a complex amorphous carbon layer consisting of a mixture of sp<sup>2</sup>&#8211; and sp<sup>3</sup>-hybridized carbon as well as very small amount of fullerenes, SiO, and so on.</p>



<p>Here, we focus our experimental study on the Raman spectroscopic characterization of defected as-deposited graphene layers (including polarized spectroscopy) as well as graphene flakes exfoliated from similar specimens by two different ways using 488, 514, and 633 nm excitation laser wavelengths aiming at unambiguous confirmation of the graphene deposition of as well as the identification of the exact composition of the interlayers between the Si substrate and graphene layer/s.</p>



<h2 class="wp-block-heading has-text-align-center" id="contact-us-to-interpret-your-raman-spectra-professionally"><strong><mark><a href="http://www.analyzetest.com/index.php/contact-us/">Contact us</a> to interpret your Raman spectra professionally </mark></strong></h2>



<h4 class="wp-block-heading" id="experimental">2. Experimental</h4>



<h5 class="wp-block-heading" id="sec2.1">2.1. CVD Process</h5>



<p>We use 2 inches in diameter (001) Si substrates and a horizontal tube quartz CVD reactor with an internal diameter of approximately 70 mm. The experimental setup also consists of a gas-supply system (inlet and outlet parts), a thermostat with acetone evaporation alert/indication system, a quartz substrate holder, and a resistive heating furnace. The CVD process is based on thermal decomposition of acetone in Ar main gas flow. The deposition temperature was in the range 1150–1160°C. The temperature of the thermostat was kept at 12°C. In order to prevent the supersaturation in the high-temperature zone of the reactor, we used a “pulsed” regime in experiments by alternating the flow of the gas mixture of Ar + C<sub>3</sub>H<sub>6</sub>O) for 3 min on top of the main flow of pure Ar of about 150–180 cm<sup>3</sup>/min for 1.5 min for each pulse. The optimal results (predominantly single-layered graphene) were obtained after two deposition pulses.</p>



<h5 class="wp-block-heading" id="sec2.2">2.2. Exfoliation</h5>



<p>We exfoliated the carbon films deposited on (001) Si substrates by the following two different techniques:(i)The Scotch tape method (see, e.g., [<a>9</a>]): we put tightly the adhesive Scotch tape on the multilayered graphene side of the specimens. After peeling the tape off the specimen, a single- to few-layered graphene remains on the tape’s surface and the interlayer between the upper few layers of graphene and the substrate becomes accessible for spectroscopic examination. Then, we put tightly the Scotch tape with graphene flakes either on 320 nm SiO<sub>2</sub>/Si or on glass substrate. About 30–50% of the graphene flakes remain adhered to the SiO<sub>2</sub>&nbsp;or glass substrate after removing the tape due to the Van der Waals force.(ii)We also adhered the multilayered graphene side of the specimens to epoxy resin. After careful cleavage, the most part of the graphene layer/s remains on the surface of the resin. Then, the adhered to the resin graphene film becomes accessible for spectroscopic examination. The Raman spectrum of the epoxy resin does not contain strong peaks around the 2D band of graphene (the area around 2630–2670 cm<sup>−1</sup>). We established that the 2D band of graphene is clearly distinguishable for graphene regions lying on gas bubbles close to the surface of the resin; otherwise, the 2D band of graphene is weak.</p>



<h5 class="wp-block-heading" id="sec2.3">2.3. Characterization</h5>



<p>The Raman measurements were carried out in backscattering geometry at a micro-Raman HORIBA Jobin Yvon Labram HR 800 visible spectrometer equipped with a Peltier-cooled CCD detector with a He-Ne (633 nm wavelength and 0.5 mW) laser excitation. The 514 nm (about 23 mW) as well as 488 nm (about 24 mW) lines of an external Ar laser were also used. The laser beam was focused on a spot of about 1 <em>μ</em>m in diameter, the spectral resolution being 0.5, 0.7, and 1 cm<sup>−1</sup>, respectively, or better.</p>



<p>The Raman spectrum of graphene is a clearly established fingerprint of this 2D material (see [<a>10</a>]). The main first-order features in the Raman spectra of graphene and defect-infested graphene excited at 633 nm wavelength are the following:(i)G band (~1582 cm<sup>−1</sup>) is the only band in graphene allowed by selection rules for first-order Raman effect; it is ascribed to optical (iTO and LO) doubly degenerate phonons of E<sub>2g</sub>&nbsp;symmetry at the Γ point (initially described by Tuinstra and Koenig [<a>11</a>]).(ii)D band (~1330 cm<sup>−1</sup>) is due to breathing-like bands of C hexagonal rings (corresponding to transverse optical phonons near the K point) and requires a defect for its activation via an intervalley double-resonance Raman process (see [<a>12</a>]).(iii)D’ band (at about 1615 cm<sup>−1</sup>; defect induced similarly to the D band) occurs via an intravalley double-resonance process (see, e.g., [<a>13</a>]).(iv)D” band (at about 1145 cm<sup>−1</sup>) is resulting from double-resonance intervalley scattering of LA phonons on defects (see [<a>14</a>]). The intensity of this band should be about 100 times lower than that of the D band.</p>



<p>Overtones and combination bands:(i)2D band (historically known from graphite and carbon nanotube-related literature as G’- peak) appears at about 2648–2665 cm<sup>−1</sup>. It is clearly shown [<a>15</a>–<a>20</a>] that the shape and width of the 2D band can be used for the identification of the mono-, bi-, and three-layered graphene.(ii)The overtone of the D’- peak (2D’) and combination G&nbsp;(phonons), as well as (D+D’) bands, occur around 3230, 2450, and 2930 cm<sup>−1</sup>, respectively (see [<a>21</a>]).</p>



<h4 class="wp-block-heading" id="results-and-discussion">3. Results and Discussion</h4>



<p>Two areas with different surface morphologies are observed by optical microscopy (Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig1/#a" target="_blank" rel="noreferrer noopener">1(a)</a>): a clear relief (ridge-like formations) lying along &lt;001&gt; directions covers the first area denoted as DLC while the second area (denoted as&nbsp;<em>α</em>C) is covered by an inhomogeneous film with a constant depth. It should be also mentioned that optical inhomogeneities are observed on the DLC as well as&nbsp;<em>α</em>C-marked areas.<img decoding="async" alt="(a)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.001a.svgz"><br><strong>(a)</strong><img decoding="async" alt="(b)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.001b.svgz"><br><strong>(b)</strong><img decoding="async" alt="(c)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.001c.svgz"><br><strong>(c)</strong><img decoding="async" alt="(d)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.001d.svgz"><br><strong>(d)</strong><img decoding="async" alt="(e)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.001e.svgz"><br><strong>(e)</strong><img decoding="async" alt="(a)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.001a.svgz"><br><strong>(a)</strong><img decoding="async" alt="(b)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.001b.svgz"><br><strong>(b)</strong><img decoding="async" alt="(c)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.001c.svgz"><br><strong>(c)</strong><img decoding="async" alt="(d)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.001d.svgz"><br><strong>(d)</strong><img decoding="async" alt="(e)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.001e.svgz"><br><strong>(e)</strong><strong>Figure 1</strong>Optical microscopy image of the surface morphology of (a) as-deposited graphene and graphene-related phases on diamond-like carbon (DLC) and amorphous carbon (<em>α</em>C) interlayers. The arrows remarked [100] and [010] directions of the Si substrate. The marker represents 20 <em>μ</em>m. (b) The exfoliated and transferred graphene flakes on 320 nm SiO<sub>2</sub>. The Raman spectra are taken from “+”-marked positions. The marker represents 30 <em>μ</em>m. (c) The layers remaining on the surface of the substrate after exfoliation by Scotch tape. The Raman spectra are taken from the “+”-marked positions near points 1, 2, and 3. The marker represents 30 <em>μ</em>m. (d) The exfoliated and transferred graphene flakes on glass substrate. The Raman spectra are taken from the “+”-marked positions near points 1 and 2. The marker represents 20 <em>μ</em>m. (e) A graphene flake on air bubble near the epoxy resin surface. The Raman spectra are taken from the square-marked position. The marker represents 20 <em>μ</em>m.</p>



<p>It should be recalled that the Raman spectrum (excited at 633 nm laser wavelength) taken from&nbsp;<em>α</em>C- and DLC-denoted areas (see [<a>8</a>]) contains all features typical for graphene: symmetric and clearly pronounced 2D band with full width at a half maximum (FWHM) of 40–56 cm<sup>−1</sup>, I<sub>2D</sub>/I<sub>G</sub>&nbsp;ratio between 2 and 3.5, and I<sub>2D</sub>/I<sub>D</sub>&nbsp;ratio between 2 and 4. However, the 2D band appears at about 2660–2668 cm<sup>−1</sup>&nbsp;(for single- and bilayered graphene, respectively), that is, it is blueshifted by about 20 cm<sup>−1</sup>&nbsp;relative to the results presented in [<a>15</a>,&nbsp;<a>22</a>,&nbsp;<a>23</a>].</p>



<p>Due to the double-resonance origin of most of the monitored spectral features, we perform a Raman spectroscopy examination of as-deposited defected graphene at 488, 514, and 633 nm excitation wavelengths and the results are presented in Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig2/" target="_blank" rel="noreferrer noopener">2</a>. The 2D bands are blueshifted by about 20 cm<sup>−1</sup>&nbsp;and can be typically deconvoluted into (a) a single Lorentzian with FWHM of about 40-41 cm<sup>−1</sup>&nbsp;(see Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig3/#a" target="_blank" rel="noreferrer noopener">3(a)</a>); (b) four Lorentzians (FWHM of 22 (±1) cm<sup>−1</sup>) for 2D band with total width of 45–56 cm<sup>−1</sup>&nbsp;(see Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig3/#b" target="_blank" rel="noreferrer noopener">3(b)</a>); and (c) six Lorentzians (Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig3/#c" target="_blank" rel="noreferrer noopener">3(c)</a>) for 2D band with total width larger than 56 cm<sup>−1</sup>. The results of the deconvolution indicate the presence of single-, bi-, and three-layered defected graphene, respectively (see [<a>15</a>–<a>20</a>]). We did not establish a clear difference between the graphene layers deposited on&nbsp;<em>α</em>C and DLC interlayers; however, bi- and three-layered areas were more frequently observed on DLC interlayers. The results for predominantly single-layered (SL) and bilayered (BL) defected graphene (according to the deconvolution of 2D bands) are summarized in Table&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/tab1/" target="_blank" rel="noreferrer noopener">1</a>.</p>



<figure class="wp-block-image"><img decoding="async" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.002.svgz" alt=""/></figure>



<p><strong>Figure 2</strong>Raman spectra taken from as-grown films excited at 633 nm (red trace), 514 nm (blue trace), and 488 nm (green trace) laser wavelengths.<img decoding="async" alt="(a)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.003a.svgz"><br><strong>(a)</strong><img decoding="async" alt="(b)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.003b.svgz"><br><strong>(b)</strong><img decoding="async" alt="(c)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.003c.svgz"><br><strong>(c)</strong><img decoding="async" alt="(a)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.003a.svgz"><br><strong>(a)</strong><img decoding="async" alt="(b)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.003b.svgz"><br><strong>(b)</strong><img decoding="async" alt="(c)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.003c.svgz"><br><strong>(c)</strong><strong>Figure 3</strong>Deconvolution of 2D band identified as coming from single-layered (a), bilayered (b), and three-layered defected graphene deposited on&nbsp;<em>α</em>C. The spectrum is excited at 633 nm laser wavelength.<strong>Table 1</strong>Summarized results of Raman spectroscopy examination of as-deposited defected graphene films.</p>



<p>In order to access the interlayers as well as graphene flakes for Raman examination, the so-called Scotch tape method was initially used for exfoliation. The Raman spectra of the graphene flakes exfoliated in this way with some occasional amorphous (<em>α</em>C) interlayers transferred to Si/SiO<sub>2</sub>&nbsp;(300 nm) or glass substrate are shown in Figures&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig4/" target="_blank" rel="noreferrer noopener">4</a>&nbsp;and&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig5/" target="_blank" rel="noreferrer noopener">5</a>, respectively.</p>



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<p><strong>Figure 4</strong>The Raman spectrum of defected 1-2-layered graphene transferred on 320 nm SiO<sub>2</sub>. The 2D band is symmetric and appears at 2658-2659 cm<sup>−1</sup>&nbsp;with FWHM of 38–40 cm<sup>−1</sup>&nbsp;(measured in point 2) and 40–42 cm<sup>−1</sup>&nbsp;(measured in point 1).</p>



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<p><strong>Figure 5</strong>The Raman spectrum of the interlayer (point 1, Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig1/#c" target="_blank" rel="noopener">1(c)</a>) of&nbsp;<em>α</em>C after exfoliation by Scotch tape. The features observed at about 1450 and 1530 cm<sup>−1</sup>&nbsp;are typical for C<sub>70</sub>&nbsp;fullerenes.</p>



<p>A lot of flakes (of the order of 10<sup>2</sup>) were transferred on Si/SiO<sub>2</sub>&nbsp;and examined by Raman spectroscopy. The Raman spectra are enhanced due to interference effects caused by the SiO<sub>2</sub>&nbsp;300 nm layer over the Si substrate, and I<sub>2D</sub>/I<sub>G</sub>&nbsp;varies in the range 3.5-6.0. However, it was impossible to isolate single-layered graphene flake (or to obtain clear Raman response of single-layered graphene) in this way. The exfoliated flakes were never transparent (see point 1 in Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig1/#b" target="_blank" rel="noreferrer noopener">1(b)</a>). The best spectra were recorded from the points in a darker contrast (point 2 in Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig1/#b" target="_blank" rel="noreferrer noopener">1(b)</a>), but the FWHM of 2D Raman band remains &gt;35 cm<sup>−1</sup>. Moreover, the D” band slightly overlaps with the second order of Si substrate when the spectrum is excited at 514 as well as 488 nm laser wavelengths.</p>



<p>After peeling the tape off the specimen, the interlayer between the upper flake and the substrate is accessed. The remaining interlayers have different optical contrasts (see Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig1/#c" target="_blank" rel="noreferrer noopener">1(c)</a>) and Raman spectra: the spectrum of typically retained interlayer (point 1 in Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig1/#c" target="_blank" rel="noreferrer noopener">1(c)</a>) in Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig5/" target="_blank" rel="noreferrer noopener">5</a>&nbsp;is very similar to that of turbostratic graphite (see [<a>24</a>]), but weak peaks of C<sub>70</sub>&nbsp;fullerenes (the features observed at about 1450 and 1530 cm<sup>−1</sup>&nbsp;(see [<a>25</a>,&nbsp;<a>26</a>])) are also clearly distinguished (Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig5/" target="_blank" rel="noreferrer noopener">5</a>). The strong modes of fullerenes C<sub>70</sub>&nbsp;at about 1180 and 1568 cm<sup>−1</sup>&nbsp;are merged with D” and G bands.</p>



<p>The Raman spectra (Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig6/" target="_blank" rel="noreferrer noopener">6</a>) taken from points 2 and 3 (Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig1/#c" target="_blank" rel="noreferrer noopener">1(c)</a>) are similar as they contain the most prominent modes of C<sub>70</sub>&nbsp;peaks at 1160, 1220, 1454, 1526, and 1565 cm<sup>−1</sup>&nbsp;[<a>25</a>,&nbsp;<a>26</a>], nanodiamond (Nd) peaks at 1330 and 1620 cm<sup>−1</sup>&nbsp;(see [<a>27</a>]), and turbostratic graphite. The D, G, and D’ bands are found at 1335, 1590, and 1612 cm<sup>−1</sup>, respectively, but in a different proportion: the spectrum from point 3 is dominated by the peaks of C<sub>70</sub>&nbsp;and Nd while the spectrum from point 2 is dominated by turbostratic graphite (see Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig6/" target="_blank" rel="noreferrer noopener">6</a>). It should be also remarked that features of C<sub>60</sub>&nbsp;fullerenes (see, e.g., [<a>25</a>,&nbsp;<a>26</a>]) were not observed.</p>



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<p><strong>Figure 6</strong>Raman spectra of the interlayer that remains on the substrate after exfoliation by the Scotch tape method taken from points 2 and 3 (Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig1/#c" target="_blank" rel="noopener">1(c)</a>).</p>



<p>As it was mentioned above, the D” band overlaps with the second-order band of Si substrate especially when the spectrum is excited at 488 and 514 nm laser wavelengths. In order to distinguish the dispersion of the D” band of several Scotch tape methods, exfoliated flakes were transferred on glass substrates. The flakes have very similar surface morphology to those transferred on SiO<sub>2</sub>/Si substrates (Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig1/#d" target="_blank" rel="noreferrer noopener">1(d)</a>). The Raman spectrum of such flakes is not significantly different from that of the as-deposited layers (Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig7/" target="_blank" rel="noreferrer noopener">7</a>); however, the D” band appears at 1096 (for 488 nm excitation) and at 1135 cm<sup>−1</sup>&nbsp;(for 633 nm excitation), respectively, that is, they coincide with the data of Herziger et al. [<a>14</a>].</p>



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<p><strong>Figure 7</strong>The Raman spectra of as-grown graphene on&nbsp;<em>α</em>C excited at 488 nm (green trace) and 633 nm (black trace) wavelengths. The similar spectra of exfoliated graphene transferred on a glass substrate excited at 488 nm (blue trace) and 633 nm (red trace). The inset: magnified part of the region 900–1200 cm<sup>−1</sup>.</p>



<p>According to the above results, we conclude that the exfoliation by the Scotch tape method does not enable splitting up between the defected graphene and the interlayers (especially the&nbsp;<em>α</em>C-designated one). Another way for exfoliation was probed (by exfoliation on epoxy resin), and the optical micrograph image of the area of the edge of a resin bubble and the Raman spectrum taken from this area (excited at 633 nm) are shown in Figures&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig1/#e" target="_blank" rel="noreferrer noopener">1(e)</a>&nbsp;and&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig8/" target="_blank" rel="noreferrer noopener">8</a>, respectively. The Raman spectrum of epoxy resin does not contain any features in the 2D region of graphene (upper trace in Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig8/" target="_blank" rel="noreferrer noopener">8</a>); hence, 2D bands of a single- and bilayered graphene were identified at the edge of a lot of bubbles on the surface of the resin (Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig1/#e" target="_blank" rel="noreferrer noopener">1(e)</a>). It should be clearly remarked that the measured FWHM of the 2D band of such single-layered graphene is about 27–29 cm<sup>−1</sup>, but it is situated at 2654–2656 cm<sup>−1</sup>, that is, it remains upshifted with about 10–15 cm<sup>−1</sup>.</p>



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<p><strong>Figure 8</strong>Raman spectra of graphene films situated on air bubbles/cavities. The 2D band is situated at 2655 cm<sup>−1</sup>&nbsp;and has FWHM ~28 cm<sup>−1</sup>&nbsp;(i.e., it corresponds to single-layered graphene—blue trace).</p>



<p>Recently, Li et al. [<a>28</a>] established that the intensity of 2D band varies as a cosine to the fourth power when the laser propagation direction is parallel to the graphene layer and the polarization is rotated around it. They also derived the orientation distribution function of monolayered graphene as well as that of graphene paper and highly oriented pyrolytic graphite. We perform similar measurements in&nbsp;<em>X</em>(<em>Y<sub>φ</sub>Y<sub>φ</sub></em>)<em>X</em>&nbsp;geometry,&nbsp;<em>φ</em>&nbsp;being the angle between the incident laser beam polarization and the graphene layer plane;&nbsp;<em>Z</em>&nbsp;is the axis perpendicular to the graphene plane, and the laser beam propagates transversely to the graphene layer along the&nbsp;<em>X</em>&nbsp;direction (see Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig9/#a" target="_blank" rel="noreferrer noopener">9(a)</a>). The excitation laser beam was focused in a manner to comprise no more than 30% of the edge of the Si substrate and graphene film (Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig9/#a" target="_blank" rel="noreferrer noopener">9(a)</a>). The parallel scattering geometry was used. The measurements were performed starting from&nbsp;<em>φ</em> = 0° (corresponding to&nbsp;<em>X</em>(<em>YY</em>)<em>X</em>&nbsp;in Porto notations) and finished at&nbsp;<em>φ</em> = 180°. The preliminary results of these rotational angle-dependent Raman measurements of as-deposited specimen are presented in Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig9/" target="_blank" rel="noreferrer noopener">9</a>. The signal significantly drops upon changing the angle from 0° to 90° and increases again in the interval between 90 and 180° which resembles indeed the cos<sup>4</sup>&nbsp;law. At 90° (corresponding to&nbsp;<em>X</em>(<em>ZZ</em>)<em>X</em>&nbsp;in Porto notations), the Raman signal is very weak but still observable (Figure&nbsp;<a href="https://www.hindawi.com/journals/jspec/2017/3495432/fig9/" target="_blank" rel="noreferrer noopener">9</a>), and the rotational angle-independent features of C<sub>70</sub>&nbsp;fullerenes and nanodiamond (Nd) dominate the spectrum. The residual features in the Raman spectra taken at&nbsp;<em>φ</em> = 90° point out that the measured polarized Raman spectra are taken from graphene deposited on DLC interlayer. The measurements in this scattering geometry (<em>X</em>(<em>YY</em>)<em>X</em>&nbsp;in Porto notations) access measurements of the interlayer/s without exfoliation. On the other hand, the polarized Raman study confirms the deposition of graphene because the intensities of the most prominent Raman features of graphite (D, G, and 2D bands) show similar behavior in similar conditions as those of graphene. However, the intensity of the Raman features of graphene decreases significantly slower than those of graphene as it is shown in [<a>28</a>].<img decoding="async" alt="(a)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.009a.svgz"><br><strong>(a)</strong><img decoding="async" alt="(b)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.009b.svgz"><br><strong>(b)</strong><img decoding="async" alt="(a)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.009a.svgz"><br><strong>(a)</strong><img decoding="async" alt="(b)" src="https://static-01.hindawi.com/articles/jspec/volume-2017/3495432/figures/3495432.fig.009b.svgz"><br><strong>(b)</strong><strong>Figure 9</strong>(a) Optical photography of the specimen in&nbsp;<em>X</em>(<em>YY</em>)<em>X</em>&nbsp;geometry (in Porto notations). The inset: optical photography of the specimen in&nbsp;<em>Z</em>(<em>YY</em>)<em>Z</em>&nbsp;geometry (in Porto notations). The arrow-remarked laser spots are eye guide showing the real area of the laser spot during measurements. The marker represents 10 <em>μ</em>m. (b) Spatially resolved Raman spectra of as-deposited defected graphene at 633 nm excitation.</p>



<p>It is worth noting that the 2D band from the single-layered graphene regions is symmetric and strong, but it is somewhat broadened with FWHM of about 40–42 cm<sup>−1</sup>and is blueshifted by 15–20 cm<sup>−1</sup>&nbsp;in as-grown specimens. It is well known that such behavior is usually related to strain (see [<a>29</a>–<a>32</a>]) and doping [<a>33</a>]. Moreover, Lee et al. [<a>34</a>] and Bouhafs et al. [<a>35</a>] experimentally studied the influence of these parameters on the position and FWHM of G and 2D bands in single- and bi-/multilayered graphene, respectively. The deduced simple plot of the 2D versus G band positions enables distinguishing the influence of doping and strain on the positions of G and 2D bands. In our single-layered specimens, the G band is slightly uphifted by 1-2 cm<sup>−1</sup>&nbsp;while the 2D band is more significantly blueshifted and broadened by 10–20 cm<sup>−1</sup>. Therefore it can be assumed that the 2D band blueshift and broadening are due to the lattice strain predominantly as well as to the doping. It can be suggested that the lattice strain is due to the bonding between graphene and the interlayers while the doping should be related to charge transfer from the interlayers/interfaces to graphene as well as to different intrinsic (grain boundaries, etc.) and extrinsic (trapped nitrogen, oxygen, and impurities during the deposition) defects, that is, it can be related to the influence of the interlayers/substrates as well as of the deposition process.</p>



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<h4 class="wp-block-heading" id="conclusions">4. Conclusions</h4>



<p>We extended the analysis of defected graphene deposited by CVD as well as the two types of interlayers between the defected graphene layer/s and Si substrates by both unpolarized and polarized Raman spectroscopy. The performed Raman spectroscopy examination of as-deposited defected graphene at 488, 514, and 633 nm excitation wavelengths enables the most of the monitored spectral features of double-resonance origin (D, D”, and 2D bands). The Raman studies of exfoliation by the so-called Scotch tape method revealed that (a) the composition of the designated DLC interlayers varies with depth: the initial layers on the Si substrate consist of a mixed phase of turbostratic graphite, nanodiamond/diamond-like carbon, and C<sub>70</sub>&nbsp;fullerenes while the upper ones are dominated by diamond-like carbon and some C<sub>70</sub>&nbsp;fullerenes and (b) the amorphous carbon interlayer is dominated by turbostratic graphite and contains a larger quantity of C<sub>70</sub>&nbsp;than the DLC-designated interlayers. Single- and bilayered defected graphene flakes were exfoliated on epoxy resin. The preliminary results of polarized Raman experiments show that the intensity of the 2D band varies as a cosine to the fourth power when the laser propagation direction is parallel to the graphene layer and the polarization is rotated around it which is an additional indication of the deposition of single-layered graphene. The results of Raman spectroscopic studies of as-grown and exfoliated graphene films tend to assume that the observed slight upshift of the 2D band as well as the broadening of 2D band is due to the strain and can be related to the bonding between the graphene and the interlayers, that is, it could be regarded as an influence of the interlayers between the defected graphene and the Si substrates.</p>



<h4 class="wp-block-heading" id="conflicts-of-interest">Conflicts of Interest</h4>



<p>The authors declare that there is no conflict of interest regarding the publication of this paper.</p>



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</ol>



<p>Authors: <strong>T. I. Milenov</strong>,<sup>1</sup>&nbsp;E. Valcheva,<sup>2</sup>&nbsp;and&nbsp;V. N. Popov<sup>2</sup></p>
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		<title>Determination of band gap using UV-Vis spectra</title>
		<link>https://www.analyzetest.com/2021/04/04/determination-of-band-gap-using-uv-vis-spectra/</link>
		
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				<category><![CDATA[How To Analyze ...]]></category>
		<category><![CDATA[UV-Vis]]></category>
		<category><![CDATA[band gap]]></category>
		<category><![CDATA[calculation]]></category>
		<category><![CDATA[data]]></category>
		<category><![CDATA[diagram]]></category>
		<category><![CDATA[energy]]></category>
		<category><![CDATA[garph]]></category>
		<category><![CDATA[interpretation]]></category>
		<category><![CDATA[m]]></category>
		<category><![CDATA[peak]]></category>
		<category><![CDATA[spectra]]></category>
		<category><![CDATA[spectroscopy]]></category>
		<category><![CDATA[spectrum]]></category>
		<category><![CDATA[Ultraviolet]]></category>
		<category><![CDATA[visible]]></category>
		<category><![CDATA[wavelength]]></category>
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					<description><![CDATA[Click here to see more posts about UV-Vis spectroscopy Only 10$ per sample for interpreting of your UV-Vis spectrum Payment Upon Completion Send your UV-Vis spectra... STEP1:&#160;Open the absorption graph of the material, which is obtained from the UV Vis spectroscopy. Theory Behind Calculations:&#160;UV Vis Spectroscopy absorption peak means the Electrons are absorbing the Energy [&#8230;]]]></description>
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<p class="has-text-align-center"><strong><em><a href="http://www.analyzetest.com/index.php/category/analyzing/uv-vis/">Click here to see more posts about UV-Vis spectroscopy</a></em></strong></p>



<pre class="wp-block-verse has-text-align-center"><span style="color:#ffffff" class="tadv-color">Only 10$ per sample for interpreting of your UV-Vis spectrum
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<p><strong>STEP1:</strong>&nbsp;Open the absorption graph of the material, which is obtained from the UV Vis spectroscopy. </p>



<p><strong>Theory Behind Calculations:</strong>&nbsp;UV Vis Spectroscopy absorption peak means the Electrons are absorbing the Energy at some specific wavelength. Electrons are absorbing Energy means the Electrons are going to excited state from its ground state. Electrons are going to excited state from its ground state means the material is having band gap, thus which can be determine by absorption wavelength.</p>



<figure class="wp-block-image size-large"><a href="http://www.analyzetest.com/index.php/contact-us/"><img decoding="async" src="http://s7.picofile.com/file/8392387600/uv_vis_in.gif" alt=""/></a></figure>



<span id="more-953"></span>



<figure class="wp-block-image size-large"><img fetchpriority="high" decoding="async" width="695" height="327" src="http://www.analyzetest.com/wp-content/uploads/2021/04/uv.png" alt="" class="wp-image-954" srcset="https://www.analyzetest.com/wp-content/uploads/2021/04/uv.png 695w, https://www.analyzetest.com/wp-content/uploads/2021/04/uv-300x141.png 300w" sizes="(max-width: 695px) 100vw, 695px" /></figure>



<p>Energy Equation of Quantum Mechanics:</p>



<p>Energy (E) = Planks Constant (h) * Speed of Light (C) / Wavelength (λ)</p>



<p>Where, Energy (E) = Band gap, Planks constant (h) = 6.626×10^-34 Joules sec, Velocity of Light (C) = 2.99×10^8 meter/sec and Wavelength (λ) = Absorption peak value. Also 1eV = 1.6×10^-19 Joules (Conversion factor)</p>



<p>By this formula band gap can be calculated easily, from UV Vis spectroscopy absorption peak.</p>



<p><strong>The basis of the spectrophotometer</strong><br>In general, the amount of light absorbed by a substance in a liquid state is directly related to the concentration of that substance in the liquid. If the sample is solid, it must first be dissolved in a clear solvent to be measurable. The sample solvent (known as the control) is usually considered without adsorption or in practice its partial adsorption is less than the total adsorption (sample with solvent). The sample with the solvent is usually poured into a clear glass container or a quartz container and placed in front of the light passing through the spectrophotometer. This dish is called Cell or Quvette. Of course, using add-ons on the spectrometer device, solid or gas samples can also be analyzed, which will be discussed in detail in the articles of this article.</p>



<p>The spectrophotometer uses a tungsten lamp to produce visible light and a deuterium lamp to produce ultraviolet or UV light. The normally measured wavelength range in this device is from 1100 nm to 190 nm. More equipped devices are usually used to measure areas outside this range. Given that a particular molecule may absorb light in a well-defined region of the wavelength range, the light produced must be separated and adjustable to the component wavelengths in a given region. Grating Mirror or prism mirror is used to uniformize the light in the spectrophotometer.</p>



<p>Parts of the ultraviolet and visible spectrometer<br>the source of light<br>Prism or grating mirror<br>Monochromator<br>Detector, detector or photodiode<br>Processor<br>The following figure shows an overview of how this device works.</p>



<p>Visible ultraviolet spectrophotometer<br>Spectrophotometer device diagram</p>



<p>In the visible and ultraviolet spectrometer, after the light passes through the solution, the remaining light sample is inside a detector of Photomultiplier or Photodiode type and after computer processing as a number of one hundred as the percentage of light transmission or its logarithm with The title of the light absorption number appears on the display. Calculations of light absorption or transmission follow Lambert Beer&#8217;s law. Mathematically, the amount of light I0 passes through an environment with length X and concentration C, the intensity of the residual light I after passing through the environment is:<br>I = I0e-KCX<br>In this relation, K will be a relative constant (absorption coefficient). Therefore, the absorption of the environment or A is obtained as follows:<br>A = log (I0 / I) = KCX</p>



<p>Spectrophotometer is available in two types of single beam single beam and double beam double beam. The single beam system compares the light absorbed after placing the sample in the device with the main light before placing the sample in the device. One of the advantages of this system is its simplicity, smallness and cheapness, and one of its disadvantages is a small error due to the instability of the measurement environment.</p>



<p>But the two-beam system has two beams, one of which goes to the detector at the same time and the other passes through the sample and the difference between the two is calculated. One of the advantages of this system is more accuracy compared to the single-beam system, and its disadvantages are its complexity and more expensive price. The image below is a schematic of a 2-ray spectrophotometer.</p>



<p>Depending on the spectral region in which the spectral region is performed and which radiation properties (absorption, emission, transmission, scattering, reflection, etc.) are examined, the type of electronic transmissions and consequently the type of spectroscopy and device will be different.<br>In nasal spectroscopy, absorption is a process in which a chemical species in a transparent medium selectively attenuates (reduces its intensity) certain frequencies of electromagnetic radiation. In the ultraviolet / visible region, the energy of electromagnetic radiation is such that it causes electron transitions in valence electrons. For atoms and ions in the elemental state, the energy of each level is due to the movement of electrons around the nucleus. These states of energy are called electronic states. In addition to having electron energy levels, molecules also have vibrational energy levels and rotational energy levels. These alignments result from the vibration between the atoms in the molecule and from the rotation of the molecules around their own center of mass in space, respectively. In the energy level level diagram, several rotational levels are placed between the two vibrational levels and several vibrational levels are placed between the electronic level levels. Accordingly, each electronic level has vibrating levels and each vibrating level in turn has its own rotational levels. Each of these energy states is about ten times smaller than each other</p>
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		<title>Quantification of FT-IR spectrum</title>
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		<pubDate>Sun, 04 Apr 2021 12:21:07 +0000</pubDate>
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					<description><![CDATA[Click here to see other posts about FT-IR Only 10 $ per sample for interpreting of your FT-IR spectrum Payment Upon Completion Send your spectra... FTIR Spectroscopy is an analytical technique used to identify organic, polymeric, and, in some cases, inorganic materials. The&#160;FTIR analysis&#160;method uses&#160;infrared&#160;light to scan&#160;testsamples and observe chemical properties. When trying to identify [&#8230;]]]></description>
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<p>FTIR Spectroscopy is an analytical technique used to identify organic, polymeric, and, in some cases, inorganic materials. The&nbsp;FTIR analysis&nbsp;method uses&nbsp;infrared&nbsp;light to scan&nbsp;testsamples and observe chemical properties. When trying to identify an unknown material, FTIR (Fourier Transform Infrared Spectroscopy) analysis is a great tool to answer, &#8220;What is it?&#8221;. It works well for solids, liquids and gases, and can be applied to pure substances or mixtures. Quantitative or qualitative analysis is available. FTIR is not the best technique to measure trace contaminants, but functions extremely well identifying bulk materials.&nbsp;</p>



<span id="more-948"></span>



<p><br>Are you trying to determine material composition, identify impurities, or track changes in your raw materials or finished product? FTIR can provide quality control for your manufacturing process. FTIR analysis also has regulatory compliance applications, such as Respirable silica (NIOSH 7602), for industrial hygiene at construction and petroleum fracking sites.&nbsp;<br>Fourier Transform Infrared Spectroscopy (or FTIR for short) identifies chemical bonds in materials via their infrared absorption spectrum. Transmission and Attenuated Total Reflectance (ATR) modes permit analysis of a wide range of solids, powders, non-aqueous liquids and gases.&nbsp;<br>The FTIR spectrum is the &#8220;infrared fingerprint&#8221; of the material. Qualitatively, unknowns can be identified by comparison with an extensive library of FTIR spectra. Our reference sample database includes tens of thousands of spectra for comparison purposes. Quantitatively, FTIR-ATR Analysis is often the first step in the materials analysis process due to its speed and simplicity.&nbsp;<br>Samples weighing as little as 50 milligrams can be evaluated using FTIR-ATR analysis. The small sample size allows for selective identification of particles, residues, films or fibers.</p>



<p><strong>Applications of FTIR Transmission &amp; ATR Analysis:</strong></p>



<ul class="wp-block-list">
<li>Quantitative Scans</li>



<li>Qualitative Scans</li>



<li>Solids</li>



<li>Non-Aqueous Liquids</li>



<li>Organic Samples</li>



<li>Inorganic Samples</li>



<li>Unknowns Identification</li>



<li>Impurities Screening &#8211; Routine QA/QC analysis with Accept/Reject limits</li>



<li>Soil Pharmaceuticals</li>



<li>Paints, Coatings</li>



<li>Laminates</li>



<li>Assessing purity &#8211; raw materials, intermediate materials, finished product</li>



<li><strong>Polymers, plastics &#8211; Identifying:</strong>
<ul class="wp-block-list">
<li>Base polymer composition</li>



<li>Additives</li>



<li>Organic contaminants</li>



<li>General type of material being analyzed when there are unknows</li>
</ul>
</li>



<li><strong>Common Household Items</strong>
<ul class="wp-block-list">
<li>Cleansers and Detergents</li>



<li>Baking Powders and Ingredients</li>



<li>Paints</li>



<li>Oils</li>



<li>Paper</li>



<li>Medications</li>
</ul>
</li>



<li><strong>Fibers</strong>
<ul class="wp-block-list">
<li>Synthetic Fibers (acrylic, nylon, polyester, rayon)</li>



<li>Natural Fibers (cotton, silk, wood)</li>
</ul>
</li>



<li><strong>Adhesives</strong>
<ul class="wp-block-list">
<li>Glue</li>



<li>Epoxy</li>



<li>Resin</li>
</ul>
</li>



<li><strong>Biodiesel Content in Diesel Fuel</strong>
<ul class="wp-block-list">
<li>Trace Level (0.025%) measurement for biodiesel averse applications</li>



<li>Gross composition</li>
</ul>
</li>
</ul>



<p><strong>Qualitative Scans</strong>&nbsp;</p>



<p>Qualitative scans can be used to rapidly assess unknown materials for identification and for rapid checks on impurities. In terms of process QC, high quality spectral scan of your reference material(s) can be generated and stored in our spectral library database and quickly compared to new materials in your manufacturing process and flag them as acceptable or unacceptable.</p>



<p><strong>Quantitative Scans</strong>&nbsp;</p>



<p>A wide variety of materials can be quantified using the FTIR-ATR materials characterization technique. Quantification requires that a standard calibration curve of known concentrations be created. This is how FTIR is used for the analysis of respirable silica using the NIOSH 7602 method or for determining low levels of Biodiesl in diesel fuel.</p>



<p>ATR-FTIR can be effectively used for quantitative analysis. Non-destructive measurement of samples is possible using ATR-FTIR. Prepare known concentrations of your samples and analyze. For this you must know the prominent IR peak in your sample. Measure &nbsp;peak heights/areas and prepare a calibration curve. From this you can determine the concentration in unknown sample by noting peak height.&nbsp;It depends on what kind of material you are analyzing. If your material varies in composition as a function of time or temperature, the thickness of your sample may vary too (e.g. due to evaporation of solvent etc). In such case, you have to select a peak that remains constant (not shifting) during the entire process. In absorption mode, find out the area (not the height) of the main peak (of your interest) and divide with the area of the constant peak.</p>



<p><strong>Below is our calibration for respirable alpha silica using NIST standards:</strong></p>



<figure class="wp-block-image"><img decoding="async" src="https://www.mccampbell.com/images/FTIR_1.jpg" alt="FTIR Calibration Example using NIST Standards"/></figure>



<p><strong>A few of the spectra used in this calibration (from NIST Standards) are shown below:</strong></p>



<figure class="wp-block-image"><img decoding="async" src="https://www.mccampbell.com/images/FTIR.jpg" alt="FTIR Calibration Spectra (NIST STandards)"/></figure>



<h2 class="wp-block-heading" id="how-do-i-find-the-area-under-my-curve-using-origin"><strong>How do I find the area under my curve using origin?</strong></h2>



<p>Plot your data (if you have not already) and make the graph window active, you can either use&nbsp;<strong>Integration</strong>&nbsp;gadget or&nbsp;<strong>Peak Analyzer</strong>.</p>



<p>For&nbsp;<strong>Integration</strong>&nbsp;gadget, go to&nbsp;<strong>Gadgets:Integrate&#8230;</strong>&nbsp;and click&nbsp;<strong>OK</strong>&nbsp;in the coming up dialog to bring up the yellow Region of Interest (ROI) box. Drag to position and resize the box to the area you want to calculate, then the&nbsp;<strong>Area</strong>&nbsp;and&nbsp;<strong>FWHM</strong>&nbsp;information will show up on the ROI top.</p>



<p>For&nbsp;<strong>Peak Analyzer</strong>, follow the steps below:</p>



<ol class="wp-block-list">
<li>Choose&nbsp;<strong>Analysis: Peaks and Baseline: Peak Analyzer</strong>.</li>



<li>In the first page (the&nbsp;<strong>Goal</strong>&nbsp;page), select the&nbsp;<strong>Integrate Peaks</strong>&nbsp;radio button in the&nbsp;<strong>Goal</strong>&nbsp;group.</li>



<li>For nominal data with positive and negative peaks, step through the four steps in the dialog window: Baseline Mode, Subtract Baseline, Find Peaks and Integrate Peaks.</li>



<li>The resulting plot will label each peak with the x-coordinates.</li>



<li>The workbook containing results output shows the calculated result parameters for each peak, including peak areas, in the Integration_Result<em>n</em>&nbsp;worksheet. The data for the integral curve can be found in the Integrated_Curve_Data<em>n</em>&nbsp;worksheet.</li>
</ol>



<h2 class="wp-block-heading" id="how-to-calculate-area-under-a-plotted-curve-in-excel">How To Calculate Area Under A Plotted Curve In Excel?</h2>



<p>For example, you have created a plotted curve as below screenshot shown. This method will split the area between the curve and x axis to multiple trapezoids, calculate the area of every trapezoid individually, and then sum up these areas.<br><img decoding="async" src="https://cdn.extendoffice.com/images/stories/doc-excel/calculate-area-under-curve/doc-calculate-area-under-curve-1.png" alt=""></p>



<p><strong>1</strong>. The first trapezoid is between x=1 and x=2 under the curve as below screenshot shown. You can calculate its area easily with this formula: &nbsp;<strong>=(C3+C4)/2*(B4-B3)</strong>.&nbsp;<br><img decoding="async" src="https://cdn.extendoffice.com/images/stories/doc-excel/calculate-area-under-curve/doc-calculate-area-under-curve-2.png" alt=""></p>



<p><strong>2</strong>. Then you can drag the AutoFill handle of the formula cell down to calculate areas of other trapezoids.<br><strong>Note</strong>: The last trapezoid is between x=14 and x=15 under the curve. Therefore, drag the AutoFill handle to the second to last cell as below screenshot shown.&nbsp; &nbsp;<br><img decoding="async" src="https://cdn.extendoffice.com/images/stories/doc-excel/calculate-area-under-curve/doc-calculate-area-under-curve-3.png" alt=""></p>



<p><strong>3</strong>. Now the areas of all trapezoids are figured out. Select a blank cell, type the formula&nbsp;<strong>=SUM(D3:D16)</strong>&nbsp;to get the total area under the plotted area.<br><img decoding="async" src="https://cdn.extendoffice.com/images/stories/doc-excel/calculate-area-under-curve/doc-calculate-area-under-curve-4.png" alt=""></p>



<h4 class="wp-block-heading" id="calculate-area-under-a-plotted-curve-with-chart-trendline">&nbsp;Calculate Area Under A Plotted Curve With Chart Trendline</h4>



<p>This method will use the chart trendline to get an equation for the plotted curve, and then calculate area under the plotted curve with the definite integral of the equation.</p>



<p><strong>1</strong>. Select the plotted chart, and click&nbsp;<strong>Design</strong>&nbsp;(or&nbsp;<strong>Chart Design</strong>) &gt;<strong>&nbsp;Add Chart Element</strong>&nbsp;&gt;<strong>&nbsp;Trendline</strong>&nbsp;&gt;&nbsp;<strong>More Trendline Options</strong>. See screenshot:<br><img decoding="async" src="https://cdn.extendoffice.com/images/stories/doc-excel/calculate-area-under-curve/doc-calculate-area-under-curve-5.png" alt=""></p>



<p><strong>2</strong>. In the&nbsp;<strong>Format Trendline&nbsp;</strong>pane:<br>(1) In the<strong>&nbsp;Trendline Options</strong>&nbsp;section, choose one option which is most matched with your curve;<br>(2) Check the&nbsp;<strong>Display Equation on chart</strong>&nbsp;option.&nbsp;<br><img decoding="async" src="https://cdn.extendoffice.com/images/stories/doc-excel/calculate-area-under-curve/doc-calculate-area-under-curve-6.png" alt=""></p>



<p><strong>3</strong>. Now the equation is added into the chart. Copy the equation into your worksheet, and then get the definite integral of the equation.</p>



<p>In my case, the equation general by trendline is&nbsp;<strong>y = 0.0219x^2 + 0.7604x + 5.1736</strong>, therefore its definite integral is&nbsp;<strong>F(x)</strong>&nbsp;<strong>= (0.0219/3)x^3 + (0.7604/2)x^2 + 5.1736x + c</strong>.</p>



<p><strong>4</strong>. Now we plug in the x=1 and x=15 to the definite integral, and calculate the difference between both calculations results. The difference represents the area under the plotted curve.&nbsp;<br><img decoding="async" src="https://cdn.extendoffice.com/images/stories/doc-excel/calculate-area-under-curve/doc-calculate-area-under-curve-7.png" alt="">&nbsp;</p>



<p>Area = F(15)-F(1)<br>Area =(0.0219/3)*15^3+(0.7604/2)*15^2+5.1736*15-(0.0219/3)*1^3-(0.7604/2)*1^2-5.1736*1<br>Area = 182.225</p>



<figure class="wp-block-image size-large"><a href="http://www.analyzetest.com/index.php/contact-us/"><img decoding="async" src="http://s7.picofile.com/file/8392387542/ftir_in.gif" alt=""/></a></figure>
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		<title>What is Raman spectroscopy?</title>
		<link>https://www.analyzetest.com/2021/03/17/663/</link>
		
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		<pubDate>Wed, 17 Mar 2021 15:33:09 +0000</pubDate>
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					<description><![CDATA[Click here to see other posts about Raman Only 10 $ per sample for interpreting of your Raman spectrum Payment Upon Completion Contact us... In this course the general introduction to Raman spectroscopy and microscopy will be provided and practical tips as well as examples will be given. The capability of Raman spectroscopy for the [&#8230;]]]></description>
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<p>In this course the general introduction to Raman spectroscopy and microscopy will be provided and practical tips as well as examples will be given. The capability of Raman spectroscopy for the analysis of real-life samples (paint components, clays, coating materials, etc.) taken from historical and archaeological objects will be discussed.</p>



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<h2 class="wp-block-heading" id="1-principles-of-raman-spectroscopy">1. Principles of Raman spectroscopy</h2>



<p><strong>Raman spectroscopy</strong>&nbsp;is widely used in the investigation of cultural heritage materials due to its high spatial resolution (typically in the range of 1 to 10 µm), large amount of obtainable information, non-destructivity and ability to perform in-situ analysis.<sup>1,2</sup>&nbsp;With Raman spectroscopy it’s possible to analyse various materials: minerals, inorganic and organic pigments, binding media, varnishes, ceramics, plastics, textile fibres etc.<sup>2</sup></p>



<p><br>The following video explains the principles and instrumentation of Raman spectroscopy.https://www.uttv.ee/embed?id=29055</p>



<p>Similarly to infrared spectroscopy, Raman spectroscopy is classified as vibrational spectroscopy.<sup>3</sup>&nbsp;Raman spectroscopy is based on Raman scattering (or Raman effect) that reveals the vibrational, rotational and other low frequency modes of molecules<sup>4</sup>. In this technique, the sample is exposed to an intense beam of monochromatic light (typically&nbsp;a laser beam) in the frequency range of visible, near-infrared or near-ultraviolet region.<sup>5</sup>&nbsp;The electromagnetic radiation, interacting with a substance, can be transmitted, absorbed, or scattered<sup>6</sup>. When the monochromatic radiation is scattered by molecules, the majority of the radiation undergoes the common&nbsp;<strong>Rayleigh scattering</strong>&nbsp;(radiation&#8217;s&nbsp; frequency/wavelength is unchanged). However, a small fraction of the scattered radiation is observed to have a slightly different frequency from that of the incident radiation. This is known as the&nbsp;<strong>Raman effect</strong><sup>7</sup>. The Raman lines show up pairwise. The dominant&nbsp;<strong>Stokes lines</strong>&nbsp;have a lower frequency (longer wavelength) than the initial radiation, whereas the weaker (often nondetectable)&nbsp;<strong>anti-Stokes</strong>&nbsp;<strong>lines</strong>&nbsp;have a higher frequency (shorter wavelength).<sup>4,5</sup>&nbsp;The frequency shifts are virtually independent of the excitation wavelength and are characteristic of the particular substance/molecule. Usually one only records the relatively strong Stokes lines, which therefore are attributed a positive frequency shift. Such spectral coordinate is called the&nbsp;<strong>Raman shift</strong>&nbsp;and measured in wavenumbers (in cm<sup>-1</sup>).<sup>4</sup>&nbsp;See scheme in Figure 1.</p>



<figure class="wp-block-image"><img decoding="async" src="https://sisu.ut.ee/sites/default/files/heritage-analysis/files/fig1_raman_scheme.png" alt="Raman_scheme" title="Figure 1. Scheme of Raman scattering."/></figure>



<p>Figure 1. Scheme of Raman scattering.</p>



<p>In Raman spectroscopy, as it is a scattering technique,&nbsp;<strong>samples are simply placed in the laser beam and the scattered radiation is collected</strong>&nbsp;and analysed<sup>8</sup>. Raman spectrometer measures the wavelength-dependent intensity of the inelastically scattered light.</p>



<p>The obtained Raman spectra are essentially vibrational spectra. Hence, if presented in the Raman shift scale, they are directly comparable to corresponding infrared absorption spectra (see Figure 2). However, Raman spectrum arises in a different manner and the rules, which vibrations are Raman-active (and thus produce signals in the spectrum), are different. It turns out that a vibration is Raman-active (i.e. revealed as a spectral line in the Raman spectrum), if the polarizability of the molecule changes during the vibration.<sup>7</sup>&nbsp;It often happens that vibrations that are active (or give high-intensity signals) in Raman scattering are inactive (or give low-intensity signals) in the infrared, and vice versa.<sup>7</sup>Therefore, Raman spectra often provide complementary information to IR spectra.</p>



<figure class="wp-block-image"><img decoding="async" src="https://sisu.ut.ee/sites/default/files/heritage-analysis/files/fig2_benzene-ir-raman.png" alt="benzene" title="Figure 2. Raman (laser 514.5 nm) and IR spectra of benzene."/></figure>



<p>Figure 2. Raman (laser 514.5 nm) and IR spectra of benzene.</p>



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<h2 class="wp-block-heading" id="1-1-instrumentation">1.1. Instrumentation</h2>



<p>There are two types of Raman spectrometers:&nbsp;<strong>dispersive spectrometers</strong>&nbsp;(based on the use of diffraction grating) and interferometer containing&nbsp;<strong>Fourier-transform Raman spectrometers (FT-Raman)</strong><sup>9</sup>.</p>



<p>In general the main components of Raman spectrometers are presented on the following scheme:</p>



<figure class="wp-block-image"><img decoding="async" src="https://sisu.ut.ee/sites/default/files/heritage-analysis/files/raman_scheme.jpg" alt="Raman_scheme" title=""/></figure>



<p>In Raman spectroscopy, the choice of&nbsp;<strong>excitation wavelength</strong>&nbsp;and&nbsp;<strong>intensity</strong>&nbsp;is very important. Different wavelengths are suitable for the analysis of different types of material. The wavelength&nbsp;will affect the Raman intensity, spatial resolution, background fluorescence, and potential damage to the sample. Almost exclusively&nbsp;<strong>lasers</strong>&nbsp;are used as&nbsp;<strong>excitation sources</strong>, because they are highly monochromatic, give high-intensity radiation and can be efficiently focused due to their high coherence. Only&nbsp;<strong>continuous wave (CW) lasers</strong>&nbsp;are used, as pulsed lasers easily damage the sample. Some popular CW lasers are presented in Table 1. Traditionally, laser wavelengths up to 830 nm have been used in dispersive instruments while the 1064 nm laser line has been employed in FT-Raman setups. With the availability of sensitive InGaAs array detectors, it has become meaningful to use also the 1064 nm lasers with dispersive Raman instruments.</p>



<p>Table 1. Laser sources for Raman spectroscopy.</p>



<figure class="wp-block-table"><table><tbody><tr><td><strong>Laser Type</strong></td><td><strong>Available wavelengths (nm)</strong></td></tr><tr><td>Argon ion (Ar<sup>+</sup>)</td><td>364, 457, 488, 514.5 (VIS)</td></tr><tr><td>Nd<sup>3+</sup>:YAG or Nd<sup>3+</sup>:YVO<sub>4</sub></td><td>1064 (Near-IR) or 532 (frequency-doubled) (VIS)</td></tr><tr><td>He-Ne</td><td>632.8 (VIS)</td></tr><tr><td>Laser diodes</td><td>785 or 830 (Near-IR)</td></tr></tbody></table></figure>



<p>Raman scattering efficiency decreases with increasing excitation wavelength as λ<sup>−4</sup>. However, short-wavelength lasers more easily induce fluorescence, absorb in the sample or cause other undesirable effects due to their high photon energy. Hence, most common laser wavelengths in Raman spectroscopy are in the visible and NIR region (such as 633 or 785 nm) which offer low fluorescence whilst retaining relatively high Raman intensity. For samples which exhibit fluorescence even under red excitation (for example dyes), the 1064 nm laser may be needed. While near-infrared lasers have a smaller photon energy, compared to visible lasers, they are usually more powerful, in order to compensate for the reduced Raman scattering efficiency. Therefore, they may still damage the sample. It is especially important for strongly absorbing (black) samples, in which case the UV/visible lasers (operating at lower intensities) may yield a stronger Raman signal.</p>



<h2 class="wp-block-heading" id="dispersive-raman-spectrometers"><em>Dispersive Raman spectrometers</em></h2>



<p>A dispersive spectrometer utilizes a diffraction grating to angularly disperse the light. As a result, at the detector plane, different wavelengths become spatially separated. Nevertheless, prior to entering the spectrometer, the incoming light should go through a special edge or notch filter to suppress the primary (Raman-scattered) light and thereby reduce the scattering inside the spectrometer. A matrix detector is used to record the dispersed spectrum. Typically, a silicon-based cooled CCD is used, which is very sensitive in the visible and NIR region (up to 1100 nm).</p>



<h2 class="wp-block-heading" id="ft-raman-spectrometers"><em>FT-Raman spectrometers</em></h2>



<p>Commercial FT-Raman spectrometers were introduced in the late 1980s<sup>10</sup>. Their operating principle is similar to that of FTIR spectrometers and is based on an interferometer. As the Raman-scattered light enters the instrument, the interferometer selectively modulates the individual spectral components by systematically changing an optical path length difference. The resulting beam of light is recorded by a point detector. FT-Raman is superior to a dispersive instrument in the near-IR region beyond 1000 nm. Commonly, the 1064 nm laser excitation along with germanium or indium gallium arsenide (InGaAs) detector is used. They also offer excellent wavelength accuracy and can potentially combine IR absorption and Raman measurement capacity in single instrument. However, FT-Raman frequently needs to use high laser intensities due to the reduced Raman scattering efficiency at longer wavelengths, which may damage the sample.</p>



<h2 class="wp-block-heading" id="different-types-of-raman-spectroscopy"><em>Different types of Raman Spectroscopy</em></h2>



<p>A variety of Raman instruments and special techniques are used for the analysis of cultural heritage materials. The choice of instrument determines the sensitivity, spectral range and resolution, spatial resolution, availability of different excitation sources, and convenience of operation.&nbsp;</p>



<ul class="wp-block-list">
<li><strong>Micro-Raman spectrometer (or Raman microscope)</strong>&nbsp;is the most common bench-top Raman instrument. A high-resolution spectrometer (either dispersive or FT) and one or several laser sources are coupled through an optical microscope. The excitation beam is focused and the secondary emission is collected simultaneously by the microscope objective in backscattering geometry. A high-numerical aperture (NA) objective yields both a high spatial resolution and a high collection efficiency.</li>



<li><strong>Surface-enhanced Raman spectroscopy (SERS)</strong>&nbsp;involves inelastic light scattering by molecules placed close to nanometal surfaces, which amplify the scattering by plasmonic resonance. One approach is to study molecules adsorbed onto corrugated metal surfaces such as silver or gold nanoparticles<sup>11</sup>. Another approach is to stimulate the molecules by a sharp metal tip. Such tip-enhanced Raman spectroscopy is typically implemented by combining a confocal microscope and a scanning probe microscope.&nbsp;</li>



<li>In&nbsp;<strong>Resonance Raman spectroscopy (RRS)</strong>&nbsp;the incident photon energy is close in energy to an electronic transition of a compound or material under examination.&nbsp;</li>



<li>In a&nbsp;<strong>portable Raman spectrometer</strong>, a miniature dispersive spectrometer and a small laser source are integrated into a portable, hand-held device. Hence, the instrument can be used to perform&nbsp;<em>in situ</em>&nbsp;analysis in museums, archives, also outdoors on archaeological sites for the analysis of mural or cave paintings. Such portable devices frequently employ a fiber-optic probes.&nbsp;</li>
</ul>



<h2 class="wp-block-heading" id="1-2-problems-with-raman-spectroscopy">1.2. Problems with Raman spectroscopy</h2>



<p>Compared to IR absorption, the primary disadvantage of Raman spectroscopy is the fluorescent background (see Figure 3). As Raman scattering is inherently weak, one has to use an intense laser beam for excitation, and for many materials, this results in a strong fluorescence – either due to the material itself of impurities. Sometimes even trace impurities – if they are strongly fluorescent – can lead to disturbing fluorescence background. Fortunately, Raman lines are spectrally close to the laser beam whereas fluorescence has typically a large Stokes shift.&nbsp;</p>



<figure class="wp-block-image"><img decoding="async" src="https://sisu.ut.ee/sites/default/files/heritage-analysis/files/fig3_raman_red_paint_fluorescence.png" alt="fluorescence" title="Figure 3. Example of the fluorescence in the Raman spectrum of red lead containing paint."/></figure>



<p>Figure 3. Example of the fluorescence in the Raman spectrum of red lead containing paint.</p>



<p>Relative to the Raman signal, the fluorescent background can be highly intense and even the tail of the fluorescence band may obscure the Raman spectrum. Although the problem can be partially resolved by careful sample preparation, time resolved spectroscopy or&nbsp;<strong>coherent anti-Stokes Raman spectroscopy (CARS)</strong>, there will always be experiments that remain difficult to perform.<sup>7</sup></p>



<p>In addition to fluorescence, intense focused laser irradiation can cause heating and degradation of the sample. The problems are typical for organic, soft, photosensitive or dark/coloured materials whereas transparent inorganic materials have usually quite high damage threshold.</p>



<h2 class="wp-block-heading" id="2-analysis-with-raman-spectroscopy">2. Analysis with Raman spectroscopy</h2>



<p>In the following video Senior Research Fellow Dr. Valter Kiisk demonstrates and explains how to perform measurements with a typical micro-Raman spectrometer.https://www.uttv.ee/embed?id=29396</p>



<p>Identification of the composition of the studied material is often based on the comparison of its Raman spectrum with a spectral library of reference materials.<sup>12</sup>&nbsp;Different papers and books have been published from where Raman spectra or information about excitation wavelengths and list of wavenumbers in the Raman spectra&nbsp;are available&nbsp;<sup>5,13,14</sup>. Also a very valuable on-line database is made available by the&nbsp;<strong>Infrared &amp; Raman Users Group (IRUG)</strong>&#8211;&nbsp;<a rel="noreferrer noopener" href="http://irug.org/" target="_blank">http://irug.org/</a>&nbsp;&#8211; from where&nbsp;different Raman (and also IR) spectra of cultural heritage materials can be obtained free of charge.</p>



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		<title>Everythings about UV-Vis spectroscopy</title>
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					<description><![CDATA[Click here to see more posts about UV-Vis spectroscopy Only 10$ for interpretation of your UV-Vis spectrum Payment Upon Completion Send your UV-Vis spectra... In Figure 10.9 we examined Nessler’s original method for matching the color of a sample to the color of a standard. Matching the colors was a labor intensive process for the [&#8230;]]]></description>
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<p>In Figure 10.9 we examined Nessler’s original method for matching the color of a sample to the color of a standard. Matching the colors was a labor intensive process for the analyst. Not surprisingly, spectroscopic methods of analysis were slow to develop. The 1930s and 1940s saw the introduction of photoelectric transducers for ultraviolet and visible radiation, and thermocouples for infrared radiation. As a result, modern instrumentation for absorption spectroscopy became routinely available in the 1940s—progress has been rapid ever since.</p>



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<h2 class="wp-block-heading" id="10-3-1-instrumentation">10.3.1 Instrumentation</h2>



<p>Frequently an analyst must select—from among several instruments of different design—the one instrument best suited for a particular analysis. In this section we examine several different instruments for molecular absorption spectroscopy, emphasizing their advantages and limitations. Methods of sample introduction are also covered in this section.</p>



<h3 class="wp-block-heading" id="instrument-designs-for-molecular-uv-vis-absorption">Instrument Designs for Molecular UV/Vis Absorption</h3>



<p><em><strong>Filter Photometer.</strong></em>&nbsp;The simplest instrument for molecular UV/Vis absorption is a&nbsp;<strong>filter photometer</strong>&nbsp;(Figure 10.25), which uses an absorption or interference filter to isolate a band of radiation. The filter is placed between the source and the sample to prevent the sample from decomposing when exposed to higher energy radiation. A filter photometer has a single optical path between the source and detector, and is called a&nbsp;<strong>single-beam</strong>&nbsp;instrument. The instrument is calibrated to 0% T while using a shutter to block the source radiation from the detector. After opening the shutter, the instrument is calibrated to 100% T using an appropriate blank. The blank is then replaced with the sample and its transmittance measured. Because the source’s incident power and the sensitivity of the detector vary with wavelength, the photometer must be recalibrated whenever the filter is changed. Photometers have the advantage of being relatively inexpensive, rugged, and easy to maintain. Another advantage of a photometer is its portability, making it easy to take into the field. Disadvantages of a photometer include the inability to record an absorption spectrum and the source’s relatively large effective bandwidth, which limits the calibration curve’s linearity.</p>



<p>Note</p>



<p>The percent transmittance varies between 0% and 100%. As we learned in Figure 10.21, we use a blank to determine&nbsp;<em>P</em><sub>0</sub>, which corresponds to 100% T. Even in the absence of light the detector records a signal. Closing the shutter allows us to assign 0% T to this signal. Together, setting 0% T and 100% T calibrates the instrument. The amount of light passing through a sample produces a signal that is greater than or equal to that for 0% T and smaller than or equal to that for 100%T.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12706/Figure10.25.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12706/Figure10.25.jpg?revision=1&amp;size=bestfit&amp;width=474&amp;height=362" alt="Figure10.25.jpg"/></a></figure>



<p><strong>Figure 10.25</strong>&nbsp;Schematic diagram of a filter photometer. The analyst either inserts a removable filter or the filters are placed in a carousel, an example of which is shown in the photographic inset. The analyst selects a filter by rotating it into place.</p>



<p><em><strong>Single-Beam Spectrophotometer.&nbsp;</strong></em>An instrument that uses a monochromator for wavelength selection is called a&nbsp;<strong>spectrophotometer</strong>. The simplest spectrophotometer is a single-beam instrument equipped with a fixed-wavelength monochromator (Figure 10.26). Single-beam spectrophotometers are calibrated and used in the same manner as a photometer. One example of a single-beam spectrophotometer is Thermo Scientific’s Spectronic 20D+, which is shown in the photographic insert to Figure 10.26. The Spectronic 20D+ has a range of 340–625 nm (950 nm when using a red-sensitive detector), and a fixed effective bandwidth of 20 nm. Battery-operated, hand-held single-beam spectrophotometers are available, which are easy to transport into the field. Other single-beam spectrophotometers also are available with effective bandwidths of 2–8 nm. Fixed wavelength single-beam spectrophotometers are not practical for recording spectra because manually adjusting the wavelength and recalibrating the spectrophotometer is awkward and time-consuming. The accuracy of a single-beam spectrophotometer is limited by the stability of its source and detector over time.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12707/Figure10.26.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12707/Figure10.26.jpg?revision=1&amp;size=bestfit&amp;width=475&amp;height=349" alt="Figure10.26.jpg"/></a></figure>



<p><strong>Figure 10.26</strong>&nbsp;Schematic diagram of a fixed-wavelength single-beam spectrophotometer. The photographic inset shows a typical instrument. The shutter remains closed until the sample or blank is placed in the sample compartment. The analyst manually selects the wavelength by adjusting the wavelength dial. Inset photo modified from:&nbsp;<a href="http://commons.wikimedia.org/wiki/File:Spektrofotometr.JPG" rel="noreferrer noopener" target="_blank">Adi</a>&nbsp;(www.commons.wikipedia.org).</p>



<p><em><strong>Double-Beam Spectrophotometer.</strong></em>&nbsp;The limitations of fixed-wavelength, single-beam spectrophotometers are minimized by using a&nbsp;<strong>double-beam</strong>spectrophotometer (Figure 10.27). A chopper controls the radiation’s path, alternating it between the sample, the blank, and a shutter. The signal processor uses the chopper’s known speed of rotation to resolve the signal reaching the detector into the transmission of the blank,&nbsp;<em>P</em><sub>0</sub>, and the sample,&nbsp;<em>P</em><sub>T</sub>. By including an opaque surface as a shutter, it is possible to continuously adjust 0% T. The effective bandwidth of a double-beam spectrophotometer is controlled by adjusting the monochromator’s entrance and exit slits. Effective bandwidths of 0.2–3.0 nm are common. A scanning monochromator allows for the automated recording of spectra. Double-beam instruments are more versatile than single-beam instruments, being useful for both quantitative and qualitative analyses, but also are more expensive.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12708/Figure10.27.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12708/Figure10.27.jpg?revision=1&amp;size=bestfit&amp;width=700&amp;height=437" alt="Figure10.27.jpg"/></a></figure>



<p><strong>Figure 10.27</strong>&nbsp;Schematic diagram of a scanning, double-beam spectrophotometer. A chopper directs the source’s radiation, using a transparent window to pass radiation to the sample and a mirror to reflect radiation to the blank. The chopper’s opaque surface serves as a shutter, which allows for a constant adjustment of the spectrophotometer’s 0% T. The photographic insert shows a typical instrument. The unit in the middle of the photo is a temperature control unit that allows the sample to be heated or cooled.</p>



<p><em><strong>Diode Array Spectrometer.</strong></em>&nbsp;An instrument with a single detector can monitor only one wavelength at a time. If we replace a single photomultiplier with many photodiodes, we can use the resulting array of detectors to record an entire spectrum simultaneously in as little as 0.1 s. In a diode array spectrometer the source radiation passes through the sample and is dispersed by a grating (Figure 10.28). The photodiode array is situated at the grating’s focal plane, with each diode recording the radiant power over a narrow range of wavelengths. Because we replace a full monochromator with just a grating, a diode array spectrometer is small and compact.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12709/Figure10.28.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12709/Figure10.28.jpg?revision=1&amp;size=bestfit&amp;width=565&amp;height=431" alt="Figure10.28.jpg"/></a></figure>



<p><strong>Figure 10.28</strong>&nbsp;Schematic diagram of a diode array spectrophotometer. The photographic insert shows a typical instrument. Note that the 50-mL beaker provides a sense of scale.</p>



<p>One advantage of a diode array spectrometer is the speed of data acquisition, which allows to collect several spectra for a single sample. Individual spectra are added and averaged to obtain the final spectrum. This&nbsp;<strong>signal averaging</strong>&nbsp;improves a spectrum’s signal-to-noise ratio. If we add together&nbsp;<em>n</em>&nbsp;spectra, the sum of the signal at any point,&nbsp;<em>x</em>, increases as&nbsp;<em>nS<sub>x</sub></em>, where&nbsp;<em>S<sub>x</sub>&nbsp;</em>is the signal. The noise at any point,&nbsp;<em>N<sub>x</sub></em>, is a random event, which increases as&nbsp;√<em>nN<sub>x</sub></em>&nbsp;when we add together&nbsp;<em>n</em>spectra. The&nbsp;<strong>signal-to-noise ratio</strong>&nbsp;(S/N) after&nbsp;<em>n</em>&nbsp;scans isSN=nSxn−−√Nx=n−−√SxnNx(4.8.1)(4.8.1)SN=nSxnNx=nSxnNx</p>



<p>where&nbsp;<em>S<sub>x</sub></em>/<em>N<sub>x</sub></em>&nbsp;is the signal-to-noise ratio for a single scan. The impact of signal averaging is shown in Figure 10.29. The first spectrum shows the signal for a single scan, which consists of a single, noisy peak. Signal averaging using 4 scans and 16 scans decreases the noise and improves the signal-to-noise ratio. One disadvantage of a photodiode array is that the effective bandwidth per diode is roughly an order of magnitude larger than that for a high quality monochromator.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12710/Figure10.29.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12710/Figure10.29.jpg?revision=1&amp;size=bestfit&amp;width=275&amp;height=734" alt="Figure10.29.jpg"/></a></figure>



<p><strong>Figure 10.29</strong>&nbsp;Effect of signal averaging on a spectrum’s signal-to-noise ratio. From top to bottom: spectrum for a single scan; average spectrum after four scans; and average spectrum after adding 16 scans.</p>



<p><em><strong>Sample Cells.&nbsp;</strong></em>The sample compartment provides a light-tight environment that limits the addition of stray radiation. Samples are normally in the liquid or solution state, and are placed in cells constructed with UV/Vis transparent materials, such as quartz, glass, and plastic (Figure 10.30). A quartz or fused-silica cell is required when working at a wavelength &lt;300 nm where other materials show a significant absorption. The most common pathlength is 1 cm (10 mm), although cells with shorter (as little as 0.1 cm) and longer pathlengths (up to 10 cm) are available. Longer pathlength cells are useful when analyzing a very dilute solution, or for gas samples. The highest quality cells allow the radiation to strike a flat surface at a 90<sup>o</sup>&nbsp;angle, minimizing the loss of radiation to reflection. A test tube is often used as a sample cell with simple, single-beam instruments, although differences in the cell’s pathlength and optical properties add an additional source of error to the analysis.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12781/Figure_10.30.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12781/Figure_10.30.jpg?revision=1&amp;size=bestfit&amp;width=675&amp;height=262" alt="Figure 10.30.jpg"/></a></figure>



<p><strong>Figure 10.30</strong>&nbsp;Examples of sample cells for UV/Vis spectroscopy. From left to right (with path lengths in parentheses): rectangular plastic cuvette (10.0 mm), rectangular quartz cuvette (5.000 mm), rectangular quartz cuvette (1.000 mm), cylindrical quartz cuvette (10.00 mm), cylindrical quartz cuvette (100.0 mm). Cells often are available as a matched pair, which is important when using a double-beam instrument.</p>



<p>If we need to monitor an analyte’s concentration over time, it may not be possible to physically remove samples for analysis. This is often the case, for example, when monitoring industrial production lines or waste lines, when monitoring a patient’s blood, or when monitoring environmental systems. With a&nbsp;<strong>fiber-optic probe</strong>&nbsp;we can analyze samples in situ. An example of a remote sensing fiber-optic probe is shown in Figure 10.31. The probe consists of two bundles of fiber-optic cable. One bundle transmits radiation from the source to the probe’s tip, which is designed to allow the sample to flow through the sample cell. Radiation from the source passes through the solution and is reflected back by a mirror. The second bundle of fiber-optic cable transmits the nonabsorbed radiation to the wavelength selector. Another design replaces the flow cell shown in Figure 10.31 with a membrane containing a reagent that reacts with the analyte. When the analyte diffuses across the membrane it reacts with the reagent, producing a product that absorbs UV or visible radiation. The nonabsorbed radiation from the source is reflected or scattered back to the detector. Fiber optic probes that show chemical selectivity are called optrodes.<sup>6</sup></p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12711/Figure10.31.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12711/Figure10.31.jpg?revision=1&amp;size=bestfit&amp;width=500&amp;height=324" alt="Figure10.31.jpg"/></a></figure>



<p><strong>Figure 10.31</strong>&nbsp;Example of a fiber-optic probe. The inset photographs provide a close-up look at the probe’s flow cell and the reflecting mirror.</p>



<h3 class="wp-block-heading" id="instrument-designs-for-infrared-absorption">Instrument Designs for Infrared Absorption</h3>



<p><em><strong>Filter Photometer.</strong></em>&nbsp;The simplest instrument for IR absorption spectroscopy is a filter photometer similar to that shown in Figure 10.25 for UV/Vis absorption. These instruments have the advantage of portability, and typically are used as dedicated analyzers for gases such as HCN and CO.</p>



<p><em><strong>Double-beam spectrophotometer.</strong></em>&nbsp;Infrared instruments using a monochromator for wavelength selection use double-beam optics similar to that shown in Figure 10.27. Double-beam optics are preferred over single-beam optics because the sources and detectors for infrared radiation are less stable than those for UV/Vis radiation. In addition, it is easier to correct for the absorption of infrared radiation by atmospheric CO<sub>2</sub>&nbsp;and H<sub>2</sub>O vapor when using double-beam optics. Resolutions of 1–3 cm<sup>–1</sup>&nbsp;are typical for most instruments.</p>



<p><em><strong>Fourier transform spectrometer.</strong></em>&nbsp;In a Fourier transform infrared spectrometer, or FT–IR, the monochromator is replaced with an interferometer (Figure 10.13). Because an FT-IR includes only a single optical path, it is necessary to collect a separate spectrum to compensate for the absorbance of atmospheric CO<sub>2</sub>&nbsp;and H<sub>2</sub>O vapor. This is done by collecting a background spectrum without the sample and storing the result in the instrument’s computer memory. The background spectrum is removed from the sample’s spectrum by ratioing the two signals. In comparison to other instrument designs, an FT–IR provides for rapid data acquisition, allowing an enhancement in signal-to-noise ratio through signal-averaging.</p>



<p><em><strong>Sample Cells.</strong></em>&nbsp;Infrared spectroscopy is routinely used to analyze gas, liquid, and solid samples. Sample cells are made from materials, such as NaCl and KBr, that are transparent to infrared radiation. Gases are analyzed using a cell with a pathlength of approximately 10 cm. Longer pathlengths are obtained by using mirrors to pass the beam of radiation through the sample several times.</p>



<p>A liquid samples may be analyzed using a variety of different sample cells (Figure 10.32). For non-volatile liquids a suitable sample can be prepared by placing a drop of the liquid between two NaCl plates, forming a thin film that typically is less than 0.01 mm thick. Volatile liquids must be placed in a sealed cell to prevent their evaporation.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12712/Figure10.32.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12712/Figure10.32.jpg?revision=1&amp;size=bestfit&amp;width=700&amp;height=403" alt="Figure10.32.jpg"/></a></figure>



<p><strong>Figure 10.32</strong>&nbsp;Three examples of IR sample cells: (a) NaCl salts plates; (b) fixed pathlength (0.5 mm) sample cell with NaCl windows; (c) disposable card with a polyethylene window that is IR transparent with the exception of strong absorption bands at 2918 cm<sup>–1</sup>&nbsp;and 2849 cm<sup>–1</sup>.</p>



<p>The analysis of solution samples is limited by the solvent’s IR absorbing properties, with CCl<sub>4</sub>, CS<sub>2</sub>, and CHCl<sub>3</sub>&nbsp;being the most common solvents. Solutions are placed in cells containing two NaCl windows separated by a Teflon spacer. By changing the Teflon spacer, pathlengths from 0.015–1.0 mm can be obtained.</p>



<p>Transparent solid samples can be analyzed directly by placing them in the IR beam. Most solid samples, however, are opaque, and must be dispersed in a more transparent medium before recording the IR spectrum. If a suitable solvent is available, then the solid can be analyzed by preparing a solution and analyzing as described above. When a suitable solvent is not available, solid samples may be analyzed by preparing a mull of the finely powdered sample with a suitable oil. Alternatively, the powdered sample can be mixed with KBr and pressed into an optically transparent pellet.</p>



<p>The analysis of an aqueous sample is complicated by the solubility of the NaCl cell window in water. One approach to obtaining infrared spectra on aqueous solutions is to use&nbsp;<strong>attenuated total reflectance</strong>&nbsp;instead of transmission. Figure 10.33 shows a diagram of a typical attenuated total reflectance (ATR) FT–IR instrument. The ATR cell consists of a high refractive index material, such as ZnSe or diamond, sandwiched between a low refractive index substrate and a lower refractive index sample. Radiation from the source enters the ATR crystal where it undergoes a series of total internal reflections before exiting the crystal. During each reflection the radiation penetrates into the sample to a depth of a few microns. The result is a selective attenuation of the radiation at those wavelengths where the sample absorbs. ATR spectra are similar, but not identical, to those obtained by measuring the transmission of radiation.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12713/Figure10.33.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12713/Figure10.33.jpg?revision=1&amp;size=bestfit&amp;width=700&amp;height=327" alt="Figure10.33.jpg"/></a></figure>



<p><strong>Figure 10.33</strong>&nbsp;FT-IR spectrometer equipped with a diamond ATR sample cell. The inserts show a close-up photo of the sample platform, a sketch of the ATR’s sample slot, and a schematic showing how the source’s radiation interacts with the sample. The pressure tower is used to ensure the contact of solid samples with the ATR crystal.</p>



<p>Solid samples also can be analyzed using an ATR sample cell. After placing the solid in the sample slot, a compression tip ensures that it is in contact with the ATR crystal. Examples of solids that have been analyzed by ATR include polymers, fibers, fabrics, powders, and biological tissue samples. Another reflectance method is diffuse reflectance, in which radiation is reflected from a rough surface, such as a powder. Powdered samples are mixed with a non-absorbing material, such as powdered KBr, and the reflected light is collected and analyzed. As with ATR, the resulting spectrum is similar to that obtained by conventional transmission methods.</p>



<p>Note</p>



<p>Further details about these, and other methods for preparing solids for infrared analysis can be found in this chapter’s&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/Additional_Resources#Chapter_10" target="_blank" rel="noopener">additional resources</a>.</p>



<h2 class="wp-block-heading" id="10-3-2-quantitative-applications">10.3.2 Quantitative Applications</h2>



<p>The determination of an analyte’s concentration based on its absorption of ultraviolet or visible radiation is one of the most frequently encountered quantitative analytical methods. One reason for its popularity is that many organic and inorganic compounds have strong absorption bands in the UV/Vis region of the electromagnetic spectrum. In addition, if an analyte does not absorb UV/Vis radiation—or if its absorbance is too weak—we often can react it with another species that is strongly absorbing. For example, a dilute solution of Fe<sup>2</sup><sup>+</sup>&nbsp;does not absorb visible light. Reacting Fe<sup>2</sup><sup>+</sup>&nbsp;with&nbsp;<em>o</em>-phenanthroline, however, forms an orange–red complex of Fe(phen)<sub>3</sub><sup>2+</sup>&nbsp;that has a strong, broad absorbance band near 500 nm. An additional advantage to UV/Vis absorption is that in most cases it is relatively easy to adjust experimental and instrumental conditions so that Beer’s law is obeyed.</p>



<p>Note</p>



<p>Figure 10.18 shows the visible spectrum for Fe(phen)<sub>3</sub><sup>2+</sup>.</p>



<p>A quantitative analysis based on the absorption of infrared radiation, although important, is less frequently encountered than those for UV/Vis absorption. One reason is the greater tendency for instrumental deviations from Beer’s law when using infrared radiation. Because an infrared absorption band is relatively narrow, any deviation due to the lack of monochromatic radiation is more pronounced. In addition, infrared sources are less intense than UV/Vis sources, making stray radiation more of a problem. Differences in pathlength for samples and standards when using thin liquid films or KBr pellets are a problem, although an internal standard can be used to correct for any difference in pathlength. Finally, establishing a 100% T (<em>A</em>&nbsp;= 0) baseline is often difficult because the optical properties of NaCl sample cells may change significantly with wavelength due to contamination and degradation. We can minimize this problem by measuring absorbance relative to a baseline established for the absorption band. Figure 10.34 shows how this is accomplished.</p>



<p>Note</p>



<p>Another approach is to use a cell with a fixed pathlength, such as that shown in Figure 10.32b.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12714/Figure10.34.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12714/Figure10.34.jpg?revision=1&amp;size=bestfit&amp;width=450&amp;height=385" alt="Figure10.34.jpg"/></a></figure>



<p><strong>Figure 10.34</strong>&nbsp;Method for determining absorbance from an IR spectrum.</p>



<h3 class="wp-block-heading" id="environmental-applications">Environmental Applications</h3>



<p>The analysis of waters and wastewaters often relies on the absorption of ultraviolet and visible radiation. Many of these methods are outlined in Table 10.6. Several of these methods are described here in more detail.</p>



<figure class="wp-block-table"><table><thead><tr><th scope="col">Analyte</th><th scope="col">Method</th><th scope="col">λ&nbsp;(nm)</th></tr></thead><tbody><tr><td><em>T</em><em>r</em><em>ace Metals</em></td></tr><tr><td>aluminum</td><td>react with Eriochrome cyanide R dye at pH6; forms red to pink complex</td><td>535</td></tr><tr><td>arsenic</td><td>reduce to AsH<sub>3</sub>&nbsp;using Zn and react with silver diethyldithiocarbamate; forms red complex</td><td>535</td></tr><tr><td>cadmium</td><td>extract into CHCl<sub>3</sub>&nbsp;containing dithizone from a sample made basic with NaOH; forms pink to red complex</td><td>518</td></tr><tr><td>chromium</td><td>oxidize to Cr(VI) and react with diphenylcarbazide; forms red-violet product</td><td>540</td></tr><tr><td>copper</td><td>react with neocuprine in neutral to slightly acid solution and extract into CHCl<sub>3</sub>/CH<sub>3</sub>OH; forms yellow complex</td><td>457</td></tr><tr><td>iron</td><td>reduce to Fe<sup>2</sup><sup>+</sup>&nbsp;and react with&nbsp;<em>o</em>-phenanthroline; forms orange-red complex</td><td>510</td></tr><tr><td>lead</td><td>extract into CHCl<sub>3</sub>&nbsp;containing dithizone from sample made basic with NH<sub>3</sub>/NH<sub>4</sub><sup>+</sup>&nbsp;buffer; forms cherry red complex</td><td>510</td></tr><tr><td>manganese</td><td>oxidize to MnO<sub>4</sub><sup>–</sup>&nbsp;with persulfate; forms purple solution</td><td>525</td></tr><tr><td>mercury</td><td>extract into CHCl<sub>3</sub>&nbsp;containing dithizone from acidic sample; forms orange complex</td><td>492</td></tr><tr><td>zinc</td><td>react with zincon at pH 9; forms blue complex</td><td>620</td></tr><tr><td><em>I</em><em>norganic Nonmetals</em></td></tr><tr><td>ammonia</td><td>reaction with hypochlorite and phenol using a manganous salt catalyst; forms blue indophenol as product</td><td>630</td></tr><tr><td>cyanide</td><td>react with chloroamine-T to form CNCl and then with a pyridine-barbituric acid; forms a red-blue dye</td><td>578</td></tr><tr><td>fluoride</td><td>react with red Zr-SPADNS lake; formation of ZrF<sub>6</sub><sup>2–</sup>&nbsp;decreases color of the red lake</td><td>570</td></tr><tr><td>chlorine (residual)</td><td>react with leuco crystal violet; forms blue product</td><td>592</td></tr><tr><td>nitrate</td><td>react with Cd to form NO<sub>2</sub><sup>–</sup>&nbsp;and then react with sulfanilamide and&nbsp;<em>N</em>-(1-napthyl)-ethylenediamine; forms red azo dye</td><td>543</td></tr><tr><td>phosphate</td><td>react with ammonium molybdate and then reduce with SnCl<sub>2</sub>; forms molybdenum blue</td><td>690</td></tr><tr><td><em>O</em><em>rganics</em></td></tr><tr><td>phenol</td><td>react with 4-aminoantipyrine and K<sub>3</sub>Fe(CN)<sub>6</sub>; forms yellow antipyrine dye</td><td>460</td></tr><tr><td>anionic surfactant</td><td>react with cationic methylene blue dye and extract into CHCl<sub>3</sub>; forms blue ion pair</td><td>652</td></tr></tbody></table></figure>



<p><img decoding="async" alt="dithizone.png" width="68px" height="184px" src="https://chem.libretexts.org/@api/deki/files/12102/dithizone.png?revision=1&amp;size=bestfit&amp;width=68&amp;height=184">Although the quantitative analysis of metals in waters and wastewaters is accomplished primarily by atomic absorption or atomic emission spectroscopy, many metals also can be analyzed following the formation of a colored metal–ligand complex. One advantage to these spectroscopic methods is that they are easily adapted to the analysis of samples in the field using a filter photometer. One ligand that is used in the analysis of several metals is diphenylthiocarbazone, also known as dithizone. Dithizone is not soluble in water, but when a solution of dithizone in CHCl<sub>3</sub>&nbsp;is shaken with an aqueous solution containing an appropriate metal ion, a colored metal–dithizonate complex forms that is soluble in CHCl<sub>3</sub>. The selectivity of dithizone is controlled by adjusting the sample’s pH. For example, Cd<sup>2</sup><sup>+</sup>&nbsp;is extracted from solutions that are made strongly basic with NaOH, Pb<sup>2</sup><sup>+</sup>&nbsp;from solutions that are made basic with an NH<sub>3</sub>/NH<sub>4</sub><sup>+</sup>&nbsp;buffer, and Hg<sup>2</sup><sup>+</sup>&nbsp;from solutions that are slightly acidic.</p>



<p>Note</p>



<p>Atomic absorption is the subject of&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.4%3A_Atomic_Absorption_Spectroscopy" target="_blank" rel="noopener">Section 10.4</a>&nbsp;and atomic emission is the subject of&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.7%3A_Atomic_Emission_Spectroscopy" target="_blank" rel="noopener">Section 10.7</a>.</p>



<p>The structure of dithizone is shown to the right. See Chapter 7 for a discussion of extracting metal ions using dithizone.</p>



<p>When chlorine is added to water the portion available for disinfection is called the chlorine residual. There are two forms of chlorine residual. The free chlorine residual includes Cl<sub>2</sub>, HOCl, and OCl<sup>–</sup>. The combined chlorine residual, which forms from the reaction of NH<sub>3</sub>&nbsp;with HOCl, consists of monochloramine, NH<sub>2</sub>Cl, dichloramine, NHCl<sub>2</sub>, and trichloramine, NCl<sub>3</sub>. Because the free chlorine residual is more efficient at disinfection, there is an interest in methods that can distinguish between the different forms of the total chlorine residual. One such method is the leuco crystal violet method. The free residual chlorine is determined by adding leuco crystal violet to the sample, which instantaneously oxidizes to give a blue colored compound that is monitored at 592 nm. Completing the analysis in less than five minutes prevents a possible interference from the combined chlorine residual. The total chlorine residual (free + combined) is determined by reacting a separate sample with iodide, which reacts with both chlorine residuals to form HOI. When the reaction is complete, leuco crystal violet is added and oxidized by HOI, giving the same blue colored product. The combined chlorine residual is determined by difference.</p>



<p>Note</p>



<p>In Chapter 9 we explored how the total chlorine residual can be determined by a redox titration; see&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/09_Titrimetric_Methods/9.4%3A_Redox_Titrations#Representative_Method_9.3" target="_blank" rel="noopener">Representative Method 9.3</a>&nbsp;for further details. The method described here allows us to divide the total chlorine residual into its component parts.</p>



<p>The concentration of fluoride in drinking water may be determined indirectly by its ability to form a complex with zirconium. In the presence of the dye SPADNS, solutions of zirconium form a red colored compound, called a lake, that absorbs at 570 nm. When fluoride is added, the formation of the stable ZrF<sub>6</sub><sup>2–</sup>&nbsp;complex causes a portion of the lake to dissociate, decreasing the absorbance. A plot of absorbance versus the concentration of fluoride, therefore, has a negative slope.</p>



<p>Note</p>



<p>SPADNS, which is shown below, is an abbreviation for the sodium salt of 2-(4-sulfophenylazo)-1,8-dihydroxy-3,6-napthalenedisulfonic acid, which is a mouthful to say.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12103/SPADNS2.png?revision=1" alt="SPADNS2.png"/></figure>



<p><img decoding="async" alt="4-aminoantipyrene.png" src="https://chem.libretexts.org/@api/deki/files/12104/4-aminoantipyrene.png?revision=1">Spectroscopic methods also are used to determine organic constituents in water. For example, the combined concentrations of phenol, and ortho- and meta- substituted phenols are determined by using steam distillation to separate the phenols from nonvolatile impurities. The distillate reacts with 4-aminoantipyrine at pH 7.9 ± 0.1 in the presence of K<sub>3</sub>Fe(CN)<sub>6</sub>, forming a yellow colored antipyrine dye. After extracting the dye into CHCl<sub>3</sub>, its absorbance is monitored at 460 nm. A calibration curve is prepared using only the unsubstituted phenol, C<sub>6</sub>H<sub>5</sub>OH. Because the molar absorptivity of substituted phenols are generally less than that for phenol, the reported concentration represents the minimum concentration of phenolic compounds.</p>



<p>Molecular absorption also can be used for the analysis of environmentally significant airborne pollutants. In many cases the analysis is carried out by collecting the sample in water, converting the analyte to an aqueous form that can be analyzed by methods such as those described in Table 10.6. For example, the concentration of NO<sub>2</sub>&nbsp;can be determined by oxidizing NO<sub>2</sub>&nbsp;to NO<sub>3</sub><sup>–</sup>. The&nbsp;<img decoding="async" alt="red azo dye.png" src="https://chem.libretexts.org/@api/deki/files/12105/red_azo_dye.png?revision=1">concentration of NO<sub>3</sub><sup>–</sup>&nbsp;is then determined by first reducing it to NO<sub>2</sub><sup>–</sup>&nbsp;with Cd, and then reacting NO<sub>2</sub><sup>–</sup>&nbsp;with sulfanilamide and&nbsp;<em>N</em>-(1-naphthyl)-ethylenediamine to form a red azo dye. Another important application is the analysis for SO<sub>2</sub>, which is determined by collecting the sample in an aqueous solution of HgCl<sub>4</sub><sup>2–</sup>&nbsp;where it reacts to form Hg(SO<sub>3</sub>)<sub>2</sub><sup>2–</sup>. Addition of&nbsp;<em>p</em>-rosaniline and formaldehyde produces a purple complex that is monitored at 569 nm. Infrared absorption is useful for the analysis of organic vapors, including HCN, SO<sub>2</sub>, nitrobenzene, methyl mercaptan, and vinyl chloride. Frequently, these analyses are accomplished using portable, dedicated infrared photometers.</p>



<figure class="wp-block-image size-large"><a href="http://www.analyzetest.com/index.php/contact-us/"><img decoding="async" src="http://s7.picofile.com/file/8392387600/uv_vis_in.gif" alt=""/></a></figure>



<h3 class="wp-block-heading" id="clinical-applications">Clinical Applications</h3>



<p>The analysis of clinical samples is often complicated by the complexity of the sample matrix, which may contribute a significant background absorption at the desired wavelength. The determination of serum barbiturates provides one example of how this problem is overcome. The barbiturates are first extracted from a sample of serum with CHCl<sub>3</sub>&nbsp;and then extracted from the CHCl<sub>3</sub>&nbsp;into 0.45 M NaOH (pH ≈ 13). The absorbance of the aqueous extract is measured at 260 nm, and includes contributions from the barbiturates as well as other components extracted from the serum sample. The pH of the sample is then lowered to approximately 10 by adding NH<sub>4</sub>Cl and the absorbance remeasured. Because the barbiturates do not absorb at this pH, we can use the absorbance at pH 10,&nbsp;<em>A</em><sub>pH</sub><sub>&nbsp;10</sub>, to correct the absorbance at pH 13,&nbsp;<em>A</em><sub>pH</sub><sub>&nbsp;13</sub>Abarb=ApH 13−Vsamp+VNH4ClVsamp×ApH 10(4.8.2)(4.8.2)Abarb=ApH 13−Vsamp+VNH4ClVsamp×ApH 10</p>



<p>where&nbsp;<em>A</em><sub>barb</sub>&nbsp;is the absorbance due to the serum barbiturates, and&nbsp;<em>V</em><sub>samp</sub>&nbsp;and&nbsp;<em>V</em><sub>NH4Cl</sub>&nbsp;are the volumes of sample and NH<sub>4</sub>Cl, respectively. Table 10.7 provides a summary of several other methods for analyzing clinical samples.</p>



<figure class="wp-block-table"><table><thead><tr><th scope="col">Analyte</th><th scope="col">Method</th><th scope="col">λ&nbsp;(nm)</th></tr></thead><tbody><tr><td>total serum protein</td><td>react with NaOH and Cu<sup>2</sup><sup>+</sup>; forms blue-violet complex</td><td>540</td></tr><tr><td>serum cholesterol</td><td>react with Fe<sup>3</sup><sup>+</sup>&nbsp;in presence of isopropanol, acetic acid, and H<sub>2</sub>SO<sub>4</sub>; forms blue-violet complex</td><td>540</td></tr><tr><td>uric acid</td><td>react with phosphotungstic acid; forms tungsten blue</td><td>710</td></tr><tr><td>serum barbiturates</td><td>extract into CHCl<sub>3</sub>&nbsp;to isolate from interferents and then extract into 0.45 M NaOH</td><td>260</td></tr><tr><td>glucose</td><td>react with&nbsp;<em>o</em>-toludine at 100<sup>o</sup>C; forms blue-green complex</td><td>630</td></tr><tr><td>protein-bound iodine</td><td>decompose protein to release iodide, which catalyzes redox reaction between Ce<sup>3</sup><sup>+</sup>&nbsp;and As<sup>3</sup><sup>+</sup>; forms yellow colored Ce<sup>4</sup><sup>+</sup></td><td>420</td></tr></tbody></table></figure>



<h3 class="wp-block-heading" id="industrial-analysis">Industrial Analysis</h3>



<p>UV/Vis molecular absorption is used for the analysis of a diverse array of industrial samples including pharmaceuticals, food, paint, glass, and metals. In many cases the methods are similar to those described in Table 10.6 and Table 10.7. For example, the amount of iron in food can be determined by bringing the iron into solution and analyzing using the&nbsp;<em>o</em>-phenanthroline method listed in Table 10.6.</p>



<p>Many pharmaceutical compounds contain chromophores that make them suitable for analysis by UV/Vis absorption. Products that have been analyzed in this fashion include antibiotics, hormones, vitamins, and analgesics. One example of the use of UV absorption is in determining the purity of aspirin tablets, for which the active ingredient is acetylsalicylic acid. Salicylic acid, which is produced by the hydrolysis of acetylsalicylic acid, is an undesirable impurity in aspirin tablets, and should not be present at more than 0.01% w/w. Samples can be screened for unacceptable levels of salicylic acid by monitoring the absorbance at a wavelength of 312 nm. Acetylsalicylic acid absorbs at 280 nm, but absorbs poorly at 312 nm. Conditions for preparing the sample are chosen such that an absorbance of greater than 0.02 signifies an unacceptable level of salicylic acid.</p>



<h3 class="wp-block-heading" id="forensic-applications">Forensic Applications</h3>



<p>UV/Vis molecular absorption is routinely used for the analysis of narcotics and for drug testing. One interesting forensic application is the determination of blood alcohol using the Breathalyzer test. In this test a 52.5-mL breath sample is bubbled through an acidified solution of K<sub>2</sub>Cr<sub>2</sub>O<sub>7</sub>, which oxidizes ethanol to acetic acid. The concentration of ethanol in the breath sample is determined by the decrease in absorbance at 440 nm where the dichromate ion absorbs. A blood alcohol content of 0.10%, which is above the legal limit, corresponds to 0.025 mg of ethanol in the breath sample.</p>



<h3 class="wp-block-heading" id="developing-a-quantitative-method-for-a-single-component">Developing a Quantitative Method for a Single Component</h3>



<p>In developing a quantitative analytical method, the conditions under which Beer’s law is obeyed must be established. First, the most appropriate wavelength for the analysis is determined from an absorption spectrum. In most cases the best wavelength corresponds to an absorption maximum because it provides greater sensitivity and is less susceptible to instrumental limitations. Second, if an instrument with adjustable slits is being used, then an appropriate slit width needs to be chosen. The absorption spectrum also aids in selecting a slit width. Usually we set the slits to be as wide as possible because this increases the throughput of source radiation, while also being narrow enough to avoid instrumental limitations to Beer’s law. Finally, a calibration curve is constructed to determine the range of concentrations for which Beer’s law is valid. Additional considerations that are important in any quantitative method are the effect of potential interferents and establishing an appropriate blank.</p>



<p>Note</p>



<p>The best way to appreciate the theoretical and practical details discussed in this section is to carefully examine a typical analytical method. Although each method is unique, the following description of the determination of iron in water and wastewater provides an instructive example of a typical procedure. The description here is based on Method 3500- Fe B as published in&nbsp;<em>Standard Methods for the Examination of Water and Wastewater</em>, 20th Ed., American Public Health Association: Washington, D. C., 1998.</p>



<p>Representative Method 10.1</p>



<p><strong>Determination of Iron in Water and Wastewater</strong></p>



<p><em><strong>Description of Method</strong></em></p>



<p>Iron in the +2 oxidation state reacts with&nbsp;<em>o</em>-phenanthroline to form the orange-red Fe(phen)<sub>3</sub><sup>2+</sup>&nbsp;complex. The intensity of the complex’s color is independent of solution acidity between a pH of 3 and 9. Because the complex forms more rapidly at lower pH levels, the reaction is usually carried out within a pH range of 3.0–3.5. Any iron present in the +3 oxidation state is reduced with hydroxylamine before adding&nbsp;<em>o</em>-phenanthroline. The most important interferents are strong oxidizing agents, polyphosphates, and metal ions such as Cu<sup>2</sup><sup>+</sup>, Zn<sup>2</sup><sup>+</sup>, Ni<sup>2</sup><sup>+</sup>, and Cd<sup>2</sup><sup>+</sup>. An interference from oxidizing agents is minimized by adding an excess of hydroxylamine, and an interference from polyphosphate is minimized by boiling the sample in the presence of acid. The absorbance of samples and standards are measured at a wavelength of 510 nm using a 1-cm cell (longer pathlength cells also may be used). Beer’s law is obeyed for concentrations of within the range of 0.2–4.0 mg Fe/L.</p>



<p>(Figure 10.18 shows the visible spectrum for Fe(phen)<sub>3</sub><sup>2+</sup>.)</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12106/o-phenanthroline1.png?revision=1" alt="o-phenanthroline1.png"/></figure>



<p><em><strong>Procedure</strong></em></p>



<p>For samples containing less than 2 mg Fe/L, directly transfer a 50-mL portion to a 125-mL Erlenmeyer flask. Samples containing more than 2 mg Fe/L must be diluted before acquiring the 50-mL portion. Add 2 mL of concentrated HCl and 1 mL of hydroxylamine to the sample. Heat the solution to boiling and continue boiling until the solution’s volume is reduced to between 15 and 20 mL. After cooling to room temperature, transfer the solution to a 50-mL volumetric flask, add 10 mL of an ammonium acetate buffer, 2 mL of a 1000 ppm solution of&nbsp;<em>o</em>-phenanthroline, and dilute to volume. Allow 10–15 minutes for color development before measuring the absorbance, using distilled water to set 100% T. Calibration standards, including a blank, are prepared by the same procedure using a stock solution containing a known concentration of Fe<sup>2</sup><sup>+</sup>.</p>



<p><em><strong>Questions</strong></em></p>



<p>1. Explain why strong oxidizing agents are interferents, and why an excess of hydroxylamine prevents the interference.</p>



<p>A strong oxidizing agent oxidizes some Fe<sup>2</sup><sup>+</sup>&nbsp;to Fe<sup>3</sup><sup>+</sup>. Because Fe(phen)<sub>3</sub><sup>3+</sup>&nbsp;does not absorb as strongly as Fe(phen)<sub>3</sub><sup>2+</sup>, the absorbance decreases, producing a negative determinate error. The excess hydroxylamine reacts with the oxidizing agents, removing them from the solution.</p>



<p>2. The color of the complex is stable between pH levels of 3 and 9. What are some possible complications at more acidic or more basic pH’s?</p>



<p>Because&nbsp;<em>o</em>-phenanthroline is a weak base, its conditional formation constant for Fe(phen)<sub>3</sub><sup>2+</sup>&nbsp;is less favorable at more acidic pH levels, where&nbsp;<em>o</em>-phenanthroline is protonated. The result is a decrease in absorbance and a less sensitive analytical method.</p>



<p>(In&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/09_Titrimetric_Methods/9.3%3A_Complexation_Titrations" target="_blank" rel="noopener">Chapter 9</a>&nbsp;we saw the same effect of pH on the complexation reactions between EDTA and metal ions.)</p>



<p>When the pH is greater than 9, competition between OH<sup>–</sup>&nbsp;and&nbsp;<em>o</em>-phenanthroline for Fe<sup>2</sup><sup>+</sup>&nbsp;also decreased the absorbance. In addition, if the pH is sufficiently basic there is a risk that the iron will precipitate as Fe(OH)<sub>2</sub>.</p>



<p>3. Cadmium is an interferent because it forms a precipitate with&nbsp;<em>o</em>-phenanthroline. What effect would the formation of precipitate have on the determination of iron?</p>



<p>Because&nbsp;<em>o</em>-phenanthroline is present in large excess (2000 μg of&nbsp;<em>o</em>-phenanthroline for 100 μg of Fe<sup>2</sup><sup>+</sup>), it is not likely that the interference is due to an insufficient amount of&nbsp;<em>o</em>-phenanthroline being available to react with the Fe<sup>2</sup><sup>+</sup>. The presence of a precipitate in the sample cell results in the scattering of radiation, which causes an apparent increase in absorbance. Because the measured absorbance increases, the reported concentration is too high.</p>



<p>(Although scattering is a problem here, it can serve as the basis of a useful analytical method. See&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.8%3A_Spectroscopy_Based_on_Scattering" target="_blank" rel="noopener">Section 10.8</a>&nbsp;for further details.)</p>



<p>4. Even high quality ammonium acetate contains a significant amount of iron. Why is this source of iron not a problem?</p>



<p>Because all samples and standards are prepared using the same volume of ammonium acetate buffer, the contribution of this source of iron is accounted for by the calibration curve’s reagent blank.</p>



<h3 class="wp-block-heading" id="quantitative-analysis-for-a-single-analyte">Quantitative Analysis for a Single Analyte</h3>



<p>To determine the concentration of a an analyte we measure its absorbance and apply Beer’s law using any of the standardization methods described in Chapter 5. The most common methods are a normal calibration curve using external standards and the method of standard additions. A single point standardization is also possible, although we must first verify that Beer’s law holds for the concentration of analyte in the samples and the standard.</p>



<p>Example 10.5</p>



<p>The determination of Fe in an industrial waste stream was carried out by the&nbsp;<em>o</em>‑phenanthroline described in&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.3%3A_UV%2F%2FVis_and_IR_Spectroscopy#Representative_Method_10.1" target="_blank" rel="noopener">Representative Method 10.1</a>. Using the data in the following table, determine the mg Fe/L in the waste stream.</p>



<figure class="wp-block-table"><table><tbody><tr><td>mg Fe/L</td><td>absorbance</td></tr><tr><td>0.00</td><td>0.000</td></tr><tr><td>1.00</td><td>0.183</td></tr><tr><td>2.00</td><td>0.364</td></tr><tr><td>3.00</td><td>0.546</td></tr><tr><td>4.00</td><td>0.727</td></tr><tr><td>sample</td><td>0.269</td></tr></tbody></table></figure>



<p><strong><em>Solution</em></strong></p>



<p>Linear regression of absorbance versus the concentration of Fe in the standards gives a calibration curve with the following equation.A=0.0006+0.1817×(mgFe/L)(4.8.3)(4.8.3)A=0.0006+0.1817×(mgFe/L)</p>



<p>Substituting the sample’s absorbance into the calibration expression gives the concentration of Fe in the waste stream as 1.48 mg Fe/L.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12107/absorbance_vs_Fe.png?revision=1" alt="absorbance vs Fe.png"/></figure>



<p>Practice Exercise 10.5</p>



<p>The concentration of Cu<sup>2</sup><sup>+</sup>&nbsp;in a sample can be determined by reacting it with the ligand cuprizone and measuring its absorbance at 606 nm in a 1.00-cm cell. When a 5.00-mL sample is treated with cuprizone and diluted to 10.00 mL, the resulting solution has an absorbance of 0.118. A second 5.00-mL sample is mixed with 1.00 mL of a 20.00 mg/L standard of Cu<sup>2</sup><sup>+</sup>, treated with cuprizone and diluted to 10.00 mL, giving an absorbance of 0.162. Report the mg Cu<sup>2</sup><sup>+</sup>/L in the sample.</p>



<p>Click&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.E%3A_Spectroscopic_Methods_(Exercises)#Practice_Exercise_10.5" target="_blank" rel="noopener">here</a>&nbsp;to review your answer to this exercise.</p>



<h3 class="wp-block-heading" id="quantitative-analysis-of-mixtures">Quantitative Analysis of Mixtures</h3>



<p>Suppose we need to determine the concentration of two analytes, X and Y, in a sample. If each analyte has a wavelength where the other analyte does not absorb, then we can proceed using the approach in Example 10.5. Unfortunately, UV/Vis absorption bands are so broad that it frequently is not possible to find suitable wavelengths. Because Beer’s law is additive the mixture’s absorbance,&nbsp;<em>A</em><sub>mix</sub>, is(Amix)λ1=(εX)λ1bCX+(εY)λ1bCY(10.11)(10.11)(Amix)λ1=(εX)λ1bCX+(εY)λ1bCY</p>



<p>where&nbsp;λ1 is the wavelength at which we measure the absorbance. Because equation 10.11 includes terms for the concentration of both X and Y, the absorbance at one wavelength does not provide enough information to determine either&nbsp;<em>C</em><sub>X</sub>&nbsp;or&nbsp;<em>C</em><sub>Y</sub>. If we measure the absorbance at a second wavelength(Amix)λ2=(εX)λ2bCX+(εY)λ2bCY(10.12)(10.12)(Amix)λ2=(εX)λ2bCX+(εY)λ2bCY</p>



<p>then&nbsp;<em>C</em><sub>X</sub>&nbsp;and&nbsp;<em>C</em><sub>Y</sub>&nbsp;can be determined by solving simultaneously equation10.11 and equation 10.12. Of course, we also must determine the value for ε<sub>X</sub>&nbsp;and ε<sub>Y</sub>&nbsp;at each wavelength. For a mixture of&nbsp;<em>n</em>&nbsp;components, we must measure the absorbance at&nbsp;<em>n</em>&nbsp;different wavelengths.</p>



<p>Example 10.6</p>



<p>The concentrations of Fe<sup>3</sup><sup>+</sup>&nbsp;and Cu<sup>2</sup><sup>+</sup>&nbsp;in a mixture can be determined following their reaction with hexacyanoruthenate (II), Ru(CN)<sub>6</sub><sup>4–</sup>, which forms a purple-blue complex with Fe<sup>3</sup><sup>+</sup>&nbsp;(λ<sub>max</sub>&nbsp;= 550 nm) and a pale-green complex with Cu<sup>2</sup><sup>+</sup>&nbsp;(λ<sub>max</sub>&nbsp;= 396 nm).<sup>7</sup>&nbsp;The molar absorptivities (M<sup>–1</sup>&nbsp;cm<sup>–1</sup>) for the metal complexes at the two wavelengths are summarized in the following table.</p>



<figure class="wp-block-table"><table><tbody><tr><td></td><td>ε<sub>550</sub></td><td>ε<sub>396</sub></td></tr><tr><td>Fe<sup>3</sup><sup>+</sup></td><td>9970</td><td>84</td></tr><tr><td>Cu<sup>2</sup><sup>+</sup></td><td>34</td><td>856</td></tr></tbody></table></figure>



<p>When a sample containing Fe<sup>3</sup><sup>+</sup>&nbsp;and Cu<sup>2</sup><sup>+</sup>&nbsp;is analyzed in a cell with a pathlength of 1.00 cm, the absorbance at 550 nm is 0.183 and the absorbance at 396 nm is 0.109. What are the molar concentrations of Fe<sup>3</sup><sup>+</sup>&nbsp;and Cu<sup>2</sup><sup>+</sup>&nbsp;in the sample?</p>



<p><strong><em>Solution</em></strong></p>



<p>Substituting known values into equations 10.11 and 10.12 givesA550=0.183=9970CFe+34CCu(4.8.4)(4.8.4)A550=0.183=9970CFe+34CCuA396=0.109=84CFe+856CCu(4.8.5)(4.8.5)A396=0.109=84CFe+856CCu</p>



<p>To determine&nbsp;<em>C</em><sub>Fe</sub>&nbsp;and&nbsp;<em>C</em><sub>Cu</sub>&nbsp;we solve the first equation for&nbsp;<em>C</em><sub>Cu</sub>CCu=0.183–9970CFe34(4.8.6)(4.8.6)CCu=0.183–9970CFe34</p>



<p>and substitute the result into the second equation.0.109=84CFe+856×0.183−9970CFe34=4.607–(2.51×105)CFe(4.8.7)(4.8.7)0.109=84CFe+856×0.183−9970CFe34=4.607–(2.51×105)CFe</p>



<p>Solving for&nbsp;<em>C</em><sub>Fe</sub>&nbsp;gives the concentration of Fe<sup>3+</sup>&nbsp;as 1.79 × 10<sup>–5</sup>&nbsp;M. Substituting this concentration back into the equation for the mixture’s absorbance at 396 nm gives the concentration of Cu<sup>2</sup><sup>+</sup>&nbsp;as 1.26 × 10<sup>–4</sup>&nbsp;M.</p>



<p>(Another approach is to multiply the first equation by 856/34 giving4.607=251009CFe+856CCu(4.8.8)(4.8.8)4.607=251009CFe+856CCu</p>



<p>Subtracting the second equation from this equation4.607=251009CFe+856CCu−0.109=84CFe+856CCu–––––––––––––––––––––––––––––––4.498=250925CFe(4.8.9)(4.8.10)(4.8.11)(4.8.9)−4.607=251009CFe+856CCu(4.8.10)−0.109=84CFe+856CCu6CCu_(4.8.11)−4.498=250925CFe</p>



<p>we find that&nbsp;<em>C</em><sub>Fe</sub>&nbsp;is 1.79×10<sup>–5</sup>. Having determined&nbsp;<em>C</em><sub>Fe</sub>&nbsp;we can substitute back into one of the other equations to solve for&nbsp;<em>C</em><sub>Cu</sub>, which is 1.26×10<sup>–5</sup>.)</p>



<p>Practice Exercise 10.6</p>



<p>The absorbance spectra for Cr<sup>3</sup><sup>+</sup>&nbsp;and Co<sup>2</sup><sup>+</sup>&nbsp;overlap significantly. To determine the concentration of these analytes in a mixture, its absorbance was measured at 400 nm and at 505 nm, yielding values of 0.336 and 0.187, respectively. The individual molar absorptivities (M<sup>–1</sup>&nbsp;cm<sup>–1</sup>) are</p>



<figure class="wp-block-table"><table><tbody><tr><td></td><td>ε<sub>400</sub></td><td>ε<sub>505</sub></td></tr><tr><td>Cr<sup>3</sup><sup>+</sup></td><td>15.2</td><td>0.533</td></tr><tr><td>Co<sup>2</sup><sup>+</sup></td><td>5.60</td><td>5.07</td></tr></tbody></table></figure>



<p>Click&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.E%3A_Spectroscopic_Methods_(Exercises)#Practice_Exercise_10.6" target="_blank" rel="noopener">here</a>&nbsp;to review your answer to this exercise.</p>



<p>To obtain results with good accuracy and precision the two wavelengths should be selected so that ε<sub>X</sub>&nbsp;&gt; ε<sub>Y</sub>&nbsp;at one wavelength and ε<sub>X</sub>&nbsp;&lt; ε<sub>Y</sub>&nbsp;at the other wavelength. It is easy to appreciate why this is true. Because the absorbance at each wavelength is dominated by one analyte, any uncertainty in the concentration of the other analyte has less of an impact. Figure 10.35 shows that the choice of wavelengths for Practice Exercise 10.6 are reasonable. When the choice of wavelengths is not obvious, one method for locating the optimum wavelengths is to plot ε<sub>X</sub>/ε<sub>Y</sub>&nbsp;as function of wavelength, and determine the wavelengths where ε<sub>X</sub>/ε<sub>Y</sub>&nbsp;reaches maximum and minimum values.<sup>8</sup></p>



<p>Note</p>



<p>For example, in Example 10.6 the molar absorptivity for Fe<sup>3</sup><sup>+</sup>&nbsp;at 550 nm is 119× that for Cu<sup>2</sup><sup>+</sup>, and the molar absorptivity for Cu<sup>2+</sup>&nbsp;at 396 nm is 10.2× that for Fe<sup>3</sup><sup>+</sup>.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12715/Figure10.35.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12715/Figure10.35.jpg?revision=1&amp;size=bestfit&amp;width=450&amp;height=394" alt="Figure10.35.jpg"/></a></figure>



<p><strong>Figure 10.35</strong>&nbsp;Visible absorption spectra for 0.0250 M Cr<sup>3</sup><sup>+</sup>, 0.0750 M Co<sup>2</sup><sup>+</sup>, and for a mixture of Cr<sup>3</sup><sup>+</sup>&nbsp;and Co<sup>2</sup><sup>+</sup>. The two wavelengths used for analyzing the mixture of Cr<sup>3+</sup>&nbsp;and Co<sup>2</sup><sup>+</sup>&nbsp;are shown by the dashed lines. The data for the two standard solutions are from reference 7.</p>



<p>When the analyte’s spectra overlap severely, such that ε<sub>X</sub>&nbsp;≈ ε<sub>Y</sub>&nbsp;at all wavelength, other computational methods may provide better accuracy and precision. In a multiwavelength linear regression analysis, for example, a mixture’s absorbance is compared to that for a set of standard solutions at several wavelengths.<sup>9</sup>&nbsp;If&nbsp;<em>A</em><sub>SX</sub>and&nbsp;<em>A</em><sub>SY</sub>&nbsp;are the absorbance values for standard solutions of components X and Y at any wavelength, thenASX=εXbCSX(10.13)(10.13)ASX=εXbCSXASY=εYbCSY(10.14)(10.14)ASY=εYbCSY</p>



<p>where&nbsp;<em>C</em><sub>SX</sub>&nbsp;and&nbsp;<em>C</em><sub>SY</sub>&nbsp;are the known concentrations of X and Y in the standard solutions. Solving equation 10.13 and equation 10.14 for ε<sub>X</sub>&nbsp;and ε<sub>Y</sub>, substituting into equation 10.11, and rearranging, givesAmixASX=CXCSX+CYCSY×ASYASX(4.8.12)(4.8.12)AmixASX=CXCSX+CYCSY×ASYASX</p>



<p>To determine&nbsp;<em>C</em><sub>X</sub>&nbsp;and&nbsp;<em>C</em><sub>Y</sub>&nbsp;the mixture’s absorbance and the absorbances of the standard solutions are measured at several wavelengths. Graphing&nbsp;<em>A</em><sub>mix</sub>/<em>A</em><sub>SX</sub>&nbsp;versus&nbsp;<em>A</em><sub>SY</sub>/<em>A</em><sub>SX</sub>&nbsp;gives a straight line with a slope of&nbsp;<em>C</em><sub>Y</sub>/<em>C</em><sub>SY</sub>&nbsp;and a&nbsp;<em>y</em>-intercept of&nbsp;<em>C</em><sub>X</sub>/<em>C</em><sub>SX</sub>. This approach is particularly helpful when it is not possible to find wavelengths where ε<sub>X</sub>&nbsp;&gt; ε<sub>Y</sub>&nbsp;and ε<sub>X</sub>&nbsp;&lt; ε<sub>Y</sub>.</p>



<p>Note</p>



<p>The approach outlined here for a multiwavelength linear regression uses a single standard solution for each analyte. A more rigorous approach uses multiple standards for each analyte. The math behind the analysis of this data—what we call a multiple linear regression—is beyond the level of this text. For more details about multiple linear regression see Brereton, R. G.&nbsp;<em>Chemometrics: Data Analysis for the Laboratory and Chemical Plant</em>, Wiley: Chichester, England, 2003.</p>



<p>Example 10.7</p>



<p>Figure 10.35 shows visible absorbance spectra for a standard solution of 0.0250 M Cr<sup>3</sup><sup>+</sup>, a standard solution of 0.0750 M Co<sup>2+</sup>, and a mixture containing unknown concentrations of each ion. The data for these spectra are shown here.<sup>10</sup></p>



<figure class="wp-block-table"><table><tbody><tr><td>λ&nbsp;(nm)</td><td><em>A</em><sub>Cr</sub></td><td><em>A</em><sub>Co</sub></td><td><em>A</em><sub>mix</sub></td><td>λ&nbsp;(nm)</td><td><em>A</em><sub>Cr</sub></td><td><em>A</em><sub>Co</sub></td><td><em>A</em><sub>mix</sub></td></tr><tr><td>375</td><td>0.26</td><td>0.01</td><td>0.53</td><td>520</td><td>0.19</td><td>0.38</td><td>0.63</td></tr><tr><td>400</td><td>0.43</td><td>0.03</td><td>0.88</td><td>530</td><td>0.24</td><td>0.33</td><td>0.70</td></tr><tr><td>425</td><td>0.39</td><td>0.07</td><td>0.83</td><td>540</td><td>0.28</td><td>0.26</td><td>0.73</td></tr><tr><td>440</td><td>0.29</td><td>0.13</td><td>0.67</td><td>550</td><td>0.32</td><td>0.18</td><td>0.76</td></tr><tr><td>455</td><td>0.20</td><td>0.21</td><td>0.54</td><td>570</td><td>0.38</td><td>0.08</td><td>0.81</td></tr><tr><td>470</td><td>0.14</td><td>0.28</td><td>0.47</td><td>575</td><td>0.39</td><td>0.06</td><td>0.82</td></tr><tr><td>480</td><td>0.12</td><td>0.30</td><td>0.44</td><td>580</td><td>0.38</td><td>0.05</td><td>0.79</td></tr><tr><td>490</td><td>0.11</td><td>0.34</td><td>0.45</td><td>600</td><td>0.34</td><td>0.03</td><td>0.70</td></tr><tr><td>500</td><td>0.13</td><td>0.38</td><td>0.51</td><td>625</td><td>0.24</td><td>0.02</td><td>0.49</td></tr></tbody></table></figure>



<p>Use a multiwavelength regression analysis to determine the composition of the unknown.</p>



<p><em><strong>Solution</strong></em></p>



<p>First we need to calculate values for&nbsp;<em>A</em><sub>mix</sub>/<em>A</em><sub>SX</sub>&nbsp;and for&nbsp;<em>A</em><sub>SY</sub>/<em>A</em><sub>SX</sub>. Let’s define X as Co<sup>2</sup><sup>+</sup>&nbsp;and Y as Cr<sup>3</sup><sup>+</sup>. For example, at a wavelength of 375 nm&nbsp;<em>A</em><sub>mix</sub>/<em>A</em><sub>SX</sub>&nbsp;is 0.53/0.01, or 53 and&nbsp;<em>A</em><sub>SY</sub>/<em>A</em><sub>SX</sub>&nbsp;is 0.26/0.01, or 26. Completing the calculation for all wavelengths and graphing&nbsp;<em>A</em><sub>mix</sub>/<em>A</em><sub>SX</sub>&nbsp;versus&nbsp;<em>A</em><sub>SY</sub>/<em>A</em><sub>SX</sub>gives the result shown in Figure 10.36. Fitting a straight-line to the data gives a regression model ofAmixASX=0.636+2.01×ASYASX(4.8.13)(4.8.13)AmixASX=0.636+2.01×ASYASX</p>



<p>Using the&nbsp;<em>y</em>-intercept, the concentration of Co<sup>2</sup><sup>+</sup>&nbsp;isCXCSX=CCo0.0750M=0.636(4.8.14)(4.8.14)CXCSX=CCo0.0750M=0.636</p>



<p>or&nbsp;<em>C</em><sub>Co</sub>&nbsp;= 0.048 M, and using the slope the concentration of Cr<sup>3+</sup>&nbsp;isCYCSY=CCr0.0250M=2.01(4.8.15)(4.8.15)CYCSY=CCr0.0250M=2.01</p>



<p>or&nbsp;<em>C</em><sub>Cr</sub>&nbsp;= 0.050 M.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12716/Figure10.36.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12716/Figure10.36.jpg?revision=1&amp;size=bestfit&amp;width=330&amp;height=286" alt="Figure10.36.jpg"/></a></figure>



<p><strong>Figure 10.36</strong>&nbsp;Multiwavelength linear regression analysis for the data in Example 10.7.</p>



<p>Practice Exercise 10.7</p>



<p>A mixture of MnO<sub>4</sub><sup>–</sup>&nbsp;and Cr<sub>2</sub>O<sub>7</sub><sup>2–</sup>, and standards of 0.10 mM KMnO<sub>4</sub>&nbsp;and of 0.10 mM K<sub>2</sub>Cr<sub>2</sub>O<sub>7</sub>&nbsp;gives the results shown in the following table. Determine the composition of the mixture. The data for this problem is from Blanco, M. C.; Iturriaga, H.; Maspoch, S.; Tarin, P.&nbsp;<em>J. Chem. Educ.&nbsp;</em><strong>1989</strong>,&nbsp;<em>66</em>, 178–180.</p>



<figure class="wp-block-table"><table><tbody><tr><td>λ&nbsp;(nm)</td><td><em>A</em><sub>Mn</sub></td><td><em>A</em><sub>Cr</sub></td><td><em>A</em><sub>mix</sub></td></tr><tr><td>266</td><td>0.042</td><td>0.410</td><td>0.766</td></tr><tr><td>288</td><td>0.082</td><td>0.283</td><td>0.571</td></tr><tr><td>320</td><td>0.168</td><td>0.158</td><td>0.422</td></tr><tr><td>350</td><td>0.125</td><td>0.318</td><td>0.672</td></tr><tr><td>360</td><td>0.056</td><td>0.181</td><td>0.366</td></tr></tbody></table></figure>



<p>(There are many additional ways to analyze mixtures spectrophotometrically, including generalized standard additions, H-point standard additions, principal component regression to name a few. Consult the chapter’s&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/Additional_Resources#Chapter_10" target="_blank" rel="noopener">additional resources</a>&nbsp;for further information.)</p>



<p>Click&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.E%3A_Spectroscopic_Methods_(Exercises)#Practice_Exercise_10.7" target="_blank" rel="noopener">here</a>&nbsp;to review your answer to this exercise.</p>



<h2 class="wp-block-heading" id="10-3-3-qualitative-applications">10.3.3 Qualitative Applications</h2>



<p>As discussed earlier in&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.2%3A_Spectroscopy_Based_on_Absorption#10.2.1_Absorbance_Spectra" target="_blank" rel="noopener">Section 10.2.1</a>, ultraviolet, visible, and infrared absorption bands result from the absorption of electromagnetic radiation by specific valence electrons or bonds. The energy at which the absorption occurs, and its intensity is determined by the chemical environment of the absorbing moiety. For example, benzene has several ultraviolet absorption bands due to π → π* transitions. The position and intensity of two of these bands, 203.5 nm (ε = 7400 M<sup>–1</sup>&nbsp;cm<sup>–1</sup>) and 254 nm (ε = 204 M<sup>–1</sup>&nbsp;cm<sup>–1</sup>), are sensitive to substitution. For benzoic acid, in which a carboxylic acid group replaces one of the aromatic hydrogens, the two bands shift to 230 nm (ε = 11 600 M<sup>–1</sup>&nbsp;cm<sup>–1</sup>) and 273 nm (ε = 970 M<sup>–1</sup>&nbsp;cm<sup>–1</sup>). A variety of rules have been developed to aid in correlating UV/Vis absorption bands to chemical structure. Similar correlations have been developed for infrared absorption bands. For example a carbonyl’s C=O stretch is sensitive to adjacent functional groups, occurring at 1650 cm<sup>–1</sup>&nbsp;for acids, 1700 cm<sup>–1</sup>&nbsp;for ketones, and 1800 cm<sup>–1</sup>&nbsp;for acid chlorides. The interpretation of UV/Vis and IR spectra receives adequate coverage elsewhere in the chemistry curriculum, notably in organic chemistry, and is not considered further in this text.</p>



<p>With the availability of computerized data acquisition and storage it is possible to build digital libraries of standard reference spectra. The identity of an a unknown compound can often be determined by comparing its spectrum against a library of reference spectra, a process is known as&nbsp;<strong>spectral searching</strong>. Comparisons are made using an algorithm that calculates the cumulative difference between the sample’s spectrum and a reference spectrum. For example, one simple algorithm uses the following equationD=∑i=1n|(Asample)i−(Areference)i|(4.8.16)(4.8.16)D=∑i=1n|(Asample)i−(Areference)i|</p>



<p>where&nbsp;<em>D</em>&nbsp;is the cumulative difference,&nbsp;<em>A</em><sub>sample</sub>&nbsp;is the sample’s absorbance at wavelength or wavenumber&nbsp;<em>i</em>,&nbsp;<em>A</em><sub>reference</sub>&nbsp;is the absorbance of the reference compound at the same wavelength or wavenumber, and&nbsp;<em>n</em>&nbsp;is the number of digitized points in the spectra. The cumulative difference is calculated for each reference spectrum. The reference compound with the smallest value of&nbsp;<em>D</em>&nbsp;provides the closest match to the unknown compound. The accuracy of spectral searching is limited by the number and type of compounds included in the library, and by the effect of the sample’s matrix on the spectrum.</p>



<p>Another advantage of computerized data acquisition is the ability to subtract one spectrum from another. When coupled with spectral searching it may be possible, by repeatedly searching and subtracting reference spectra, to determine the identity of several components in a sample without the need of a prior separation step. An example is shown in Figure 10.37 in which the composition of a two-component mixture is determined by successive searching and subtraction. Figure 10.37a shows the spectrum of the mixture. A search of the spectral library selects cocaine&nbsp;<sup>.</sup>&nbsp;HCl (Figure 10.37b) as a likely component of the mixture. Subtracting the reference spectrum for cocaine&nbsp;<sup>.&nbsp;</sup>HCl from the mixture’s spectrum leaves a result (Figure 10.37c) that closely matches mannitol’s reference spectrum (Figure 10.37d). Subtracting the reference spectrum for leaves only a small residual signal (Figure 10.37e).</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12717/Figure10.37.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12717/Figure10.37.jpg?revision=1&amp;size=bestfit&amp;width=600&amp;height=838" alt="Figure10.37.jpg"/></a></figure>



<p><strong>Figure 10.37</strong>&nbsp;Identifying the components of a mixture by spectral searching and subtracting. (a) IR spectrum of the mixture; (b) Reference IR spectrum of cocaine<sup>.</sup>&nbsp;HCl; (c) Result of subtracting the spectrum of cocaine&nbsp;<sup>.</sup>&nbsp;HCl from the mixture’s spectrum; (d) Reference IR spectrum of mannitol; and (e) The residual spectrum after removing mannitol’s contribution to the mixture’s spectrum.</p>



<p>Note</p>



<p>IR spectra traditionally are displayed using percent transmittance, %T, along the<em>&nbsp;y</em>-axis (for example, see Figure 10.16). Because absorbance—not percent transmittance—is a linear function of concentration, spectral searching and spectral subtraction, is easier to do when displaying absorbance on the&nbsp;<em>y</em>-axis.</p>



<h2 class="wp-block-heading" id="10-3-4-characterization-applications">10.3.4 Characterization Applications</h2>



<p>Molecular absorption, particularly in the UV/Vis range, has been used for a variety of different characterization studies, including determining the stoichiometry of metal–ligand complexes and determining equilibrium constants. Both of these examples are examined in this section.</p>



<h3 class="wp-block-heading" id="stoichiometry-of-a-metal-ligand-complex">Stoichiometry of a Metal-Ligand Complex</h3>



<p>We can determine the stoichiometry of a metal–ligand complexation reactionM+yL⇋MLy(4.8.17)(4.8.17)M+yL⇋MLy</p>



<p>using one of three methods: the method of continuous variations, the mole-ratio method, and the slope-ratio method. Of these approaches, the&nbsp;<strong>method of continuous variations</strong>, also called Job’s method, is the most popular. In this method a series of solutions is prepared such that the total moles of metal and ligand,&nbsp;<em>n</em><sub>total</sub>, in each solution is the same. If (<em>n</em><sub>M</sub>)<sub><em>i</em></sub>&nbsp;and (<em>n</em><sub>L</sub>)<sub><em>i</em></sub>&nbsp;are, respectively, the moles of metal and ligand in solution&nbsp;<em>i</em>, thenntotal=(nM)i+(nL)i(4.8.18)(4.8.18)ntotal=(nM)i+(nL)i</p>



<p>The relative amount of ligand and metal in each solution is expressed as the mole fraction of ligand, (<em>X</em><sub>L</sub>)<sub><em>i</em></sub>, and the mole fraction of metal, (<em>X</em><sub>M</sub>)<sub><em>i</em></sub>,(XL)i=(nL)intotal(4.8.19)(4.8.19)(XL)i=(nL)intotal(XM)i=1−(nL)intotal=(nM)intotal(4.8.20)(4.8.20)(XM)i=1−(nL)intotal=(nM)intotal</p>



<p>The concentration of the metal–ligand complex in any solution is determined by the limiting reagent, with the greatest concentration occurring when the metal and the ligand are mixed stoichiometrically. If we monitor the complexation reaction at a wavelength where only the metal–ligand complex absorbs, a graph of absorbance versus the mole fraction of ligand will have two linear branches—one when the ligand is the limiting reagent and a second when the metal is the limiting reagent. The intersection of these two branches represents a stoichiometric mixing of the metal and the ligand. We can use the mole fraction of ligand at the intersection to determine the value of&nbsp;<em>y</em>&nbsp;for the metal–ligand complex ML<sub><em>y</em></sub>.y=nLnM=XLXM=XL1−XL(4.8.21)(4.8.21)y=nLnM=XLXM=XL1−XL</p>



<p>Note</p>



<p>You also can plot the data as absorbance versus the mole fraction of metal. In this case, y is equal to (1–<em>X</em><sub>M</sub>)/<em>X</em><sub>M</sub>.</p>



<figure class="wp-block-image size-large"><img decoding="async" src="http://s7.picofile.com/file/8392387600/uv_vis_in.gif" alt=""/></figure>



<p>Example 10.8</p>



<p>To determine the formula for the complex between Fe<sup>2+</sup>&nbsp;and&nbsp;<em>o</em>-phenanthroline, a series of solutions is prepared in which the total concentration of metal and ligand is held constant at 3.15 × 10<sup>–4</sup>&nbsp;M. The absorbance of each solution is measured at a wavelength of 510 nm. Using the following data, determine the formula for the complex.</p>



<figure class="wp-block-table"><table><tbody><tr><td><em>X</em><sub>L</sub></td><td>absorbance</td><td><em>X</em><sub>L</sub></td><td>absorbance</td></tr><tr><td>0.000</td><td>0.000</td><td>0.600</td><td>0.693</td></tr><tr><td>0.100</td><td>0.116</td><td>0.700</td><td>0.809</td></tr><tr><td>0.200</td><td>0.231</td><td>0.800</td><td>0.693</td></tr><tr><td>0.300</td><td>0.347</td><td>0.900</td><td>0.347</td></tr><tr><td>0.400</td><td>0.462</td><td>1.000</td><td>0.000</td></tr><tr><td>0.500</td><td>0.578</td><td></td><td></td></tr></tbody></table></figure>



<p>(To prepare the solutions for this example I first prepared a solution of 3.15 × 10<sup>-4</sup>&nbsp;M Fe<sup>2</sup><sup>+</sup>&nbsp;and a solution of 3.15 × 10<sup>-4</sup>&nbsp;M&nbsp;<em>o</em>-phenanthroline. Because the two stock solutions are of equal concentration, diluting a portion of one solution with the other solution gives a mixture in which the combined concentration of&nbsp;<em>o</em>-phenanthroline and Fe<sup>2</sup><sup>+</sup>&nbsp;is 3.15 × 10<sup>-4</sup>&nbsp;M. If each solution has the same volume, then each solution contains the same total moles of metal and ligand.)</p>



<p><strong><em>Solution</em></strong></p>



<p>A plot of absorbance versus the mole fraction of ligand is shown in Figure 10.38. To find the maximum absorbance, we extrapolate the two linear portions of the plot. The two lines intersect at a mole fraction of ligand of 0.75. Solving for&nbsp;<em>y</em>&nbsp;givesy=XL1–XL=0.751–0.75=3(4.8.22)(4.8.22)y=XL1–XL=0.751–0.75=3</p>



<p>The formula for the metal–ligand complex is Fe(<em>o</em>-phenanthroline)<sub>3</sub><sup>2+</sup>.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12718/Figure10.38.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12718/Figure10.38.jpg?revision=1&amp;size=bestfit&amp;width=600&amp;height=565" alt="Figure10.38.jpg"/></a></figure>



<p><strong>Figure 10.38&nbsp;</strong>Continuous variations plot for Example 10.8. The photo shows the solutions used in gathering the data. Each solution is displayed directly below its corresponding point on the continuous variations plot.</p>



<p>Practice Exercise 10.8</p>



<p>Use the continuous variations data in the following table to determine the formula for the complex between Fe<sup>2</sup><sup>+</sup>&nbsp;and SCN<sup>–</sup>. The data for this problem is adapted from Meloun, M.; Havel, J.; Högfeldt, E.&nbsp;<em>Computation of Solution Equilibria</em>, Ellis Horwood: Chichester, England, 1988, p. 236.</p>



<figure class="wp-block-table"><table><tbody><tr><td><em>X</em><sub>L</sub></td><td>absorbance</td><td><em>X</em><sub>L</sub></td><td>absorbance</td><td><em>X</em><sub>L</sub></td><td>absorbance</td><td><em>X</em><sub>L</sub></td><td>absorbance</td></tr><tr><td>0.0200</td><td>0.068</td><td>0.2951</td><td>0.670</td><td>0.5811</td><td>0.790</td><td>0.8923</td><td>0.325</td></tr><tr><td>0.0870</td><td>0.262</td><td>0.3887</td><td>0.767</td><td>0.6860</td><td>0.701</td><td>0.9787</td><td>0.071</td></tr><tr><td>0.1792</td><td>0.471</td><td>0.4964</td><td>0.807</td><td>0.7885</td><td>0.540</td><td></td><td></td></tr></tbody></table></figure>



<p>Click&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.E%3A_Spectroscopic_Methods_(Exercises)#Practice_Exercise_10.8" target="_blank" rel="noopener">here</a>&nbsp;to review your answer to this exercise.</p>



<p>Several precautions are necessary when using the method of continuous variations. First, the metal and the ligand must form only one metal–ligand complex. To determine if this condition is true, plots of absorbance versus&nbsp;<em>X</em><sub>L</sub>&nbsp;are constructed at several different wavelengths and for several different values of&nbsp;<em>n</em><sub>total</sub>. If the maximum absorbance does not occur at the same value of&nbsp;<em>X</em><sub>L</sub>&nbsp;for each set of conditions, then more than one metal–ligand complex must be present. A second precaution is that the metal–ligand complex’s absorbance must obey Beer’s law. Third, if the metal–ligand complex’s formation constant is relatively small, a plot of absorbance versus&nbsp;<em>X</em><sub>L</sub>&nbsp;may show significant curvature. In this case it is often difficult to determine the stoichiometry by extrapolation. Finally, because the stability of a metal–ligand complex may be influenced by solution conditions, the composition of the solutions must be carefully controlled. When the ligand is a weak base, for example, the solutions must be buffered to the same pH.</p>



<p>In the&nbsp;<strong>mole-ratio method</strong>&nbsp;the amount of one reactant, usually the moles of metal, is held constant, while the amount of the other reactant is varied. The absorbance is monitored at a wavelength where the metal–ligand complex absorbs. A plot of absorbance as a function of the ligand-to-metal mole ratio,&nbsp;<em>n</em><sub>L</sub>/<em>n</em><sub>M</sub>, has two linear branches, which intersect at a mole–ratio corresponding to the complex’s formula. Figure 10.39a shows a mole-ratio plot for the formation of a 1:1 complex in which the absorbance is monitored at a wavelength where only the complex absorbs. Figure 10.39b shows a mole-ratio plot for a 1:2 complex in which all three species—the metal, the ligand, and the complex—absorb at the selected wavelength. Unlike the method of continuous variations, the mole-ratio method can be used for complexation reactions that occur in a stepwise fashion if there is a difference in the molar absorptivities of the metal–ligand complexes, and if the formation constants are sufficiently different. A typical mole-ratio plot for the step-wise formation of ML and ML<sub>2</sub>&nbsp;is shown in Figure 10.39c.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12719/Figure10.39.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12719/Figure10.39.jpg?revision=1&amp;size=bestfit&amp;width=700&amp;height=202" alt="Figure10.39.jpg"/></a></figure>



<p><strong>Figure 10.39</strong>&nbsp;Mole-ratio plots for: (a) a 1:1 metal–ligand complex in which only the complex absorbs; (b) a 1:2 metal–ligand complex in which the metal, the ligand, and the complex absorb; and (c) the stepwise formation of a 1:1 and a 1:2 metal–ligand complex.</p>



<p>In both the method of continuous variations and the mole-ratio method we determine the complex’s stoichiometry by extrapolating absorbance data from conditions in which there is a linear relationship between absorbance and the relative amounts of metal and ligand. If a metal–ligand complex is very weak, a plot of absorbance versus<em>&nbsp;X</em><sub>L</sub>&nbsp;or&nbsp;<em>n</em><sub>L</sub>/<em>n</em><sub>M</sub>&nbsp;may be so curved that it is impossible to determine the stoichiometry by extrapolation. In this case the slope-ratio may be used.</p>



<p>In the&nbsp;<strong>slope-ratio method</strong>&nbsp;two sets of solutions are prepared. The first set of solutions contains a constant amount of metal and a variable amount of ligand, chosen such that the total concentration of metal,&nbsp;<em>C</em><sub>M</sub>, is much larger than the total concentration of ligand,&nbsp;<em>C</em><sub>L</sub>. Under these conditions we may assume that essentially all the ligand reacts in forming the metal–ligand complex. The concentration of the complex, which has the general form M<sub><em>x</em></sub>L<sub><em>y</em></sub>, is[MxLy]=CLy(4.8.23)(4.8.23)[MxLy]=CLy</p>



<p>If we monitor the absorbance at a wavelength where only M<sub><em>x</em></sub>L<sub><em>y</em></sub>&nbsp;absorbs, thenA=εb[MxLy]=εbCLy(4.8.24)(4.8.24)A=εb[MxLy]=εbCLy</p>



<p>and a plot of absorbance versus&nbsp;<em>C</em><sub>L</sub>&nbsp;is linear with a slope,&nbsp;<em>s</em><sub>L</sub>, ofsL=εby(4.8.25)(4.8.25)sL=εby</p>



<p>A second set of solutions is prepared with a fixed concentration of ligand that is much greater than a variable concentration of metal; thus[MxLy]=CMx(4.8.26)(4.8.26)[MxLy]=CMxA=εb[MxLy]=εbCMx(4.8.27)(4.8.27)A=εb[MxLy]=εbCMxsM=εbx(4.8.28)(4.8.28)sM=εbx</p>



<p>A ratio of the slopes provides the relative values of&nbsp;<em>x</em>&nbsp;and&nbsp;<em>y</em>.sMsL=εb/xεb/y=yx(4.8.29)(4.8.29)sMsL=εb/xεb/y=yx</p>



<p>An important assumption in the slope-ratio method is that the complexation reaction continues to completion in the presence of a sufficiently large excess of metal or ligand. The slope-ratio method also is limited to systems in which only a single complex is formed and for which Beer’s law is obeyed.</p>



<h3 class="wp-block-heading" id="determination-of-equilibrium-constants">Determination of Equilibrium Constants</h3>



<p>Another important application of molecular absorption spectroscopy is the determination of equilibrium constants. Let’s consider, as a simple example, an acid–base reaction of the general formHIn(aq)+H2O(l)⇋H3O+(aq)+In−(aq)(4.8.30)(4.8.30)HIn(aq)+H2O(l)⇋H3O+(aq)+In−(aq)</p>



<p>where HIn and In<sup>–</sup>&nbsp;are the conjugate weak acid and weak base forms of an acid–base indicator. The equilibrium constant for this reaction isKa=[H3O+][In−][HIn](4.8.31)(4.8.31)Ka=[H3O+][In−][HIn]</p>



<p>To determine the equilibrium constant’s value, we prepare a solution in which the reaction is in a state of equilibrium and determine the equilibrium concentration of H<sub>3</sub>O<sup>+</sup>, HIn, and In<sup>–</sup>. The concentration of H<sub>3</sub>O<sup>+</sup>&nbsp;is easy to determine by simply measuring the solution’s pH. To determine the concentration of HIn and In<sup>–</sup>&nbsp;we can measure the solution’s absorbance.</p>



<p>If both HIn and In<sup>–</sup>&nbsp;absorb at the selected wavelength, then, from equation 10.6, we know thatA=εHInb[HIn]+εInb[In−](10.15)(10.15)A=εHInb[HIn]+εInb[In−]</p>



<p>where ε<sub>HIn</sub>&nbsp;and ε<sub>In</sub>&nbsp;are the molar absorptivities for HIn and In<sup>–</sup>. The total concentration of indicator,&nbsp;<em>C</em>, is given by a mass balance equationC=[HIn]+[In−](10.16)(10.16)C=[HIn]+[In−]</p>



<p>Solving equation 10.16 for [HIn] and substituting into equation 10.15 givesA=εHInb(C−[In−])+εInb[In−](4.8.32)(4.8.32)A=εHInb(C−[In−])+εInb[In−]</p>



<p>which we simplify toA=εHInbC−εHInb[In−]+εInb[In−](4.8.33)(4.8.33)A=εHInbC−εHInb[In−]+εInb[In−]A=AHIn+b[In−](εIn−εHIn)(10.17)(10.17)A=AHIn+b[In−](εIn−εHIn)</p>



<p>where&nbsp;<em>A</em><sub>HIn</sub>, which is equal to ε<sub>HIn</sub><em>bC</em>, is the absorbance when the pH is acidic enough that essentially all the indicator is present as HIn. Solving equation 10.17 for the concentration of In<sup>–</sup>&nbsp;gives[In−]=A−AHInb(εIn−εHIn)(10.18)(10.18)[In−]=A−AHInb(εIn−εHIn)</p>



<p>Proceeding in the same fashion, we can derive a similar equation for the concentration of HIn[HIn]=AIn−Ab(εIn−εHIn)(10.19)(10.19)[HIn]=AIn−Ab(εIn−εHIn)</p>



<p>where&nbsp;<em>A</em><sub>In</sub>, which is equal to ε<sub>In</sub><em>bC</em>, is the absorbance when the pH is basic enough that only In<sup>–</sup>&nbsp;contributes to the absorbance. Substituting equation 10.18 and equation 10.19 into the equilibrium constant expression for HIn givesKa=[H3O+]A−AHInAIn−A(10.20)(10.20)Ka=[H3O+]A−AHInAIn−A</p>



<p>We can use equation 10.20 to determine the value of&nbsp;<em>K</em><sub>a</sub>&nbsp;in one of two ways. The simplest approach is to prepare three solutions, each of which contains the same amount,&nbsp;<em>C</em>, of indicator. The pH of one solution is made sufficiently acidic such that [HIn] &gt;&gt; [In<sup>−</sup>]. The absorbance of this solution gives&nbsp;<em>A</em><sub>HIn</sub>. The value of&nbsp;<em>A</em><sub>In</sub>&nbsp;is determined by adjusting the pH of the second solution such that [In<sup>−</sup>] &gt;&gt; [HIn]. Finally, the pH of the third solution is adjusted to an intermediate value, and the pH and absorbance,&nbsp;<em>A</em>, recorded. The value of&nbsp;<em>K</em><sub>a</sub>&nbsp;is calculated using equation 10.20.</p>



<p>Example 10.9</p>



<p>The acidity constant for an acid–base indicator is determined by preparing three solutions, each of which has a total indicator concentration of 5.00 × 10<sup>–5</sup>&nbsp;M. The first solution is made strongly acidic with HCl and has an absorbance of 0.250. The second solution was made strongly basic and has an absorbance of 1.40. The pH of the third solution is 2.91 and has an absorbance of 0.662. What is the value of&nbsp;<em>K</em><sub>a</sub>&nbsp;for the indicator?</p>



<p><strong><em>Solution</em></strong></p>



<p>The value of&nbsp;<em>K</em><sub>a</sub>&nbsp;is determined by making appropriate substitutions into 10.20; thusKa=(1.23×10−3)×0.662−0.2501.40−0.662=6.87×10−4(4.8.34)(4.8.34)Ka=(1.23×10−3)×0.662−0.2501.40−0.662=6.87×10−4</p>



<p>Practice Exercise 10.9</p>



<p>To determine the&nbsp;<em>K</em><sub>a</sub>&nbsp;of a merocyanine dye, the absorbance of a solution of 3.5×10<sup>–4</sup>&nbsp;M dye was measured at a pH of 2.00, a pH of 6.00, and a pH of 12.00, yielding absorbances of 0.000, 0.225, and 0.680, respectively. What is the value of&nbsp;<em>K</em><sub>a</sub>&nbsp;for this dye? The data for this problem is adapted from Lu, H.; Rutan, S. C.&nbsp;<em>Anal. Chem.</em>,&nbsp;<strong>1996</strong>,&nbsp;<em>68</em>, 1381–1386.</p>



<p>Click&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.E%3A_Spectroscopic_Methods_(Exercises)#Practice_Exercise_10.9" target="_blank" rel="noopener">here</a>&nbsp;to review your answer to this exercise.</p>



<p>A second approach for determining&nbsp;<em>K</em><sub>a</sub>&nbsp;is to prepare a series of solutions, each containing the same amount of indicator. Two solutions are used to determine values for&nbsp;<em>A</em><sub>HIn</sub>&nbsp;and&nbsp;<em>A</em><sub>In</sub>. Taking the log of both sides of equation 10.20 and rearranging leave us with the following equation.logA−AHInAIn−A=pH−pKa(10.21)(10.21)log⁡A−AHInAIn−A=pH−pKa</p>



<p>A plot of log[(<em>A</em>&nbsp;–&nbsp;<em>A</em><sub>HIn</sub>)/(<em>A</em><sub>In</sub>&nbsp;–&nbsp;<em>A</em>)] versus pH is a straight-line with a slope of +1 and a&nbsp;<em>y</em>-intercept of –p<em>K</em><sub>a</sub>.</p>



<p>Practice Exercise 10.10</p>



<p>To determine the&nbsp;<em>K</em><sub>a</sub>&nbsp;of the indicator bromothymol blue, the absorbance of a series of solutions containing the same concentration of the indicator was measured at pH levels of 3.35, 3.65, 3.94, 4.30, and 4.64, yielding absorbances of 0.170, 0.287, 0.411, 0.562, and 0.670, respectively. Acidifying the first solution to a pH of 2 changes its absorbance to 0.006, and adjusting the pH of the last solution to 12 changes its absorbance to 0.818. What is the value of&nbsp;<em>K</em><sub>a</sub>&nbsp;for this day? The data for this problem is from Patterson, G. S.<em>&nbsp;J. Chem. Educ.</em>,&nbsp;<strong>1999</strong>,&nbsp;<em>76</em>, 395–398.</p>



<p>Click&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/10_Spectroscopic_Methods/10.E%3A_Spectroscopic_Methods_(Exercises)#Practice_Exercise_10.10" target="_blank" rel="noopener">here</a>&nbsp;to review your answer to this exercise.</p>



<p>In developing these approaches for determining&nbsp;<em>K</em><sub>a</sub>&nbsp;we considered a relatively simple system in which the absorbance of HIn and In<sup>–</sup>&nbsp;are easy to measure and for which it is easy to determine the concentration of H<sub>3</sub>O<sup>+</sup>. In addition to acid–base reactions, we can adapt these approaches to any reaction of the general formX(aq)+Y(aq)⇋Z(aq)(4.8.35)(4.8.35)X(aq)+Y(aq)⇋Z(aq)</p>



<p>including metal–ligand complexation reactions and redox reactions, provided that we can determine spectrophotometrically the concentration of the product, Z, and one of the reactants, and that the concentration of the other reactant can be measured by another method. With appropriate modifications, more complicated systems, in which one or more of these parameters can not be measured, also can be treated.<sup>11</sup></p>



<h2 class="wp-block-heading" id="10-3-5-evaluation-of-uv-vis-and-ir-spectroscopy">10.3.5 Evaluation of UV/Vis and IR Spectroscopy</h2>



<h3 class="wp-block-heading" id="scale-of-operation">Scale of Operation</h3>



<p>Molecular UV/Vis absorption is routinely used for the analysis of trace analytes in macro and meso samples. Major and minor analytes can be determined by diluting the sample before analysis, while concentrating a sample may allow for the analysis of ultratrace analytes. The scale of operations for infrared absorption is generally poorer than that for UV/Vis absorption.</p>



<p>Note</p>



<p>See&nbsp;<a href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Analytical_Chemistry_2.0_(Harvey)/03_The_Vocabulary_of_Analytical_Chemistry/3.4%3A_Selecting_an_Analytical_Method#3D.6_Scale_of_Operation" target="_blank" rel="noopener">Figure 3.5</a>&nbsp;to review the meaning of macro and meso for describing samples, and the meaning of major, minor, and ultratrace for describing analytes.</p>



<h3 class="wp-block-heading" id="accuracy">Accuracy</h3>



<p>Under normal conditions a relative error of 1–5% is easy to obtained with UV/Vis absorption. Accuracy is usually limited by the quality of the blank. Examples of the type of problems that may be encountered include the presence of particulates in a sample that scatter radiation and interferents that react with analytical reagents. In the latter case the interferent may react to form an absorbing species, giving rise to a positive determinate error. Interferents also may prevent the analyte from reacting, leading to a negative determinate error. With care, it may be possible to improve the accuracy of an analysis by as much as an order of magnitude.</p>



<h3 class="wp-block-heading" id="precision">Precision</h3>



<p>In absorption spectroscopy, precision is limited by indeterminate errors—primarily instrumental noise—introduced when measuring absorbance. Precision is generally worse for low absorbances where&nbsp;<em>P</em><sub>0&nbsp;</sub>≈&nbsp;<em>P</em><sub>T</sub>, and for high absorbances when&nbsp;<em>P</em><sub>T</sub>&nbsp;approaches 0. We might expect, therefore, that precision will vary with transmittance.</p>



<p>We can derive an expression between precision and transmittance by applying the propagation of uncertainty as described in Chapter 4. To do so we rewrite Beer’s law asC=−1εblogT(10.22)(10.22)C=−1εblog⁡T</p>



<p>Table 4.10 in Chapter 4 helps us in completing the propagation of uncertainty for equation 10.22, giving the absolute uncertainty in the concentration,&nbsp;<em>s</em><sub>C</sub>, assC=−0.4343εb×sTT(10.23)(10.23)sC=−0.4343εb×sTT</p>



<p>where&nbsp;<em>s</em><sub>T</sub>&nbsp;is the absolute uncertainty in the transmittance. Dividing equation 10.23 by equation 10.22 gives the relative uncertainty in concentration,&nbsp;<em>s</em><sub>C</sub>/<em>C</em>, assCC=0.4343sTTlogT(4.8.36)(4.8.36)sCC=0.4343sTTlog⁡T</p>



<p>If we know the absolute uncertainty in transmittance, we can determine the relative uncertainty in concentration for any transmittance.</p>



<p>Determining the relative uncertainty in concentration is complicated because&nbsp;<em>s</em><sub>T</sub>&nbsp;may be a function of the transmittance. As shown in Table 10.8, three categories of indeterminate instrumental error have been observed.<sup>12</sup>&nbsp;A constant&nbsp;<em>s</em><sub>T</sub>&nbsp;is observed for the uncertainty associated with reading %T on a meter’s analog or digital scale. Typical values are ±0.2–0.3% (a&nbsp;<em>k</em><sub>1</sub>&nbsp;of ±0.002–0.003) for an analog scale, and ±0.001% a (<em>k</em><sub>1</sub>&nbsp;of ±0.000 01) for a digital scale. A constant&nbsp;<em>s</em><sub>T</sub>&nbsp;also is observed for the thermal transducers used in infrared spectrophotometers. The effect of a constant&nbsp;<em>s</em><sub>T</sub>&nbsp;on the relative uncertainty in concentration is shown by curve A in Figure 10.40. Note that the relative uncertainty is very large for both high and low absorbances, reaching a minimum when the absorbance is 0.4343. This source of indeterminate error is important for infrared spectrophotometers and for inexpensive UV/Vis spectrophotometers. To obtain a relative uncertainty in concentration of ±1–2%, the absorbance must be kept within the range 0.1–1.</p>



<figure class="wp-block-table"><table><thead><tr><th scope="col">Category</th><th scope="col">Sources of Indeterminate Error</th><th scope="col">Relative Uncertainty in Concentration</th></tr></thead><tbody><tr><td>sT=k1sT=k1</td><td>%T readout resolution noise in thermal detectors</td><td>sCC=0.4343k1TlogTsCC=0.4343k1Tlog⁡T</td></tr><tr><td>sT=k2T2+T−−−−−−√sT=k2T2+T</td><td>noise in photon detectors</td><td>sCC=0.4343k2logT1+1T−−−−−√sCC=0.4343k2log⁡T1+1T</td></tr><tr><td>sT=k3TsT=k3T</td><td>positioning of sample cell fluctuations in source intensity</td><td>sCC=0.4343k3logTsCC=0.4343k3log⁡T</td></tr></tbody></table></figure>



<p>Values of&nbsp;<em>s</em><sub>T</sub>&nbsp;are a complex function of transmittance when indeterminate errors are dominated by the noise associated with photon detectors. Curve B in Figure 10.40 shows that the relative uncertainty in concentration is very large for low absorbances, but is less at higher absorbances. Although the relative uncertainty reaches a minimum when the absorbance is 0.963, there is little change in the relative uncertainty for absorbances within the range 0.5–2. This source of indeterminate error generally limits the precision of high quality UV/Vis spectrophotometers for mid-to-high absorbances.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12720/Figure10.40.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12720/Figure10.40.jpg?revision=1&amp;size=bestfit&amp;width=450&amp;height=392" alt="Figure10.40.jpg"/></a></figure>



<p><strong>Figure 10.40</strong>&nbsp;Percent relative uncertainty in concentration as a function of absorbance for the categories of indeterminate errors in Table 10.8. A:&nbsp;<em>k</em><sub>1</sub>&nbsp;= ±0.0030; B:&nbsp;<em>k</em><sub>2</sub>&nbsp;= ±0.0030; C:<em>k</em><sub>3</sub>&nbsp;= ±0.0130. The dashed lines correspond to the minimum uncertainty for curve A (absorbance of 0.4343) and for curve B (absorbance of 0.963).</p>



<p>Finally, the value of&nbsp;<em>s</em><sub>T</sub>&nbsp;is directly proportional to transmittance for indeterminate errors resulting from fluctuations in the source’s intensity and from uncertainty in positioning the sample within the spectrometer. The latter is particularly important because the optical properties of any sample cell are not uniform. As a result, repositioning the sample cell may lead to a change in the intensity of transmitted radiation. As shown by curve C in Figure 10.40, the effect is only important at low absorbances. This source of indeterminate errors is usually the limiting factor for high quality UV/Vis spectrophotometers when the absorbance is relatively small.</p>



<p>When the relative uncertainty in concentration is limited by the %T readout resolution, the precision of the analysis can be improved by redefining 100% T and 0% T. Normally 100% T is established using a blank and 0% T is established while preventing the source’s radiation from reaching the detector. If the absorbance is too high, precision can be improved by resetting 100% T using a standard solution of the analyte whose concentration is less than that of the sample (Figure 10.41a). For a sample whose absorbance is too low, precision can be improved by redefining 0% T using a standard solution of the analyte whose concentration is greater than that of the analyte (Figure 10.41b). In this case a calibration curve is required because a linear relationship between absorbance and concentration no longer exists. Precision can be further increased by combining these two methods (Figure 10.41c). Again, a calibration curve is necessary since the relationship between absorbance and concentration is no longer linear.</p>



<figure class="wp-block-image"><a href="https://chem.libretexts.org/@api/deki/files/12721/Figure10.41.jpg?revision=1" target="_blank" rel="noopener"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/12721/Figure10.41.jpg?revision=1&amp;size=bestfit&amp;width=300&amp;height=330" alt="Figure10.41.jpg"/></a></figure>



<p><strong>Figure 10.41</strong>&nbsp;Methods for improving the precision of absorption methods: (a) high-absorbance method; (b) low-absorbance method; (c) maximum precision method.</p>



<h3 class="wp-block-heading" id="sensitivity">Sensitivity</h3>



<p>The sensitivity of a molecular absorption method, which is the slope of a Beer’s law calibration curve, is the product of the analyte’s absorptivity and the pathlength of the sample cell (ε<em>b</em>). You can improve a method’s sensitivity by selecting a wavelength where absorbance is at a maximum or by increasing the pathlength.</p>



<p>Note</p>



<p>See Figure 10.24 for an example of how the choice of wavelength affects a calibration curve’s sensitivity.</p>



<h3 class="wp-block-heading" id="selectivity">Selectivity</h3>



<p>Selectivity is rarely a problem in molecular absorption spectrophotometry. In many cases it is possible to find a wavelength where only the analyte absorbs. When two or more species do contribute to the measured absorbance, a multicomponent analysis is still possible, as shown in Example 10.6 and Example 10.7.</p>



<h3 class="wp-block-heading" id="time-cost-and-equipment">Time, Cost, and Equipment</h3>



<p>The analysis of a sample by molecular absorption spectroscopy is relatively rapid, although additional time may be required if we need to chemically convert a nonabsorbing analyte into an absorbing form. The cost of UV/Vis instrumentation ranges from several hundred dollars for a simple filter photometer, to more than $50,000 for a computer controlled high resolution, double-beam instrument equipped with variable slits, and operating over an extended range of wavelengths. Fourier transform infrared spectrometers can be obtained for as little as $15,000–$20,000, although more expensive models are available.</p>



<h2 class="wp-block-heading" id="contributors">Contributors</h2>



<p><a rel="noreferrer noopener" href="http://dpuadweb.depauw.edu/harvey_web/Index.html" target="_blank">David Harvey</a>&nbsp;<a rel="noreferrer noopener" href="http://www.depauw.edu/" target="_blank">(DePauw University)</a></p>



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<p>While interaction with infrared light causes molecules to undergo vibrational transitions, the shorter wavelength, higher energy radiation in the UV (200-400 nm) and visible (400-700 nm) range of the electromagnetic spectrum causes many organic molecules to undergo&nbsp;<strong>electronic transitions</strong>. What this means is that when the energy from UV or visible light is absorbed by a molecule, one of its electrons jumps from a lower energy to a higher energy molecular orbital.</p>



<figure class="wp-block-image size-large"><a href="http://www.analyzetest.com/index.php/contact-us/"><img decoding="async" src="http://s7.picofile.com/file/8392387600/uv_vis_in.gif" alt=""/></a></figure>



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<h2 class="wp-block-heading" id="electronic-transitions">Electronic transitions</h2>



<p>Let’s take as our first example the simple case of molecular hydrogen, H<sub>2</sub>. As you may recall from section 2.1A, the molecular orbital picture for the hydrogen molecule consists of one bonding&nbsp;σ&nbsp;MO, and a higher energy antibonding&nbsp;σ* MO. When the molecule is in the ground state, both electrons are paired in the lower-energy bonding orbital – this is the Highest Occupied Molecular Orbital (HOMO). The antibonding&nbsp;σ* orbital, in turn, is the Lowest Unoccupied Molecular Orbital (LUMO).</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140660/image023.png?revision=1" alt="image024.png"/></figure>



<p>If the molecule is exposed to light of a wavelength with energy equal to&nbsp;<strong>Δ</strong>E, the HOMO-LUMO energy gap, this wavelength will be absorbed and the energy used to bump one of the electrons from the HOMO to the LUMO – in other words, from the&nbsp;σ&nbsp;to the&nbsp;σ* orbital. This is referred to as a&nbsp;<strong>σ&nbsp;</strong><strong>&#8211;&nbsp;</strong><strong>σ</strong><strong>* transition</strong>.&nbsp;<strong>Δ</strong>E for this electronic transition is 258 kcal/mol, corresponding to light with a wavelength of 111 nm.</p>



<p>When a double-bonded molecule such as ethene (common name ethylene) absorbs light, it undergoes a&nbsp;<strong>π</strong><strong>&nbsp;&#8211;&nbsp;</strong><strong>π</strong><strong>* transition.&nbsp;</strong>Because&nbsp;π-&nbsp;π* energy gaps are narrower than&nbsp;σ&nbsp;<strong>&#8211;</strong>&nbsp;σ<strong>*&nbsp;</strong>gaps, ethene absorbs light at 165 nm &#8211; a longer wavelength than molecular hydrogen.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140652/image025.png?revision=1" alt="image026.png"/></figure>



<p>The electronic transitions of both molecular hydrogen and ethene are too energetic to be accurately recorded by standard UV spectrophotometers, which generally have a range of 220 – 700 nm. Where UV-vis spectroscopy becomes useful to most organic and biological chemists is in the study of molecules with conjugated&nbsp;ππsystems. In these groups, the energy gap for&nbsp;π&nbsp;-π* transitions is smaller than for isolated double bonds, and thus the wavelength absorbed is longer. Molecules or parts of molecules that absorb light strongly in the UV-vis region are called&nbsp;<strong>chromophores</strong>.</p>



<p>Let’s revisit the MO picture for 1,3-butadiene, the simplest conjugated system. Recall that we can draw a diagram showing the four pi MO’s that result from combining the four 2p<sub>z</sub>&nbsp;atomic orbitals. The lower two orbitals are bonding, while the upper two are antibonding.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140644/image027.png?revision=1" alt="image028.png"/></figure>



<p>Comparing this MO picture to that of ethene, our isolated pi-bond example, we see that the HOMO-LUMO energy gap is indeed smaller for the conjugated system. 1,3-butadiene absorbs UV light with a wavelength of 217 nm.</p>



<p>As conjugated pi systems become larger, the energy gap for a&nbsp;π&nbsp;&#8211;&nbsp;π* transition becomes increasingly narrow, and the wavelength of light absorbed correspondingly becomes longer. The absorbance due to the&nbsp;π&nbsp;&#8211;&nbsp;π* transition in 1,3,5-hexatriene, for example, occurs at 258 nm, corresponding to a&nbsp;<strong>Δ</strong>E of 111 kcal/mol.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140637/image029.png?revision=1" alt="image030.png"/></figure>



<p>In molecules with extended pi systems, the HOMO-LUMO energy gap becomes so small that absorption occurs in the visible rather then the UV region of the electromagnetic spectrum. Beta-carotene, with its system of 11 conjugated double bonds, absorbs light with wavelengths in the blue region of the visible spectrum while allowing other visible wavelengths – mainly those in the red-yellow region &#8211; to be transmitted. This is why carrots are orange.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140631/image031.png?revision=1" alt="image032.png"/></figure>



<p>The conjugated pi system in 4-methyl-3-penten-2-one gives rise to a strong UV absorbance at 236 nm due to a&nbsp;π&nbsp;&#8211;&nbsp;π* transition. However, this molecule also absorbs at 314 nm. This second absorbance is due to the transition of a non-bonding (lone pair) electron on the oxygen up to a&nbsp;π* antibonding MO:</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140625/image033.png?revision=1" alt="image034.png"/></figure>



<p>This is referred to as an&nbsp;<strong>n</strong><strong>&nbsp;&#8211;&nbsp;π</strong><strong>* transition</strong>. The nonbonding (n) MO’s are higher in energy than the highest bonding p orbitals, so the energy gap for an&nbsp;n→π∗n→π∗transition is smaller that that of a&nbsp;π&nbsp;&#8211;&nbsp;π* transition – and thus the n &#8211;&nbsp;π* peak is at a longer wavelength. In general, n &#8211;&nbsp;π* transitions are weaker (less light absorbed) than those due to&nbsp;π &#8211;&nbsp;π* transitions.</p>



<p><strong><u>Exercise 4.9</u></strong></p>



<p>What is the energy of the photons (in kJ/mol) of light with wavelength of 470 nm, the&nbsp;l<sub>max</sub>&nbsp;of&nbsp;b-carotene?</p>



<p><strong><u>Exercise 4.10</u></strong></p>



<p>Which of the following molecules would you expect absorb at a longer wavelength in the UV region of the electromagnetic spectrum? Explain your answer.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140619/image035.png?revision=1&amp;size=bestfit&amp;width=306&amp;height=155" alt="image036.png"/></figure>



<p><a target="_blank" href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)/Solution_Manual/Chapter_04_Solutions" rel="noreferrer noopener">Solutions</a></p>



<p><strong>Protecting yourself from sunburn</strong></p>



<p>Human skin can be damaged by exposure to ultraviolet light from the sun. We naturally produce a pigment, called melanin, which protects the skin by absorbing much of the ultraviolet radiation. Melanin is a complex polymer, two of the most common monomers units of which are shown below.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140772/sunscreen.png?revision=1&amp;size=bestfit&amp;width=461&amp;height=391" alt=""/></figure>



<p>Overexposure to the sun is still dangerous, because there is a limit to how much radiation our melanin can absorb. Most commercial sunscreens claim to offer additional protection from both UV-A and UV-B radiation: UV-A refers to wavelengths between 315-400 nm, UV-B to shorter, more harmful wavelengths between 280-315 nm. PABA (<em>para</em>-aminobenzoic acid) was used in sunscreens in the past, but its relatively high polarity meant that it was not very soluble in oily lotions, and it tended to rinse away when swimming. Many sunscreens today contain, among other active ingredients, a more hydrophobic derivative of PABA called Padimate O.</p>



<figure class="wp-block-image size-large"><a href="http://www.analyzetest.com/index.php/contact-us/"><img decoding="async" src="http://s7.picofile.com/file/8392387600/uv_vis_in.gif" alt=""/></a></figure>



<h2 class="wp-block-heading" id="looking-at-uv-vis-spectra">Looking at UV-vis spectra</h2>



<p>We have been talking in general terms about how molecules absorb UV and visible light – now let&#8217;s look at some actual examples of data from a UV-vis absorbance spectrophotometer. The basic setup is the same as for IR spectroscopy: radiation with a range of wavelengths is directed through a sample of interest, and a detector records which wavelengths were absorbed and to what extent the absorption occurred.</p>



<p><img decoding="async" alt="" width="670px" height="376px" src="https://chem.libretexts.org/@api/deki/files/140776/Schematic_of_UV-_visible_spectrophotometer.png?revision=1&amp;size=bestfit&amp;width=670&amp;height=376"><strong>Schematic for a UV-Vis spectrophotometer</strong></p>



<p>(Image from&nbsp;<a target="_blank" href="https://upload.wikimedia.org/wikipedia/commons/9/95/Schematic_of_UV-_visible_spectrophotometer.png" rel="noreferrer noopener">Wikipedia Commons</a>)</p>



<p>Below is the absorbance spectrum of an important biological molecule called nicotinamide adenine dinucleotide, abbreviated NAD<sup>+</sup>. This compound absorbs light in the UV range due to the presence of conjugated pi-bonding systems.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140612/image037.png?revision=1" alt="image038.png"/></figure>



<p>You’ll notice that this UV spectrum is much simpler than the IR spectra we saw earlier: this one has only one peak, although many molecules have more than one. Notice also that the convention in UV-vis spectroscopy is to show the baseline at the bottom of the graph with the peaks pointing up. Wavelength values on the x-axis are generally measured in nanometers (nm) rather than in cm<sup>-1</sup>&nbsp;as is the convention in IR spectroscopy.</p>



<p>Peaks in UV spectra tend to be quite broad, often spanning well over 20 nm at half-maximal height. Typically, there are two things that we look for and record from a UV-Vis spectrum. The first is&nbsp;λmaxλmax, which is the wavelength at maximal light absorbance. As you can see, NAD<sup>+</sup>&nbsp;has&nbsp;λmax=260nmλmax=260nm. We also want to record how much light is absorbed at&nbsp;λmaxλmax. Here we use a unitless number called&nbsp;<strong>absorbance</strong>, abbreviated &#8216;A&#8217;. This contains the same information as the &#8216;percent transmittance&#8217; number used in IR spectroscopy, just expressed in slightly different terms. To calculate absorbance at a given wavelength, the computer in the spectrophotometer simply takes the intensity of light at that wavelength&nbsp;<em>before</em>&nbsp;it passes through the sample (I<sub>0</sub>), divides this value by the intensity of the same wavelength&nbsp;<em>after</em>&nbsp;it passes through the sample (I), then takes the log<sub>10</sub>&nbsp;of that number:A=logI0I(4.3.1)(4.3.1)A=log⁡I0I</p>



<p>You can see that the absorbance value at 260 nm (A<sub>260</sub>) is about 1.0 in this spectrum.</p>



<p><strong>Exercise 4.11</strong></p>



<p>Express A = 1.0 in terms of percent transmittance (%T, the unit usually used in IR spectroscopy (and sometimes in UV-vis as well).</p>



<p><a target="_blank" href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)/Solution_Manual/Chapter_04_Solutions" rel="noreferrer noopener">Solutions</a></p>



<p>Here is the absorbance spectrum of the common food coloring Red #3:</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140602/image039.png?revision=1" alt="image040.png"/></figure>



<p>Here, we see that the extended system of conjugated pi bonds causes the molecule to absorb light in the visible range. Because the&nbsp;<strong>λ</strong><sub>max&nbsp;</sub>of 524 nm falls within the green region of the spectrum, the compound appears red to our eyes. Now, take a look at the spectrum of another food coloring, Blue #1:</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140595/image041.png?revision=1" alt="image042.png"/></figure>



<p>Here, maximum absorbance is at 630 nm, in the orange range of the visible spectrum, and the compound appears blue.</p>



<h2 class="wp-block-heading" id="applications-of-uv-spectroscopy-in-organic-and-biological-chemistry">Applications of UV spectroscopy in organic and biological chemistry</h2>



<p>UV-vis spectroscopy has many different applications in organic and biological chemistry. One of the most basic of these applications is the use of the&nbsp;<a href="https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)/Spectroscopy/Electronic_Spectroscopy/Electronic_Spectroscopy_Basics/The_Beer-Lambert_Law" target="_blank" rel="noopener"><strong>Beer &#8211; Lambert Law</strong></a>&nbsp;to determine the concentration of a chromophore. You most likely have performed a Beer – Lambert experiment in a previous chemistry lab. The law is simply an application of the observation that, within certain ranges, the absorbance of a chromophore at a given wavelength varies in a linear fashion with its concentration: the higher the concentration of the molecule, the greater its absorbance.</p>



<p>If we divide the observed value of A at&nbsp;λ<sub>max</sub>&nbsp;by the concentration of the sample (<em>c</em>, in mol/L), we obtain the&nbsp;<strong>molar absorptivity</strong>, or&nbsp;<strong>extinction coefficient</strong>&nbsp;(<strong>ε</strong>), which is a characteristic value for a given compound.ϵ=Ac(4.3.2)(4.3.2)ϵ=Ac</p>



<p>The absorbance will also depend, of course, on the&nbsp;<strong>path length</strong>&nbsp;&#8211; in other words, the distance that the beam of light travels though the sample. In most cases, sample holders are designed so that the path length is equal to 1 cm, so the units for molar absorptivity are L<sub>*</sub>&nbsp;mol<sup>-1</sup><sub>*</sub>cm<sup>-1</sup>. If we look up the value of e for our compound at&nbsp;λ<sub>max</sub>, and we measure absorbance at this wavelength, we can easily calculate the concentration of our sample. As an example, for NAD<sup>+</sup>&nbsp;the literature value of&nbsp;ε&nbsp;at 260 nm is 18,000 L<sub>*</sub>&nbsp;mol<sup>-1</sup><sub>*</sub>cm<sup>-1</sup>. In our NAD<sup>+</sup>&nbsp;spectrum we observed A<sub>260</sub>&nbsp;= 1.0, so using equation 4.4 and solving for concentration we find that our sample is 5.6 x 10<sup>-5</sup>&nbsp;M.</p>



<p>The bases of DNA and RNA are good chromophores:</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140587/image043.png?revision=1" alt="image044.png"/></figure>



<p>Biochemists and molecular biologists often determine the concentration of a DNA sample by assuming an average value of&nbsp;ε&nbsp;= 0.020 ng<sup>-1</sup>×mL for double-stranded DNA at its&nbsp;λ<sub>max</sub>&nbsp;of 260 nm (notice that concentration in this application is expressed in mass/volume rather than molarity: ng/mL is often a convenient unit for DNA concentration when doing molecular biology).<strong><u>Exercise 4.12</u></strong>50&nbsp;microliters of an aqueous sample of double stranded DNA is dissolved in 950 microliters of water. This diluted solution has a maximal absorbance of 0.326 at 260 nm. What is the concentration of the original (more concentrated) DNA sample, expressed in&nbsp;micrograms&nbsp;per microliter?<a target="_blank" href="https://chem.libretexts.org/Under_Construction/Purgatory/Book%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)/Solution_Manual/Chapter_04_Solutions" rel="noreferrer noopener">Solutions</a></p>



<p>Because the extinction coefficient of double stranded DNA is slightly lower than that of single stranded DNA, we can use UV spectroscopy to monitor a process known as DNA melting. If a short stretch of double stranded DNA is gradually heated up, it will begin to ‘melt’, or break apart, as the temperature increases (recall that two strands of DNA are held together by a specific pattern of hydrogen bonds formed by ‘base-pairing’).</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140579/image045.png?revision=1" alt="image046.png"/></figure>



<p>As melting proceeds, the absorbance value for the sample increases, eventually reaching a high plateau as all of the double-stranded DNA breaks apart, or ‘melts’. The mid-point of this process, called the ‘melting temperature’, provides a good indication of how tightly the two strands of DNA are able to bind to each other.</p>



<p>Later we will see how the Beer &#8211; Lambert Law and UV spectroscopy provides us with a convenient way to follow the progress of many different enzymatic redox (oxidation-reduction) reactions. In biochemistry, oxidation of an organic molecule often occurs concurrently with reduction of nicotinamide adenine dinucleotide (NAD<sup>+</sup>, the compound whose spectrum we saw earlier in this section) to NADH:</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140570/image047.png?revision=1" alt="image048.png"/></figure>



<p>Both NAD<sup>+</sup>&nbsp;and NADH absorb at 260 nm. However NADH, unlike NAD<sup>+</sup>, has a second absorbance band with&nbsp;λ<sub>max</sub>&nbsp;= 340 nm and&nbsp;ε&nbsp;= 6290 L<sub>*</sub>mol<sup>-1</sup><sub>*</sub>cm<sup>-1</sup>. The figure below shows the spectra of both compounds superimposed, with the NADH spectrum offset slightly on the y-axis:</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140562/image049.png?revision=1" alt="image050.png"/></figure>



<p>By monitoring the absorbance of a reaction mixture at 340 nm, we can &#8216;watch&#8217; NADH being formed as the reaction proceeds, and calculate the rate of the reaction.</p>



<p>UV spectroscopy is also very useful in the study of proteins. Proteins absorb light in the UV range due to the presence of the aromatic amino acids tryptophan, phenylalanine, and tyrosine, all of which are chromophores.</p>



<figure class="wp-block-image"><img decoding="async" src="https://chem.libretexts.org/@api/deki/files/140551/image051.png?revision=1" alt="image052.png"/></figure>



<p>Biochemists frequently use UV spectroscopy to study conformational changes in proteins &#8211; how they change shape in response to different conditions. When a protein undergoes a conformational shift (partial unfolding, for example), the resulting change in the environment around an aromatic amino acid chromophore can cause its UV spectrum to be altered.</p>



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		<title>Analysis and interpretation of Energy-Dispersive X-Ray Spectroscopy (EDS) results</title>
		<link>https://www.analyzetest.com/2021/01/19/analysis-and-interpretation-of-energy-dispersive-x-ray-spectroscopy-eds-results/</link>
		
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		<pubDate>Tue, 19 Jan 2021 10:38:45 +0000</pubDate>
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					<description><![CDATA[Click here to see other posts about EDS Only 8$ for interpretation of your EDS spectrum and 10$ for interpretation of your SEM/TEM micrograghs Payment Upon Completion Send your results... Interaction of an electron beam&#160;with a sample target produces a variety of emissions, including x-rays. An energy-dispersive (EDS) detector is used to separate the characteristic [&#8230;]]]></description>
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<p>Interaction of an electron beam&nbsp;with a sample target produces a variety of emissions, including x-rays. An energy-dispersive (EDS) detector is used to separate the characteristic x-rays of different elements into an energy spectrum, and EDS system software is used to analyze the energy spectrum in order to determine the abundance of specific elements. EDS can be used to find the chemical composition of materials down to a spot size of a few microns, and to create&nbsp;element composition maps&nbsp;over a much broader raster area. Together, these capabilities provide fundamental compositional information for a wide variety of materials.</p>



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<h2 class="wp-block-heading" id="how-it-works-eds">How it Works &#8211; EDS</h2>



<figure class="wp-block-image"><a href="https://d32ogoqmya1dw8.cloudfront.net/images/research_education/geochemsheets/eds_detector.jpg" target="_blank" rel="noreferrer noopener"><img decoding="async" src="https://d32ogoqmya1dw8.cloudfront.net/images/research_education/geochemsheets/eds_detector_100.jpg" alt="Photo of an EDS detector."/></a></figure>



<p><a href="javascript:swapDiv(546870,true, 'block')">Show caption</a></p>



<p>EDS systems are typically integrated into either an&nbsp;<a href="https://serc.carleton.edu/research_education/geochemsheets/techniques/SEM.html" target="_blank" rel="noopener">SEM</a>&nbsp;or&nbsp;<a href="https://serc.carleton.edu/research_education/geochemsheets/techniques/EPMA.html" target="_blank" rel="noopener">EPMA</a>&nbsp;instrument. EDS systems include a sensitive x-ray detector, a liquid nitrogen dewar for cooling, and software to collect and analyze energy spectra. The detector is mounted in the sample chamber of the main instrument at the end of a long arm, which is itself cooled by liquid nitrogen. The most common detectors are made of Si(Li) crystals that operate at low voltages to improve sensitivity, but recent advances in detector technology make availabale so-called &#8220;silicon drift detectors&#8221; that operate at higher count rates without liquid nitrogen cooling.</p>



<p>An EDS detector contains a crystal that absorbs the energy of incoming x-rays by ionization, yielding free electrons in the crystal that become conductive and produce an electrical charge bias. The x-ray absorption thus converts the energy of individual x-rays into electrical voltages of proportional size; the electrical pulses correspond to the characteristic x-rays of the element.</p>



<h2 class="wp-block-heading" id="strengths">Strengths</h2>



<ul class="wp-block-list"><li>When used in &#8220;spot&#8221; mode, a user can acquire a full elemental spectrum in only a few seconds. Supporting software makes it possible to readily identify peaks, which makes EDS a great survey tool to quickly identify unknown phases prior to quantitative analysis.</li><li>EDS can be used in semi-quantitative mode to determine chemical composition by peak-height ratio relative to a standard.</li></ul>



<h2 class="wp-block-heading" id="limitations">Limitations</h2>



<ul class="wp-block-list"><li>There are energy peak overlaps among different elements, particularly those corresponding to x-rays generated by emission from different energy-level shells (K, L and M) in different elements. For example, there are close overlaps of Mn-K<sub>α</sub>&nbsp;and Cr-K<sub>β</sub>, or Ti-K<sub>α</sub>&nbsp;and various L lines in Ba. Particularly at higher energies, individual peaks may correspond to several different elements; in this case, the user can apply deconvolution methods to try peak separation, or simply consider which elements make &#8220;most sense&#8221; given the known context of the sample.</li><li>Because the wavelength-dispersive (<a href="https://serc.carleton.edu/research_education/geochemsheets/wds.html" target="_blank" rel="noopener">WDS</a>) method is more precise and capable of detecting lower elemental abundances, EDS is less commonly used for actual chemical analysis although improvements in detector resolution make EDS a reliable and precise alternative.</li><li>EDS cannot detect the lightest elements, typically below the atomic number of Na for detectors equipped with a Be window. Polymer-based thin windows allow for detection of light elements, depending on the instrument and operating conditions.</li></ul>



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<h2 class="wp-block-heading" id="results">Results</h2>



<p>A typical EDS spectrum is portrayed as a plot of x-ray counts vs. energy (in keV). Energy peaks correspond to the various elements in the sample. Generally they are narrow and readily resolved, but many elements yield multiple peaks. For example, iron commonly shows strong K<sub>α</sub>&nbsp;and K<sub>β</sub>peaks. Elements in low abundance will generate x-ray peaks that may not be resolvable from the background radiation.</p>



<figure class="wp-block-image"><a href="https://d32ogoqmya1dw8.cloudfront.net/images/research_education/geochemsheets/eds_spectrum_of_glass.png" target="_blank" rel="noreferrer noopener"><img decoding="async" src="https://d32ogoqmya1dw8.cloudfront.net/images/research_education/geochemsheets/eds_spectrum_of_glass_300.png" alt="X-ray energy spectrum of glass."/></a></figure>



<p>EDS spectrum of multi-element glass (NIST K309) containing O, Al, Si, Ca, Ba and Fe (Goldstein et al., 2003).&nbsp;<a href="https://serc.carleton.edu/details/images/8461.html" target="_blank" rel="noopener">Details</a></p>



<figure class="wp-block-image"><a href="https://d32ogoqmya1dw8.cloudfront.net/images/research_education/geochemsheets/eds_spectrum_biotite.png" target="_blank" rel="noreferrer noopener"><img decoding="async" src="https://d32ogoqmya1dw8.cloudfront.net/images/research_education/geochemsheets/eds_spectrum_biotite_300.png" alt="X-ray energy spectrum of biotite."/></a></figure>



<p>EDS spectrum of biotite, containing detectable Mg, Al, Si, K, Ti and Fe (from Goodge, 2003).&nbsp;<a href="https://serc.carleton.edu/details/images/8462.html" target="_blank" rel="noopener">Details</a></p>



<h2 class="wp-block-heading" id="references">References</h2>



<ul class="wp-block-list"><li>Severin, Kenneth P., 2004, Energy Dispersive Spectrometry of Common Rock Forming Minerals. Kluwer Academic Publishers, 225 p.&#8211;<em>Highly recommended reference book of representative EDS spectra of the rock-forming minerals, as well as practical tips for spectral acquisition and interpretation.</em></li><li>Goldstein, J. (2003) Scanning electron microscopy and x-ray microanalysis. Kluwer Adacemic/Plenum Pulbishers, 689 p.</li><li>Reimer, L. (1998) Scanning electron microscopy : physics of image formation and microanalysis. Springer, 527 p.</li><li>Egerton, R. F. (2005) Physical principles of electron microscopy : an introduction to TEM, SEM, and AEM. Springer, 202.</li><li>Clarke, A. R. (2002) Microscopy techniques for materials science. CRC Press (electronic resource)</li><li></li></ul>



<pre class="wp-block-code"><code>&#91;corner-ad id="1"]</code></pre>



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		<title>Basic Principles of Raman Spectroscopy</title>
		<link>https://www.analyzetest.com/2021/01/17/basic-principles-of-raman-spectroscopy/</link>
		
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		<pubDate>Sun, 17 Jan 2021 19:09:15 +0000</pubDate>
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					<description><![CDATA[Click here to see other posts about Raman Only 10 $ for interpretation of your Raman spectrum Payment Upon Completion Contact us&#8230; It is the shift in wavelength of the inelastically scattered radiation that provides the chemical and structural information.&#160;Raman shifted photons&#160;can be of either higher or lower energy, depending upon the vibrational state of [&#8230;]]]></description>
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<p class="has-text-align-center">It is the shift in wavelength of the inelastically scattered radiation that provides the chemical and structural information.&nbsp;<strong>Raman shifted photons</strong>&nbsp;can be of either higher or lower energy, depending upon the vibrational state of the molecule under study. A simplified energy diagram that illustrates these concepts is shown below.</p>



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<span id="more-332"></span>



<p><strong>Stokes radiation</strong>&nbsp;occurs at lower energy (longer wavelength) than the Rayleigh radiation, and&nbsp;<strong>anti-Stokes radiation</strong>&nbsp;has greater energy. The energy increase or decrease is related to the vibrational energy levels in the ground electronic state of the molecule, and as such, the observed Raman shift of the Stokes and anti-Stokes features are a direct measure of the vibrational energies of the molecule. A schematic Raman spectrum may appear as shown below.</p>



<p>The energy of the scattered radiation is less than the incident radiation for the Stokes line and the energy of the scattered radiation is more than the incident radiation for the anti-Stokes line. The energy increase or decrease from the excitation is related to the vibrational energy spacing in the ground electronic state of the molecule and therefore the wavenumber of the Stokes and anti-Stokes lines are a direct measure of the vibrational energies of the molecule.</p>



<p>In the example spectrum, notice that the Stokes and anti-Stokes lines are equally displaced from the Rayleigh line. This occurs because in either case one vibrational quantum of energy is gained or lost. Also, note that the anti-Stokes line is much less intense than the Stokes line. This occurs because only molecules that are vibrationally excited prior to irradiation can give rise to the anti-Stokes line. Hence, in&nbsp;<strong>Raman spectroscopy</strong>, only the more intense Stokes line is normally measured &#8211; Raman scattering is a relatively weak process. The number of photons Raman scattered is quite small. However, there are several processes which can be used to enhance the sensitivity of a Raman measurement.</p>



<figure class="wp-block-image"><img decoding="async" src="https://www.oxinst.com/learning/uploads/inline-images/raman-spectroscopy-20171121152923.jpg" alt="Raman Spectroscopy"/></figure>



<p><strong>Simplified energy diagram</strong></p>



<p>If the wavelength of the exciting laser coincides with an electronic absorption of a molecule, the intensity of Raman-active vibrations associated with the absorbing chromophore are enhanced by a factor of 102 to 104. This resonance enhancement or resonance Raman effect can be extremely useful, not just in significantly lowering the detection limits, but also in introducing electronic selectivety. Thus the resonance Raman technique is used for providing both structural and electronic insight into species of interest.</p>



<p>Metalloporphyrins, carotenoids and several other classes of biologically important molecules have strongly allowed electronic transitions in the visible, making them ideal candidates for resonance Raman spectroscopy. Resonance selectivity has a further practical use, in that spectrum of the chromophoric moiety is resonance enhanced and that of the surrounding environment is not. For biological chromophores, this means that absorbing active centres can be specifically probed by visible excitation wavelengths, and not the surrounding protein matrix (which would require UV lasers to bring into resonance).</p>



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<p><strong>Resonance Raman spectroscopy</strong>&nbsp;is also an important probe of the chemistry of metal centred complexes, fullerenes, polydiacetylenes and other &#8220;exotic&#8221; molecules which strongly absorb in the visible. Although many more molecules absorb in the ultraviolet, the high cost of lasers and optics for this spectral region have limited ultraviolet (UV) resonance Raman spectroscopy to a small number of specialist groups.</p>



<figure class="wp-block-image"><img decoding="async" src="https://www.oxinst.com/learning/uploads/inline-images/raman-spectroscopy1-20171121152937.jpg" alt="Raman Spectroscopy"/></figure>



<p><strong>Schematic Raman spectrum</strong></p>



<p>Vibrations which are resonantly enhanced fall into two or three general mechanistic classes. The most common case is&nbsp;<strong>Franck-Condon enhancement</strong>, in which a component of the normal coordinate of the vibration occurs in a direction in which the molecule expands during an electronic excitation. The more the molecule expands along this axis when it absorbs light, the larger the enhancement factor. The easily visualized ring breathing (in-plane expansion) modes of porphyrins fall into this class. Vibrations which couple two electronic excited states are also resonantly enhanced, through a mechanism called vibronic enhancement. In both cases, enhancement factors roughly follow the intensities of the absorption spectrum. The fuller theory of resonance enhancement is beyond the scope of this section.</p>



<p>Resonance enhancement does not begin at a sharply defined wavelength. In fact, enhancement of 5x to 10x is observed if the exciting laser is within even a few 100 wavenumbers below the electronic transition of a molecule. This &#8220;pre-resonance&#8221; enhancement can be experimentally useful.</p>



<p>The Raman scattering from a compound (or ion) adsorbed on or even within a few Angstroms of a structured metal surface can be 103 to 106x greater than in solution. This surface-enhanced Raman scattering is strongest on silver, but is observable on gold and copper as well. At practical excitation wavelengths, enhancement on other metals is unimportant.</p>



<p>SERS arises from&nbsp;<strong>two</strong>&nbsp;mechanisms:</p>



<ol class="wp-block-list"><li>The first is an&nbsp;<strong>enhanced electromagnetic field</strong>&nbsp;produced at the surface of the metal. When the wavelength of the incident light is close to the plasma wavelength of the metal, conduction electrons in the metal surface are excited into an extended surface electronic excited state called a surface plasmon resonance. Molecules adsorbed or in close proximity to the surface experience an exceptionally large electromagnetic field. Vibrational modes normal to the surface are most strongly enhanced.</li><li>The second mode of enhancement is by the&nbsp;<strong>formation of a charge-transfer complex</strong>&nbsp;between the surface and analyte molecule. The electronic transitions of many charge transfer complexes are in the visible, so that resonance enhancement occurs. Molecules with lone pair electrons or pi clouds show the strongest SERS. The effect was first discovered with pyridine.</li></ol>



<p>Other aromatic nitrogen or oxygen containing compounds, such as aromatic amines or phenols, are strongly SERS active. The effect can also be seen with other electron-rich functionalities such as carboxylic acids. The intensity of the surface plasmon resonance is dependent on many factors including the wavelength of the incident light and the morphology of the metal surface. The wavelength should match the plasma wavelength of the metal. This is about 382 nm for a 5μm silver particle, but can be as high as 600nm for larger ellipsoidal silver particles. The plasma wavelength is to the red of 650nm for copper and gold, the other two metals which show SERS at wavelengths in the 350-1000 nm region. The best morphology for surface plasmon resonance excitation is a small (&lt;100nm) particle or an atomically rough surface. SERS is commonly employed to study monolayers of materials adsorbed on metals, including electrodes.</p>



<p>Other popular surfaces include colloids, metal films on dielectric substrates and, recently, arrays of metal particles bound to metal or dielectric colloids through short linkages. Although SERS allows easy observation of Raman spectra from solution concentrations in the micromolar (10x-6) range,non-reproducability of quantitative measurements has in the past marred its utility for analytical purposes. However, standardization in production of SERS active media is steadily improving its potential in this area also.</p>



<p><strong>UVRRS</strong>&nbsp;is a powerful tool in the molecular analysis of complex biological systems. Most biological systems absorb UV radiation and hence have the ability to offer resonance with UV Raman excitation. This results in the highly selective resonance Raman effect enabling enhancement of important biological targets such as protein or DNA. For example, excitation around 200nm enhances the Raman peaks from vibrations of amide groups; excitation around 220nm enhances peaks from certain aromatic residues. The Raman scatter from water is weak, allowing for analysis of very weak aqueous systems.</p>



<figure class="wp-block-image"><img decoding="async" src="https://www.oxinst.com/learning/uploads/inline-images/raman-spectroscopy2-20171121152952.jpg" alt="Raman Spectroscopy"/></figure>



<p><strong>Fiber optic UVRRS configuration</strong></p>



<p>Due to the selective nature of UVRRS, a tunable laser is typically required as the excitation source. Since truly tunable continuous-wave lasers are not yet available, a Nd:YAG-pumped dye laser with frequency-doubled output is one suitable UVRRS system. Depending on the dyes used, this laser setup can give almost any required UV wavelength.&nbsp;<a href="https://andor.oxinst.com/products/intensified-camera-series/" target="_blank" rel="noopener">Intensified CCDs</a>&nbsp;(ICCDs) with UV photocathodes, back-illuminated CCDs or CCDs with UV enhancing (BASF lumogen)coatings can be used as detectors for UVRRS. These detectors are used on account of their&nbsp;<strong>high detection efficiency</strong>&nbsp;and&nbsp;<strong>multichannel capabilities</strong>. The primary obstacle to the merging of the worlds of UVRRS and fiber-optic spectroscopy is solarization, the process by which UV radiation causes opacity of fiber-optics (even quite pure silica fibers). This opacity impairs transmission, rendering standard fiber-optics useless for UVRRS.</p>



<figure class="wp-block-image"><img decoding="async" src="https://www.oxinst.com/learning/uploads/inline-images/raman-spectroscopy3-20171121153055.jpg" alt="Raman Spectroscopy"/></figure>



<p><strong>Species of Interest</strong></p>



<p>Pulsed lasers are typically utilized in the study of short-lived species. A laser pulse can be supplied to a molecular system with enough energy to redistribute the electrons in a molecule causing the formation of an excited state as illustrated on the right. The Raman spectrum of this excited state molecule can be studied either using the same laser pulse or a different pulse from a second laser (single color and two-color pulsed Raman). Excited states of interest can have lifetimes, from picoseconds to milliseconds, but the majority can be studied using gating in the order of 5ns. As the majority of excited states are generated using UV and visible lasers, photocathodes with high UV and visible Quantum Efficiencies (QEs) are typically suitable.</p>



<figure class="wp-block-image"><img decoding="async" src="https://www.oxinst.com/learning/uploads/inline-images/raman-spectroscopy5-20171121153107.jpg" alt="Raman Spectroscopy"/></figure>



<p><strong>Schematic of pump-probe (two color) Raman</strong></p>



<p>The simplest pulsed laser experiments are so-called single-color experiments where high irradiance laser pulses are used both to initiate the photoreaction, and then to Raman probe the transient species created within the pulse width. By opening the intensifier tube as shown on the right, only the Raman spectrum of the excited state will be recorded. This pulse/ICCD gate combination will be repeated and accumulated hundreds to thousands of times in order to achieve a good overall signal-to-noise ratio with high dynamic range.</p>



<p>In Time Resolved Resonance Raman (TR3) spectroscopy, pairs of laser pulses of different wavelength are used to photolyse (optically &#8220;pump&#8221;) and then to Raman probe the transient species of interest. The spectral window of the spectrograph/detector is chosen so that it corresponds to the frequency range of the Raman scattering from the probe laser.</p>



<figure class="wp-block-image"><img decoding="async" src="https://www.oxinst.com/learning/uploads/inline-images/raman-spectroscopy6-20171121153113.jpg" alt="Raman Spectroscopy"/></figure>



<p><strong>Pulsed two color Raman layout with delays under the control of a delay generator</strong></p>



<p>In&nbsp;<strong>Time Resolved Resonance Raman (TR3) spectroscopy</strong>, pairs of laser pulses of different wavelength are used to photolyse (optically &#8220;pump&#8221;) and then to Raman probe the transient species of interest. The spectral window of the spectrograph/detector is chosen so that it corresponds to the frequency range of the Raman scattering from the probe laser.</p>



<p>The time evolution of the transient signal is monitored by recording a series of spectra at different delays after the photolysis event, i.e. at a series of time delays between the excitation and probe pulses. The&nbsp;<a href="https://andor.oxinst.com/products/intensified-camera-series/" target="_blank" rel="noopener">ICCD camera</a>&nbsp;or either of the lasers can supply the trigger. A delay generator is used to control the delays.</p>



<p>In Raman microscopy, a research grade optical microscope is coupled to the excitation laser and the spectrometer, thus producing a platform capable of obtaining both conventional images and in addition generating Raman Spectra from sample areas approaching the diffraction limit (~1 micron). Imaging and spectroscopy can be combined to generate &#8220;Raman cubes&#8221;, 3- dimensional data sets, yielding spectral information at every pixel of the 2D image.</p>



<p>A motorized xyz microscope stage can be used to automatically record spectral files, which will constitute the basis of Raman images, Raman maps or a set of Raman spectra recorded from preselected points. Specific software routines will allow the quick and easy reconstruction of these maps. The possibility of generating two-dimensional and three-dimensional images of a sample, using various special features, is an evident advantage over either traditional spectroscopy or microscopy.</p>



<figure class="wp-block-image"><img decoding="async" src="https://www.oxinst.com/learning/uploads/inline-images/raman-spectroscopy7-20171121153118.jpg" alt="Raman Spectroscopy"/></figure>



<p><strong>Time delay sequences</strong></p>



<p>The first ever Raman &#8220;instrument&#8221; was constructed in 1928. This instrument used monochromatized sunlight as a light source and a human eye as a detector. Raman instrumentation was developed (based around arc lamps and photographic plates) and soon became very popular up until the 1950s. Since these early days, Raman instrumentation has evolved markedly. Modern instrumentation typically consists of a laser, Rayleigh filter, a few lenses, a spectrograph and a detector (typically a CCD or ICCD).</p>



<figure class="wp-block-image"><img decoding="async" src="https://www.oxinst.com/learning/uploads/inline-images/raman-spectroscopy8-20171121153125.jpg" alt="Raman Spectroscopy"/></figure>



<p><strong>Typical Continuous Wave (CW) Raman layout</strong></p>



<p>One of the major advantages of dispersive Raman is that it offers the possibility to select the optimal laser excitation wavelength to permit the recording of the best Raman information. For example, wavelengths can be selected to offer the best resonance with the sample under investigation.</p>



<p>One might also need to tune wavelength to avoid fluorescence and thermal emission backgrounds. Nowadays, it is possible to use laser lines from UV, (down to 200nm) up to the infrared, (1.06μm Nd:YAG laser line), from microWatts up to several Watts.</p>



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		<title>Raman spectroscopy in simple terms</title>
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<p>Light interacts with matter in different ways, transmitting through some materials, while reflecting or scattering off others. Both the material and the colour (wavelength) of the light affect this interaction. We call the study of this light ‘spectroscopy&#8217;. Which parts of the visible spectrum enter our eyes determines which colours we perceive.</p>



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<p>A substance might appear blue, for example, if it absorbs the red parts of the spectrum of light falling upon it, only reflecting (or scattering) the blue parts into our eyes.</p>



<ul class="wp-block-list" id="ElementMediaGalleryList76563"><li></li></ul>



<h2 class="wp-block-heading" id="raman-spectroscopy-looks-at-the-scattered-light">Raman spectroscopy looks at the scattered light</h2>



<p>If you were to shine blue light—from just one part of the spectrum—onto the material, you might expect to just see blue light reflected from it, or no light at all if it is completely absorbed (i.e. a black material).</p>



<p>However, by using a Raman spectrometer, you can see that often a very tiny fraction of the scattered light has a different colour. It has changed frequency because, during the scattering process, its energy changed by interacting with molecular vibrations. This is the Raman scattering process, named after its discoverer, the famous Indian physicist C.V. Raman. He was awarded the 1930 physics Nobel Prize for this great discovery.</p>



<p>By studying the vibration of the atoms we can discover the chemical composition and other useful information about the material.</p>



<p>The Raman effect is very weak; only about 1 part in 10 million of the scattered light has a shifted colour. This is too weak to see with the naked eye, so we analyse the light with a highly sensitive spectrometer.</p>



<h2 class="wp-block-heading" id="raman-spectrometers">Raman spectrometers</h2>



<p>These systems consist of:</p>



<ul class="wp-block-list"><li>one or more single coloured light sources (lasers)</li><li>lenses (both to focus the light onto the sample and to collect the scattered light)</li><li>filters (to purify the reflected and scattered light so that only the Raman light is collected)</li><li>a means of splitting the light into its constituent colours (normally a diffraction grating or prism)</li><li>a very sensitive detector (to detect the weak light)</li><li>a device such as a computer to control the whole system, display the spectrum and enable this information to be analysed</li></ul>



<p>Raman scattering&nbsp;<a href="https://www.renishaw.com/en/why-we-use-raman-spectroscopy--25803" target="_blank" rel="noopener">offers significant advantages</a>&nbsp;for the investigation of materials over other analytical techniques, such as x-raying them or seeing how they absorb light (e.g. infrared absorption or ultraviolet absorption).</p>



<p>aman spectroscopy reveals the chemical and structural composition of samples. Generally, all materials produce&nbsp;<a href="https://www.renishaw.com/en/raman-spectra-explained--25807" target="_blank" rel="noopener">Raman spectra</a>, with the exception of pure metals.</p>



<h2 class="wp-block-heading" id="raman-scattering">Raman scattering</h2>



<p>Raman scattering occurs when light interacts with molecular vibrations. This is similar to the more widely known infrared absorption spectroscopy, but different rules apply. A change in molecular polarisability is required during the vibration for the Raman effect to occur.</p>



<p>You will see some vibrations in the Raman spectrum that are not visible in the infrared spectrum, and vice-versa, because of the different selection rules. For example, Raman spectroscopy is superb for studying the carbon atoms that make up the structure of diamond, unlike infrared absorption spectroscopy.</p>



<h2 class="wp-block-heading" id="scattered-light">Scattered light</h2>



<p>The first step in producing a Raman spectrum is to illuminate your sample with a monochromatic light source, such as a laser.</p>



<p>Most of the light that scatters off is unchanged in energy (&#8216;Rayleigh scattered&#8217;). A minute fraction—perhaps 1 part in 10 million—has lost or gained energy (&#8216;Raman scattered&#8217;). This Raman shift occurs because photons (particles of light) exchange part of their energy with molecular vibrations in the material.</p>



<p>Where energy is lost the Raman scattering is designated as &#8216;Stokes&#8217;; where energy is gained the Raman scattering is designated as &#8216;anti-Stokes&#8217;. We rarely use anti-Stokes Raman light as it is less intense than the Stokes, however it does represent equivalent vibrational information of the molecule.</p>



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<ul class="wp-block-list" id="ElementMediaGalleryList76565"><li></li></ul>



<h2 class="wp-block-heading" id="vibrating-atoms">Vibrating atoms</h2>



<p>The change in energy depends on the frequency of vibration of the molecule. If it is very fast (high frequency)—light atoms held together with strong bonds—the energy change is significant. If it is very slow (low frequency)—heavy atoms held together with weak bonds—the energy change is small.</p>



<h2 class="wp-block-heading" id="raman-spectrometers">Raman spectrometers</h2>



<p>Renishaw inVia systems consist of:</p>



<ul class="wp-block-list"><li>single or multiple lasers, from UV (244 nm) to IR (1064 nm) – switch with a single click</li><li>high quality objective lenses, from high confocal 100× to long working distance and immersion options</li><li>custom designed motorised spectrometer lenses­ &#8211; automatically align for each configuration</li><li>laser-line-specific Rayleigh filters with a dual filter arrangement to optimise sensitivity</li><li>highest quality master diffraction gratings provide exceptional dispersion and longevity</li><li>thermoelectrically cooled (- 70 ºC) CCD detector – stable and sensitive</li><li>high specification multi-core PC for data collection and analysis</li></ul>



<h2 class="wp-block-heading" id="raman-spectra">Raman spectra</h2>



<p>We graphically depict the results of our measurements as Raman spectra. We plot the intensity of the scattered light (y-axis) for each energy (frequency) of light (x-axis). The frequency is traditionally measured in a unit called the wavenumber (number of waves per cm, cm<sup>-1</sup>).</p>



<p>We plot the x-axis frequencies relative to that of the laser as it is the shift in energy of the light that is of particular interest.</p>



<ul class="wp-block-list" id="ElementMediaGalleryList76566"><li></li></ul>



<h2 class="wp-block-heading" id="how-do-i-get-the-information-i-want-from-my-spectrum">How do I get the information I want from my spectrum?</h2>



<p>You can tell a great deal about a material from its Raman spectrum, with different features relating to different aspects of the material.</p>



<p>The key features are:</p>



<p><strong>The Raman shifts and relative intensities of all of the Raman bands of the material</strong><br>With this, we can&nbsp;<a href="https://www.renishaw.com/media/img/en/4d6afd8479524817b6b5b71f2eafde6a.jpg" target="_blank" rel="noopener">identify the material.</a></p>



<p><strong>Individual band changes<br></strong>A band may shift, narrow or broaden, or vary in intensity. These changes can reveal information about stresses in the sample, variations in&nbsp;<a href="https://www.renishaw.com/media/img/gen/391f300fc0104d9b8a0bfa12aadaf900.jpg" target="_blank" rel="noopener">crystallinity</a>, and the amount of material respectively.</p>



<p><strong>Variations in spectra with position on the sample</strong><br>This will reveal changes in the uniformity (homogeneity) of the material. You can analyse at several arbitrary points, or systematically measure an array of points (enabling the production of images of&nbsp;<a href="https://www.renishaw.com/media/img/gen/bc393cb46bee4c918050f2aa1f373d43.jpg" target="_blank" rel="noopener">composition</a>,&nbsp;<a href="https://www.renishaw.com/media/img/gen/de893cb019d6437b9d271d858c52923a.jpg" target="_blank" rel="noopener">stress</a>, crystallinity, etc.)</p>



<h2 class="wp-block-heading" id="what-do-the-raman-bands-represent">What do the Raman bands represent?</h2>



<p>It is easy to understand the Raman spectrum of crystals with a regular array of identical atoms, all in the same configuration (such as the carbon atoms in diamond). In these cases, you often see just one dominant Raman band (because there is just one molecular environment of the crystal).</p>



<p>The Raman spectrum of polystyrene, however, is much more complex because the molecule is less symmetric and has hydrogen atoms in addition to carbon atoms. There are also different bond types connecting the atoms.</p>



<ul class="wp-block-list" id="ElementMediaGalleryList76567"><li></li></ul>



<h2 class="wp-block-heading" id="vibration-frequencies">Vibration frequencies</h2>



<p>The frequencies of vibration depend on the masses of the atoms involved and the strength of the bonds between them. Heavy atoms and weak bonds have low Raman shifts. Light atoms and strong bonds have high Raman shifts.</p>



<p>We see the high frequency carbon-hydrogen (C-H) vibrations in the polystyrene spectrum at about 3000 cm<sup>-1</sup>. The low frequency carbon-carbon (C-C) vibrations are at around 800 cm<sup>-1</sup>. The C-H vibrations have a higher frequency than the C-C vibrations because hydrogen is lighter than carbon.</p>



<p>We see the vibrations of two carbon atoms linked by strong double bonds (C=C) at around 1600 cm<sup>-1</sup>. This is at a higher frequency than two carbon atoms lined by a weaker single bond (C-C, 800 cm<sup>-1</sup>).</p>



<p>You can use these simple rules to explain many of the features of Raman spectra.</p>



<h2 class="wp-block-heading" id="vibrations-in-detail">Vibrations in detail</h2>



<p>You can see more subtle effects if you inspect spectra closely. The strength of bonds also affects their vibration rates. For example, the C-H vibrations of polystyrene appear in two bands, at approximately 2900 cm<sup>-1</sup>&nbsp;and 3050 cm<sup>-1</sup>. The carbons in the former are part of carbon chains (&#8216;aliphatic&#8217;), whereas the carbons in the latter form part of carbon rings (&#8216;aromatic&#8217;).</p>



<p>You can view the vibrations of a complex molecule as partly consisting of many simple diatomic vibrations. However the full richness of the Raman spectrum can only be understood by considering the vibrations of larger groups of atoms (such as the expanding/contracting ‘breathing mode&#8217; of the aromatic carbon ring that appears at 1000 cm<sup>-1&nbsp;</sup>in polystyrene).</p>



<h2 class="wp-block-heading" id="low-frequency-vibrations">Low frequency vibrations</h2>



<p>You can also study Raman bands with low Raman shifts, below 100 cm<sup>-1</sup>. These originate from very heavy atoms or very large-scale vibrations, such as the whole crystal lattice vibrating. Renishaw&#8217;s Raman instruments enable you to study these modes and explore a wide range of materials and crystals, and distinguish between different crystalline forms (polymorphs).</p>



<h2 class="wp-block-heading" id="the-big-picture">The big picture</h2>



<p>A Raman spectrum therefore consists of a range of features, each associated with a vibrational mode. The spectrum is unique to the material and enables you to identify it. It is important to note that, although a full understanding of the vibrational modes is of interest, you rarely need this as you can use a reference database for identification.</p>



<p>When a sample is illuminated by a laser, both Raman scattering and photoluminescence (PL) can occur. The latter can be many times stronger than the former and can prevent successful Raman analysis.</p>



<p>PL comprises both fluorescence and phosphorescence processes and originates from an absorption/emission process between different electronic energy levels in the material. The amount and type of PL depends on which material you are studying and which laser wavelength you are using. Unwanted fluorescence interference can normally be avoided by choosing an appropriate laser wavelength.</p>



<ul class="wp-block-list" id="ElementMediaGalleryList76568"><li><a href="https://www.renishaw.com/media/img/en/50e033cc197a416db28909dc584e38a1.jpg" target="_blank" rel="noopener"></a><a href="https://www.renishaw.com/media/img/en/50e033cc197a416db28909dc584e38a1.jpg" target="_blank" rel="noopener">Energy diagram showing absorption of light and the processes involved in the emission of light as fluorescence and phosphorescence.</a></li></ul>



<h2 class="wp-block-heading" id="what-pl-can-tell-us">What PL can tell us</h2>



<p>In many cases photoluminescence carries useful information that can facilitate sample analysis and augment the Raman data. inVia confocal Raman microscopes are suited to the analysis of both Raman scattering and PL.</p>



<p>Fluorescence imaging (a type of PL) is often employed in the biological sciences, where fluorescent tags are used to reveal the presence and distribution of molecular species. However, this approach is more invasive than Raman analysis, which is typically tag-free. Renishaw&#8217;s inVia confocal Raman microscope can be used to generate images of fluorescent tags, but more commonly provides valuable tag-free chemical information.</p>



<p>You can also use PL to study crystal defects, such as atomic vacancies and substitutions. This is of particular importance for materials such as diamond and silicon carbide (SiC). Not only can you identify the defect, but you can also tell if the crystal has internal stresses.</p>



<ul class="wp-block-list" id="ElementMediaGalleryList76569"><li><a href="https://www.renishaw.com/media/img/gen/c658b220e9c640d0b62697c210e5c3e9.jpg" target="_blank" rel="noopener"></a><a href="https://www.renishaw.com/media/img/gen/c658b220e9c640d0b62697c210e5c3e9.jpg" target="_blank" rel="noopener">Stress image generated from the ruby R2 PL band position</a></li></ul>



<h2 class="wp-block-heading" id="how-to-avoid-pl-backgrounds">How to avoid PL backgrounds</h2>



<p>Occasionally PL bands are strong and broad, masking Raman information. You can counter this by using a different laser wavelength. This can move the Raman bands away from the peak emission of the PL band and may even avoid generation of the PL entirely.</p>



<p>Ideally, a Raman instrument should be able to switch rapidly and easily between different laser wavelengths, so that you can select or avoid PL features, depending on your requirements.</p>



<p>Raman images (sometimes referred to as maps) depict a variation in spectral information from different points on, or in your sample. They can take the form of one-dimensional profiles, two-dimensional images, or three-dimensional rendered volumes. With them, you can rapidly see how a Raman parameter alters with position.</p>



<p>The parameter could be as simple as the intensity of a particular Raman band, or you could derive it from a more complicated analysis of the whole Raman spectrum.</p>



<p>The two main methods of collecting the spectral data to generate these images are Raman mapping and Raman imaging.</p>



<ul class="wp-block-list" id="ElementMediaGalleryList76570"><li><a href="https://www.renishaw.com/media/img/gen/5c817273421b48769a6bbdf29df25533.jpg" target="_blank" rel="noopener"></a><a href="https://www.renishaw.com/media/img/gen/5c817273421b48769a6bbdf29df25533.jpg" target="_blank" rel="noopener">White light and Raman images of washing powder</a></li></ul>



<h2 class="wp-block-heading" id="raman-mapping">Raman mapping</h2>



<p>Raman mapping collects a spectral hypercube (a Raman spectrum from each position on the sample in a single file), rather than a simple intensity image. The hypercube is analysed to produce Raman images.</p>



<p>There are several Raman mapping methods, such as:</p>



<ul class="wp-block-list"><li><strong>Point-by-point mapping</strong><br>The laser is focused to a spot. A motorised stage moves the sample under the laser. Spectra are sequentially acquired from an array of sample points spanning the defined region of interest. Fast versions of this are Renishaw&#8217;s&nbsp;<a href="https://www.renishaw.com/en/streamhr-generate-high-resolution-chemical-images--25501" target="_blank" rel="noopener">StreamHR™ and StreamHR&nbsp;<em>Rapide</em>.</a></li><li><strong>Line focus mapping</strong><br>This is similar to point-by-point mapping, but the laser illuminates a line on the sample, rather than a spot. This enables you to simultaneously collect spectra from multiple positions on the sample, saving time. With this method you can use higher laser powers without damaging the sample (reducing exposure times). Renishaw&#8217;s&nbsp;<a href="https://www.renishaw.com/en/streamline-generate-chemical-images-rapidly--9449" target="_blank" rel="noopener">StreamLine™</a>&nbsp;is a sophisticated modern implementation of this concept.</li></ul>



<p>It is important to consider the potentially undesirable effects of undersampling when mapping. This is most clearly illustrated when point-by-point mapping: parts of the sample will be &#8216;missed&#8217; if the laser spot is smaller than the spacing between acquisition points. Renishaw has solved this problem through the use of the&nbsp;<a href="https://www.renishaw.com/en/streamline-slalom--25499" target="_blank" rel="noopener">StreamLine™ Slalom</a>&nbsp;mode.</p>



<p><strong>Generating Raman images from map data</strong></p>



<p>Once all the Raman spectra are collected from the mapping experiment, they can be analysed to produce profiles, images or rendered volumes. Analysis options in Renishaw&#8217;s WiRE software include:</p>



<ul class="wp-block-list"><li><strong>Intensity at one frequency in the spectrum</strong><br>This produces an equivalent image to that from Raman imaging. These are quick to generate but may be misleading because it is not possible to differentiate between intensities arising from a Raman band of interest and those associated with a broad background fluorescence.</li><li><strong>Curve fit parameters<br></strong>All the spectra in the set have a theoretical curve fitted to one of the Raman bands. Images are then made based on the theoretical curve parameters for each spectrum. Images are often made using the centre frequency of the curve (band), or the full width at half maximum (FWHM), as this is sensitive to stresses and crystallinity within the sample respectively.</li><li><strong>Multivariate parameters<br></strong>Images can be generated using chemometric tools, such as generic principal component analysis (PCA), or Renishaw&#8217;s Empty Modelling™, which is optimised for Raman data. The Empty Modelling method reveals systematic variations between the Raman spectra, and highlights the distribution of these variations across the sample as an image. This is achieved without the need for prior knowledge of what is present within the sample, which greatly simplifies the analysis process. Multivariate analysis is very powerful because it uses information from the entire spectrum, not just one part of it (intensity at one frequency) or one curve-fitted band. This typically results in higher quality Raman images.</li></ul>



<h2 class="wp-block-heading" id="raman-imaging">Raman imaging</h2>



<p>Raman imaging is analogous to taking a photograph; spectral intensity values are collected simultaneously from the entire area of interest. The laser illuminates a square or circular region on the sample. The light is filtered so that the intensity of just one narrow part of the spectrum is recorded on the detector.</p>



<p>The single image collected contains limited information, just the intensity of the light at that frequency. However, these images can be acquired rapidly. This is especially true if you have a high power laser; because the light is spread over an area, you can use all the power without damaging your samples, with correspondingly short exposure times.</p>



<p>Two-dimensional images are typically produced using this method. Renishaw&#8217;s&nbsp;<a href="https://www.renishaw.com/en/true-raman-imaging--25925" target="_blank" rel="noopener">True Raman Imaging</a>&nbsp;is an example of Raman imaging.</p>



<p>Note that it is possible to collect intensity values covering multiple points of the spectrum by using multiple and/or tuneable filters.</p>



<h2 class="wp-block-heading" id="spatial-resolution">Spatial resolution</h2>



<h3 class="wp-block-heading" id="point-by-point-raman-mapping">Point-by-point Raman mapping</h3>



<p>Spatial resolution is determined by a combination of the laser spot size and the spacing between acquisition points on the sample.</p>



<ul class="wp-block-list"><li><strong>Laser spot size<br></strong>This is a function of the objective magnification and the laser wavelength (higher magnification and shorter wavelengths produce smaller spot sizes)</li><li><strong>Spacing between acquisition points on the sample (sampling)</strong><br>This is a function of the sample stage (ideally stages should have a large travel range while still enabling a step size down to 100 nm, smaller than the smallest spot size)</li></ul>



<h3 class="wp-block-heading" id="raman-imaging">Raman imaging</h3>



<p>Spatial resolution is determined by the magnification of the optics in the system and the size of the elements in the detector. Ultimately this is limited, by the inherent wavelike nature of light, to a little under a micrometre.</p>



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